Users' Mathboxes Mathbox for Zhi Wang < Previous   Next >
Nearby theorems
Mirrors  >  Home  >  MPE Home  >  Th. List  >   Mathboxes  >  mosssn2 Structured version   Visualization version   GIF version

Theorem mosssn2 49615
Description: Two ways of expressing "at most one" element in a class. (Contributed by Zhi Wang, 23-Sep-2024.)
Assertion
Ref Expression
mosssn2 (∃*𝑥 𝑥𝐴 ↔ ∃𝑦 𝐴 ⊆ {𝑦})
Distinct variable groups:   𝑥,𝐴   𝑦,𝐴

Proof of Theorem mosssn2
StepHypRef Expression
1 19.45v 2029 . 2 (∃𝑦(𝐴 = ∅ ∨ 𝐴 = {𝑦}) ↔ (𝐴 = ∅ ∨ ∃𝑦 𝐴 = {𝑦}))
2 sssn 4792 . . 3 (𝐴 ⊆ {𝑦} ↔ (𝐴 = ∅ ∨ 𝐴 = {𝑦}))
32exbii 1878 . 2 (∃𝑦 𝐴 ⊆ {𝑦} ↔ ∃𝑦(𝐴 = ∅ ∨ 𝐴 = {𝑦}))
4 mo0sn 49614 . 2 (∃*𝑥 𝑥𝐴 ↔ (𝐴 = ∅ ∨ ∃𝑦 𝐴 = {𝑦}))
51, 3, 43bitr4ri 307 1 (∃*𝑥 𝑥𝐴 ↔ ∃𝑦 𝐴 ⊆ {𝑦})
Colors of variables: wff setvar class
Syntax hints:  wb 209  wo 860   = wceq 1570  wex 1809  wcel 2143  ∃*wmo 2565  wss 3905  c0 4286  {csn 4589
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1825  ax-4 1839  ax-5 1940  ax-6 1997  ax-7 2038  ax-8 2145  ax-9 2153  ax-10 2176  ax-11 2192  ax-12 2213  ax-ext 2735  ax-sep 5257
This theorem depends on definitions:  df-bi 210  df-an 401  df-or 861  df-3an 1105  df-tru 1573  df-fal 1583  df-ex 1810  df-nf 1814  df-sb 2097  df-mo 2567  df-eu 2597  df-clab 2742  df-cleq 2755  df-clel 2838  df-nfc 2912  df-ral 3080  df-rex 3090  df-rmo 3369  df-reu 3370  df-v 3457  df-sbc 3745  df-dif 3908  df-ss 3922  df-nul 4287  df-sn 4590
This theorem is referenced by:  subthinc  50241
  Copyright terms: Public domain W3C validator