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Theorem basgen 12874

Description: Given a topology

, show that a subset

satisfying the third antecedent is a basis for it. Lemma 2.3 of [Munkres] p. 81 using abbreviations. (Contributed by NM, 22-Jul-2006.) (Revised by Mario Carneiro, 2-Sep-2015.)

**Assertion**
Ref	Expression
basgen	$/\$ $/\$

**Proof of Theorem basgen**
Step	Hyp	Ref	Expression
1		tgss 12857	. . . 4 $/\$
2	1	3adant3 1012	. . 3 $/\$ $/\$
3		tgtop 12862	. . . 4
4	3	3ad2ant1 1013	. . 3 $/\$ $/\$
5	2, 4	sseqtrd 3185	. 2 $/\$ $/\$
6		simp3 994	. 2 $/\$ $/\$
7	5, 6	eqssd 3164	1 $/\$ $/\$

Colors of variables: wff set class

Syntax hints:

wi 4 $/\$ w3a 973

wceq 1348

wcel 2141

wss 3121

cfv 5198

ctg 12594

ctop 12789

This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia1 105 ax-ia2 106 ax-ia3 107 ax-io 704 ax-5 1440 ax-7 1441 ax-gen 1442 ax-ie1 1486 ax-ie2 1487 ax-8 1497 ax-10 1498 ax-11 1499 ax-i12 1500 ax-bndl 1502 ax-4 1503 ax-17 1519 ax-i9 1523 ax-ial 1527 ax-i5r 1528 ax-13 2143 ax-14 2144 ax-ext 2152 ax-sep 4107 ax-pow 4160 ax-pr 4194 ax-un 4418

This theorem depends on definitions: df-bi 116 df-3an 975 df-tru 1351 df-nf 1454 df-sb 1756 df-eu 2022 df-mo 2023 df-clab 2157 df-cleq 2163 df-clel 2166 df-nfc 2301 df-ral 2453 df-rex 2454 df-v 2732 df-sbc 2956 df-un 3125 df-in 3127 df-ss 3134 df-pw 3568 df-sn 3589 df-pr 3590 df-op 3592 df-uni 3797 df-br 3990 df-opab 4051 df-mpt 4052 df-id 4278 df-xp 4617 df-rel 4618 df-cnv 4619 df-co 4620 df-dm 4621 df-iota 5160 df-fun 5200 df-fv 5206 df-topgen 12600 df-top 12790

This theorem is referenced by: basgen2 12875

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