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Theorem basgen 14627

Description: Given a topology

, show that a subset

satisfying the third antecedent is a basis for it. Lemma 2.3 of [Munkres] p. 81 using abbreviations. (Contributed by NM, 22-Jul-2006.) (Revised by Mario Carneiro, 2-Sep-2015.)

**Assertion**
Ref	Expression
basgen	$/\$ $/\$

**Proof of Theorem basgen**
Step	Hyp	Ref	Expression
1		tgss 14610	. . . 4 $/\$
2	1	3adant3 1020	. . 3 $/\$ $/\$
3		tgtop 14615	. . . 4
4	3	3ad2ant1 1021	. . 3 $/\$ $/\$
5	2, 4	sseqtrd 3235	. 2 $/\$ $/\$
6		simp3 1002	. 2 $/\$ $/\$
7	5, 6	eqssd 3214	1 $/\$ $/\$

Colors of variables: wff set class

Syntax hints:

wi 4 $/\$ w3a 981

wceq 1373

wcel 2177

wss 3170

cfv 5280

ctg 13161

ctop 14544

This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia1 106 ax-ia2 107 ax-ia3 108 ax-io 711 ax-5 1471 ax-7 1472 ax-gen 1473 ax-ie1 1517 ax-ie2 1518 ax-8 1528 ax-10 1529 ax-11 1530 ax-i12 1531 ax-bndl 1533 ax-4 1534 ax-17 1550 ax-i9 1554 ax-ial 1558 ax-i5r 1559 ax-13 2179 ax-14 2180 ax-ext 2188 ax-sep 4170 ax-pow 4226 ax-pr 4261 ax-un 4488

This theorem depends on definitions: df-bi 117 df-3an 983 df-tru 1376 df-nf 1485 df-sb 1787 df-eu 2058 df-mo 2059 df-clab 2193 df-cleq 2199 df-clel 2202 df-nfc 2338 df-ral 2490 df-rex 2491 df-v 2775 df-sbc 3003 df-un 3174 df-in 3176 df-ss 3183 df-pw 3623 df-sn 3644 df-pr 3645 df-op 3647 df-uni 3857 df-br 4052 df-opab 4114 df-mpt 4115 df-id 4348 df-xp 4689 df-rel 4690 df-cnv 4691 df-co 4692 df-dm 4693 df-iota 5241 df-fun 5282 df-fv 5288 df-topgen 13167 df-top 14545

This theorem is referenced by: basgen2 14628

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