Theorem f0dom0 5561

Description: A function is empty iff it has an empty domain. (Contributed by AV, 10-Feb-2019.)

Assertion

Ref	Expression
f0dom0	|- ( F : X --> Y -> ( X = (/) <-> F = (/) ) )

Proof of Theorem f0dom0

Step	Hyp	Ref	Expression
1		feq2 5492	. . . 4 |- ( X = (/) -> ( F : X --> Y <-> F : (/) --> Y ) )
2		f0bi 5560	. . . . 5 |- ( F : (/) --> Y <-> F = (/) )
3	2	biimpi 120	. . . 4 |- ( F : (/) --> Y -> F = (/) )
4	1, 3	biimtrdi 163	. . 3 |- ( X = (/) -> ( F : X --> Y -> F = (/) ) )
5	4	com12 30	. 2 |- ( F : X --> Y -> ( X = (/) -> F = (/) ) )
6		feq1 5491	. . . 4 |- ( F = (/) -> ( F : X --> Y <-> (/) : X --> Y ) )
7		fdm 5514	. . . . 5 |- ( (/) : X --> Y -> dom (/) = X )
8		dm0 4970	. . . . 5 |- dom (/) = (/)
9	7, 8	eqtr3di 2280	. . . 4 |- ( (/) : X --> Y -> X = (/) )
10	6, 9	biimtrdi 163	. . 3 |- ( F = (/) -> ( F : X --> Y -> X = (/) ) )
11	10	com12 30	. 2 |- ( F : X --> Y -> ( F = (/) -> X = (/) ) )
12	5, 11	impbid 129	1 |- ( F : X --> Y -> ( X = (/) <-> F = (/) ) )

Syntax hints:   -> wi 4   <-> wb 105   = wceq 1398   (/)c0 3508   dom cdm 4749   -->wf 5348

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-in1 619  ax-in2 620  ax-io 717  ax-5 1496  ax-7 1497  ax-gen 1498  ax-ie1 1542  ax-ie2 1543  ax-8 1553  ax-10 1554  ax-11 1555  ax-i12 1556  ax-bndl 1558  ax-4 1559  ax-17 1575  ax-i9 1579  ax-ial 1583  ax-i5r 1584  ax-14 2206  ax-ext 2214  ax-sep 4228  ax-nul 4236  ax-pow 4287  ax-pr 4322

This theorem depends on definitions:  df-bi 117  df-3an 1007  df-tru 1401  df-fal 1404  df-nf 1510  df-sb 1812  df-eu 2083  df-mo 2084  df-clab 2219  df-cleq 2225  df-clel 2228  df-nfc 2373  df-ral 2525  df-rex 2526  df-v 2815  df-dif 3213  df-un 3215  df-in 3217  df-ss 3224  df-nul 3509  df-pw 3671  df-sn 3695  df-pr 3696  df-op 3698  df-br 4110  df-opab 4172  df-id 4414  df-xp 4755  df-rel 4756  df-cnv 4757  df-co 4758  df-dm 4759  df-rn 4760  df-fun 5354  df-fn 5355  df-f 5356

This theorem is referenced by:  pfxn0  11380