Theorem feq2 5429

Description: Equality theorem for functions. (Contributed by NM, 1-Aug-1994.)

Assertion

Ref	Expression
feq2	|- ( A = B -> ( F : A --> C <-> F : B --> C ) )

Proof of Theorem feq2

Step	Hyp	Ref	Expression
1		fneq2 5382	. . 3 |- ( A = B -> ( F Fn A <-> F Fn B ) )
2	1	anbi1d 465	. 2 |- ( A = B -> ( ( F Fn A /\ ran F C_ C ) <-> ( F Fn B /\ ran F C_ C ) ) )
3		df-f 5294	. 2 |- ( F : A --> C <-> ( F Fn A /\ ran F C_ C ) )
4		df-f 5294	. 2 |- ( F : B --> C <-> ( F Fn B /\ ran F C_ C ) )
5	2, 3, 4	3bitr4g 223	1 |- ( A = B -> ( F : A --> C <-> F : B --> C ) )

Syntax hints:   -> wi 4   /\ wa 104   <-> wb 105   = wceq 1373   C_ wss 3174   ran crn 4694   Fn wfn 5285   -->wf 5286

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-5 1471  ax-gen 1473  ax-4 1534  ax-17 1550  ax-ext 2189

This theorem depends on definitions:  df-bi 117  df-cleq 2200  df-fn 5293  df-f 5294

This theorem is referenced by:  feq23  5431  feq2d  5433  feq2i  5439  f00  5489  f0dom0  5491  f1eq2  5499  fressnfv  5794  tfrcllemsucfn  6462  tfrcllemsucaccv  6463  tfrcllembxssdm  6465  tfrcllembfn  6466  tfrcllemaccex  6470  tfrcllemres  6471  tfrcldm  6472  tfrcl  6473  mapvalg  6768  map0g  6798  ac6sfi  7021  isomni  7264  ismkv  7281  iswomni  7293  isghm  13694