Theorem fneq1i 5376

Description: Equality inference for function predicate with domain. (Contributed by Paul Chapman, 22-Jun-2011.)

Hypothesis

Ref	Expression
fneq1i.1	|- F = G

Assertion

Ref	Expression
fneq1i	|- ( F Fn A <-> G Fn A )

Proof of Theorem fneq1i

Step	Hyp	Ref	Expression
1		fneq1i.1	. 2 |- F = G
2		fneq1 5370	. 2 |- ( F = G -> ( F Fn A <-> G Fn A ) )
3	1, 2	ax-mp 5	1 |- ( F Fn A <-> G Fn A )

Syntax hints:   <-> wb 105   = wceq 1373   Fn wfn 5274

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-io 711  ax-5 1471  ax-7 1472  ax-gen 1473  ax-ie1 1517  ax-ie2 1518  ax-8 1528  ax-10 1529  ax-11 1530  ax-i12 1531  ax-bndl 1533  ax-4 1534  ax-17 1550  ax-i9 1554  ax-ial 1558  ax-i5r 1559  ax-ext 2188

This theorem depends on definitions:  df-bi 117  df-3an 983  df-tru 1376  df-nf 1485  df-sb 1787  df-clab 2193  df-cleq 2199  df-clel 2202  df-nfc 2338  df-v 2775  df-un 3174  df-in 3176  df-ss 3183  df-sn 3643  df-pr 3644  df-op 3646  df-br 4051  df-opab 4113  df-rel 4689  df-cnv 4690  df-co 4691  df-dm 4692  df-fun 5281  df-fn 5282

This theorem is referenced by:  fnunsn  5391  fnopabg  5408  f1oun  5553  f1oi  5572  f1osn  5574  ovid  6074  tfri1d  6433  frec2uzrand  10567  frec2uzf1od  10568  frecfzennn  10588  xnn0nnen  10599  prdsinvlem  13510  dfrelog  15402  edgstruct  15730  nninfsellemeqinf  16088