Theorem fneq1 5305

Description: Equality theorem for function predicate with domain. (Contributed by NM, 1-Aug-1994.)

Assertion

Ref	Expression
fneq1	|- ( F = G -> ( F Fn A <-> G Fn A ) )

Proof of Theorem fneq1

Step	Hyp	Ref	Expression
1		funeq 5237	. . 3 |- ( F = G -> ( Fun F <-> Fun G ) )
2		dmeq 4828	. . . 4 |- ( F = G -> dom F = dom G )
3	2	eqeq1d 2186	. . 3 |- ( F = G -> ( dom F = A <-> dom G = A ) )
4	1, 3	anbi12d 473	. 2 |- ( F = G -> ( ( Fun F /\ dom F = A ) <-> ( Fun G /\ dom G = A ) ) )
5		df-fn 5220	. 2 |- ( F Fn A <-> ( Fun F /\ dom F = A ) )
6		df-fn 5220	. 2 |- ( G Fn A <-> ( Fun G /\ dom G = A ) )
7	4, 5, 6	3bitr4g 223	1 |- ( F = G -> ( F Fn A <-> G Fn A ) )

Syntax hints:   -> wi 4   /\ wa 104   <-> wb 105   = wceq 1353   dom cdm 4627   Fun wfun 5211   Fn wfn 5212

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-io 709  ax-5 1447  ax-7 1448  ax-gen 1449  ax-ie1 1493  ax-ie2 1494  ax-8 1504  ax-10 1505  ax-11 1506  ax-i12 1507  ax-bndl 1509  ax-4 1510  ax-17 1526  ax-i9 1530  ax-ial 1534  ax-i5r 1535  ax-ext 2159

This theorem depends on definitions:  df-bi 117  df-3an 980  df-tru 1356  df-nf 1461  df-sb 1763  df-clab 2164  df-cleq 2170  df-clel 2173  df-nfc 2308  df-v 2740  df-un 3134  df-in 3136  df-ss 3143  df-sn 3599  df-pr 3600  df-op 3602  df-br 4005  df-opab 4066  df-rel 4634  df-cnv 4635  df-co 4636  df-dm 4637  df-fun 5219  df-fn 5220

This theorem is referenced by:  fneq1d  5307  fneq1i  5311  fn0  5336  feq1  5349  foeq1  5435  f1ocnv  5475  mpteqb  5607  eufnfv  5748  tfr0dm  6323  tfrlemiex  6332  tfr1onlemsucfn  6341  tfr1onlemsucaccv  6342  tfr1onlembxssdm  6344  tfr1onlembfn  6345  tfr1onlemex  6348  tfr1onlemaccex  6349  tfr1onlemres  6350  mapval2  6678  elixp2  6702  ixpfn  6704  elixpsn  6735  cc2lem  7265  cc3  7267  lmodfopnelem1  13414