Theorem fneq1 5362

Description: Equality theorem for function predicate with domain. (Contributed by NM, 1-Aug-1994.)

Assertion

Ref	Expression
fneq1	|- ( F = G -> ( F Fn A <-> G Fn A ) )

Proof of Theorem fneq1

Step	Hyp	Ref	Expression
1		funeq 5291	. . 3 |- ( F = G -> ( Fun F <-> Fun G ) )
2		dmeq 4878	. . . 4 |- ( F = G -> dom F = dom G )
3	2	eqeq1d 2214	. . 3 |- ( F = G -> ( dom F = A <-> dom G = A ) )
4	1, 3	anbi12d 473	. 2 |- ( F = G -> ( ( Fun F /\ dom F = A ) <-> ( Fun G /\ dom G = A ) ) )
5		df-fn 5274	. 2 |- ( F Fn A <-> ( Fun F /\ dom F = A ) )
6		df-fn 5274	. 2 |- ( G Fn A <-> ( Fun G /\ dom G = A ) )
7	4, 5, 6	3bitr4g 223	1 |- ( F = G -> ( F Fn A <-> G Fn A ) )

Syntax hints:   -> wi 4   /\ wa 104   <-> wb 105   = wceq 1373   dom cdm 4675   Fun wfun 5265   Fn wfn 5266

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-io 711  ax-5 1470  ax-7 1471  ax-gen 1472  ax-ie1 1516  ax-ie2 1517  ax-8 1527  ax-10 1528  ax-11 1529  ax-i12 1530  ax-bndl 1532  ax-4 1533  ax-17 1549  ax-i9 1553  ax-ial 1557  ax-i5r 1558  ax-ext 2187

This theorem depends on definitions:  df-bi 117  df-3an 983  df-tru 1376  df-nf 1484  df-sb 1786  df-clab 2192  df-cleq 2198  df-clel 2201  df-nfc 2337  df-v 2774  df-un 3170  df-in 3172  df-ss 3179  df-sn 3639  df-pr 3640  df-op 3642  df-br 4045  df-opab 4106  df-rel 4682  df-cnv 4683  df-co 4684  df-dm 4685  df-fun 5273  df-fn 5274

This theorem is referenced by:  fneq1d  5364  fneq1i  5368  fn0  5395  feq1  5408  foeq1  5494  f1ocnv  5535  mpteqb  5670  eufnfv  5815  uchoice  6223  tfr0dm  6408  tfrlemiex  6417  tfr1onlemsucfn  6426  tfr1onlemsucaccv  6427  tfr1onlembxssdm  6429  tfr1onlembfn  6430  tfr1onlemex  6433  tfr1onlemaccex  6434  tfr1onlemres  6435  mapval2  6765  elixp2  6789  ixpfn  6791  elixpsn  6822  cc2lem  7378  cc3  7380  lmodfopnelem1  14086