Theorem fneq1 5464

Description: Equality theorem for function predicate with domain. (Contributed by NM, 1-Aug-1994.)

Assertion

Ref	Expression
fneq1	|- ( F = G -> ( F Fn A <-> G Fn A ) )

Proof of Theorem fneq1

Step	Hyp	Ref	Expression
1		funeq 5392	. . 3 |- ( F = G -> ( Fun F <-> Fun G ) )
2		dmeq 4976	. . . 4 |- ( F = G -> dom F = dom G )
3	2	eqeq1d 2247	. . 3 |- ( F = G -> ( dom F = A <-> dom G = A ) )
4	1, 3	anbi12d 477	. 2 |- ( F = G -> ( ( Fun F /\ dom F = A ) <-> ( Fun G /\ dom G = A ) ) )
5		df-fn 5375	. 2 |- ( F Fn A <-> ( Fun F /\ dom F = A ) )
6		df-fn 5375	. 2 |- ( G Fn A <-> ( Fun G /\ dom G = A ) )
7	4, 5, 6	3bitr4g 223	1 |- ( F = G -> ( F Fn A <-> G Fn A ) )

Syntax hints:   -> wi 4   /\ wa 104   <-> wb 105   = wceq 1402   dom cdm 4769   Fun wfun 5366   Fn wfn 5367

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-io 721  ax-5 1500  ax-7 1501  ax-gen 1502  ax-ie1 1546  ax-ie2 1547  ax-8 1557  ax-10 1558  ax-11 1559  ax-i12 1560  ax-bndl 1562  ax-4 1563  ax-17 1579  ax-i9 1583  ax-ial 1587  ax-i5r 1588  ax-ext 2220

This theorem depends on definitions:  df-bi 117  df-3an 1011  df-tru 1405  df-nf 1514  df-sb 1816  df-clab 2225  df-cleq 2231  df-clel 2234  df-nfc 2381  df-v 2823  df-un 3224  df-in 3226  df-ss 3233  df-sn 3711  df-pr 3712  df-op 3714  df-br 4126  df-opab 4188  df-rel 4776  df-cnv 4777  df-co 4778  df-dm 4779  df-fun 5374  df-fn 5375

This theorem is referenced by:  fneq1d  5466  fneq1i  5470  fn0  5498  feq1  5511  foeq1  5606  f1ocnv  5647  mpteqb  5790  eufnfv  5939  uchoice  6361  tfr0dm  6583  tfrlemiex  6592  tfr1onlemsucfn  6601  tfr1onlemsucaccv  6602  tfr1onlembxssdm  6604  tfr1onlembfn  6605  tfr1onlemex  6608  tfr1onlemaccex  6609  tfr1onlemres  6610  fsetdmprc0  6940  mapval2  6949  elixp2  6974  ixpfn  6976  elixpsn  7007  cc2lem  7622  cc3  7624  lmodfopnelem1  14633