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Theorem sotritrieq 4152
Description: A trichotomy relationship, given a trichotomous order. (Contributed by Jim Kingdon, 13-Dec-2019.)
Hypotheses
Ref Expression
sotritric.or  |-  R  Or  A
sotritric.tri  |-  ( ( B  e.  A  /\  C  e.  A )  ->  ( B R C  \/  B  =  C  \/  C R B ) )
Assertion
Ref Expression
sotritrieq  |-  ( ( B  e.  A  /\  C  e.  A )  ->  ( B  =  C  <->  -.  ( B R C  \/  C R B ) ) )

Proof of Theorem sotritrieq
StepHypRef Expression
1 sotritric.or . . . . . . 7  |-  R  Or  A
2 sonr 4144 . . . . . . 7  |-  ( ( R  Or  A  /\  B  e.  A )  ->  -.  B R B )
31, 2mpan 415 . . . . . 6  |-  ( B  e.  A  ->  -.  B R B )
4 breq2 3849 . . . . . . 7  |-  ( B  =  C  ->  ( B R B  <->  B R C ) )
54notbid 627 . . . . . 6  |-  ( B  =  C  ->  ( -.  B R B  <->  -.  B R C ) )
63, 5syl5ibcom 153 . . . . 5  |-  ( B  e.  A  ->  ( B  =  C  ->  -.  B R C ) )
7 breq1 3848 . . . . . . 7  |-  ( B  =  C  ->  ( B R B  <->  C R B ) )
87notbid 627 . . . . . 6  |-  ( B  =  C  ->  ( -.  B R B  <->  -.  C R B ) )
93, 8syl5ibcom 153 . . . . 5  |-  ( B  e.  A  ->  ( B  =  C  ->  -.  C R B ) )
106, 9jcad 301 . . . 4  |-  ( B  e.  A  ->  ( B  =  C  ->  ( -.  B R C  /\  -.  C R B ) ) )
11 ioran 704 . . . 4  |-  ( -.  ( B R C  \/  C R B )  <->  ( -.  B R C  /\  -.  C R B ) )
1210, 11syl6ibr 160 . . 3  |-  ( B  e.  A  ->  ( B  =  C  ->  -.  ( B R C  \/  C R B ) ) )
1312adantr 270 . 2  |-  ( ( B  e.  A  /\  C  e.  A )  ->  ( B  =  C  ->  -.  ( B R C  \/  C R B ) ) )
14 sotritric.tri . . 3  |-  ( ( B  e.  A  /\  C  e.  A )  ->  ( B R C  \/  B  =  C  \/  C R B ) )
15 3orrot 930 . . . . . . 7  |-  ( ( B R C  \/  B  =  C  \/  C R B )  <->  ( B  =  C  \/  C R B  \/  B R C ) )
16 3orcomb 933 . . . . . . 7  |-  ( ( B  =  C  \/  C R B  \/  B R C )  <->  ( B  =  C  \/  B R C  \/  C R B ) )
17 3orass 927 . . . . . . 7  |-  ( ( B  =  C  \/  B R C  \/  C R B )  <->  ( B  =  C  \/  ( B R C  \/  C R B ) ) )
1815, 16, 173bitri 204 . . . . . 6  |-  ( ( B R C  \/  B  =  C  \/  C R B )  <->  ( B  =  C  \/  ( B R C  \/  C R B ) ) )
1918biimpi 118 . . . . 5  |-  ( ( B R C  \/  B  =  C  \/  C R B )  -> 
( B  =  C  \/  ( B R C  \/  C R B ) ) )
2019orcomd 683 . . . 4  |-  ( ( B R C  \/  B  =  C  \/  C R B )  -> 
( ( B R C  \/  C R B )  \/  B  =  C ) )
2120ord 678 . . 3  |-  ( ( B R C  \/  B  =  C  \/  C R B )  -> 
( -.  ( B R C  \/  C R B )  ->  B  =  C ) )
2214, 21syl 14 . 2  |-  ( ( B  e.  A  /\  C  e.  A )  ->  ( -.  ( B R C  \/  C R B )  ->  B  =  C ) )
2313, 22impbid 127 1  |-  ( ( B  e.  A  /\  C  e.  A )  ->  ( B  =  C  <->  -.  ( B R C  \/  C R B ) ) )
Colors of variables: wff set class
Syntax hints:   -. wn 3    -> wi 4    /\ wa 102    <-> wb 103    \/ wo 664    \/ w3o 923    = wceq 1289    e. wcel 1438   class class class wbr 3845    Or wor 4122
This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 104  ax-ia2 105  ax-ia3 106  ax-in1 579  ax-in2 580  ax-io 665  ax-5 1381  ax-7 1382  ax-gen 1383  ax-ie1 1427  ax-ie2 1428  ax-8 1440  ax-10 1441  ax-11 1442  ax-i12 1443  ax-bndl 1444  ax-4 1445  ax-17 1464  ax-i9 1468  ax-ial 1472  ax-i5r 1473  ax-ext 2070
This theorem depends on definitions:  df-bi 115  df-3or 925  df-3an 926  df-tru 1292  df-nf 1395  df-sb 1693  df-clab 2075  df-cleq 2081  df-clel 2084  df-nfc 2217  df-ral 2364  df-v 2621  df-un 3003  df-sn 3452  df-pr 3453  df-op 3455  df-br 3846  df-po 4123  df-iso 4124
This theorem is referenced by:  distrlem4prl  7141  distrlem4pru  7142
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