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Theorem isomni 6958
Description: The predicate of being omniscient. (Contributed by Jim Kingdon, 28-Jun-2022.)
Assertion
Ref Expression
isomni (𝐴𝑉 → (𝐴 ∈ Omni ↔ ∀𝑓(𝑓:𝐴⟶2o → (∃𝑥𝐴 (𝑓𝑥) = ∅ ∨ ∀𝑥𝐴 (𝑓𝑥) = 1o))))
Distinct variable group:   𝐴,𝑓,𝑥
Allowed substitution hints:   𝑉(𝑥,𝑓)

Proof of Theorem isomni
Dummy variable 𝑦 is distinct from all other variables.
StepHypRef Expression
1 feq2 5214 . . . 4 (𝑦 = 𝐴 → (𝑓:𝑦⟶2o𝑓:𝐴⟶2o))
2 rexeq 2601 . . . . 5 (𝑦 = 𝐴 → (∃𝑥𝑦 (𝑓𝑥) = ∅ ↔ ∃𝑥𝐴 (𝑓𝑥) = ∅))
3 raleq 2600 . . . . 5 (𝑦 = 𝐴 → (∀𝑥𝑦 (𝑓𝑥) = 1o ↔ ∀𝑥𝐴 (𝑓𝑥) = 1o))
42, 3orbi12d 765 . . . 4 (𝑦 = 𝐴 → ((∃𝑥𝑦 (𝑓𝑥) = ∅ ∨ ∀𝑥𝑦 (𝑓𝑥) = 1o) ↔ (∃𝑥𝐴 (𝑓𝑥) = ∅ ∨ ∀𝑥𝐴 (𝑓𝑥) = 1o)))
51, 4imbi12d 233 . . 3 (𝑦 = 𝐴 → ((𝑓:𝑦⟶2o → (∃𝑥𝑦 (𝑓𝑥) = ∅ ∨ ∀𝑥𝑦 (𝑓𝑥) = 1o)) ↔ (𝑓:𝐴⟶2o → (∃𝑥𝐴 (𝑓𝑥) = ∅ ∨ ∀𝑥𝐴 (𝑓𝑥) = 1o))))
65albidv 1778 . 2 (𝑦 = 𝐴 → (∀𝑓(𝑓:𝑦⟶2o → (∃𝑥𝑦 (𝑓𝑥) = ∅ ∨ ∀𝑥𝑦 (𝑓𝑥) = 1o)) ↔ ∀𝑓(𝑓:𝐴⟶2o → (∃𝑥𝐴 (𝑓𝑥) = ∅ ∨ ∀𝑥𝐴 (𝑓𝑥) = 1o))))
7 df-omni 6956 . 2 Omni = {𝑦 ∣ ∀𝑓(𝑓:𝑦⟶2o → (∃𝑥𝑦 (𝑓𝑥) = ∅ ∨ ∀𝑥𝑦 (𝑓𝑥) = 1o))}
86, 7elab2g 2800 1 (𝐴𝑉 → (𝐴 ∈ Omni ↔ ∀𝑓(𝑓:𝐴⟶2o → (∃𝑥𝐴 (𝑓𝑥) = ∅ ∨ ∀𝑥𝐴 (𝑓𝑥) = 1o))))
Colors of variables: wff set class
Syntax hints:  wi 4  wb 104  wo 680  wal 1312   = wceq 1314  wcel 1463  wral 2390  wrex 2391  c0 3329  wf 5077  cfv 5081  1oc1o 6260  2oc2o 6261  Omnicomni 6954
This theorem was proved from axioms:  ax-1 5  ax-2 6  ax-mp 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-io 681  ax-5 1406  ax-7 1407  ax-gen 1408  ax-ie1 1452  ax-ie2 1453  ax-8 1465  ax-10 1466  ax-11 1467  ax-i12 1468  ax-bndl 1469  ax-4 1470  ax-17 1489  ax-i9 1493  ax-ial 1497  ax-i5r 1498  ax-ext 2097
This theorem depends on definitions:  df-bi 116  df-tru 1317  df-nf 1420  df-sb 1719  df-clab 2102  df-cleq 2108  df-clel 2111  df-nfc 2244  df-ral 2395  df-rex 2396  df-v 2659  df-fn 5084  df-f 5085  df-omni 6956
This theorem is referenced by:  isomnimap  6959  finomni  6962  exmidomniim  6963  exmidomni  6964  omnimkv  6980
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