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| Mirrors > Home > ILE Home > Th. List > iununir | GIF version | ||
| Description: A relationship involving union and indexed union. Exercise 25 of [Enderton] p. 33 but with biconditional changed to implication. (Contributed by Jim Kingdon, 19-Aug-2018.) |
| Ref | Expression |
|---|---|
| iununir | ⊢ ((𝐴 ∪ ∪ 𝐵) = ∪ 𝑥 ∈ 𝐵 (𝐴 ∪ 𝑥) → (𝐵 = ∅ → 𝐴 = ∅)) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | unieq 3859 | . . . . . 6 ⊢ (𝐵 = ∅ → ∪ 𝐵 = ∪ ∅) | |
| 2 | uni0 3877 | . . . . . 6 ⊢ ∪ ∅ = ∅ | |
| 3 | 1, 2 | eqtrdi 2254 | . . . . 5 ⊢ (𝐵 = ∅ → ∪ 𝐵 = ∅) |
| 4 | 3 | uneq2d 3327 | . . . 4 ⊢ (𝐵 = ∅ → (𝐴 ∪ ∪ 𝐵) = (𝐴 ∪ ∅)) |
| 5 | un0 3494 | . . . 4 ⊢ (𝐴 ∪ ∅) = 𝐴 | |
| 6 | 4, 5 | eqtrdi 2254 | . . 3 ⊢ (𝐵 = ∅ → (𝐴 ∪ ∪ 𝐵) = 𝐴) |
| 7 | iuneq1 3940 | . . . 4 ⊢ (𝐵 = ∅ → ∪ 𝑥 ∈ 𝐵 (𝐴 ∪ 𝑥) = ∪ 𝑥 ∈ ∅ (𝐴 ∪ 𝑥)) | |
| 8 | 0iun 3985 | . . . 4 ⊢ ∪ 𝑥 ∈ ∅ (𝐴 ∪ 𝑥) = ∅ | |
| 9 | 7, 8 | eqtrdi 2254 | . . 3 ⊢ (𝐵 = ∅ → ∪ 𝑥 ∈ 𝐵 (𝐴 ∪ 𝑥) = ∅) |
| 10 | 6, 9 | eqeq12d 2220 | . 2 ⊢ (𝐵 = ∅ → ((𝐴 ∪ ∪ 𝐵) = ∪ 𝑥 ∈ 𝐵 (𝐴 ∪ 𝑥) ↔ 𝐴 = ∅)) |
| 11 | 10 | biimpcd 159 | 1 ⊢ ((𝐴 ∪ ∪ 𝐵) = ∪ 𝑥 ∈ 𝐵 (𝐴 ∪ 𝑥) → (𝐵 = ∅ → 𝐴 = ∅)) |
| Colors of variables: wff set class |
| Syntax hints: → wi 4 = wceq 1373 ∪ cun 3164 ∅c0 3460 ∪ cuni 3850 ∪ ciun 3927 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia1 106 ax-ia2 107 ax-ia3 108 ax-in1 615 ax-in2 616 ax-io 711 ax-5 1470 ax-7 1471 ax-gen 1472 ax-ie1 1516 ax-ie2 1517 ax-8 1527 ax-10 1528 ax-11 1529 ax-i12 1530 ax-bndl 1532 ax-4 1533 ax-17 1549 ax-i9 1553 ax-ial 1557 ax-i5r 1558 ax-ext 2187 |
| This theorem depends on definitions: df-bi 117 df-tru 1376 df-fal 1379 df-nf 1484 df-sb 1786 df-clab 2192 df-cleq 2198 df-clel 2201 df-nfc 2337 df-ral 2489 df-rex 2490 df-v 2774 df-dif 3168 df-un 3170 df-in 3172 df-ss 3179 df-nul 3461 df-sn 3639 df-uni 3851 df-iun 3929 |
| This theorem is referenced by: (None) |
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