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Theorem nmzbi 14012
Description: Defining property of the normalizer. (Contributed by Mario Carneiro, 18-Jan-2015.)
Hypothesis
Ref Expression
elnmz.1 𝑁 = {𝑥𝑋 ∣ ∀𝑦𝑋 ((𝑥 + 𝑦) ∈ 𝑆 ↔ (𝑦 + 𝑥) ∈ 𝑆)}
Assertion
Ref Expression
nmzbi ((𝐴𝑁𝐵𝑋) → ((𝐴 + 𝐵) ∈ 𝑆 ↔ (𝐵 + 𝐴) ∈ 𝑆))
Distinct variable groups:   𝑥,𝐴   𝑥,𝑦,𝑆   𝑥, + ,𝑦   𝑥,𝑋,𝑦
Allowed substitution hints:   𝐴(𝑦)   𝐵(𝑥, 𝑦)   𝑁(𝑥, 𝑦)

Proof of Theorem nmzbi
Dummy variable 𝑧 is distinct from all other variables.
StepHypRef Expression
1 elnmz.1 . . . 4 𝑁 = {𝑥𝑋 ∣ ∀𝑦𝑋 ((𝑥 + 𝑦) ∈ 𝑆 ↔ (𝑦 + 𝑥) ∈ 𝑆)}
21elnmz 14011 . . 3 (𝐴𝑁 ↔ (𝐴𝑋 ∧ ∀𝑧𝑋 ((𝐴 + 𝑧) ∈ 𝑆 ↔ (𝑧 + 𝐴) ∈ 𝑆)))
32simprbi 275 . 2 (𝐴𝑁 → ∀𝑧𝑋 ((𝐴 + 𝑧) ∈ 𝑆 ↔ (𝑧 + 𝐴) ∈ 𝑆))
4 oveq2 6093 . . . . 5 (𝑧 = 𝐵 → (𝐴 + 𝑧) = (𝐴 + 𝐵))
54eleq1d 2307 . . . 4 (𝑧 = 𝐵 → ((𝐴 + 𝑧) ∈ 𝑆 ↔ (𝐴 + 𝐵) ∈ 𝑆))
6 oveq1 6092 . . . . 5 (𝑧 = 𝐵 → (𝑧 + 𝐴) = (𝐵 + 𝐴))
76eleq1d 2307 . . . 4 (𝑧 = 𝐵 → ((𝑧 + 𝐴) ∈ 𝑆 ↔ (𝐵 + 𝐴) ∈ 𝑆))
85, 7bibi12d 235 . . 3 (𝑧 = 𝐵 → (((𝐴 + 𝑧) ∈ 𝑆 ↔ (𝑧 + 𝐴) ∈ 𝑆) ↔ ((𝐴 + 𝐵) ∈ 𝑆 ↔ (𝐵 + 𝐴) ∈ 𝑆)))
98rspccva 2928 . 2 ((∀𝑧𝑋 ((𝐴 + 𝑧) ∈ 𝑆 ↔ (𝑧 + 𝐴) ∈ 𝑆) ∧ 𝐵𝑋) → ((𝐴 + 𝐵) ∈ 𝑆 ↔ (𝐵 + 𝐴) ∈ 𝑆))
103, 9sylan 283 1 ((𝐴𝑁𝐵𝑋) → ((𝐴 + 𝐵) ∈ 𝑆 ↔ (𝐵 + 𝐴) ∈ 𝑆))
Colors of variables:    wff set class
This proof depends on syntax axioms:  wi 4  wa 104  wb 105   = wceq 1402  wcel 2209  wral 2528  {crab 2532  (class class class)co 6085
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-io 721  ax-5 1500  ax-7 1501  ax-gen 1502  ax-ie1 1546  ax-ie2 1547  ax-8 1557  ax-10 1558  ax-11 1559  ax-i12 1560  ax-bndl 1562  ax-4 1563  ax-17 1579  ax-i9 1583  ax-ial 1587  ax-i5r 1588  ax-ext 2220
This proof depends on definitions:  df-bi 117  df-3an 1011  df-tru 1405  df-nf 1514  df-sb 1816  df-clab 2225  df-cleq 2231  df-clel 2234  df-nfc 2381  df-ral 2533  df-rex 2534  df-rab 2537  df-v 2823  df-un 3224  df-sn 3715  df-pr 3716  df-op 3718  df-uni 3936  df-br 4131  df-iota 5337  df-fv 5385  df-ov 6088
This theorem is used by:  nmzsubg  14013  nmznsg  14016  conjnmz  14082
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