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Theorem relss 4626
Description: Subclass theorem for relation predicate. Theorem 2 of [Suppes] p. 58. (Contributed by NM, 15-Aug-1994.)
Assertion
Ref Expression
relss (𝐴𝐵 → (Rel 𝐵 → Rel 𝐴))

Proof of Theorem relss
StepHypRef Expression
1 sstr2 3104 . 2 (𝐴𝐵 → (𝐵 ⊆ (V × V) → 𝐴 ⊆ (V × V)))
2 df-rel 4546 . 2 (Rel 𝐵𝐵 ⊆ (V × V))
3 df-rel 4546 . 2 (Rel 𝐴𝐴 ⊆ (V × V))
41, 2, 33imtr4g 204 1 (𝐴𝐵 → (Rel 𝐵 → Rel 𝐴))
Colors of variables: wff set class
Syntax hints:  wi 4  Vcvv 2686  wss 3071   × cxp 4537  Rel wrel 4544
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-5 1423  ax-7 1424  ax-gen 1425  ax-ie1 1469  ax-ie2 1470  ax-8 1482  ax-11 1484  ax-4 1487  ax-17 1506  ax-i9 1510  ax-ial 1514  ax-i5r 1515  ax-ext 2121
This theorem depends on definitions:  df-bi 116  df-nf 1437  df-sb 1736  df-clab 2126  df-cleq 2132  df-clel 2135  df-in 3077  df-ss 3084  df-rel 4546
This theorem is referenced by:  relin1  4657  relin2  4658  reldif  4659  relres  4847  iss  4865  cnvdif  4945  funss  5142  funssres  5165  fliftcnv  5696  fliftfun  5697  reltpos  6147  tpostpos  6161  swoer  6457  erinxp  6503  ltrel  7826  lerel  7828  txdis1cn  12447  xmeter  12605
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