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Theorem relss 4634
Description: Subclass theorem for relation predicate. Theorem 2 of [Suppes] p. 58. (Contributed by NM, 15-Aug-1994.)
Assertion
Ref Expression
relss (𝐴𝐵 → (Rel 𝐵 → Rel 𝐴))

Proof of Theorem relss
StepHypRef Expression
1 sstr2 3109 . 2 (𝐴𝐵 → (𝐵 ⊆ (V × V) → 𝐴 ⊆ (V × V)))
2 df-rel 4554 . 2 (Rel 𝐵𝐵 ⊆ (V × V))
3 df-rel 4554 . 2 (Rel 𝐴𝐴 ⊆ (V × V))
41, 2, 33imtr4g 204 1 (𝐴𝐵 → (Rel 𝐵 → Rel 𝐴))
Colors of variables: wff set class
Syntax hints:  wi 4  Vcvv 2689  wss 3076   × cxp 4545  Rel wrel 4552
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-5 1424  ax-7 1425  ax-gen 1426  ax-ie1 1470  ax-ie2 1471  ax-8 1483  ax-11 1485  ax-4 1488  ax-17 1507  ax-i9 1511  ax-ial 1515  ax-i5r 1516  ax-ext 2122
This theorem depends on definitions:  df-bi 116  df-nf 1438  df-sb 1737  df-clab 2127  df-cleq 2133  df-clel 2136  df-in 3082  df-ss 3089  df-rel 4554
This theorem is referenced by:  relin1  4665  relin2  4666  reldif  4667  relres  4855  iss  4873  cnvdif  4953  funss  5150  funssres  5173  fliftcnv  5704  fliftfun  5705  reltpos  6155  tpostpos  6169  swoer  6465  erinxp  6511  ltrel  7850  lerel  7852  txdis1cn  12486  xmeter  12644
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