ILE Home Intuitionistic Logic Explorer < Previous   Next >
Nearby theorems
Mirrors  >  Home  >  ILE Home  >  Th. List  >  relss GIF version

Theorem relss 4715
Description: Subclass theorem for relation predicate. Theorem 2 of [Suppes] p. 58. (Contributed by NM, 15-Aug-1994.)
Assertion
Ref Expression
relss (𝐴𝐵 → (Rel 𝐵 → Rel 𝐴))

Proof of Theorem relss
StepHypRef Expression
1 sstr2 3164 . 2 (𝐴𝐵 → (𝐵 ⊆ (V × V) → 𝐴 ⊆ (V × V)))
2 df-rel 4635 . 2 (Rel 𝐵𝐵 ⊆ (V × V))
3 df-rel 4635 . 2 (Rel 𝐴𝐴 ⊆ (V × V))
41, 2, 33imtr4g 205 1 (𝐴𝐵 → (Rel 𝐵 → Rel 𝐴))
Colors of variables: wff set class
Syntax hints:  wi 4  Vcvv 2739  wss 3131   × cxp 4626  Rel wrel 4633
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-5 1447  ax-7 1448  ax-gen 1449  ax-ie1 1493  ax-ie2 1494  ax-8 1504  ax-11 1506  ax-4 1510  ax-17 1526  ax-i9 1530  ax-ial 1534  ax-i5r 1535  ax-ext 2159
This theorem depends on definitions:  df-bi 117  df-nf 1461  df-sb 1763  df-clab 2164  df-cleq 2170  df-clel 2173  df-in 3137  df-ss 3144  df-rel 4635
This theorem is referenced by:  relin1  4746  relin2  4747  reldif  4748  relres  4937  iss  4955  cnvdif  5037  funss  5237  funssres  5260  fliftcnv  5798  fliftfun  5799  reltpos  6253  tpostpos  6267  swoer  6565  erinxp  6611  ltrel  8021  lerel  8023  txdis1cn  13863  xmeter  14021
  Copyright terms: Public domain W3C validator