Theorem List for Intuitionistic Logic Explorer - 4701-4800 *Has distinct variable
group(s)
Type | Label | Description |
Statement |
|
Theorem | ssrel2 4701* |
A subclass relationship depends only on a relation's ordered pairs.
This version of ssrel 4699 is restricted to the relation's domain.
(Contributed by Thierry Arnoux, 25-Jan-2018.)
|
⊢ (𝑅 ⊆ (𝐴 × 𝐵) → (𝑅 ⊆ 𝑆 ↔ ∀𝑥 ∈ 𝐴 ∀𝑦 ∈ 𝐵 (〈𝑥, 𝑦〉 ∈ 𝑅 → 〈𝑥, 𝑦〉 ∈ 𝑆))) |
|
Theorem | relssi 4702* |
Inference from subclass principle for relations. (Contributed by NM,
31-Mar-1998.)
|
⊢ Rel 𝐴
& ⊢ (〈𝑥, 𝑦〉 ∈ 𝐴 → 〈𝑥, 𝑦〉 ∈ 𝐵) ⇒ ⊢ 𝐴 ⊆ 𝐵 |
|
Theorem | relssdv 4703* |
Deduction from subclass principle for relations. (Contributed by NM,
11-Sep-2004.)
|
⊢ (𝜑 → Rel 𝐴)
& ⊢ (𝜑 → (〈𝑥, 𝑦〉 ∈ 𝐴 → 〈𝑥, 𝑦〉 ∈ 𝐵)) ⇒ ⊢ (𝜑 → 𝐴 ⊆ 𝐵) |
|
Theorem | eqrelriv 4704* |
Inference from extensionality principle for relations. (Contributed by
FL, 15-Oct-2012.)
|
⊢ (〈𝑥, 𝑦〉 ∈ 𝐴 ↔ 〈𝑥, 𝑦〉 ∈ 𝐵) ⇒ ⊢ ((Rel 𝐴 ∧ Rel 𝐵) → 𝐴 = 𝐵) |
|
Theorem | eqrelriiv 4705* |
Inference from extensionality principle for relations. (Contributed by
NM, 17-Mar-1995.)
|
⊢ Rel 𝐴
& ⊢ Rel 𝐵
& ⊢ (〈𝑥, 𝑦〉 ∈ 𝐴 ↔ 〈𝑥, 𝑦〉 ∈ 𝐵) ⇒ ⊢ 𝐴 = 𝐵 |
|
Theorem | eqbrriv 4706* |
Inference from extensionality principle for relations. (Contributed by
NM, 12-Dec-2006.)
|
⊢ Rel 𝐴
& ⊢ Rel 𝐵
& ⊢ (𝑥𝐴𝑦 ↔ 𝑥𝐵𝑦) ⇒ ⊢ 𝐴 = 𝐵 |
|
Theorem | eqrelrdv 4707* |
Deduce equality of relations from equivalence of membership.
(Contributed by Rodolfo Medina, 10-Oct-2010.)
|
⊢ Rel 𝐴
& ⊢ Rel 𝐵
& ⊢ (𝜑 → (〈𝑥, 𝑦〉 ∈ 𝐴 ↔ 〈𝑥, 𝑦〉 ∈ 𝐵)) ⇒ ⊢ (𝜑 → 𝐴 = 𝐵) |
|
Theorem | eqbrrdv 4708* |
Deduction from extensionality principle for relations. (Contributed by
Mario Carneiro, 3-Jan-2017.)
|
⊢ (𝜑 → Rel 𝐴)
& ⊢ (𝜑 → Rel 𝐵)
& ⊢ (𝜑 → (𝑥𝐴𝑦 ↔ 𝑥𝐵𝑦)) ⇒ ⊢ (𝜑 → 𝐴 = 𝐵) |
|
Theorem | eqbrrdiv 4709* |
Deduction from extensionality principle for relations. (Contributed by
Rodolfo Medina, 10-Oct-2010.)
|
⊢ Rel 𝐴
& ⊢ Rel 𝐵
& ⊢ (𝜑 → (𝑥𝐴𝑦 ↔ 𝑥𝐵𝑦)) ⇒ ⊢ (𝜑 → 𝐴 = 𝐵) |
|
Theorem | eqrelrdv2 4710* |
A version of eqrelrdv 4707. (Contributed by Rodolfo Medina,
10-Oct-2010.)
|
⊢ (𝜑 → (〈𝑥, 𝑦〉 ∈ 𝐴 ↔ 〈𝑥, 𝑦〉 ∈ 𝐵)) ⇒ ⊢ (((Rel 𝐴 ∧ Rel 𝐵) ∧ 𝜑) → 𝐴 = 𝐵) |
|
Theorem | ssrelrel 4711* |
A subclass relationship determined by ordered triples. Use relrelss 5137
to express the antecedent in terms of the relation predicate.
(Contributed by NM, 17-Dec-2008.) (Proof shortened by Andrew Salmon,
27-Aug-2011.)
|
⊢ (𝐴 ⊆ ((V × V) × V) →
(𝐴 ⊆ 𝐵 ↔ ∀𝑥∀𝑦∀𝑧(〈〈𝑥, 𝑦〉, 𝑧〉 ∈ 𝐴 → 〈〈𝑥, 𝑦〉, 𝑧〉 ∈ 𝐵))) |
|
Theorem | eqrelrel 4712* |
Extensionality principle for ordered triples, analogous to eqrel 4700.
Use relrelss 5137 to express the antecedent in terms of the
relation
predicate. (Contributed by NM, 17-Dec-2008.)
|
⊢ ((𝐴 ∪ 𝐵) ⊆ ((V × V) × V) →
(𝐴 = 𝐵 ↔ ∀𝑥∀𝑦∀𝑧(〈〈𝑥, 𝑦〉, 𝑧〉 ∈ 𝐴 ↔ 〈〈𝑥, 𝑦〉, 𝑧〉 ∈ 𝐵))) |
|
Theorem | elrel 4713* |
A member of a relation is an ordered pair. (Contributed by NM,
17-Sep-2006.)
|
⊢ ((Rel 𝑅 ∧ 𝐴 ∈ 𝑅) → ∃𝑥∃𝑦 𝐴 = 〈𝑥, 𝑦〉) |
|
Theorem | relsng 4714 |
A singleton is a relation iff it is an ordered pair. (Contributed by NM,
24-Sep-2013.) (Revised by BJ, 12-Feb-2022.)
|
⊢ (𝐴 ∈ 𝑉 → (Rel {𝐴} ↔ 𝐴 ∈ (V × V))) |
|
Theorem | relsnopg 4715 |
A singleton of an ordered pair is a relation. (Contributed by NM,
17-May-1998.) (Revised by BJ, 12-Feb-2022.)
|
⊢ ((𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊) → Rel {〈𝐴, 𝐵〉}) |
|
Theorem | relsn 4716 |
A singleton is a relation iff it is an ordered pair. (Contributed by
NM, 24-Sep-2013.)
|
⊢ 𝐴 ∈ V ⇒ ⊢ (Rel {𝐴} ↔ 𝐴 ∈ (V × V)) |
|
Theorem | relsnop 4717 |
A singleton of an ordered pair is a relation. (Contributed by NM,
17-May-1998.) (Revised by Mario Carneiro, 26-Apr-2015.)
|
⊢ 𝐴 ∈ V & ⊢ 𝐵 ∈
V ⇒ ⊢ Rel {〈𝐴, 𝐵〉} |
|
Theorem | xpss12 4718 |
Subset theorem for cross product. Generalization of Theorem 101 of
[Suppes] p. 52. (Contributed by NM,
26-Aug-1995.) (Proof shortened by
Andrew Salmon, 27-Aug-2011.)
|
⊢ ((𝐴 ⊆ 𝐵 ∧ 𝐶 ⊆ 𝐷) → (𝐴 × 𝐶) ⊆ (𝐵 × 𝐷)) |
|
Theorem | xpss 4719 |
A cross product is included in the ordered pair universe. Exercise 3 of
[TakeutiZaring] p. 25. (Contributed
by NM, 2-Aug-1994.)
|
⊢ (𝐴 × 𝐵) ⊆ (V × V) |
|
Theorem | relxp 4720 |
A cross product is a relation. Theorem 3.13(i) of [Monk1] p. 37.
(Contributed by NM, 2-Aug-1994.)
|
⊢ Rel (𝐴 × 𝐵) |
|
Theorem | xpss1 4721 |
Subset relation for cross product. (Contributed by Jeff Hankins,
30-Aug-2009.)
|
⊢ (𝐴 ⊆ 𝐵 → (𝐴 × 𝐶) ⊆ (𝐵 × 𝐶)) |
|
Theorem | xpss2 4722 |
Subset relation for cross product. (Contributed by Jeff Hankins,
30-Aug-2009.)
|
⊢ (𝐴 ⊆ 𝐵 → (𝐶 × 𝐴) ⊆ (𝐶 × 𝐵)) |
|
Theorem | xpsspw 4723 |
A cross product is included in the power of the power of the union of
its arguments. (Contributed by NM, 13-Sep-2006.)
|
⊢ (𝐴 × 𝐵) ⊆ 𝒫 𝒫 (𝐴 ∪ 𝐵) |
|
Theorem | unixpss 4724 |
The double class union of a cross product is included in the union of its
arguments. (Contributed by NM, 16-Sep-2006.)
|
⊢ ∪ ∪ (𝐴
× 𝐵) ⊆ (𝐴 ∪ 𝐵) |
|
Theorem | xpexg 4725 |
The cross product of two sets is a set. Proposition 6.2 of
[TakeutiZaring] p. 23. (Contributed
by NM, 14-Aug-1994.)
|
⊢ ((𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊) → (𝐴 × 𝐵) ∈ V) |
|
Theorem | xpex 4726 |
The cross product of two sets is a set. Proposition 6.2 of
[TakeutiZaring] p. 23.
(Contributed by NM, 14-Aug-1994.)
|
⊢ 𝐴 ∈ V & ⊢ 𝐵 ∈
V ⇒ ⊢ (𝐴 × 𝐵) ∈ V |
|
Theorem | sqxpexg 4727 |
The Cartesian square of a set is a set. (Contributed by AV,
13-Jan-2020.)
|
⊢ (𝐴 ∈ 𝑉 → (𝐴 × 𝐴) ∈ V) |
|
Theorem | relun 4728 |
The union of two relations is a relation. Compare Exercise 5 of
[TakeutiZaring] p. 25. (Contributed
by NM, 12-Aug-1994.)
|
⊢ (Rel (𝐴 ∪ 𝐵) ↔ (Rel 𝐴 ∧ Rel 𝐵)) |
|
Theorem | relin1 4729 |
The intersection with a relation is a relation. (Contributed by NM,
16-Aug-1994.)
|
⊢ (Rel 𝐴 → Rel (𝐴 ∩ 𝐵)) |
|
Theorem | relin2 4730 |
The intersection with a relation is a relation. (Contributed by NM,
17-Jan-2006.)
|
⊢ (Rel 𝐵 → Rel (𝐴 ∩ 𝐵)) |
|
Theorem | reldif 4731 |
A difference cutting down a relation is a relation. (Contributed by NM,
31-Mar-1998.)
|
⊢ (Rel 𝐴 → Rel (𝐴 ∖ 𝐵)) |
|
Theorem | reliun 4732 |
An indexed union is a relation iff each member of its indexed family is
a relation. (Contributed by NM, 19-Dec-2008.)
|
⊢ (Rel ∪
𝑥 ∈ 𝐴 𝐵 ↔ ∀𝑥 ∈ 𝐴 Rel 𝐵) |
|
Theorem | reliin 4733 |
An indexed intersection is a relation if at least one of the member of the
indexed family is a relation. (Contributed by NM, 8-Mar-2014.)
|
⊢ (∃𝑥 ∈ 𝐴 Rel 𝐵 → Rel ∩ 𝑥 ∈ 𝐴 𝐵) |
|
Theorem | reluni 4734* |
The union of a class is a relation iff any member is a relation.
Exercise 6 of [TakeutiZaring] p.
25 and its converse. (Contributed by
NM, 13-Aug-2004.)
|
⊢ (Rel ∪ 𝐴 ↔ ∀𝑥 ∈ 𝐴 Rel 𝑥) |
|
Theorem | relint 4735* |
The intersection of a class is a relation if at least one member is a
relation. (Contributed by NM, 8-Mar-2014.)
|
⊢ (∃𝑥 ∈ 𝐴 Rel 𝑥 → Rel ∩
𝐴) |
|
Theorem | rel0 4736 |
The empty set is a relation. (Contributed by NM, 26-Apr-1998.)
|
⊢ Rel ∅ |
|
Theorem | relopabi 4737 |
A class of ordered pairs is a relation. (Contributed by Mario Carneiro,
21-Dec-2013.)
|
⊢ 𝐴 = {〈𝑥, 𝑦〉 ∣ 𝜑} ⇒ ⊢ Rel 𝐴 |
|
Theorem | relopab 4738 |
A class of ordered pairs is a relation. (Contributed by NM, 8-Mar-1995.)
(Unnecessary distinct variable restrictions were removed by Alan Sare,
9-Jul-2013.) (Proof shortened by Mario Carneiro, 21-Dec-2013.)
|
⊢ Rel {〈𝑥, 𝑦〉 ∣ 𝜑} |
|
Theorem | mptrel 4739 |
The maps-to notation always describes a relationship. (Contributed by
Scott Fenton, 16-Apr-2012.)
|
⊢ Rel (𝑥 ∈ 𝐴 ↦ 𝐵) |
|
Theorem | reli 4740 |
The identity relation is a relation. Part of Exercise 4.12(p) of
[Mendelson] p. 235. (Contributed by
NM, 26-Apr-1998.) (Revised by
Mario Carneiro, 21-Dec-2013.)
|
⊢ Rel I |
|
Theorem | rele 4741 |
The membership relation is a relation. (Contributed by NM,
26-Apr-1998.) (Revised by Mario Carneiro, 21-Dec-2013.)
|
⊢ Rel E |
|
Theorem | opabid2 4742* |
A relation expressed as an ordered pair abstraction. (Contributed by
NM, 11-Dec-2006.)
|
⊢ (Rel 𝐴 → {〈𝑥, 𝑦〉 ∣ 〈𝑥, 𝑦〉 ∈ 𝐴} = 𝐴) |
|
Theorem | inopab 4743* |
Intersection of two ordered pair class abstractions. (Contributed by
NM, 30-Sep-2002.)
|
⊢ ({〈𝑥, 𝑦〉 ∣ 𝜑} ∩ {〈𝑥, 𝑦〉 ∣ 𝜓}) = {〈𝑥, 𝑦〉 ∣ (𝜑 ∧ 𝜓)} |
|
Theorem | difopab 4744* |
The difference of two ordered-pair abstractions. (Contributed by Stefan
O'Rear, 17-Jan-2015.)
|
⊢ ({〈𝑥, 𝑦〉 ∣ 𝜑} ∖ {〈𝑥, 𝑦〉 ∣ 𝜓}) = {〈𝑥, 𝑦〉 ∣ (𝜑 ∧ ¬ 𝜓)} |
|
Theorem | inxp 4745 |
The intersection of two cross products. Exercise 9 of [TakeutiZaring]
p. 25. (Contributed by NM, 3-Aug-1994.) (Proof shortened by Andrew
Salmon, 27-Aug-2011.)
|
⊢ ((𝐴 × 𝐵) ∩ (𝐶 × 𝐷)) = ((𝐴 ∩ 𝐶) × (𝐵 ∩ 𝐷)) |
|
Theorem | xpindi 4746 |
Distributive law for cross product over intersection. Theorem 102 of
[Suppes] p. 52. (Contributed by NM,
26-Sep-2004.)
|
⊢ (𝐴 × (𝐵 ∩ 𝐶)) = ((𝐴 × 𝐵) ∩ (𝐴 × 𝐶)) |
|
Theorem | xpindir 4747 |
Distributive law for cross product over intersection. Similar to
Theorem 102 of [Suppes] p. 52.
(Contributed by NM, 26-Sep-2004.)
|
⊢ ((𝐴 ∩ 𝐵) × 𝐶) = ((𝐴 × 𝐶) ∩ (𝐵 × 𝐶)) |
|
Theorem | xpiindim 4748* |
Distributive law for cross product over indexed intersection.
(Contributed by Jim Kingdon, 7-Dec-2018.)
|
⊢ (∃𝑦 𝑦 ∈ 𝐴 → (𝐶 × ∩ 𝑥 ∈ 𝐴 𝐵) = ∩
𝑥 ∈ 𝐴 (𝐶 × 𝐵)) |
|
Theorem | xpriindim 4749* |
Distributive law for cross product over relativized indexed
intersection. (Contributed by Jim Kingdon, 7-Dec-2018.)
|
⊢ (∃𝑦 𝑦 ∈ 𝐴 → (𝐶 × (𝐷 ∩ ∩
𝑥 ∈ 𝐴 𝐵)) = ((𝐶 × 𝐷) ∩ ∩
𝑥 ∈ 𝐴 (𝐶 × 𝐵))) |
|
Theorem | eliunxp 4750* |
Membership in a union of cross products. Analogue of elxp 4628
for
nonconstant 𝐵(𝑥). (Contributed by Mario Carneiro,
29-Dec-2014.)
|
⊢ (𝐶 ∈ ∪
𝑥 ∈ 𝐴 ({𝑥} × 𝐵) ↔ ∃𝑥∃𝑦(𝐶 = 〈𝑥, 𝑦〉 ∧ (𝑥 ∈ 𝐴 ∧ 𝑦 ∈ 𝐵))) |
|
Theorem | opeliunxp2 4751* |
Membership in a union of cross products. (Contributed by Mario
Carneiro, 14-Feb-2015.)
|
⊢ (𝑥 = 𝐶 → 𝐵 = 𝐸) ⇒ ⊢ (〈𝐶, 𝐷〉 ∈ ∪ 𝑥 ∈ 𝐴 ({𝑥} × 𝐵) ↔ (𝐶 ∈ 𝐴 ∧ 𝐷 ∈ 𝐸)) |
|
Theorem | raliunxp 4752* |
Write a double restricted quantification as one universal quantifier.
In this version of ralxp 4754, 𝐵(𝑦) is not assumed to be constant.
(Contributed by Mario Carneiro, 29-Dec-2014.)
|
⊢ (𝑥 = 〈𝑦, 𝑧〉 → (𝜑 ↔ 𝜓)) ⇒ ⊢ (∀𝑥 ∈ ∪
𝑦 ∈ 𝐴 ({𝑦} × 𝐵)𝜑 ↔ ∀𝑦 ∈ 𝐴 ∀𝑧 ∈ 𝐵 𝜓) |
|
Theorem | rexiunxp 4753* |
Write a double restricted quantification as one universal quantifier.
In this version of rexxp 4755, 𝐵(𝑦) is not assumed to be constant.
(Contributed by Mario Carneiro, 14-Feb-2015.)
|
⊢ (𝑥 = 〈𝑦, 𝑧〉 → (𝜑 ↔ 𝜓)) ⇒ ⊢ (∃𝑥 ∈ ∪
𝑦 ∈ 𝐴 ({𝑦} × 𝐵)𝜑 ↔ ∃𝑦 ∈ 𝐴 ∃𝑧 ∈ 𝐵 𝜓) |
|
Theorem | ralxp 4754* |
Universal quantification restricted to a cross product is equivalent to
a double restricted quantification. The hypothesis specifies an
implicit substitution. (Contributed by NM, 7-Feb-2004.) (Revised by
Mario Carneiro, 29-Dec-2014.)
|
⊢ (𝑥 = 〈𝑦, 𝑧〉 → (𝜑 ↔ 𝜓)) ⇒ ⊢ (∀𝑥 ∈ (𝐴 × 𝐵)𝜑 ↔ ∀𝑦 ∈ 𝐴 ∀𝑧 ∈ 𝐵 𝜓) |
|
Theorem | rexxp 4755* |
Existential quantification restricted to a cross product is equivalent
to a double restricted quantification. (Contributed by NM,
11-Nov-1995.) (Revised by Mario Carneiro, 14-Feb-2015.)
|
⊢ (𝑥 = 〈𝑦, 𝑧〉 → (𝜑 ↔ 𝜓)) ⇒ ⊢ (∃𝑥 ∈ (𝐴 × 𝐵)𝜑 ↔ ∃𝑦 ∈ 𝐴 ∃𝑧 ∈ 𝐵 𝜓) |
|
Theorem | djussxp 4756* |
Disjoint union is a subset of a cross product. (Contributed by Stefan
O'Rear, 21-Nov-2014.)
|
⊢ ∪ 𝑥 ∈ 𝐴 ({𝑥} × 𝐵) ⊆ (𝐴 × V) |
|
Theorem | ralxpf 4757* |
Version of ralxp 4754 with bound-variable hypotheses. (Contributed
by NM,
18-Aug-2006.) (Revised by Mario Carneiro, 15-Oct-2016.)
|
⊢ Ⅎ𝑦𝜑
& ⊢ Ⅎ𝑧𝜑
& ⊢ Ⅎ𝑥𝜓
& ⊢ (𝑥 = 〈𝑦, 𝑧〉 → (𝜑 ↔ 𝜓)) ⇒ ⊢ (∀𝑥 ∈ (𝐴 × 𝐵)𝜑 ↔ ∀𝑦 ∈ 𝐴 ∀𝑧 ∈ 𝐵 𝜓) |
|
Theorem | rexxpf 4758* |
Version of rexxp 4755 with bound-variable hypotheses. (Contributed
by NM,
19-Dec-2008.) (Revised by Mario Carneiro, 15-Oct-2016.)
|
⊢ Ⅎ𝑦𝜑
& ⊢ Ⅎ𝑧𝜑
& ⊢ Ⅎ𝑥𝜓
& ⊢ (𝑥 = 〈𝑦, 𝑧〉 → (𝜑 ↔ 𝜓)) ⇒ ⊢ (∃𝑥 ∈ (𝐴 × 𝐵)𝜑 ↔ ∃𝑦 ∈ 𝐴 ∃𝑧 ∈ 𝐵 𝜓) |
|
Theorem | iunxpf 4759* |
Indexed union on a cross product is equals a double indexed union. The
hypothesis specifies an implicit substitution. (Contributed by NM,
19-Dec-2008.)
|
⊢ Ⅎ𝑦𝐶
& ⊢ Ⅎ𝑧𝐶
& ⊢ Ⅎ𝑥𝐷
& ⊢ (𝑥 = 〈𝑦, 𝑧〉 → 𝐶 = 𝐷) ⇒ ⊢ ∪ 𝑥 ∈ (𝐴 × 𝐵)𝐶 = ∪
𝑦 ∈ 𝐴 ∪ 𝑧 ∈ 𝐵 𝐷 |
|
Theorem | opabbi2dv 4760* |
Deduce equality of a relation and an ordered-pair class builder.
Compare abbi2dv 2289. (Contributed by NM, 24-Feb-2014.)
|
⊢ Rel 𝐴
& ⊢ (𝜑 → (〈𝑥, 𝑦〉 ∈ 𝐴 ↔ 𝜓)) ⇒ ⊢ (𝜑 → 𝐴 = {〈𝑥, 𝑦〉 ∣ 𝜓}) |
|
Theorem | relop 4761* |
A necessary and sufficient condition for a Kuratowski ordered pair to be
a relation. (Contributed by NM, 3-Jun-2008.) (Avoid depending on this
detail.)
|
⊢ 𝐴 ∈ V & ⊢ 𝐵 ∈
V ⇒ ⊢ (Rel 〈𝐴, 𝐵〉 ↔ ∃𝑥∃𝑦(𝐴 = {𝑥} ∧ 𝐵 = {𝑥, 𝑦})) |
|
Theorem | ideqg 4762 |
For sets, the identity relation is the same as equality. (Contributed
by NM, 30-Apr-2004.) (Proof shortened by Andrew Salmon,
27-Aug-2011.)
|
⊢ (𝐵 ∈ 𝑉 → (𝐴 I 𝐵 ↔ 𝐴 = 𝐵)) |
|
Theorem | ideq 4763 |
For sets, the identity relation is the same as equality. (Contributed
by NM, 13-Aug-1995.)
|
⊢ 𝐵 ∈ V ⇒ ⊢ (𝐴 I 𝐵 ↔ 𝐴 = 𝐵) |
|
Theorem | ididg 4764 |
A set is identical to itself. (Contributed by NM, 28-May-2008.) (Proof
shortened by Andrew Salmon, 27-Aug-2011.)
|
⊢ (𝐴 ∈ 𝑉 → 𝐴 I 𝐴) |
|
Theorem | issetid 4765 |
Two ways of expressing set existence. (Contributed by NM, 16-Feb-2008.)
(Proof shortened by Andrew Salmon, 27-Aug-2011.) (Revised by Mario
Carneiro, 26-Apr-2015.)
|
⊢ (𝐴 ∈ V ↔ 𝐴 I 𝐴) |
|
Theorem | coss1 4766 |
Subclass theorem for composition. (Contributed by FL, 30-Dec-2010.)
|
⊢ (𝐴 ⊆ 𝐵 → (𝐴 ∘ 𝐶) ⊆ (𝐵 ∘ 𝐶)) |
|
Theorem | coss2 4767 |
Subclass theorem for composition. (Contributed by NM, 5-Apr-2013.)
|
⊢ (𝐴 ⊆ 𝐵 → (𝐶 ∘ 𝐴) ⊆ (𝐶 ∘ 𝐵)) |
|
Theorem | coeq1 4768 |
Equality theorem for composition of two classes. (Contributed by NM,
3-Jan-1997.)
|
⊢ (𝐴 = 𝐵 → (𝐴 ∘ 𝐶) = (𝐵 ∘ 𝐶)) |
|
Theorem | coeq2 4769 |
Equality theorem for composition of two classes. (Contributed by NM,
3-Jan-1997.)
|
⊢ (𝐴 = 𝐵 → (𝐶 ∘ 𝐴) = (𝐶 ∘ 𝐵)) |
|
Theorem | coeq1i 4770 |
Equality inference for composition of two classes. (Contributed by NM,
16-Nov-2000.)
|
⊢ 𝐴 = 𝐵 ⇒ ⊢ (𝐴 ∘ 𝐶) = (𝐵 ∘ 𝐶) |
|
Theorem | coeq2i 4771 |
Equality inference for composition of two classes. (Contributed by NM,
16-Nov-2000.)
|
⊢ 𝐴 = 𝐵 ⇒ ⊢ (𝐶 ∘ 𝐴) = (𝐶 ∘ 𝐵) |
|
Theorem | coeq1d 4772 |
Equality deduction for composition of two classes. (Contributed by NM,
16-Nov-2000.)
|
⊢ (𝜑 → 𝐴 = 𝐵) ⇒ ⊢ (𝜑 → (𝐴 ∘ 𝐶) = (𝐵 ∘ 𝐶)) |
|
Theorem | coeq2d 4773 |
Equality deduction for composition of two classes. (Contributed by NM,
16-Nov-2000.)
|
⊢ (𝜑 → 𝐴 = 𝐵) ⇒ ⊢ (𝜑 → (𝐶 ∘ 𝐴) = (𝐶 ∘ 𝐵)) |
|
Theorem | coeq12i 4774 |
Equality inference for composition of two classes. (Contributed by FL,
7-Jun-2012.)
|
⊢ 𝐴 = 𝐵
& ⊢ 𝐶 = 𝐷 ⇒ ⊢ (𝐴 ∘ 𝐶) = (𝐵 ∘ 𝐷) |
|
Theorem | coeq12d 4775 |
Equality deduction for composition of two classes. (Contributed by FL,
7-Jun-2012.)
|
⊢ (𝜑 → 𝐴 = 𝐵)
& ⊢ (𝜑 → 𝐶 = 𝐷) ⇒ ⊢ (𝜑 → (𝐴 ∘ 𝐶) = (𝐵 ∘ 𝐷)) |
|
Theorem | nfco 4776 |
Bound-variable hypothesis builder for function value. (Contributed by
NM, 1-Sep-1999.)
|
⊢ Ⅎ𝑥𝐴
& ⊢ Ⅎ𝑥𝐵 ⇒ ⊢ Ⅎ𝑥(𝐴 ∘ 𝐵) |
|
Theorem | elco 4777* |
Elements of a composed relation. (Contributed by BJ, 10-Jul-2022.)
|
⊢ (𝐴 ∈ (𝑅 ∘ 𝑆) ↔ ∃𝑥∃𝑦∃𝑧(𝐴 = 〈𝑥, 𝑧〉 ∧ (𝑥𝑆𝑦 ∧ 𝑦𝑅𝑧))) |
|
Theorem | brcog 4778* |
Ordered pair membership in a composition. (Contributed by NM,
24-Feb-2015.)
|
⊢ ((𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊) → (𝐴(𝐶 ∘ 𝐷)𝐵 ↔ ∃𝑥(𝐴𝐷𝑥 ∧ 𝑥𝐶𝐵))) |
|
Theorem | opelco2g 4779* |
Ordered pair membership in a composition. (Contributed by NM,
27-Jan-1997.) (Revised by Mario Carneiro, 24-Feb-2015.)
|
⊢ ((𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊) → (〈𝐴, 𝐵〉 ∈ (𝐶 ∘ 𝐷) ↔ ∃𝑥(〈𝐴, 𝑥〉 ∈ 𝐷 ∧ 〈𝑥, 𝐵〉 ∈ 𝐶))) |
|
Theorem | brcogw 4780 |
Ordered pair membership in a composition. (Contributed by Thierry
Arnoux, 14-Jan-2018.)
|
⊢ (((𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊 ∧ 𝑋 ∈ 𝑍) ∧ (𝐴𝐷𝑋 ∧ 𝑋𝐶𝐵)) → 𝐴(𝐶 ∘ 𝐷)𝐵) |
|
Theorem | eqbrrdva 4781* |
Deduction from extensionality principle for relations, given an
equivalence only on the relation's domain and range. (Contributed by
Thierry Arnoux, 28-Nov-2017.)
|
⊢ (𝜑 → 𝐴 ⊆ (𝐶 × 𝐷)) & ⊢ (𝜑 → 𝐵 ⊆ (𝐶 × 𝐷)) & ⊢ ((𝜑 ∧ 𝑥 ∈ 𝐶 ∧ 𝑦 ∈ 𝐷) → (𝑥𝐴𝑦 ↔ 𝑥𝐵𝑦)) ⇒ ⊢ (𝜑 → 𝐴 = 𝐵) |
|
Theorem | brco 4782* |
Binary relation on a composition. (Contributed by NM, 21-Sep-2004.)
(Revised by Mario Carneiro, 24-Feb-2015.)
|
⊢ 𝐴 ∈ V & ⊢ 𝐵 ∈
V ⇒ ⊢ (𝐴(𝐶 ∘ 𝐷)𝐵 ↔ ∃𝑥(𝐴𝐷𝑥 ∧ 𝑥𝐶𝐵)) |
|
Theorem | opelco 4783* |
Ordered pair membership in a composition. (Contributed by NM,
27-Dec-1996.) (Revised by Mario Carneiro, 24-Feb-2015.)
|
⊢ 𝐴 ∈ V & ⊢ 𝐵 ∈
V ⇒ ⊢ (〈𝐴, 𝐵〉 ∈ (𝐶 ∘ 𝐷) ↔ ∃𝑥(𝐴𝐷𝑥 ∧ 𝑥𝐶𝐵)) |
|
Theorem | cnvss 4784 |
Subset theorem for converse. (Contributed by NM, 22-Mar-1998.)
|
⊢ (𝐴 ⊆ 𝐵 → ◡𝐴 ⊆ ◡𝐵) |
|
Theorem | cnveq 4785 |
Equality theorem for converse. (Contributed by NM, 13-Aug-1995.)
|
⊢ (𝐴 = 𝐵 → ◡𝐴 = ◡𝐵) |
|
Theorem | cnveqi 4786 |
Equality inference for converse. (Contributed by NM, 23-Dec-2008.)
|
⊢ 𝐴 = 𝐵 ⇒ ⊢ ◡𝐴 = ◡𝐵 |
|
Theorem | cnveqd 4787 |
Equality deduction for converse. (Contributed by NM, 6-Dec-2013.)
|
⊢ (𝜑 → 𝐴 = 𝐵) ⇒ ⊢ (𝜑 → ◡𝐴 = ◡𝐵) |
|
Theorem | elcnv 4788* |
Membership in a converse. Equation 5 of [Suppes] p. 62. (Contributed
by NM, 24-Mar-1998.)
|
⊢ (𝐴 ∈ ◡𝑅 ↔ ∃𝑥∃𝑦(𝐴 = 〈𝑥, 𝑦〉 ∧ 𝑦𝑅𝑥)) |
|
Theorem | elcnv2 4789* |
Membership in a converse. Equation 5 of [Suppes] p. 62. (Contributed
by NM, 11-Aug-2004.)
|
⊢ (𝐴 ∈ ◡𝑅 ↔ ∃𝑥∃𝑦(𝐴 = 〈𝑥, 𝑦〉 ∧ 〈𝑦, 𝑥〉 ∈ 𝑅)) |
|
Theorem | nfcnv 4790 |
Bound-variable hypothesis builder for converse. (Contributed by NM,
31-Jan-2004.) (Revised by Mario Carneiro, 15-Oct-2016.)
|
⊢ Ⅎ𝑥𝐴 ⇒ ⊢ Ⅎ𝑥◡𝐴 |
|
Theorem | opelcnvg 4791 |
Ordered-pair membership in converse. (Contributed by NM, 13-May-1999.)
(Proof shortened by Andrew Salmon, 27-Aug-2011.)
|
⊢ ((𝐴 ∈ 𝐶 ∧ 𝐵 ∈ 𝐷) → (〈𝐴, 𝐵〉 ∈ ◡𝑅 ↔ 〈𝐵, 𝐴〉 ∈ 𝑅)) |
|
Theorem | brcnvg 4792 |
The converse of a binary relation swaps arguments. Theorem 11 of [Suppes]
p. 61. (Contributed by NM, 10-Oct-2005.)
|
⊢ ((𝐴 ∈ 𝐶 ∧ 𝐵 ∈ 𝐷) → (𝐴◡𝑅𝐵 ↔ 𝐵𝑅𝐴)) |
|
Theorem | opelcnv 4793 |
Ordered-pair membership in converse. (Contributed by NM,
13-Aug-1995.)
|
⊢ 𝐴 ∈ V & ⊢ 𝐵 ∈
V ⇒ ⊢ (〈𝐴, 𝐵〉 ∈ ◡𝑅 ↔ 〈𝐵, 𝐴〉 ∈ 𝑅) |
|
Theorem | brcnv 4794 |
The converse of a binary relation swaps arguments. Theorem 11 of
[Suppes] p. 61. (Contributed by NM,
13-Aug-1995.)
|
⊢ 𝐴 ∈ V & ⊢ 𝐵 ∈
V ⇒ ⊢ (𝐴◡𝑅𝐵 ↔ 𝐵𝑅𝐴) |
|
Theorem | csbcnvg 4795 |
Move class substitution in and out of the converse of a function.
(Contributed by Thierry Arnoux, 8-Feb-2017.)
|
⊢ (𝐴 ∈ 𝑉 → ◡⦋𝐴 / 𝑥⦌𝐹 = ⦋𝐴 / 𝑥⦌◡𝐹) |
|
Theorem | cnvco 4796 |
Distributive law of converse over class composition. Theorem 26 of
[Suppes] p. 64. (Contributed by NM,
19-Mar-1998.) (Proof shortened by
Andrew Salmon, 27-Aug-2011.)
|
⊢ ◡(𝐴 ∘ 𝐵) = (◡𝐵 ∘ ◡𝐴) |
|
Theorem | cnvuni 4797* |
The converse of a class union is the (indexed) union of the converses of
its members. (Contributed by NM, 11-Aug-2004.)
|
⊢ ◡∪ 𝐴 = ∪ 𝑥 ∈ 𝐴 ◡𝑥 |
|
Theorem | dfdm3 4798* |
Alternate definition of domain. Definition 6.5(1) of [TakeutiZaring]
p. 24. (Contributed by NM, 28-Dec-1996.)
|
⊢ dom 𝐴 = {𝑥 ∣ ∃𝑦〈𝑥, 𝑦〉 ∈ 𝐴} |
|
Theorem | dfrn2 4799* |
Alternate definition of range. Definition 4 of [Suppes] p. 60.
(Contributed by NM, 27-Dec-1996.)
|
⊢ ran 𝐴 = {𝑦 ∣ ∃𝑥 𝑥𝐴𝑦} |
|
Theorem | dfrn3 4800* |
Alternate definition of range. Definition 6.5(2) of [TakeutiZaring]
p. 24. (Contributed by NM, 28-Dec-1996.)
|
⊢ ran 𝐴 = {𝑦 ∣ ∃𝑥〈𝑥, 𝑦〉 ∈ 𝐴} |