Theorem bnj1374 35428

Description: Technical lemma for bnj60 35459. This lemma may no longer be used or have become an indirect lemma of the theorem in question (i.e. a lemma of a lemma... of the theorem). (Contributed by Jonathan Ben-Naim, 3-Jun-2011.) (New usage is discouraged.)

Hypotheses

Ref	Expression
bnj1374.1	⊢ 𝐵 = {𝑑 ∣ (𝑑 ⊆ 𝐴 ∧ ∀𝑥 ∈ 𝑑 pred(𝑥, 𝐴, 𝑅) ⊆ 𝑑)}
bnj1374.2	⊢ 𝑌 = ⟨𝑥, (𝑓 ↾ pred(𝑥, 𝐴, 𝑅))⟩
bnj1374.3	⊢ 𝐶 = {𝑓 ∣ ∃𝑑 ∈ 𝐵 (𝑓 Fn 𝑑 ∧ ∀𝑥 ∈ 𝑑 (𝑓‘𝑥) = (𝐺‘𝑌))}
bnj1374.4	⊢ (𝜏 ↔ (𝑓 ∈ 𝐶 ∧ dom 𝑓 = ({𝑥} ∪ trCl(𝑥, 𝐴, 𝑅))))
bnj1374.5	⊢ 𝐷 = {𝑥 ∈ 𝐴 ∣ ¬ ∃𝑓𝜏}
bnj1374.6	⊢ (𝜓 ↔ (𝑅 FrSe 𝐴 ∧ 𝐷 ≠ ∅))
bnj1374.7	⊢ (𝜒 ↔ (𝜓 ∧ 𝑥 ∈ 𝐷 ∧ ∀𝑦 ∈ 𝐷 ¬ 𝑦𝑅𝑥))
bnj1374.8	⊢ (𝜏′ ↔ [𝑦 / 𝑥]𝜏)
bnj1374.9	⊢ 𝐻 = {𝑓 ∣ ∃𝑦 ∈ pred (𝑥, 𝐴, 𝑅)𝜏′}

Assertion

Ref	Expression
bnj1374	⊢ (𝑓 ∈ 𝐻 → 𝑓 ∈ 𝐶)

Distinct variable groups:   𝑥,𝐴   𝐵,𝑓   𝑦,𝐶   𝑥,𝑅   𝑓,𝑑,𝑥   𝑦,𝑓,𝑥

Allowed substitution hints:   𝜓(𝑥, 𝑦, 𝑓, 𝑑)   𝜒(𝑥, 𝑦, 𝑓, 𝑑)   𝜏(𝑥, 𝑦, 𝑓, 𝑑)   𝐴(𝑦, 𝑓, 𝑑)   𝐵(𝑥, 𝑦, 𝑑)   𝐶(𝑥, 𝑓, 𝑑)   𝐷(𝑥, 𝑦, 𝑓, 𝑑)   𝑅(𝑦, 𝑓, 𝑑)   𝐺(𝑥, 𝑦, 𝑓, 𝑑)   𝐻(𝑥, 𝑦, 𝑓, 𝑑)   𝑌(𝑥, 𝑦, 𝑓, 𝑑)   𝜏′(𝑥, 𝑦, 𝑓, 𝑑)

Proof of Theorem bnj1374

Step	Hyp	Ref	Expression
1		bnj1374.9	. . . . . 6 ⊢ 𝐻 = {𝑓 ∣ ∃𝑦 ∈ pred (𝑥, 𝐴, 𝑅)𝜏′}
2	1	bnj1436 35236	. . . . 5 ⊢ (𝑓 ∈ 𝐻 → ∃𝑦 ∈ pred (𝑥, 𝐴, 𝑅)𝜏′)
3		rexex 3094	. . . . 5 ⊢ (∃𝑦 ∈ pred (𝑥, 𝐴, 𝑅)𝜏′ → ∃𝑦𝜏′)
4	2, 3	syl 18	. . . 4 ⊢ (𝑓 ∈ 𝐻 → ∃𝑦𝜏′)
5		bnj1374.1	. . . . . 6 ⊢ 𝐵 = {𝑑 ∣ (𝑑 ⊆ 𝐴 ∧ ∀𝑥 ∈ 𝑑 pred(𝑥, 𝐴, 𝑅) ⊆ 𝑑)}
6		bnj1374.2	. . . . . 6 ⊢ 𝑌 = ⟨𝑥, (𝑓 ↾ pred(𝑥, 𝐴, 𝑅))⟩
7		bnj1374.3	. . . . . 6 ⊢ 𝐶 = {𝑓 ∣ ∃𝑑 ∈ 𝐵 (𝑓 Fn 𝑑 ∧ ∀𝑥 ∈ 𝑑 (𝑓‘𝑥) = (𝐺‘𝑌))}
8		bnj1374.4	. . . . . 6 ⊢ (𝜏 ↔ (𝑓 ∈ 𝐶 ∧ dom 𝑓 = ({𝑥} ∪ trCl(𝑥, 𝐴, 𝑅))))
9		bnj1374.8	. . . . . 6 ⊢ (𝜏′ ↔ [𝑦 / 𝑥]𝜏)
10	5, 6, 7, 8, 9	bnj1373 35427	. . . . 5 ⊢ (𝜏′ ↔ (𝑓 ∈ 𝐶 ∧ dom 𝑓 = ({𝑦} ∪ trCl(𝑦, 𝐴, 𝑅))))
11	10	exbii 1877	. . . 4 ⊢ (∃𝑦𝜏′ ↔ ∃𝑦(𝑓 ∈ 𝐶 ∧ dom 𝑓 = ({𝑦} ∪ trCl(𝑦, 𝐴, 𝑅))))
12	4, 11	sylib 221	. . 3 ⊢ (𝑓 ∈ 𝐻 → ∃𝑦(𝑓 ∈ 𝐶 ∧ dom 𝑓 = ({𝑦} ∪ trCl(𝑦, 𝐴, 𝑅))))
13		exsimpl 1897	. . 3 ⊢ (∃𝑦(𝑓 ∈ 𝐶 ∧ dom 𝑓 = ({𝑦} ∪ trCl(𝑦, 𝐴, 𝑅))) → ∃𝑦 𝑓 ∈ 𝐶)
14	12, 13	syl 18	. 2 ⊢ (𝑓 ∈ 𝐻 → ∃𝑦 𝑓 ∈ 𝐶)
15	14	bnj937 35169	1 ⊢ (𝑓 ∈ 𝐻 → 𝑓 ∈ 𝐶)

This proof depends on syntax axioms:  ¬ wn 3   → wi 4   ↔ wb 209   ∧ wa 400   ∧ w3a 1102   = wceq 1569  ∃wex 1808   ∈ wcel 2142  {cab 2740   ≠ wne 2957  ∀wral 3078  ∃wrex 3088  {crab 3415  [wsbc 3743   ∪ cun 3902   ⊆ wss 3904  ∅c0 4285  {csn 4588  ⟨cop 4594   class class class wbr 5108  dom cdm 5660   ↾ cres 5662   Fn wfn 6531  ‘cfv 6536   predc-bnj14 35086   FrSe w-bnj15 35090   trClc-bnj18 35092

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1824  ax-4 1838  ax-5 1939  ax-6 1996  ax-7 2037  ax-8 2144  ax-9 2152  ax-10 2175  ax-11 2191  ax-12 2212  ax-ext 2734

This proof depends on definitions:  df-bi 210  df-an 401  df-or 861  df-3an 1104  df-tru 1572  df-fal 1582  df-ex 1809  df-nf 1813  df-sb 2096  df-clab 2741  df-cleq 2754  df-clel 2837  df-nfc 2911  df-ral 3079  df-rex 3089  df-rab 3416  df-v 3456  df-sbc 3744  df-dif 3907  df-un 3909  df-ss 3921  df-nul 4286  df-if 4487  df-sn 4589  df-pr 4591  df-op 4595  df-iun 4957  df-br 5109  df-bnj14 35087  df-bnj18 35093

This theorem is used by:  bnj1384  35429