Theorem disjors 5085

Description: Two ways to say that a collection 𝐵(𝑖) for 𝑖 ∈ 𝐴 is disjoint. (Contributed by Mario Carneiro, 14-Nov-2016.)

Assertion

Ref	Expression
disjors	⊢ (Disj 𝑥 ∈ 𝐴 𝐵 ↔ ∀𝑖 ∈ 𝐴 ∀𝑗 ∈ 𝐴 (𝑖 = 𝑗 ∨ (⦋𝑖 / 𝑥⦌𝐵 ∩ ⦋𝑗 / 𝑥⦌𝐵) = ∅))

Distinct variable groups:   𝑖,𝑗,𝑥,𝐴   𝐵,𝑖,𝑗

Allowed substitution hint:   𝐵(𝑥)

Proof of Theorem disjors

Step	Hyp	Ref	Expression
1		nfcv 2922	. . 3 ⊢ Ⅎ𝑖𝐵
2		nfcsb1v 3871	. . 3 ⊢ Ⅎ𝑥⦋𝑖 / 𝑥⦌𝐵
3		csbeq1a 3861	. . 3 ⊢ (𝑥 = 𝑖 → 𝐵 = ⦋𝑖 / 𝑥⦌𝐵)
4	1, 2, 3	cbvdisj 5079	. 2 ⊢ (Disj 𝑥 ∈ 𝐴 𝐵 ↔ Disj 𝑖 ∈ 𝐴 ⦋𝑖 / 𝑥⦌𝐵)
5		csbeq1 3850	. . 3 ⊢ (𝑖 = 𝑗 → ⦋𝑖 / 𝑥⦌𝐵 = ⦋𝑗 / 𝑥⦌𝐵)
6	5	disjor 5084	. 2 ⊢ (Disj 𝑖 ∈ 𝐴 ⦋𝑖 / 𝑥⦌𝐵 ↔ ∀𝑖 ∈ 𝐴 ∀𝑗 ∈ 𝐴 (𝑖 = 𝑗 ∨ (⦋𝑖 / 𝑥⦌𝐵 ∩ ⦋𝑗 / 𝑥⦌𝐵) = ∅))
7	4, 6	bitri 278	1 ⊢ (Disj 𝑥 ∈ 𝐴 𝐵 ↔ ∀𝑖 ∈ 𝐴 ∀𝑗 ∈ 𝐴 (𝑖 = 𝑗 ∨ (⦋𝑖 / 𝑥⦌𝐵 ∩ ⦋𝑗 / 𝑥⦌𝐵) = ∅))

This proof depends on syntax axioms:   ↔ wb 209   ∨ wo 861   = wceq 1569  ∀wral 3076  ⦋csb 3847   ∩ cin 4088  ∅c0 4277  Disj wdisj 5069

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1827  ax-4 1841  ax-5 1942  ax-6 1999  ax-7 2040  ax-8 2146  ax-9 2154  ax-10 2177  ax-11 2193  ax-12 2212  ax-ext 2732

This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-tru 1572  df-fal 1582  df-ex 1812  df-nf 1816  df-sb 2099  df-mo 2564  df-clab 2739  df-cleq 2752  df-clel 2835  df-nfc 2909  df-ral 3077  df-rmo 3365  df-v 3452  df-sbc 3739  df-csb 3848  df-dif 4046  df-in 4090  df-nul 4278  df-disj 5070

This theorem is used by:  disji2  5086  disjprg  5098  disjxiun  5099  disjxun  5100  iundisj2  25877  disji2f  33220  disjpreima  33227  disjxpin  33231  iundisj2f  33233  disjunsn  33237  iundisj2fi  33437  disjxp1  46193  disjinfi  46314