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Theorem djussxp2 33004
Description: Stronger version of djussxp 5830. (Contributed by Thierry Arnoux, 23-Jun-2024.)
Assertion
Ref Expression
djussxp2 𝑘𝐴 ({𝑘} × 𝐵) ⊆ (𝐴 × 𝑘𝐴 𝐵)
Distinct variable group:   𝐴,𝑘
Allowed substitution hint:   𝐵(𝑘)

Proof of Theorem djussxp2
StepHypRef Expression
1 nfcv 2924 . . . 4 𝑘𝐴
2 nfiu1 4991 . . . 4 𝑘 𝑘𝐴 𝐵
31, 2nfxp 5693 . . 3 𝑘(𝐴 × 𝑘𝐴 𝐵)
43iunssf 5006 . 2 ( 𝑘𝐴 ({𝑘} × 𝐵) ⊆ (𝐴 × 𝑘𝐴 𝐵) ↔ ∀𝑘𝐴 ({𝑘} × 𝐵) ⊆ (𝐴 × 𝑘𝐴 𝐵))
5 snssi 4750 . . 3 (𝑘𝐴 → {𝑘} ⊆ 𝐴)
6 ssiun2 5011 . . 3 (𝑘𝐴𝐵 𝑘𝐴 𝐵)
7 xpss12 5675 . . 3 (({𝑘} ⊆ 𝐴𝐵 𝑘𝐴 𝐵) → ({𝑘} × 𝐵) ⊆ (𝐴 × 𝑘𝐴 𝐵))
85, 6, 7syl2anc 595 . 2 (𝑘𝐴 → ({𝑘} × 𝐵) ⊆ (𝐴 × 𝑘𝐴 𝐵))
94, 8mprgbir 3085 1 𝑘𝐴 ({𝑘} × 𝐵) ⊆ (𝐴 × 𝑘𝐴 𝐵)
Colors of variables:    wff setvar class
This proof depends on syntax axioms:  wcel 2142  wss 3904  {csn 4588   ciun 4955   × cxp 5658
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1824  ax-4 1838  ax-5 1939  ax-6 1996  ax-7 2037  ax-8 2144  ax-9 2152  ax-10 2175  ax-11 2191  ax-12 2212  ax-ext 2734
This proof depends on definitions:  df-bi 210  df-an 401  df-or 861  df-tru 1572  df-ex 1809  df-nf 1813  df-sb 2096  df-clab 2741  df-cleq 2754  df-clel 2837  df-nfc 2911  df-ral 3079  df-rex 3089  df-v 3456  df-ss 3921  df-sn 4589  df-iun 4957  df-opab 5173  df-xp 5666
This theorem is used by:  2ndresdju  33005  gsumpart  33392
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