Theorem nla0003 44563

Description: Extending a linear order to subsets, the empty set is greater than any subset. Note in [Alling], p. 3. (Contributed by RP, 28-Nov-2023.)

Hypotheses

Ref	Expression
nla0001.defslts	⊢ < = {⟨𝑎, 𝑏⟩ ∣ (𝑎 ⊆ 𝑆 ∧ 𝑏 ⊆ 𝑆 ∧ ∀𝑥 ∈ 𝑎 ∀𝑦 ∈ 𝑏 𝑥𝑅𝑦)}
nla0001.set	⊢ (𝜑 → 𝐴 ∈ V)
nla0002.sset	⊢ (𝜑 → 𝐴 ⊆ 𝑆)

Assertion

Ref	Expression
nla0003	⊢ (𝜑 → 𝐴 < ∅)

Distinct variable groups:   𝐴,𝑎,𝑏,𝑥,𝑦   𝑅,𝑎,𝑏   𝑆,𝑎,𝑏

Allowed substitution hints:   𝜑(𝑥, 𝑦, 𝑎, 𝑏)   𝑅(𝑥, 𝑦)   𝑆(𝑥, 𝑦)   < (𝑥, 𝑦, 𝑎, 𝑏)

Proof of Theorem nla0003

Step	Hyp	Ref	Expression
1		nla0001.set	. 2 ⊢ (𝜑 → 𝐴 ∈ V)
2		0ex 5260	. . 3 ⊢ ∅ ∈ V
3	2	a1i 11	. 2 ⊢ (𝜑 → ∅ ∈ V)
4		nla0002.sset	. . 3 ⊢ (𝜑 → 𝐴 ⊆ 𝑆)
5		0ss 4349	. . . 4 ⊢ ∅ ⊆ 𝑆
6	5	a1i 11	. . 3 ⊢ (𝜑 → ∅ ⊆ 𝑆)
7		ral0 4453	. . . . 5 ⊢ ∀𝑦 ∈ ∅ ∀𝑥 ∈ 𝐴 𝑥𝑅𝑦
8		ralcom 3290	. . . . 5 ⊢ (∀𝑦 ∈ ∅ ∀𝑥 ∈ 𝐴 𝑥𝑅𝑦 ↔ ∀𝑥 ∈ 𝐴 ∀𝑦 ∈ ∅ 𝑥𝑅𝑦)
9	7, 8	mpbi 233	. . . 4 ⊢ ∀𝑥 ∈ 𝐴 ∀𝑦 ∈ ∅ 𝑥𝑅𝑦
10	9	a1i 11	. . 3 ⊢ (𝜑 → ∀𝑥 ∈ 𝐴 ∀𝑦 ∈ ∅ 𝑥𝑅𝑦)
11	4, 6, 10	3jca 1146	. 2 ⊢ (𝜑 → (𝐴 ⊆ 𝑆 ∧ ∅ ⊆ 𝑆 ∧ ∀𝑥 ∈ 𝐴 ∀𝑦 ∈ ∅ 𝑥𝑅𝑦))
12		nla0001.defslts	. . 3 ⊢ < = {⟨𝑎, 𝑏⟩ ∣ (𝑎 ⊆ 𝑆 ∧ 𝑏 ⊆ 𝑆 ∧ ∀𝑥 ∈ 𝑎 ∀𝑦 ∈ 𝑏 𝑥𝑅𝑦)}
13	12	rp-brsslt 44561	. 2 ⊢ (𝐴 < ∅ ↔ ((𝐴 ∈ V ∧ ∅ ∈ V) ∧ (𝐴 ⊆ 𝑆 ∧ ∅ ⊆ 𝑆 ∧ ∀𝑥 ∈ 𝐴 ∀𝑦 ∈ ∅ 𝑥𝑅𝑦)))
14	1, 3, 11, 13	syl21anbrc 1363	1 ⊢ (𝜑 → 𝐴 < ∅)

This proof depends on syntax axioms:   → wi 4   ∧ w3a 1103   = wceq 1569   ∈ wcel 2144  ∀wral 3076  Vcvv 3450   ⊆ wss 3896  ∅c0 4277   class class class wbr 5102  {copab 5166

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1827  ax-4 1841  ax-5 1942  ax-6 1999  ax-7 2040  ax-8 2146  ax-9 2154  ax-11 2193  ax-ext 2732  ax-sep 5248  ax-nul 5259  ax-pr 5391

This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3an 1105  df-tru 1572  df-fal 1582  df-ex 1812  df-sb 2099  df-clab 2739  df-cleq 2752  df-clel 2835  df-ral 3077  df-rex 3087  df-rab 3413  df-v 3452  df-ss 3897  df-dif 4046  df-in 4090  df-un 4150  df-nul 4278  df-if 4482  df-sn 4585  df-pr 4587  df-op 4835  df-br 5103  df-opab 5167  df-xp 5657

This theorem is used by: (None)