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Theorem sscond 4145
Description: If 𝐴 is contained in 𝐵, then (𝐶𝐵) is contained in (𝐶𝐴). Deduction form of sscon 4142. (Contributed by David Moews, 1-May-2017.)
Hypothesis
Ref Expression
ssdifd.1 (𝜑𝐴𝐵)
Assertion
Ref Expression
sscond (𝜑 → (𝐶𝐵) ⊆ (𝐶𝐴))

Proof of Theorem sscond
StepHypRef Expression
1 ssdifd.1 . 2 (𝜑𝐴𝐵)
2 sscon 4142 . 2 (𝐴𝐵 → (𝐶𝐵) ⊆ (𝐶𝐴))
31, 2syl 17 1 (𝜑 → (𝐶𝐵) ⊆ (𝐶𝐴))
Colors of variables: wff setvar class
Syntax hints:  wi 4  cdif 3947  wss 3950
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1794  ax-4 1808  ax-5 1909  ax-6 1966  ax-7 2006  ax-8 2109  ax-9 2117  ax-ext 2707
This theorem depends on definitions:  df-bi 207  df-an 396  df-tru 1542  df-ex 1779  df-sb 2064  df-clab 2714  df-cleq 2728  df-clel 2815  df-v 3481  df-dif 3953  df-ss 3967
This theorem is referenced by:  ssdif2d  4147  eldifeldifsn  4810  fin23lem26  10366  isercoll2  15706  fctop  23012  ntrss  23064  iunconnlem  23436  clsconn  23439  regr1lem  23748  blcld  24519  rrxdstprj1  25444  voliunlem1  25586  elrgspnsubrunlem2  33253  elrspunidl  33457  carsgclctunlem2  34322  salexct  46354  meaiininclem  46506  carageniuncllem2  46542  seposep  48830
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