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Theorem List for New Foundations Explorer - 6301-6338   *Has distinct variable group(s)
TypeLabelDescription
Statement
 
Theoremnchoicelem13 6301 Lemma for nchoice 6308. The cardinality of a special set is at least one. (Contributed by SF, 18-Mar-2015.)
(M NC → 1cc Nc ( SpacM))
 
Theoremnchoicelem14 6302 Lemma for nchoice 6308. When the special set generator yields a singleton, then the cardinal is not raisable. (Contributed by SF, 19-Mar-2015.)
((M NC Nc ( SpacM) = 1c) → ¬ (Mc 0c) NC )
 
Theoremnchoicelem15 6303 Lemma for nchoice 6308. When the special set generator does not yield a singleton, then the cardinal is raisable. (Contributed by SF, 19-Mar-2015.)
((M NC 1c <c Nc ( SpacM)) → (Mc 0c) NC )
 
Theoremnchoicelem16 6304* Lemma for nchoice 6308. Set up stratification for nchoicelem17 6305. (Contributed by SF, 19-Mar-2015.)
{t ( ≤c We NCm NC ( Nc ( Spacm) = (1c +c t) → (( SpacTc m) Fin ( Nc ( SpacTc m) = ( Tc Nc ( Spacm) +c 1c) Nc ( SpacTc m) = ( Tc Nc ( Spacm) +c 2c)))))} V
 
Theoremnchoicelem17 6305 Lemma for nchoice 6308. If the special set of a cardinal is finite, then so is the special set of its T-raising, and there is a calculable relationship between their sizes. Theorem 7.2 of [Specker] p. 974. (Contributed by SF, 19-Mar-2015.)
(( ≤c We NC M NC ( SpacM) Fin ) → (( SpacTc M) Fin ( Nc ( SpacTc M) = ( Tc Nc ( SpacM) +c 1c) Nc ( SpacTc M) = ( Tc Nc ( SpacM) +c 2c))))
 
Theoremnchoicelem18 6306 Lemma for nchoice 6308. Set up stratification for nchoicelem19 6307. (Contributed by SF, 20-Mar-2015.)
{x ( Spacx) Fin } V
 
Theoremnchoicelem19 6307 Lemma for nchoice 6308. Assuming well-ordering, there is a cardinal with a finite special set that is its own T-raising. Theorem 7.3 of [Specker] p. 974. (Contributed by SF, 20-Mar-2015.)
( ≤c We NCm NC (( Spacm) Fin Tc m = m))
 
Theoremnchoice 6308 Cardinal less than or equal does not well-order the cardinals. This is equivalent to saying that the axiom of choice from ZFC is false in NF. Theorem 7.5 of [Specker] p. 974. (Contributed by SF, 20-Mar-2015.)
¬ ≤c We NC
 
2.4.7  Finite recursion
 
Syntaxcfrec 6309 Extend the definition of a class to include the finite recursive function generator.
class FRec (F, I)
 
Definitiondf-frec 6310* Define the finite recursive function generator. This is a function over Nn that obeys the standard recursion relationship. Definition adapted from theorem XI.3.24 of [Rosser] p. 412. (Contributed by Scott Fenton, 30-Jul-2019.)
FRec (F, I) = Clos1 ({0c, I}, PProd ((x V (x +c 1c)), F))
 
Theoremfreceq12 6311 Equality theorem for finite recursive function generator. (Contributed by Scott Fenton, 31-Jul-2019.)
((F = G I = J) → FRec (F, I) = FRec (G, J))
 
Theoremfrecexg 6312 The finite recursive function generator preserves sethood. (Contributed by Scott Fenton, 30-Jul-2019.)
F = FRec (G, I)       (G VF V)
 
Theoremfrecex 6313 The finite recursive function generator preserves sethood. (Contributed by Scott Fenton, 30-Jul-2019.)
F = FRec (G, I)    &   G V       F V
 
Theoremfrecxp 6314 Subset relationship for the finite recursive function generator. (Contributed by Scott Fenton, 30-Jul-2019.)
F = FRec (G, I)    &   G V       F ( Nn × (ran G ∪ {I}))
 
Theoremfrecxpg 6315 Subset relationship for the finite recursive function generator. (Contributed by Scott Fenton, 31-Jul-2019.)
F = FRec (G, I)       (G VF ( Nn × (ran G ∪ {I})))
 
Theoremdmfrec 6316 The domain of the finite recursive function generator is the naturals. (Contributed by Scott Fenton, 31-Jul-2019.)
F = FRec (G, I)    &   (φG V)    &   (φI dom G)    &   (φ → ran G dom G)       (φ → dom F = Nn )
 
Theoremfnfreclem1 6317* Lemma for fnfrec 6320. Establish stratification for induction. (Contributed by Scott Fenton, 31-Jul-2019.)
(F V → {w yz((wFy wFz) → y = z)} V)
 
Theoremfnfreclem2 6318 Lemma for fnfrec 6320. Calculate the unique value of F at zero. (Contributed by Scott Fenton, 31-Jul-2019.)
F = FRec (G, I)    &   (φG V)    &   (φI dom G)    &   (φ → ran G dom G)       (φ → (0cFXX = I))
 
Theoremfnfreclem3 6319* Lemma for fnfrec 6320. The value of F at a successor is G related to a previous element. (Contributed by Scott Fenton, 31-Jul-2019.)
F = FRec (G, I)    &   (φG V)    &   (φI dom G)    &   (φ → ran G dom G)    &   (φX Nn )    &   (φ → (X +c 1c)FY)       (φz(XFz zGY))
 
Theoremfnfrec 6320 The recursive function generator is a function over the finite cardinals. (Contributed by Scott Fenton, 31-Jul-2019.)
F = FRec (G, I)    &   (φG Funs )    &   (φI dom G)    &   (φ → ran G dom G)       (φF Fn Nn )
 
Theoremfrec0 6321 Calculate the value of the finite recursive function generator at zero. (Contributed by Scott Fenton, 31-Jul-2019.)
F = FRec (G, I)    &   (φG Funs )    &   (φI dom G)    &   (φ → ran G dom G)       (φ → (F ‘0c) = I)
 
Theoremfrecsuc 6322 Calculate the value of the finite recursive function generator at a successor. (Contributed by Scott Fenton, 31-Jul-2019.)
F = FRec (G, I)    &   (φG Funs )    &   (φI dom G)    &   (φ → ran G dom G)    &   (φX Nn )       (φ → (F ‘(X +c 1c)) = (G ‘(FX)))
 
2.5  Cantorian and Strongly Cantorian Sets
 
Syntaxccan 6323 Extend the definition of class to include the class of all Cantorian sets.
class Can
 
Definitiondf-can 6324 Define the class of all Cantorian sets. These are so-called because Cantor's Theorem Nc A <c Nc A holds for these sets. Definition from [Rosser] p. 347 and [Holmes] p. 134. (Contributed by Scott Fenton, 19-Apr-2021.)
Can = {x 1xx}
 
Syntaxcscan 6325 Extend the definition of class to include the class of all strongly Cantorian sets.
class SCan
 
Definitiondf-scan 6326* Define the class of strongly Cantorian sets. Unlike general Cantorian sets, this fixes a specific mapping between x and 1x. Definition from [Holmes] p. 134. (Contributed by Scott Fenton, 19-Apr-2021.)
SCan = {x (y x {y}) V}
 
Theoremdmsnfn 6327* The domain of the singleton function. (Contributed by Scott Fenton, 20-Apr-2021.)
dom (x A {x}) = A
 
Theoremepelcres 6328 Version of epelc 4765 with a restriction in place. (Contributed by Scott Fenton, 20-Apr-2021.)
Y V       (X A → (X( E A)YX Y))
 
Theoremelcan 6329 Membership in the class of Cantorian sets. (Contributed by Scott Fenton, 19-Apr-2021.)
(A Can1AA)
 
Theoremelscan 6330* Membership in the class of strongly Cantorian sets. (Contributed by Scott Fenton, 19-Apr-2021.)
(A SCan ↔ (x A {x}) V)
 
Theoremscancan 6331 Strongly Cantorian implies Cantorian. Observation from [Holmes], p. 134. (Contributed by Scott Fenton, 19-Apr-2021.)
(A SCanA Can )
 
Theoremcanncb 6332 The cardinality of a Cantorian set is equal to the cardinality of its unit power set. (Contributed by Scott Fenton, 23-Apr-2021.)
(A V → (A CanNc 1A = Nc A))
 
Theoremcannc 6333 The cardinality of a Cantorian set is equal to the cardinality of its unit power set. (Contributed by Scott Fenton, 21-Apr-2021.)
(A CanNc 1A = Nc A)
 
Theoremcanltpw 6334 The cardinality of a Cantorian set is strictly less than the cardinality of its power set. (Contributed by Scott Fenton, 21-Apr-2021.)
(A CanNc A <c Nc A)
 
Theoremcantcb 6335 The cardinality of a Cantorian set is equal to the Tc raising of that cardinal. (Contributed by Scott Fenton, 23-Apr-2021.)
(A V → (A CanTc Nc A = Nc A))
 
Theoremcantc 6336 The cardinality of a Cantorian set is equal to the Tc raising of that cardinal. (Contributed by Scott Fenton, 22-Apr-2021.)
(A CanTc Nc A = Nc A)
 
Theoremvncan 6337 The universe is not Cantorian. Theorem XI.1.8 of [Rosser] p. 348. (Contributed by Scott Fenton, 22-Apr-2021.)
¬ V Can
 
PART 3  GUIDES AND MISCELLANEA
 
3.1  Guides (conventions, explanations, and examples)
 
3.1.1  Conventions

This section describes the conventions we use. These conventions often refer to existing mathematical practices, which are discussed in more detail in other references.

 
Theoremconventions 6338 Unless there is a reason to diverge, we follow the conventions of the Metamath Proof Explorer (MPE, set.mm).

(Contributed by the Metamath team, 20-Jan-2024.) (New usage is discouraged.)

φ       φ
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