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| Mirrors > Home > ILE Home > Th. List > nndifsnid | Unicode version | ||
| Description: If we remove a single element from a natural number then put it back in, we end up with the original natural number. This strengthens difsnss 3861 from subset to equality but the proof relies on equality being decidable. (Contributed by Jim Kingdon, 31-Aug-2021.) |
| Ref | Expression |
|---|---|
| nndifsnid |
|
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | elnn 4753 |
. . . . . 6
| |
| 2 | 1 | expcom 116 |
. . . . 5
|
| 3 | elnn 4753 |
. . . . . 6
| |
| 4 | 3 | expcom 116 |
. . . . 5
|
| 5 | 2, 4 | anim12d 335 |
. . . 4
|
| 6 | nndceq 6772 |
. . . 4
| |
| 7 | 5, 6 | syl6 33 |
. . 3
|
| 8 | 7 | ralrimivv 2631 |
. 2
|
| 9 | dcdifsnid 6777 |
. 2
| |
| 10 | 8, 9 | sylan 283 |
1
|
| Colors of variables: wff set class |
| This proof depends on syntax axioms:
|
| This proof depends on axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia1 106 ax-ia2 107 ax-ia3 108 ax-in1 623 ax-in2 624 ax-io 721 ax-5 1500 ax-7 1501 ax-gen 1502 ax-ie1 1546 ax-ie2 1547 ax-8 1557 ax-10 1558 ax-11 1559 ax-i12 1560 ax-bndl 1562 ax-4 1563 ax-17 1579 ax-i9 1583 ax-ial 1587 ax-i5r 1588 ax-14 2212 ax-ext 2220 ax-sep 4249 ax-nul 4259 ax-pow 4311 ax-pr 4346 ax-un 4578 ax-setind 4684 ax-iinf 4735 |
| This proof depends on definitions: df-bi 117 df-dc 847 df-3or 1010 df-3an 1011 df-tru 1405 df-nf 1514 df-sb 1816 df-clab 2225 df-cleq 2231 df-clel 2234 df-nfc 2381 df-ne 2421 df-ral 2533 df-rex 2534 df-v 2823 df-dif 3222 df-un 3224 df-in 3226 df-ss 3233 df-nul 3521 df-pw 3690 df-sn 3715 df-pr 3716 df-uni 3936 df-int 3971 df-tr 4230 df-iord 4511 df-on 4513 df-suc 4516 df-iom 4738 |
| This theorem is used by: phplem2 7154 |
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