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Mirrors > Home > ILE Home > Th. List > nndifsnid | Unicode version |
Description: If we remove a single element from a natural number then put it back in, we end up with the original natural number. This strengthens difsnss 3740 from subset to equality but the proof relies on equality being decidable. (Contributed by Jim Kingdon, 31-Aug-2021.) |
Ref | Expression |
---|---|
nndifsnid |
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Step | Hyp | Ref | Expression |
---|---|---|---|
1 | elnn 4607 |
. . . . . 6
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2 | 1 | expcom 116 |
. . . . 5
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3 | elnn 4607 |
. . . . . 6
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4 | 3 | expcom 116 |
. . . . 5
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5 | 2, 4 | anim12d 335 |
. . . 4
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6 | nndceq 6503 |
. . . 4
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7 | 5, 6 | syl6 33 |
. . 3
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8 | 7 | ralrimivv 2558 |
. 2
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9 | dcdifsnid 6508 |
. 2
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10 | 8, 9 | sylan 283 |
1
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Colors of variables: wff set class |
Syntax hints: ![]() ![]() ![]() ![]() ![]() ![]() ![]() ![]() ![]() |
This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia1 106 ax-ia2 107 ax-ia3 108 ax-in1 614 ax-in2 615 ax-io 709 ax-5 1447 ax-7 1448 ax-gen 1449 ax-ie1 1493 ax-ie2 1494 ax-8 1504 ax-10 1505 ax-11 1506 ax-i12 1507 ax-bndl 1509 ax-4 1510 ax-17 1526 ax-i9 1530 ax-ial 1534 ax-i5r 1535 ax-13 2150 ax-14 2151 ax-ext 2159 ax-sep 4123 ax-nul 4131 ax-pow 4176 ax-pr 4211 ax-un 4435 ax-setind 4538 ax-iinf 4589 |
This theorem depends on definitions: df-bi 117 df-dc 835 df-3or 979 df-3an 980 df-tru 1356 df-nf 1461 df-sb 1763 df-clab 2164 df-cleq 2170 df-clel 2173 df-nfc 2308 df-ne 2348 df-ral 2460 df-rex 2461 df-v 2741 df-dif 3133 df-un 3135 df-in 3137 df-ss 3144 df-nul 3425 df-pw 3579 df-sn 3600 df-pr 3601 df-uni 3812 df-int 3847 df-tr 4104 df-iord 4368 df-on 4370 df-suc 4373 df-iom 4592 |
This theorem is referenced by: phplem2 6856 |
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