Theorem eqssi 3253

Description: Infer equality from two subclass relationships. Compare Theorem 4 of [Suppes] p. 22. (Contributed by NM, 9-Sep-1993.)

Hypotheses

Ref	Expression
eqssi.1	⊢ 𝐴 ⊆ 𝐵
eqssi.2	⊢ 𝐵 ⊆ 𝐴

Assertion

Ref	Expression
eqssi	⊢ 𝐴 = 𝐵

Proof of Theorem eqssi

Step	Hyp	Ref	Expression
1		eqssi.1	. 2 ⊢ 𝐴 ⊆ 𝐵
2		eqssi.2	. 2 ⊢ 𝐵 ⊆ 𝐴
3		eqss 3252	. 2 ⊢ (𝐴 = 𝐵 ↔ (𝐴 ⊆ 𝐵 ∧ 𝐵 ⊆ 𝐴))
4	1, 2, 3	mpbir2an 951	1 ⊢ 𝐴 = 𝐵

Syntax hints:   = wceq 1398   ⊆ wss 3210

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-5 1496  ax-7 1497  ax-gen 1498  ax-ie1 1542  ax-ie2 1543  ax-8 1553  ax-11 1555  ax-4 1559  ax-17 1575  ax-i9 1579  ax-ial 1583  ax-i5r 1584  ax-ext 2214

This theorem depends on definitions:  df-bi 117  df-nf 1510  df-sb 1812  df-clab 2219  df-cleq 2225  df-clel 2228  df-in 3216  df-ss 3223

This theorem is referenced by:  inv1  3544  unv  3545  undifabs  3585  intab  3977  intid  4339  find  4720  limom  4735  dmv  4971  0ima  5121  rnxpid  5196  dftpos4  6493  axaddf  8182  axmulf  8183  dfuzi  9687  unirnioo  10305  0bits  12641  4sqlem19  13103  txuni2  15113  dvef  15584  reeff1o  15630