Theorem equequ1 1688

Description: An equivalence law for equality. (Contributed by NM, 5-Aug-1993.)

Assertion

Ref	Expression
equequ1	⊢ (𝑥 = 𝑦 → (𝑥 = 𝑧 ↔ 𝑦 = 𝑧))

Proof of Theorem equequ1

Step	Hyp	Ref	Expression
1		ax-8 1482	. 2 ⊢ (𝑥 = 𝑦 → (𝑥 = 𝑧 → 𝑦 = 𝑧))
2		equtr 1685	. 2 ⊢ (𝑥 = 𝑦 → (𝑦 = 𝑧 → 𝑥 = 𝑧))
3	1, 2	impbid 128	1 ⊢ (𝑥 = 𝑦 → (𝑥 = 𝑧 ↔ 𝑦 = 𝑧))

Syntax hints:   → wi 4   ↔ wb 104

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-gen 1425  ax-ie2 1470  ax-8 1482  ax-17 1506  ax-i9 1510

This theorem depends on definitions:  df-bi 116

This theorem is referenced by:  equveli  1732  drsb1  1771  equsb3lem  1923  euequ1  2094  axext3  2122  reu6  2873  reu7  2879  disjiun  3924  cbviota  5093  dff13f  5671  poxp  6129  dcdifsnid  6400  supmoti  6880  isoti  6894  fsum2dlemstep  11203  ennnfonelemr  11936  ctinf  11943