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Theorem reusv1 4490
Description: Two ways to express single-valuedness of a class expression 𝐶(𝑦). (Contributed by NM, 16-Dec-2012.) (Proof shortened by Mario Carneiro, 18-Nov-2016.)
Assertion
Ref Expression
reusv1 (∃𝑦𝐵 𝜑 → (∃!𝑥𝐴𝑦𝐵 (𝜑𝑥 = 𝐶) ↔ ∃𝑥𝐴𝑦𝐵 (𝜑𝑥 = 𝐶)))
Distinct variable groups:   𝑥,𝐴   𝑥,𝐵   𝑥,𝐶   𝜑,𝑥   𝑥,𝑦
Allowed substitution hints:   𝜑(𝑦)   𝐴(𝑦)   𝐵(𝑦)   𝐶(𝑦)

Proof of Theorem reusv1
StepHypRef Expression
1 nfra1 2525 . . . 4 𝑦𝑦𝐵 (𝜑𝑥 = 𝐶)
21nfmo 2062 . . 3 𝑦∃*𝑥𝑦𝐵 (𝜑𝑥 = 𝐶)
3 rsp 2541 . . . . . . . 8 (∀𝑦𝐵 (𝜑𝑥 = 𝐶) → (𝑦𝐵 → (𝜑𝑥 = 𝐶)))
43impd 254 . . . . . . 7 (∀𝑦𝐵 (𝜑𝑥 = 𝐶) → ((𝑦𝐵𝜑) → 𝑥 = 𝐶))
54com12 30 . . . . . 6 ((𝑦𝐵𝜑) → (∀𝑦𝐵 (𝜑𝑥 = 𝐶) → 𝑥 = 𝐶))
65alrimiv 1885 . . . . 5 ((𝑦𝐵𝜑) → ∀𝑥(∀𝑦𝐵 (𝜑𝑥 = 𝐶) → 𝑥 = 𝐶))
7 moeq 2936 . . . . 5 ∃*𝑥 𝑥 = 𝐶
8 moim 2106 . . . . 5 (∀𝑥(∀𝑦𝐵 (𝜑𝑥 = 𝐶) → 𝑥 = 𝐶) → (∃*𝑥 𝑥 = 𝐶 → ∃*𝑥𝑦𝐵 (𝜑𝑥 = 𝐶)))
96, 7, 8mpisyl 1457 . . . 4 ((𝑦𝐵𝜑) → ∃*𝑥𝑦𝐵 (𝜑𝑥 = 𝐶))
109ex 115 . . 3 (𝑦𝐵 → (𝜑 → ∃*𝑥𝑦𝐵 (𝜑𝑥 = 𝐶)))
112, 10rexlimi 2604 . 2 (∃𝑦𝐵 𝜑 → ∃*𝑥𝑦𝐵 (𝜑𝑥 = 𝐶))
12 mormo 2710 . 2 (∃*𝑥𝑦𝐵 (𝜑𝑥 = 𝐶) → ∃*𝑥𝐴𝑦𝐵 (𝜑𝑥 = 𝐶))
13 reu5 2711 . . 3 (∃!𝑥𝐴𝑦𝐵 (𝜑𝑥 = 𝐶) ↔ (∃𝑥𝐴𝑦𝐵 (𝜑𝑥 = 𝐶) ∧ ∃*𝑥𝐴𝑦𝐵 (𝜑𝑥 = 𝐶)))
1413rbaib 922 . 2 (∃*𝑥𝐴𝑦𝐵 (𝜑𝑥 = 𝐶) → (∃!𝑥𝐴𝑦𝐵 (𝜑𝑥 = 𝐶) ↔ ∃𝑥𝐴𝑦𝐵 (𝜑𝑥 = 𝐶)))
1511, 12, 143syl 17 1 (∃𝑦𝐵 𝜑 → (∃!𝑥𝐴𝑦𝐵 (𝜑𝑥 = 𝐶) ↔ ∃𝑥𝐴𝑦𝐵 (𝜑𝑥 = 𝐶)))
Colors of variables: wff set class
Syntax hints:  wi 4  wa 104  wb 105  wal 1362   = wceq 1364  ∃*wmo 2043  wcel 2164  wral 2472  wrex 2473  ∃!wreu 2474  ∃*wrmo 2475
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-io 710  ax-5 1458  ax-7 1459  ax-gen 1460  ax-ie1 1504  ax-ie2 1505  ax-8 1515  ax-10 1516  ax-11 1517  ax-i12 1518  ax-bndl 1520  ax-4 1521  ax-17 1537  ax-i9 1541  ax-ial 1545  ax-i5r 1546  ax-ext 2175
This theorem depends on definitions:  df-bi 117  df-tru 1367  df-nf 1472  df-sb 1774  df-eu 2045  df-mo 2046  df-clab 2180  df-cleq 2186  df-clel 2189  df-ral 2477  df-rex 2478  df-reu 2479  df-rmo 2480  df-v 2762
This theorem is referenced by: (None)
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