Theorem 1elpr01 11331

Description: 1 is an element of {0, 1}. (Contributed by Umit Teoman Dogan, 10-Jun-2026.)

Assertion

Ref	Expression
1elpr01	⊢ 1 ∈ {0, 1}

Proof of Theorem 1elpr01

Step	Hyp	Ref	Expression
1		1ex 11330	. 2 ⊢ 1 ∈ V
2	1	prid2 4724	1 ⊢ 1 ∈ {0, 1}

This proof depends on syntax axioms:   ∈ wcel 2147  {cpr 4590  0cc0 11227  1c1 11228

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1945  ax-6 2002  ax-7 2043  ax-8 2149  ax-9 2157  ax-ext 2735  ax-1cn 11285

This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-tru 1573  df-ex 1813  df-sb 2102  df-clab 2742  df-cleq 2755  df-clel 2839  df-v 3456  df-un 4154  df-sn 4589  df-pr 4591

This theorem is used by:  ehl2eudis  25773  i1f1lem  26040  i1f1  26041  usgr2trlncl  30376  usgrwwlks2on  30577  umgrwwlks2on  30578  cyc3fv2  33769  esplyfvaln  34276  constrconj  34447  nn0constr  34463  fvrcllb1d  44887  relexp1idm  44906  corcltrcl  44931  cotrclrcl  44934  limsup10exlem  46987  stgr1  49264  gpgiedgdmellem  49349  gpgvtx1  49357  gpg3kgrtriex  49392  gpgprismgr4cycllem3  49400  gpgprismgr4cycllem9  49406  grlimedgnedg  49434  zlmodzxzscm  49674  2arympt  49966  rrx2pyel  50029