Theorem 1elpr01 11210

Description: 1 is an element of {0, 1}. (Contributed by Umit Teoman Dogan, 10-Jun-2026.)

Assertion

Ref	Expression
1elpr01	⊢ 1 ∈ {0, 1}

Proof of Theorem 1elpr01

Step	Hyp	Ref	Expression
1		1ex 11209	. 2 ⊢ 1 ∈ V
2	1	prid2 4728	1 ⊢ 1 ∈ {0, 1}

This proof depends on syntax axioms:   ∈ wcel 2142  {cpr 4590  0cc0 11106  1c1 11107

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1824  ax-4 1838  ax-5 1939  ax-6 1996  ax-7 2037  ax-8 2144  ax-9 2152  ax-ext 2734  ax-1cn 11164

This proof depends on definitions:  df-bi 210  df-an 401  df-or 861  df-tru 1572  df-ex 1809  df-sb 2096  df-clab 2741  df-cleq 2754  df-clel 2837  df-v 3456  df-un 3909  df-sn 4589  df-pr 4591

This theorem is used by:  i1f1lem  25859  i1f1  25860  usgr2trlncl  30120  usgrwwlks2on  30318  umgrwwlks2on  30319  cyc3fv2  33467  esplyfvaln  33973  constrconj  34144  nn0constr  34160  fvrcllb1d  44449  relexp1idm  44468  corcltrcl  44493  cotrclrcl  44496  limsup10exlem  46514  stgr1  48754  gpgiedgdmellem  48839  gpgvtx1  48847  gpg3kgrtriex  48882  gpgprismgr4cycllem3  48890  gpgprismgr4cycllem9  48896  grlimedgnedg  48924  zlmodzxzscm  49165  2arympt  49457