Theorem 1elpr01 11167

Description: 1 is an element of {0, 1}. (Contributed by Umit Teoman Dogan, 10-Jun-2026.)

Assertion

Ref	Expression
1elpr01	⊢ 1 ∈ {0, 1}

Proof of Theorem 1elpr01

Step	Hyp	Ref	Expression
1		1ex 11166	. 2 ⊢ 1 ∈ V
2	1	prid2 4716	1 ⊢ 1 ∈ {0, 1}

Syntax hints:   ∈ wcel 2136  {cpr 4578  0cc0 11063  1c1 11064

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1809  ax-4 1823  ax-5 1924  ax-6 1981  ax-7 2022  ax-8 2138  ax-9 2146  ax-ext 2728  ax-1cn 11121

This theorem depends on definitions:  df-bi 209  df-an 399  df-or 857  df-tru 1557  df-ex 1794  df-sb 2085  df-clab 2735  df-cleq 2748  df-clel 2831  df-v 3450  df-un 3904  df-sn 4577  df-pr 4579

This theorem is referenced by:  constrconj  33996  grlimedgnedg  48701