MPE Home Metamath Proof Explorer < Previous   Next >
Nearby theorems
Mirrors  >  Home  >  MPE Home  >  Th. List  >  clatlubcl2 Structured version   Visualization version   GIF version

Theorem clatlubcl2 18555
Description: Any subset of the base set has an LUB in a complete lattice. (Contributed by NM, 13-Sep-2018.)
Hypotheses
Ref Expression
clatlubcl.b 𝐵 = (Base‘𝐾)
clatlubcl.u 𝑈 = (lub‘𝐾)
Assertion
Ref Expression
clatlubcl2 ((𝐾 ∈ CLat ∧ 𝑆𝐵) → 𝑆 ∈ dom 𝑈)

Proof of Theorem clatlubcl2
StepHypRef Expression
1 clatlubcl.b . . . . 5 𝐵 = (Base‘𝐾)
21fvexi 6895 . . . 4 𝐵 ∈ V
32elpw2 5305 . . 3 (𝑆 ∈ 𝒫 𝐵𝑆𝐵)
43bilanri 511 . 2 ((𝐾 ∈ CLat ∧ 𝑆𝐵) → 𝑆 ∈ 𝒫 𝐵)
5 clatlubcl.u . . . . 5 𝑈 = (lub‘𝐾)
6 eqid 2763 . . . . 5 (glb‘𝐾) = (glb‘𝐾)
71, 5, 6isclat 18551 . . . 4 (𝐾 ∈ CLat ↔ (𝐾 ∈ Poset ∧ (dom 𝑈 = 𝒫 𝐵 ∧ dom (glb‘𝐾) = 𝒫 𝐵)))
8 simprl 782 . . . 4 ((𝐾 ∈ Poset ∧ (dom 𝑈 = 𝒫 𝐵 ∧ dom (glb‘𝐾) = 𝒫 𝐵)) → dom 𝑈 = 𝒫 𝐵)
97, 8sylbi 220 . . 3 (𝐾 ∈ CLat → dom 𝑈 = 𝒫 𝐵)
109adantr 485 . 2 ((𝐾 ∈ CLat ∧ 𝑆𝐵) → dom 𝑈 = 𝒫 𝐵)
114, 10eleqtrrd 2866 1 ((𝐾 ∈ CLat ∧ 𝑆𝐵) → 𝑆 ∈ dom 𝑈)
Colors of variables: wff setvar class
Syntax hints:  wi 4  wa 400   = wceq 1570  wcel 2143  wss 3905  𝒫 cpw 4562  dom cdm 5661  cfv 6536  Basecbs 17264  Posetcpo 18358  lubclub 18360  glbcglb 18361  CLatccla 18549
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1825  ax-4 1839  ax-5 1940  ax-6 1997  ax-7 2038  ax-8 2145  ax-9 2153  ax-ext 2735  ax-sep 5257  ax-nul 5269
This theorem depends on definitions:  df-bi 210  df-an 401  df-or 861  df-3an 1105  df-tru 1573  df-fal 1583  df-ex 1810  df-sb 2097  df-clab 2742  df-cleq 2755  df-clel 2838  df-ne 2959  df-rab 3417  df-v 3457  df-dif 3908  df-un 3910  df-in 3912  df-ss 3922  df-nul 4287  df-if 4488  df-pw 4564  df-sn 4590  df-pr 4592  df-op 4596  df-uni 4873  df-br 5110  df-dm 5671  df-iota 6492  df-fv 6544  df-clat 18550
This theorem is referenced by:  lublem  18561
  Copyright terms: Public domain W3C validator