Theorem clatlubcl2 18519

Description: Any subset of the base set has an LUB in a complete lattice. (Contributed by NM, 13-Sep-2018.)

Hypotheses

Ref	Expression
clatlubcl.b	⊢ 𝐵 = (Base‘𝐾)
clatlubcl.u	⊢ 𝑈 = (lub‘𝐾)

Assertion

Ref	Expression
clatlubcl2	⊢ ((𝐾 ∈ CLat ∧ 𝑆 ⊆ 𝐵) → 𝑆 ∈ dom 𝑈)

Proof of Theorem clatlubcl2

Step	Hyp	Ref	Expression
1		clatlubcl.b	. . . . . 6 ⊢ 𝐵 = (Base‘𝐾)
2	1	fvexi 6895	. . . . 5 ⊢ 𝐵 ∈ V
3	2	elpw2 5309	. . . 4 ⊢ (𝑆 ∈ 𝒫 𝐵 ↔ 𝑆 ⊆ 𝐵)
4	3	biimpri 228	. . 3 ⊢ (𝑆 ⊆ 𝐵 → 𝑆 ∈ 𝒫 𝐵)
5	4	adantl 481	. 2 ⊢ ((𝐾 ∈ CLat ∧ 𝑆 ⊆ 𝐵) → 𝑆 ∈ 𝒫 𝐵)
6		clatlubcl.u	. . . . 5 ⊢ 𝑈 = (lub‘𝐾)
7		eqid 2736	. . . . 5 ⊢ (glb‘𝐾) = (glb‘𝐾)
8	1, 6, 7	isclat 18515	. . . 4 ⊢ (𝐾 ∈ CLat ↔ (𝐾 ∈ Poset ∧ (dom 𝑈 = 𝒫 𝐵 ∧ dom (glb‘𝐾) = 𝒫 𝐵)))
9		simprl 770	. . . 4 ⊢ ((𝐾 ∈ Poset ∧ (dom 𝑈 = 𝒫 𝐵 ∧ dom (glb‘𝐾) = 𝒫 𝐵)) → dom 𝑈 = 𝒫 𝐵)
10	8, 9	sylbi 217	. . 3 ⊢ (𝐾 ∈ CLat → dom 𝑈 = 𝒫 𝐵)
11	10	adantr 480	. 2 ⊢ ((𝐾 ∈ CLat ∧ 𝑆 ⊆ 𝐵) → dom 𝑈 = 𝒫 𝐵)
12	5, 11	eleqtrrd 2838	1 ⊢ ((𝐾 ∈ CLat ∧ 𝑆 ⊆ 𝐵) → 𝑆 ∈ dom 𝑈)

Syntax hints:   → wi 4   ∧ wa 395   = wceq 1540   ∈ wcel 2109   ⊆ wss 3931  𝒫 cpw 4580  dom cdm 5659  ‘cfv 6536  Basecbs 17233  Posetcpo 18324  lubclub 18326  glbcglb 18327  CLatccla 18513

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1795  ax-4 1809  ax-5 1910  ax-6 1967  ax-7 2008  ax-8 2111  ax-9 2119  ax-ext 2708  ax-sep 5271  ax-nul 5281

This theorem depends on definitions:  df-bi 207  df-an 396  df-or 848  df-3an 1088  df-tru 1543  df-fal 1553  df-ex 1780  df-sb 2066  df-clab 2715  df-cleq 2728  df-clel 2810  df-ne 2934  df-rab 3421  df-v 3466  df-dif 3934  df-un 3936  df-in 3938  df-ss 3948  df-nul 4314  df-if 4506  df-pw 4582  df-sn 4607  df-pr 4609  df-op 4613  df-uni 4889  df-br 5125  df-dm 5669  df-iota 6489  df-fv 6544  df-clat 18514

This theorem is referenced by:  lublem  18525