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Theorem clatlubcl2 18566
Description: Any subset of the base set has an LUB in a complete lattice. (Contributed by NM, 13-Sep-2018.)
Hypotheses
Ref Expression
clatlubcl.b 𝐵 = (Base‘𝐾)
clatlubcl.u 𝑈 = (lub‘𝐾)
Assertion
Ref Expression
clatlubcl2 ((𝐾 ∈ CLat ∧ 𝑆𝐵) → 𝑆 ∈ dom 𝑈)

Proof of Theorem clatlubcl2
StepHypRef Expression
1 clatlubcl.b . . . . 5 𝐵 = (Base‘𝐾)
21fvexi 6895 . . . 4 𝐵 ∈ V
32elpw2 5304 . . 3 (𝑆 ∈ 𝒫 𝐵𝑆𝐵)
43bilanri 511 . 2 ((𝐾 ∈ CLat ∧ 𝑆𝐵) → 𝑆 ∈ 𝒫 𝐵)
5 clatlubcl.u . . . . 5 𝑈 = (lub‘𝐾)
6 eqid 2762 . . . . 5 (glb‘𝐾) = (glb‘𝐾)
71, 5, 6isclat 18562 . . . 4 (𝐾 ∈ CLat ↔ (𝐾 ∈ Poset ∧ (dom 𝑈 = 𝒫 𝐵 ∧ dom (glb‘𝐾) = 𝒫 𝐵)))
8 simprl 782 . . . 4 ((𝐾 ∈ Poset ∧ (dom 𝑈 = 𝒫 𝐵 ∧ dom (glb‘𝐾) = 𝒫 𝐵)) → dom 𝑈 = 𝒫 𝐵)
97, 8sylbi 220 . . 3 (𝐾 ∈ CLat → dom 𝑈 = 𝒫 𝐵)
109adantr 485 . 2 ((𝐾 ∈ CLat ∧ 𝑆𝐵) → dom 𝑈 = 𝒫 𝐵)
114, 10eleqtrrd 2865 1 ((𝐾 ∈ CLat ∧ 𝑆𝐵) → 𝑆 ∈ dom 𝑈)
Colors of variables:    wff setvar class
This proof depends on syntax axioms:  wi 4  wa 400   = wceq 1569  wcel 2142  wss 3904  𝒫 cpw 4561  dom cdm 5660  cfv 6536  Basecbs 17275  Posetcpo 18369  lubclub 18371  glbcglb 18372  CLatccla 18560
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1824  ax-4 1838  ax-5 1939  ax-6 1996  ax-7 2037  ax-8 2144  ax-9 2152  ax-ext 2734  ax-sep 5256  ax-nul 5268
This proof depends on definitions:  df-bi 210  df-an 401  df-or 861  df-3an 1104  df-tru 1572  df-fal 1582  df-ex 1809  df-sb 2096  df-clab 2741  df-cleq 2754  df-clel 2837  df-ne 2958  df-rab 3416  df-v 3456  df-dif 3907  df-un 3909  df-in 3911  df-ss 3921  df-nul 4286  df-if 4487  df-pw 4563  df-sn 4589  df-pr 4591  df-op 4595  df-uni 4872  df-br 5109  df-dm 5670  df-iota 6492  df-fv 6544  df-clat 18561
This theorem is used by:  lublem  18572
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