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Theorem clatlubcl2 18461
Description: Any subset of the base set has an LUB in a complete lattice. (Contributed by NM, 13-Sep-2018.)
Hypotheses
Ref Expression
clatlubcl.b 𝐵 = (Base‘𝐾)
clatlubcl.u 𝑈 = (lub‘𝐾)
Assertion
Ref Expression
clatlubcl2 ((𝐾 ∈ CLat ∧ 𝑆𝐵) → 𝑆 ∈ dom 𝑈)

Proof of Theorem clatlubcl2
StepHypRef Expression
1 clatlubcl.b . . . . 5 𝐵 = (Base‘𝐾)
21fvexi 6841 . . . 4 𝐵 ∈ V
32elpw2 5262 . . 3 (𝑆 ∈ 𝒫 𝐵𝑆𝐵)
43bilanri 507 . 2 ((𝐾 ∈ CLat ∧ 𝑆𝐵) → 𝑆 ∈ 𝒫 𝐵)
5 clatlubcl.u . . . . 5 𝑈 = (lub‘𝐾)
6 eqid 2739 . . . . 5 (glb‘𝐾) = (glb‘𝐾)
71, 5, 6isclat 18457 . . . 4 (𝐾 ∈ CLat ↔ (𝐾 ∈ Poset ∧ (dom 𝑈 = 𝒫 𝐵 ∧ dom (glb‘𝐾) = 𝒫 𝐵)))
8 simprl 776 . . . 4 ((𝐾 ∈ Poset ∧ (dom 𝑈 = 𝒫 𝐵 ∧ dom (glb‘𝐾) = 𝒫 𝐵)) → dom 𝑈 = 𝒫 𝐵)
97, 8sylbi 218 . . 3 (𝐾 ∈ CLat → dom 𝑈 = 𝒫 𝐵)
109adantr 481 . 2 ((𝐾 ∈ CLat ∧ 𝑆𝐵) → dom 𝑈 = 𝒫 𝐵)
114, 10eleqtrrd 2842 1 ((𝐾 ∈ CLat ∧ 𝑆𝐵) → 𝑆 ∈ dom 𝑈)
Colors of variables: wff setvar class
Syntax hints:  wi 4  wa 396   = wceq 1547  wcel 2119  wss 3883  𝒫 cpw 4529  dom cdm 5618  cfv 6485  Basecbs 17170  Posetcpo 18264  lubclub 18266  glbcglb 18267  CLatccla 18455
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1802  ax-4 1816  ax-5 1917  ax-6 1974  ax-7 2015  ax-8 2121  ax-9 2129  ax-ext 2711  ax-sep 5218  ax-nul 5228
This theorem depends on definitions:  df-bi 208  df-an 397  df-or 854  df-3an 1094  df-tru 1550  df-fal 1560  df-ex 1787  df-sb 2074  df-clab 2718  df-cleq 2731  df-clel 2814  df-ne 2935  df-rab 3392  df-v 3433  df-dif 3886  df-un 3888  df-in 3890  df-ss 3900  df-nul 4262  df-if 4455  df-pw 4531  df-sn 4556  df-pr 4558  df-op 4562  df-uni 4839  df-br 5073  df-dm 5628  df-iota 6441  df-fv 6493  df-clat 18456
This theorem is referenced by:  lublem  18467
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