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Theorem clatlubcl2 18271
Description: Any subset of the base set has an LUB in a complete lattice. (Contributed by NM, 13-Sep-2018.)
Hypotheses
Ref Expression
clatlubcl.b 𝐵 = (Base‘𝐾)
clatlubcl.u 𝑈 = (lub‘𝐾)
Assertion
Ref Expression
clatlubcl2 ((𝐾 ∈ CLat ∧ 𝑆𝐵) → 𝑆 ∈ dom 𝑈)

Proof of Theorem clatlubcl2
StepHypRef Expression
1 clatlubcl.b . . . . . 6 𝐵 = (Base‘𝐾)
21fvexi 6818 . . . . 5 𝐵 ∈ V
32elpw2 5278 . . . 4 (𝑆 ∈ 𝒫 𝐵𝑆𝐵)
43biimpri 227 . . 3 (𝑆𝐵𝑆 ∈ 𝒫 𝐵)
54adantl 483 . 2 ((𝐾 ∈ CLat ∧ 𝑆𝐵) → 𝑆 ∈ 𝒫 𝐵)
6 clatlubcl.u . . . . 5 𝑈 = (lub‘𝐾)
7 eqid 2736 . . . . 5 (glb‘𝐾) = (glb‘𝐾)
81, 6, 7isclat 18267 . . . 4 (𝐾 ∈ CLat ↔ (𝐾 ∈ Poset ∧ (dom 𝑈 = 𝒫 𝐵 ∧ dom (glb‘𝐾) = 𝒫 𝐵)))
9 simprl 769 . . . 4 ((𝐾 ∈ Poset ∧ (dom 𝑈 = 𝒫 𝐵 ∧ dom (glb‘𝐾) = 𝒫 𝐵)) → dom 𝑈 = 𝒫 𝐵)
108, 9sylbi 216 . . 3 (𝐾 ∈ CLat → dom 𝑈 = 𝒫 𝐵)
1110adantr 482 . 2 ((𝐾 ∈ CLat ∧ 𝑆𝐵) → dom 𝑈 = 𝒫 𝐵)
125, 11eleqtrrd 2840 1 ((𝐾 ∈ CLat ∧ 𝑆𝐵) → 𝑆 ∈ dom 𝑈)
Colors of variables: wff setvar class
Syntax hints:  wi 4  wa 397   = wceq 1539  wcel 2104  wss 3892  𝒫 cpw 4539  dom cdm 5600  cfv 6458  Basecbs 16961  Posetcpo 18074  lubclub 18076  glbcglb 18077  CLatccla 18265
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1795  ax-4 1809  ax-5 1911  ax-6 1969  ax-7 2009  ax-8 2106  ax-9 2114  ax-ext 2707  ax-sep 5232  ax-nul 5239
This theorem depends on definitions:  df-bi 206  df-an 398  df-or 846  df-3an 1089  df-tru 1542  df-fal 1552  df-ex 1780  df-sb 2066  df-clab 2714  df-cleq 2728  df-clel 2814  df-ne 2942  df-rab 3306  df-v 3439  df-dif 3895  df-un 3897  df-in 3899  df-ss 3909  df-nul 4263  df-if 4466  df-pw 4541  df-sn 4566  df-pr 4568  df-op 4572  df-uni 4845  df-br 5082  df-dm 5610  df-iota 6410  df-fv 6466  df-clat 18266
This theorem is referenced by:  lublem  18277
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