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Theorem csbcnv 5863
Description: Move class substitution in and out of the converse of a relation. (Contributed by Thierry Arnoux, 8-Feb-2017.) (Revised by NM, 23-Aug-2018.) Remove dependency on ax-sep 5251 and ax-pr 5395. (Revised by Eric Schmidt, 4-Jun-2026.)
Assertion
Ref Expression
csbcnv 𝐴 / 𝑥𝐹 = 𝐴 / 𝑥𝐹

Proof of Theorem csbcnv
Dummy variables 𝑦 𝑧 are mutually distinct and distinct from all other variables.
StepHypRef Expression
1 df-cnv 5660 . . . . 5 𝐴 / 𝑥𝐹 = {⟨𝑦, 𝑧⟩ ∣ 𝑧𝐴 / 𝑥𝐹𝑦}
2 sbcbr 5160 . . . . . 6 ([𝐴 / 𝑥]𝑧𝐹𝑦𝑧𝐴 / 𝑥𝐹𝑦)
32opabbii 5172 . . . . 5 {⟨𝑦, 𝑧⟩ ∣ [𝐴 / 𝑥]𝑧𝐹𝑦} = {⟨𝑦, 𝑧⟩ ∣ 𝑧𝐴 / 𝑥𝐹𝑦}
41, 3eqtr4i 2791 . . . 4 𝐴 / 𝑥𝐹 = {⟨𝑦, 𝑧⟩ ∣ [𝐴 / 𝑥]𝑧𝐹𝑦}
5 csbopabw 5532 . . . 4 (𝐴 ∈ V → 𝐴 / 𝑥{⟨𝑦, 𝑧⟩ ∣ 𝑧𝐹𝑦} = {⟨𝑦, 𝑧⟩ ∣ [𝐴 / 𝑥]𝑧𝐹𝑦})
64, 5eqtr4id 2819 . . 3 (𝐴 ∈ V → 𝐴 / 𝑥𝐹 = 𝐴 / 𝑥{⟨𝑦, 𝑧⟩ ∣ 𝑧𝐹𝑦})
7 df-cnv 5660 . . . 4 𝐹 = {⟨𝑦, 𝑧⟩ ∣ 𝑧𝐹𝑦}
87csbeq2i 3863 . . 3 𝐴 / 𝑥𝐹 = 𝐴 / 𝑥{⟨𝑦, 𝑧⟩ ∣ 𝑧𝐹𝑦}
96, 8eqtr4di 2818 . 2 (𝐴 ∈ V → 𝐴 / 𝑥𝐹 = 𝐴 / 𝑥𝐹)
10 cnv0 5860 . . 3 ∅ = ∅
11 csbprc 4366 . . . 4 𝐴 ∈ V → 𝐴 / 𝑥𝐹 = ∅)
1211cnveqd 5852 . . 3 𝐴 ∈ V → 𝐴 / 𝑥𝐹 = ∅)
13 csbprc 4366 . . 3 𝐴 ∈ V → 𝐴 / 𝑥𝐹 = ∅)
1410, 12, 133eqtr4a 2826 . 2 𝐴 ∈ V → 𝐴 / 𝑥𝐹 = 𝐴 / 𝑥𝐹)
159, 14pm2.61i 184 1 𝐴 / 𝑥𝐹 = 𝐴 / 𝑥𝐹
Colors of variables: wff setvar class
Syntax hints:  ¬ wn 3   = wceq 1563  wcel 2145  Vcvv 3457  [wsbc 3747  csb 3855  c0 4288   class class class wbr 5105  {copab 5167  ccnv 5651
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1818  ax-4 1832  ax-5 1933  ax-6 1990  ax-7 2031  ax-8 2147  ax-9 2155  ax-10 2178  ax-11 2194  ax-12 2215  ax-ext 2737
This theorem depends on definitions:  df-bi 210  df-an 401  df-or 861  df-3an 1103  df-tru 1566  df-fal 1576  df-ex 1803  df-nf 1807  df-sb 2094  df-clab 2744  df-cleq 2757  df-clel 2840  df-nfc 2914  df-rab 3418  df-v 3459  df-sbc 3748  df-csb 3856  df-dif 3910  df-un 3912  df-ss 3924  df-nul 4289  df-if 4484  df-sn 4586  df-pr 4588  df-op 4592  df-br 5106  df-opab 5168  df-cnv 5660
This theorem is referenced by:  csbpredg  6298  esum2dlem  34399
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