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Theorem csbcnv 5856
Description: Move class substitution in and out of the converse of a relation. (Contributed by Thierry Arnoux, 8-Feb-2017.) (Revised by NM, 23-Aug-2018.) Remove dependency on ax-sep 5245 and ax-pr 5389. (Revised by Eric Schmidt, 4-Jun-2026.)
Assertion
Ref Expression
csbcnv 𝐴 / 𝑥𝐹 = 𝐴 / 𝑥𝐹

Proof of Theorem csbcnv
Dummy variables 𝑦 𝑧 are mutually distinct and distinct from all other variables.
StepHypRef Expression
1 df-cnv 5653 . . . . 5 𝐴 / 𝑥𝐹 = {⟨𝑦, 𝑧⟩ ∣ 𝑧𝐴 / 𝑥𝐹𝑦}
2 sbcbr 5154 . . . . . 6 ([𝐴 / 𝑥]𝑧𝐹𝑦𝑧𝐴 / 𝑥𝐹𝑦)
32opabbii 5166 . . . . 5 {⟨𝑦, 𝑧⟩ ∣ [𝐴 / 𝑥]𝑧𝐹𝑦} = {⟨𝑦, 𝑧⟩ ∣ 𝑧𝐴 / 𝑥𝐹𝑦}
41, 3eqtr4i 2787 . . . 4 𝐴 / 𝑥𝐹 = {⟨𝑦, 𝑧⟩ ∣ [𝐴 / 𝑥]𝑧𝐹𝑦}
5 csbopabw 5525 . . . 4 (𝐴 ∈ V → 𝐴 / 𝑥{⟨𝑦, 𝑧⟩ ∣ 𝑧𝐹𝑦} = {⟨𝑦, 𝑧⟩ ∣ [𝐴 / 𝑥]𝑧𝐹𝑦})
64, 5eqtr4id 2815 . . 3 (𝐴 ∈ V → 𝐴 / 𝑥𝐹 = 𝐴 / 𝑥{⟨𝑦, 𝑧⟩ ∣ 𝑧𝐹𝑦})
7 df-cnv 5653 . . . 4 𝐹 = {⟨𝑦, 𝑧⟩ ∣ 𝑧𝐹𝑦}
87csbeq2i 3860 . . 3 𝐴 / 𝑥𝐹 = 𝐴 / 𝑥{⟨𝑦, 𝑧⟩ ∣ 𝑧𝐹𝑦}
96, 8eqtr4di 2814 . 2 (𝐴 ∈ V → 𝐴 / 𝑥𝐹 = 𝐴 / 𝑥𝐹)
10 cnv0 5853 . . 3 ∅ = ∅
11 csbprc 4362 . . . 4 𝐴 ∈ V → 𝐴 / 𝑥𝐹 = ∅)
1211cnveqd 5845 . . 3 𝐴 ∈ V → 𝐴 / 𝑥𝐹 = ∅)
13 csbprc 4362 . . 3 𝐴 ∈ V → 𝐴 / 𝑥𝐹 = ∅)
1410, 12, 133eqtr4a 2822 . 2 𝐴 ∈ V → 𝐴 / 𝑥𝐹 = 𝐴 / 𝑥𝐹)
159, 14pm2.61i 183 1 𝐴 / 𝑥𝐹 = 𝐴 / 𝑥𝐹
Colors of variables: wff setvar class
Syntax hints:  ¬ wn 3   = wceq 1559  wcel 2141  Vcvv 3453  [wsbc 3744  csb 3852  c0 4285   class class class wbr 5099  {copab 5161  ccnv 5644
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1814  ax-4 1828  ax-5 1929  ax-6 1986  ax-7 2027  ax-8 2143  ax-9 2151  ax-10 2174  ax-11 2190  ax-12 2211  ax-ext 2733
This theorem depends on definitions:  df-bi 209  df-an 400  df-or 859  df-3an 1099  df-tru 1562  df-fal 1572  df-ex 1799  df-nf 1803  df-sb 2090  df-clab 2740  df-cleq 2753  df-clel 2836  df-nfc 2910  df-rab 3414  df-v 3455  df-sbc 3745  df-csb 3853  df-dif 3907  df-un 3909  df-ss 3921  df-nul 4286  df-if 4480  df-sn 4582  df-pr 4584  df-op 4588  df-br 5100  df-opab 5162  df-cnv 5653
This theorem is referenced by:  csbpredg  6290  esum2dlem  34350
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