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Theorem csbcnv 5870
Description: Move class substitution in and out of the converse of a relation. (Contributed by Thierry Arnoux, 8-Feb-2017.) (Revised by NM, 23-Aug-2018.) Remove dependency on ax-sep 5255 and ax-pr 5402. (Revised by Eric Schmidt, 4-Jun-2026.)
Assertion
Ref Expression
csbcnv 𝐴 / 𝑥𝐹 = 𝐴 / 𝑥𝐹

Proof of Theorem csbcnv
Dummy variables 𝑦 𝑧 are mutually distinct and distinct from all other variables.
StepHypRef Expression
1 df-cnv 5667 . . . . 5 𝐴 / 𝑥𝐹 = {⟨𝑦, 𝑧⟩ ∣ 𝑧𝐴 / 𝑥𝐹𝑦}
2 sbcbr 5164 . . . . . 6 ([𝐴 / 𝑥]𝑧𝐹𝑦𝑧𝐴 / 𝑥𝐹𝑦)
32opabbii 5176 . . . . 5 {⟨𝑦, 𝑧⟩ ∣ [𝐴 / 𝑥]𝑧𝐹𝑦} = {⟨𝑦, 𝑧⟩ ∣ 𝑧𝐴 / 𝑥𝐹𝑦}
41, 3eqtr4i 2788 . . . 4 𝐴 / 𝑥𝐹 = {⟨𝑦, 𝑧⟩ ∣ [𝐴 / 𝑥]𝑧𝐹𝑦}
5 csbopabw 5539 . . . 4 (𝐴 ∈ V → 𝐴 / 𝑥{⟨𝑦, 𝑧⟩ ∣ 𝑧𝐹𝑦} = {⟨𝑦, 𝑧⟩ ∣ [𝐴 / 𝑥]𝑧𝐹𝑦})
64, 5eqtr4id 2816 . . 3 (𝐴 ∈ V → 𝐴 / 𝑥𝐹 = 𝐴 / 𝑥{⟨𝑦, 𝑧⟩ ∣ 𝑧𝐹𝑦})
7 df-cnv 5667 . . . 4 𝐹 = {⟨𝑦, 𝑧⟩ ∣ 𝑧𝐹𝑦}
87csbeq2i 3858 . . 3 𝐴 / 𝑥𝐹 = 𝐴 / 𝑥{⟨𝑦, 𝑧⟩ ∣ 𝑧𝐹𝑦}
96, 8eqtr4di 2815 . 2 (𝐴 ∈ V → 𝐴 / 𝑥𝐹 = 𝐴 / 𝑥𝐹)
10 cnv0 5867 . . 3 ∅ = ∅
11 csbprc 4370 . . . 4 𝐴 ∈ V → 𝐴 / 𝑥𝐹 = ∅)
1211cnveqd 5859 . . 3 𝐴 ∈ V → 𝐴 / 𝑥𝐹 = ∅)
13 csbprc 4370 . . 3 𝐴 ∈ V → 𝐴 / 𝑥𝐹 = ∅)
1410, 12, 133eqtr4a 2823 . 2 𝐴 ∈ V → 𝐴 / 𝑥𝐹 = 𝐴 / 𝑥𝐹)
159, 14pm2.61i 184 1 𝐴 / 𝑥𝐹 = 𝐴 / 𝑥𝐹
Colors of variables:    wff setvar class
This proof depends on syntax axioms:  ¬ wn 3   = wceq 1570  wcel 2145  Vcvv 3453  [wsbc 3742  csb 3850  c0 4282   class class class wbr 5107  {copab 5171  ccnv 5658
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2147  ax-9 2155  ax-10 2178  ax-11 2194  ax-12 2215  ax-ext 2734
This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3an 1105  df-tru 1573  df-fal 1583  df-ex 1813  df-nf 1817  df-sb 2100  df-clab 2741  df-cleq 2754  df-clel 2837  df-nfc 2911  df-rab 3415  df-v 3455  df-sbc 3743  df-csb 3851  df-dif 3905  df-un 3907  df-ss 3919  df-nul 4283  df-if 4486  df-sn 4588  df-pr 4590  df-op 4594  df-br 5108  df-opab 5172  df-cnv 5667
This theorem is used by:  csbpredg  6309  esum2dlem  34610
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