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| Type | Label | Description |
|---|---|---|
| Statement | ||
| Theorem | reluni 5801* | The union of a class is a relation iff any member is a relation. Exercise 6 of [TakeutiZaring] p. 25 and its converse. (Contributed by NM, 13-Aug-2004.) |
| ⊢ (Rel ∪ 𝐴 ↔ ∀𝑥 ∈ 𝐴 Rel 𝑥) | ||
| Theorem | relint 5802* | The intersection of a class is a relation if at least one member is a relation. (Contributed by NM, 8-Mar-2014.) |
| ⊢ (∃𝑥 ∈ 𝐴 Rel 𝑥 → Rel ∩ 𝐴) | ||
| Theorem | relopabiv 5803* | Alternate proof of relopabi 5805, which is shorter but requires an extra DV condition. (Contributed by BJ, 22-Jul-2023.) (Proof modification is discouraged.) (New usage is discouraged.) |
| ⊢ 𝐴 = {〈𝑥, 𝑦〉 ∣ 𝜑} ⇒ ⊢ Rel 𝐴 | ||
| Theorem | relopabvOLD 5804* | Obsolete version of relopab 5808 as of 26-Oct-2026. (Contributed by SN, 8-Sep-2024.) (Proof modification is discouraged.) (New usage is discouraged.) |
| ⊢ Rel {〈𝑥, 𝑦〉 ∣ 𝜑} | ||
| Theorem | relopabi 5805 | A class of ordered pairs is a relation. (Contributed by Mario Carneiro, 21-Dec-2013.) Remove dependency on ax-sep 5252, ax-nul 5263, ax-pr 5395. (Revised by KP, 25-Oct-2021.) Avoid ax-11 2197 and ax-12 2216. (Revised by SN, 26-Oct-2026.) |
| ⊢ 𝐴 = {〈𝑥, 𝑦〉 ∣ 𝜑} ⇒ ⊢ Rel 𝐴 | ||
| Theorem | relopabiOLD 5806 | Obsolete version of relopabi 5805 as of 26-Oct-2026. (Contributed by Mario Carneiro, 21-Dec-2013.) (Revised by KP, 25-Oct-2021.) (Proof modification is discouraged.) (New usage is discouraged.) |
| ⊢ 𝐴 = {〈𝑥, 𝑦〉 ∣ 𝜑} ⇒ ⊢ Rel 𝐴 | ||
| Theorem | relopabiALT 5807 | Alternate proof of relopabi 5805 (shorter but uses more axioms). (Contributed by Mario Carneiro, 21-Dec-2013.) (Proof modification is discouraged.) (New usage is discouraged.) |
| ⊢ 𝐴 = {〈𝑥, 𝑦〉 ∣ 𝜑} ⇒ ⊢ Rel 𝐴 | ||
| Theorem | relopab 5808 | A class of ordered pairs is a relation. (Contributed by NM, 8-Mar-1995.) Remove disjoint variable conditions. (Revised by Alan Sare, 9-Jul-2013.) (Proof shortened by Mario Carneiro, 21-Dec-2013.) |
| ⊢ Rel {〈𝑥, 𝑦〉 ∣ 𝜑} | ||
| Theorem | mptrel 5809 | The maps-to notation always describes a binary relation. (Contributed by Scott Fenton, 16-Apr-2012.) |
| ⊢ Rel (𝑥 ∈ 𝐴 ↦ 𝐵) | ||
| Theorem | reli 5810 | The identity relation is a relation. Part of Exercise 4.12(p) of [Mendelson] p. 235. (Contributed by NM, 26-Apr-1998.) (Revised by Mario Carneiro, 21-Dec-2013.) |
| ⊢ Rel I | ||
| Theorem | rele 5811 | The membership relation is a relation. (Contributed by NM, 26-Apr-1998.) (Revised by Mario Carneiro, 21-Dec-2013.) |
| ⊢ Rel E | ||
| Theorem | opabid2 5812* | A relation expressed as an ordered pair abstraction. (Contributed by NM, 11-Dec-2006.) |
| ⊢ (Rel 𝐴 → {〈𝑥, 𝑦〉 ∣ 〈𝑥, 𝑦〉 ∈ 𝐴} = 𝐴) | ||
| Theorem | inopab 5813* | Intersection of two ordered pair class abstractions. (Contributed by NM, 30-Sep-2002.) |
| ⊢ ({〈𝑥, 𝑦〉 ∣ 𝜑} ∩ {〈𝑥, 𝑦〉 ∣ 𝜓}) = {〈𝑥, 𝑦〉 ∣ (𝜑 ∧ 𝜓)} | ||
| Theorem | difopab 5814* | Difference of two ordered-pair class abstractions. (Contributed by Stefan O'Rear, 17-Jan-2015.) (Proof shortened by SN, 19-Dec-2024.) |
| ⊢ ({〈𝑥, 𝑦〉 ∣ 𝜑} ∖ {〈𝑥, 𝑦〉 ∣ 𝜓}) = {〈𝑥, 𝑦〉 ∣ (𝜑 ∧ ¬ 𝜓)} | ||
| Theorem | inxp 5815 | Intersection of two Cartesian products. Exercise 9 of [TakeutiZaring] p. 25. (Contributed by NM, 3-Aug-1994.) (Proof shortened by Andrew Salmon, 27-Aug-2011.) Avoid ax-10 2180, ax-12 2216. (Revised by SN, 5-May-2025.) |
| ⊢ ((𝐴 × 𝐵) ∩ (𝐶 × 𝐷)) = ((𝐴 ∩ 𝐶) × (𝐵 ∩ 𝐷)) | ||
| Theorem | xpindi 5816 | Distributive law for Cartesian product over intersection. Theorem 102 of [Suppes] p. 52. (Contributed by NM, 26-Sep-2004.) |
| ⊢ (𝐴 × (𝐵 ∩ 𝐶)) = ((𝐴 × 𝐵) ∩ (𝐴 × 𝐶)) | ||
| Theorem | xpindir 5817 | Distributive law for Cartesian product over intersection. Similar to Theorem 102 of [Suppes] p. 52. (Contributed by NM, 26-Sep-2004.) |
| ⊢ ((𝐴 ∩ 𝐵) × 𝐶) = ((𝐴 × 𝐶) ∩ (𝐵 × 𝐶)) | ||
| Theorem | xpiindi 5818* | Distributive law for Cartesian product over indexed intersection. (Contributed by Mario Carneiro, 21-Mar-2015.) |
| ⊢ (𝐴 ≠ ∅ → (𝐶 × ∩ 𝑥 ∈ 𝐴 𝐵) = ∩ 𝑥 ∈ 𝐴 (𝐶 × 𝐵)) | ||
| Theorem | xpriindi 5819* | Distributive law for Cartesian product over relativized indexed intersection. (Contributed by Mario Carneiro, 21-Mar-2015.) |
| ⊢ (𝐶 × (𝐷 ∩ ∩ 𝑥 ∈ 𝐴 𝐵)) = ((𝐶 × 𝐷) ∩ ∩ 𝑥 ∈ 𝐴 (𝐶 × 𝐵)) | ||
| Theorem | eliunxp 5820* | Membership in a union of Cartesian products. Analogue of elxp 5678 for nonconstant 𝐵(𝑥). (Contributed by Mario Carneiro, 29-Dec-2014.) |
| ⊢ (𝐶 ∈ ∪ 𝑥 ∈ 𝐴 ({𝑥} × 𝐵) ↔ ∃𝑥∃𝑦(𝐶 = 〈𝑥, 𝑦〉 ∧ (𝑥 ∈ 𝐴 ∧ 𝑦 ∈ 𝐵))) | ||
| Theorem | opeliunxp2 5821* | Membership in a union of Cartesian products. (Contributed by Mario Carneiro, 14-Feb-2015.) |
| ⊢ (𝑥 = 𝐶 → 𝐵 = 𝐸) ⇒ ⊢ (〈𝐶, 𝐷〉 ∈ ∪ 𝑥 ∈ 𝐴 ({𝑥} × 𝐵) ↔ (𝐶 ∈ 𝐴 ∧ 𝐷 ∈ 𝐸)) | ||
| Theorem | raliunxp 5822* | Write a double restricted quantification as one universal quantifier. In this version of ralxp 5824, 𝐵(𝑦) is not assumed to be constant. (Contributed by Mario Carneiro, 29-Dec-2014.) |
| ⊢ (𝑥 = 〈𝑦, 𝑧〉 → (𝜑 ↔ 𝜓)) ⇒ ⊢ (∀𝑥 ∈ ∪ 𝑦 ∈ 𝐴 ({𝑦} × 𝐵)𝜑 ↔ ∀𝑦 ∈ 𝐴 ∀𝑧 ∈ 𝐵 𝜓) | ||
| Theorem | rexiunxp 5823* | Write a double restricted quantification as one universal quantifier. In this version of rexxp 5825, 𝐵(𝑦) is not assumed to be constant. (Contributed by Mario Carneiro, 14-Feb-2015.) |
| ⊢ (𝑥 = 〈𝑦, 𝑧〉 → (𝜑 ↔ 𝜓)) ⇒ ⊢ (∃𝑥 ∈ ∪ 𝑦 ∈ 𝐴 ({𝑦} × 𝐵)𝜑 ↔ ∃𝑦 ∈ 𝐴 ∃𝑧 ∈ 𝐵 𝜓) | ||
| Theorem | ralxp 5824* | Universal quantification restricted to a Cartesian product is equivalent to a double restricted quantification. The hypothesis specifies an implicit substitution. (Contributed by NM, 7-Feb-2004.) (Revised by Mario Carneiro, 29-Dec-2014.) |
| ⊢ (𝑥 = 〈𝑦, 𝑧〉 → (𝜑 ↔ 𝜓)) ⇒ ⊢ (∀𝑥 ∈ (𝐴 × 𝐵)𝜑 ↔ ∀𝑦 ∈ 𝐴 ∀𝑧 ∈ 𝐵 𝜓) | ||
| Theorem | rexxp 5825* | Existential quantification restricted to a Cartesian product is equivalent to a double restricted quantification. (Contributed by NM, 11-Nov-1995.) (Revised by Mario Carneiro, 14-Feb-2015.) |
| ⊢ (𝑥 = 〈𝑦, 𝑧〉 → (𝜑 ↔ 𝜓)) ⇒ ⊢ (∃𝑥 ∈ (𝐴 × 𝐵)𝜑 ↔ ∃𝑦 ∈ 𝐴 ∃𝑧 ∈ 𝐵 𝜓) | ||
| Theorem | el2xptp 5826* | A member of a nested Cartesian product is an ordered triple. (Contributed by Alexander van der Vekens, 15-Feb-2018.) |
| ⊢ (𝐴 ∈ ((𝐵 × 𝐶) × 𝐷) ↔ ∃𝑥 ∈ 𝐵 ∃𝑦 ∈ 𝐶 ∃𝑧 ∈ 𝐷 𝐴 = 〈𝑥, 𝑦, 𝑧〉) | ||
| Theorem | exopxfr 5827* | Transfer ordered-pair existence from/to single variable existence. (Contributed by NM, 26-Feb-2014.) (Proof shortened by Mario Carneiro, 31-Aug-2015.) |
| ⊢ (𝑥 = 〈𝑦, 𝑧〉 → (𝜑 ↔ 𝜓)) ⇒ ⊢ (∃𝑥 ∈ (V × V)𝜑 ↔ ∃𝑦∃𝑧𝜓) | ||
| Theorem | exopxfr2 5828* | Transfer ordered-pair existence from/to single variable existence. (Contributed by NM, 26-Feb-2014.) |
| ⊢ (𝑥 = 〈𝑦, 𝑧〉 → (𝜑 ↔ 𝜓)) ⇒ ⊢ (Rel 𝐴 → (∃𝑥 ∈ 𝐴 𝜑 ↔ ∃𝑦∃𝑧(〈𝑦, 𝑧〉 ∈ 𝐴 ∧ 𝜓))) | ||
| Theorem | djussxp 5829* | Disjoint union is a subset of a Cartesian product. (Contributed by Stefan O'Rear, 21-Nov-2014.) |
| ⊢ ∪ 𝑥 ∈ 𝐴 ({𝑥} × 𝐵) ⊆ (𝐴 × V) | ||
| Theorem | ralxpf 5830* | Version of ralxp 5824 with bound-variable hypotheses. (Contributed by NM, 18-Aug-2006.) (Revised by Mario Carneiro, 15-Oct-2016.) |
| ⊢ Ⅎ𝑦𝜑 & ⊢ Ⅎ𝑧𝜑 & ⊢ Ⅎ𝑥𝜓 & ⊢ (𝑥 = 〈𝑦, 𝑧〉 → (𝜑 ↔ 𝜓)) ⇒ ⊢ (∀𝑥 ∈ (𝐴 × 𝐵)𝜑 ↔ ∀𝑦 ∈ 𝐴 ∀𝑧 ∈ 𝐵 𝜓) | ||
| Theorem | rexxpf 5831* | Version of rexxp 5825 with bound-variable hypotheses. (Contributed by NM, 19-Dec-2008.) (Revised by Mario Carneiro, 15-Oct-2016.) |
| ⊢ Ⅎ𝑦𝜑 & ⊢ Ⅎ𝑧𝜑 & ⊢ Ⅎ𝑥𝜓 & ⊢ (𝑥 = 〈𝑦, 𝑧〉 → (𝜑 ↔ 𝜓)) ⇒ ⊢ (∃𝑥 ∈ (𝐴 × 𝐵)𝜑 ↔ ∃𝑦 ∈ 𝐴 ∃𝑧 ∈ 𝐵 𝜓) | ||
| Theorem | iunxpf 5832* | Indexed union on a Cartesian product equals a double indexed union. The hypothesis specifies an implicit substitution. (Contributed by NM, 19-Dec-2008.) |
| ⊢ Ⅎ𝑦𝐶 & ⊢ Ⅎ𝑧𝐶 & ⊢ Ⅎ𝑥𝐷 & ⊢ (𝑥 = 〈𝑦, 𝑧〉 → 𝐶 = 𝐷) ⇒ ⊢ ∪ 𝑥 ∈ (𝐴 × 𝐵)𝐶 = ∪ 𝑦 ∈ 𝐴 ∪ 𝑧 ∈ 𝐵 𝐷 | ||
| Theorem | opabbi2dv 5833* | Deduce equality of a relation and an ordered-pair class abstraction. Compare eqabdv 2897. (Contributed by NM, 24-Feb-2014.) |
| ⊢ Rel 𝐴 & ⊢ (𝜑 → (〈𝑥, 𝑦〉 ∈ 𝐴 ↔ 𝜓)) ⇒ ⊢ (𝜑 → 𝐴 = {〈𝑥, 𝑦〉 ∣ 𝜓}) | ||
| Theorem | relop 5834* | A necessary and sufficient condition for a Kuratowski ordered pair to be a relation. (Contributed by NM, 3-Jun-2008.) A relation is a class of ordered pairs, so the fact that an ordered pair may sometimes be itself a relation is an "accident" depending on the specific encoding of ordered pairs as classes (in set.mm, the Kuratowski encoding). A more meaningful statement is relsnopg 5786, as funsng 6613 is to funop 7177. (New usage is discouraged.) |
| ⊢ 𝐴 ∈ V & ⊢ 𝐵 ∈ V ⇒ ⊢ (Rel 〈𝐴, 𝐵〉 ↔ ∃𝑥∃𝑦(𝐴 = {𝑥} ∧ 𝐵 = {𝑥, 𝑦})) | ||
| Theorem | ideqg 5835 | For sets, the identity relation is the same as equality. (Contributed by NM, 30-Apr-2004.) (Proof shortened by Andrew Salmon, 27-Aug-2011.) |
| ⊢ (𝐵 ∈ 𝑉 → (𝐴 I 𝐵 ↔ 𝐴 = 𝐵)) | ||
| Theorem | ideq 5836 | For sets, the identity relation is the same as equality. (Contributed by NM, 13-Aug-1995.) |
| ⊢ 𝐵 ∈ V ⇒ ⊢ (𝐴 I 𝐵 ↔ 𝐴 = 𝐵) | ||
| Theorem | ididg 5837 | A set is identical to itself. (Contributed by NM, 28-May-2008.) (Proof shortened by Andrew Salmon, 27-Aug-2011.) |
| ⊢ (𝐴 ∈ 𝑉 → 𝐴 I 𝐴) | ||
| Theorem | issetid 5838 | Two ways of expressing set existence. (Contributed by NM, 16-Feb-2008.) (Proof shortened by Andrew Salmon, 27-Aug-2011.) (Revised by Mario Carneiro, 26-Apr-2015.) |
| ⊢ (𝐴 ∈ V ↔ 𝐴 I 𝐴) | ||
| Theorem | coss1 5839 | Subclass theorem for composition. (Contributed by FL, 30-Dec-2010.) |
| ⊢ (𝐴 ⊆ 𝐵 → (𝐴 ∘ 𝐶) ⊆ (𝐵 ∘ 𝐶)) | ||
| Theorem | coss2 5840 | Subclass theorem for composition. (Contributed by NM, 5-Apr-2013.) |
| ⊢ (𝐴 ⊆ 𝐵 → (𝐶 ∘ 𝐴) ⊆ (𝐶 ∘ 𝐵)) | ||
| Theorem | coeq1 5841 | Equality theorem for composition of two classes. (Contributed by NM, 3-Jan-1997.) |
| ⊢ (𝐴 = 𝐵 → (𝐴 ∘ 𝐶) = (𝐵 ∘ 𝐶)) | ||
| Theorem | coeq2 5842 | Equality theorem for composition of two classes. (Contributed by NM, 3-Jan-1997.) |
| ⊢ (𝐴 = 𝐵 → (𝐶 ∘ 𝐴) = (𝐶 ∘ 𝐵)) | ||
| Theorem | coeq1i 5843 | Equality inference for composition of two classes. (Contributed by NM, 16-Nov-2000.) |
| ⊢ 𝐴 = 𝐵 ⇒ ⊢ (𝐴 ∘ 𝐶) = (𝐵 ∘ 𝐶) | ||
| Theorem | coeq2i 5844 | Equality inference for composition of two classes. (Contributed by NM, 16-Nov-2000.) |
| ⊢ 𝐴 = 𝐵 ⇒ ⊢ (𝐶 ∘ 𝐴) = (𝐶 ∘ 𝐵) | ||
| Theorem | coeq1d 5845 | Equality deduction for composition of two classes. (Contributed by NM, 16-Nov-2000.) |
| ⊢ (𝜑 → 𝐴 = 𝐵) ⇒ ⊢ (𝜑 → (𝐴 ∘ 𝐶) = (𝐵 ∘ 𝐶)) | ||
| Theorem | coeq2d 5846 | Equality deduction for composition of two classes. (Contributed by NM, 16-Nov-2000.) |
| ⊢ (𝜑 → 𝐴 = 𝐵) ⇒ ⊢ (𝜑 → (𝐶 ∘ 𝐴) = (𝐶 ∘ 𝐵)) | ||
| Theorem | coeq12i 5847 | Equality inference for composition of two classes. (Contributed by FL, 7-Jun-2012.) |
| ⊢ 𝐴 = 𝐵 & ⊢ 𝐶 = 𝐷 ⇒ ⊢ (𝐴 ∘ 𝐶) = (𝐵 ∘ 𝐷) | ||
| Theorem | coeq12d 5848 | Equality deduction for composition of two classes. (Contributed by FL, 7-Jun-2012.) |
| ⊢ (𝜑 → 𝐴 = 𝐵) & ⊢ (𝜑 → 𝐶 = 𝐷) ⇒ ⊢ (𝜑 → (𝐴 ∘ 𝐶) = (𝐵 ∘ 𝐷)) | ||
| Theorem | nfco 5849 | Bound-variable hypothesis builder for function value. (Contributed by NM, 1-Sep-1999.) |
| ⊢ Ⅎ𝑥𝐴 & ⊢ Ⅎ𝑥𝐵 ⇒ ⊢ Ⅎ𝑥(𝐴 ∘ 𝐵) | ||
| Theorem | brcog 5850* | Ordered pair membership in a composition. (Contributed by NM, 24-Feb-2015.) |
| ⊢ ((𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊) → (𝐴(𝐶 ∘ 𝐷)𝐵 ↔ ∃𝑥(𝐴𝐷𝑥 ∧ 𝑥𝐶𝐵))) | ||
| Theorem | opelco2g 5851* | Ordered pair membership in a composition. (Contributed by NM, 27-Jan-1997.) (Revised by Mario Carneiro, 24-Feb-2015.) |
| ⊢ ((𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊) → (〈𝐴, 𝐵〉 ∈ (𝐶 ∘ 𝐷) ↔ ∃𝑥(〈𝐴, 𝑥〉 ∈ 𝐷 ∧ 〈𝑥, 𝐵〉 ∈ 𝐶))) | ||
| Theorem | brcogw 5852 | Ordered pair membership in a composition. (Contributed by Thierry Arnoux, 14-Jan-2018.) |
| ⊢ (((𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊 ∧ 𝑋 ∈ 𝑍) ∧ (𝐴𝐷𝑋 ∧ 𝑋𝐶𝐵)) → 𝐴(𝐶 ∘ 𝐷)𝐵) | ||
| Theorem | brcoi 5853 | Ordered pair membership in a composition. (Contributed by BJ, 25-Oct-2026.) |
| ⊢ 𝑋 ∈ V & ⊢ 𝑌 ∈ V & ⊢ 𝑍 ∈ V ⇒ ⊢ ((𝑋𝑅𝑌 ∧ 𝑌𝑆𝑍) → 𝑋(𝑆 ∘ 𝑅)𝑍) | ||
| Theorem | eqbrrdva 5854* | Deduction from extensionality principle for relations, given an equivalence only on the relation domain and range. (Contributed by Thierry Arnoux, 28-Nov-2017.) |
| ⊢ (𝜑 → 𝐴 ⊆ (𝐶 × 𝐷)) & ⊢ (𝜑 → 𝐵 ⊆ (𝐶 × 𝐷)) & ⊢ ((𝜑 ∧ 𝑥 ∈ 𝐶 ∧ 𝑦 ∈ 𝐷) → (𝑥𝐴𝑦 ↔ 𝑥𝐵𝑦)) ⇒ ⊢ (𝜑 → 𝐴 = 𝐵) | ||
| Theorem | brco 5855* | Binary relation on a composition. (Contributed by NM, 21-Sep-2004.) (Revised by Mario Carneiro, 24-Feb-2015.) |
| ⊢ 𝐴 ∈ V & ⊢ 𝐵 ∈ V ⇒ ⊢ (𝐴(𝐶 ∘ 𝐷)𝐵 ↔ ∃𝑥(𝐴𝐷𝑥 ∧ 𝑥𝐶𝐵)) | ||
| Theorem | opelco 5856* | Ordered pair membership in a composition. (Contributed by NM, 27-Dec-1996.) (Revised by Mario Carneiro, 24-Feb-2015.) |
| ⊢ 𝐴 ∈ V & ⊢ 𝐵 ∈ V ⇒ ⊢ (〈𝐴, 𝐵〉 ∈ (𝐶 ∘ 𝐷) ↔ ∃𝑥(𝐴𝐷𝑥 ∧ 𝑥𝐶𝐵)) | ||
| Theorem | cnvss 5857 | Subset theorem for converse. (Contributed by NM, 22-Mar-1998.) (Proof shortened by Kyle Wyonch, 27-Apr-2021.) |
| ⊢ (𝐴 ⊆ 𝐵 → ◡𝐴 ⊆ ◡𝐵) | ||
| Theorem | cnveq 5858 | Equality theorem for converse relation. (Contributed by NM, 13-Aug-1995.) |
| ⊢ (𝐴 = 𝐵 → ◡𝐴 = ◡𝐵) | ||
| Theorem | cnveqi 5859 | Equality inference for converse relation. (Contributed by NM, 23-Dec-2008.) |
| ⊢ 𝐴 = 𝐵 ⇒ ⊢ ◡𝐴 = ◡𝐵 | ||
| Theorem | cnveqd 5860 | Equality deduction for converse relation. (Contributed by NM, 6-Dec-2013.) |
| ⊢ (𝜑 → 𝐴 = 𝐵) ⇒ ⊢ (𝜑 → ◡𝐴 = ◡𝐵) | ||
| Theorem | elcnv 5861* | Membership in a converse relation. Equation 5 of [Suppes] p. 62. (Contributed by NM, 24-Mar-1998.) |
| ⊢ (𝐴 ∈ ◡𝑅 ↔ ∃𝑥∃𝑦(𝐴 = 〈𝑥, 𝑦〉 ∧ 𝑦𝑅𝑥)) | ||
| Theorem | elcnv2 5862* | Membership in a converse relation. Equation 5 of [Suppes] p. 62. (Contributed by NM, 11-Aug-2004.) |
| ⊢ (𝐴 ∈ ◡𝑅 ↔ ∃𝑥∃𝑦(𝐴 = 〈𝑥, 𝑦〉 ∧ 〈𝑦, 𝑥〉 ∈ 𝑅)) | ||
| Theorem | nfcnv 5863 | Bound-variable hypothesis builder for converse relation. (Contributed by NM, 31-Jan-2004.) (Revised by Mario Carneiro, 15-Oct-2016.) |
| ⊢ Ⅎ𝑥𝐴 ⇒ ⊢ Ⅎ𝑥◡𝐴 | ||
| Theorem | brcnvg 5864 | The converse of a binary relation swaps arguments. Theorem 11 of [Suppes] p. 61. (Contributed by NM, 10-Oct-2005.) |
| ⊢ ((𝐴 ∈ 𝐶 ∧ 𝐵 ∈ 𝐷) → (𝐴◡𝑅𝐵 ↔ 𝐵𝑅𝐴)) | ||
| Theorem | opelcnvg 5865 | Ordered-pair membership in converse relation. (Contributed by NM, 13-May-1999.) (Proof shortened by Andrew Salmon, 27-Aug-2011.) |
| ⊢ ((𝐴 ∈ 𝐶 ∧ 𝐵 ∈ 𝐷) → (〈𝐴, 𝐵〉 ∈ ◡𝑅 ↔ 〈𝐵, 𝐴〉 ∈ 𝑅)) | ||
| Theorem | opelcnv 5866 | Ordered-pair membership in converse relation. (Contributed by NM, 13-Aug-1995.) |
| ⊢ 𝐴 ∈ V & ⊢ 𝐵 ∈ V ⇒ ⊢ (〈𝐴, 𝐵〉 ∈ ◡𝑅 ↔ 〈𝐵, 𝐴〉 ∈ 𝑅) | ||
| Theorem | brcnv 5867 | The converse of a binary relation swaps arguments. Theorem 11 of [Suppes] p. 61. (Contributed by NM, 13-Aug-1995.) |
| ⊢ 𝐴 ∈ V & ⊢ 𝐵 ∈ V ⇒ ⊢ (𝐴◡𝑅𝐵 ↔ 𝐵𝑅𝐴) | ||
| Theorem | cnv0 5868 | The converse of the empty set. (Contributed by NM, 6-Apr-1998.) Remove dependency on ax-sep 5252, ax-nul 5263, ax-pr 5395. (Revised by KP, 25-Oct-2021.) Avoid ax-12 2216. (Revised by TM, 31-Jan-2026.) |
| ⊢ ◡∅ = ∅ | ||
| Theorem | cnv0OLD 5869 | Obsolete version of cnv0 5868 as of 31-Jan-2026. (Contributed by NM, 6-Apr-1998.) Remove dependency on ax-sep 5252, ax-nul 5263, ax-pr 5395. (Revised by KP, 25-Oct-2021.) (Proof modification is discouraged.) (New usage is discouraged.) |
| ⊢ ◡∅ = ∅ | ||
| Theorem | cnvi 5870 | The converse of the identity relation. Theorem 3.7(ii) of [Monk1] p. 36. (Contributed by NM, 26-Apr-1998.) (Proof shortened by Andrew Salmon, 27-Aug-2011.) |
| ⊢ ◡ I = I | ||
| Theorem | csbcnv 5871 | Move class substitution in and out of the converse of a relation. (Contributed by Thierry Arnoux, 8-Feb-2017.) (Revised by NM, 23-Aug-2018.) Remove dependency on ax-sep 5252 and ax-pr 5395. (Revised by Eric Schmidt, 4-Jun-2026.) |
| ⊢ ◡⦋𝐴 / 𝑥⦌𝐹 = ⦋𝐴 / 𝑥⦌◡𝐹 | ||
| Theorem | csbcnvOLD 5872 | Obsolete version of csbcnv 5871 as of 4-Jun-2026. (Contributed by Thierry Arnoux, 8-Feb-2017.) (Revised by NM, 23-Aug-2018.) (Proof modification is discouraged.) (New usage is discouraged.) |
| ⊢ ◡⦋𝐴 / 𝑥⦌𝐹 = ⦋𝐴 / 𝑥⦌◡𝐹 | ||
| Theorem | csbcnvgALTOLD 5873 | Obsolete version of csbcnv 5871 as of 4-Jun-2026. (Contributed by Thierry Arnoux, 8-Feb-2017.) (New usage is discouraged.) (Proof modification is discouraged.) |
| ⊢ (𝐴 ∈ 𝑉 → ◡⦋𝐴 / 𝑥⦌𝐹 = ⦋𝐴 / 𝑥⦌◡𝐹) | ||
| Theorem | cnvco 5874 | Distributive law of converse over class composition. Theorem 26 of [Suppes] p. 64. (Contributed by NM, 19-Mar-1998.) (Proof shortened by Andrew Salmon, 27-Aug-2011.) |
| ⊢ ◡(𝐴 ∘ 𝐵) = (◡𝐵 ∘ ◡𝐴) | ||
| Theorem | cnvuni 5875* | The converse of a class union is the (indexed) union of the converses of its members. (Contributed by NM, 11-Aug-2004.) |
| ⊢ ◡∪ 𝐴 = ∪ 𝑥 ∈ 𝐴 ◡𝑥 | ||
| Theorem | dfdm3 5876* | Alternate definition of domain. Definition 6.5(1) of [TakeutiZaring] p. 24. (Contributed by NM, 28-Dec-1996.) |
| ⊢ dom 𝐴 = {𝑥 ∣ ∃𝑦〈𝑥, 𝑦〉 ∈ 𝐴} | ||
| Theorem | dfrn2 5877* | Alternate definition of range. Definition 4 of [Suppes] p. 60. (Contributed by NM, 27-Dec-1996.) |
| ⊢ ran 𝐴 = {𝑦 ∣ ∃𝑥 𝑥𝐴𝑦} | ||
| Theorem | dfrn3 5878* | Alternate definition of range. Definition 6.5(2) of [TakeutiZaring] p. 24. (Contributed by NM, 28-Dec-1996.) |
| ⊢ ran 𝐴 = {𝑦 ∣ ∃𝑥〈𝑥, 𝑦〉 ∈ 𝐴} | ||
| Theorem | elrn2g 5879* | Membership in a range. (Contributed by Scott Fenton, 2-Feb-2011.) |
| ⊢ (𝐴 ∈ 𝑉 → (𝐴 ∈ ran 𝐵 ↔ ∃𝑥〈𝑥, 𝐴〉 ∈ 𝐵)) | ||
| Theorem | elrng 5880* | Membership in a range. (Contributed by Scott Fenton, 2-Feb-2011.) |
| ⊢ (𝐴 ∈ 𝑉 → (𝐴 ∈ ran 𝐵 ↔ ∃𝑥 𝑥𝐵𝐴)) | ||
| Theorem | elrn2 5881* | Membership in a range. (Contributed by NM, 10-Jul-1994.) |
| ⊢ 𝐴 ∈ V ⇒ ⊢ (𝐴 ∈ ran 𝐵 ↔ ∃𝑥〈𝑥, 𝐴〉 ∈ 𝐵) | ||
| Theorem | elrn 5882* | Membership in a range. (Contributed by NM, 2-Apr-2004.) |
| ⊢ 𝐴 ∈ V ⇒ ⊢ (𝐴 ∈ ran 𝐵 ↔ ∃𝑥 𝑥𝐵𝐴) | ||
| Theorem | ssrelrn 5883* | If a relation is a subset of a cartesian product, then for each element of the range of the relation there is an element of the first set of the cartesian product which is related to the element of the range by the relation. (Contributed by AV, 24-Oct-2020.) |
| ⊢ ((𝑅 ⊆ (𝐴 × 𝐵) ∧ 𝑌 ∈ ran 𝑅) → ∃𝑎 ∈ 𝐴 𝑎𝑅𝑌) | ||
| Theorem | dfdm4 5884 | Alternate definition of domain. (Contributed by NM, 28-Dec-1996.) |
| ⊢ dom 𝐴 = ran ◡𝐴 | ||
| Theorem | dfdmf 5885* | Definition of domain, using bound-variable hypotheses instead of distinct variable conditions. (Contributed by NM, 8-Mar-1995.) (Revised by Mario Carneiro, 15-Oct-2016.) |
| ⊢ Ⅎ𝑥𝐴 & ⊢ Ⅎ𝑦𝐴 ⇒ ⊢ dom 𝐴 = {𝑥 ∣ ∃𝑦 𝑥𝐴𝑦} | ||
| Theorem | csbdm 5886 | Distribute proper substitution through the domain of a class. (Contributed by Alexander van der Vekens, 23-Jul-2017.) (Revised by NM, 24-Aug-2018.) |
| ⊢ ⦋𝐴 / 𝑥⦌dom 𝐵 = dom ⦋𝐴 / 𝑥⦌𝐵 | ||
| Theorem | eldmg 5887* | Domain membership. Theorem 4 of [Suppes] p. 59. (Contributed by Mario Carneiro, 9-Jul-2014.) |
| ⊢ (𝐴 ∈ 𝑉 → (𝐴 ∈ dom 𝐵 ↔ ∃𝑦 𝐴𝐵𝑦)) | ||
| Theorem | eldm2g 5888* | Domain membership. Theorem 4 of [Suppes] p. 59. (Contributed by NM, 27-Jan-1997.) (Revised by Mario Carneiro, 9-Jul-2014.) |
| ⊢ (𝐴 ∈ 𝑉 → (𝐴 ∈ dom 𝐵 ↔ ∃𝑦〈𝐴, 𝑦〉 ∈ 𝐵)) | ||
| Theorem | eldm 5889* | Membership in a domain. Theorem 4 of [Suppes] p. 59. (Contributed by NM, 2-Apr-2004.) |
| ⊢ 𝐴 ∈ V ⇒ ⊢ (𝐴 ∈ dom 𝐵 ↔ ∃𝑦 𝐴𝐵𝑦) | ||
| Theorem | eldm2 5890* | Membership in a domain. Theorem 4 of [Suppes] p. 59. (Contributed by NM, 1-Aug-1994.) |
| ⊢ 𝐴 ∈ V ⇒ ⊢ (𝐴 ∈ dom 𝐵 ↔ ∃𝑦〈𝐴, 𝑦〉 ∈ 𝐵) | ||
| Theorem | dmss 5891 | Subset theorem for domain. (Contributed by NM, 11-Aug-1994.) |
| ⊢ (𝐴 ⊆ 𝐵 → dom 𝐴 ⊆ dom 𝐵) | ||
| Theorem | dmeq 5892 | Equality theorem for domain. (Contributed by NM, 11-Aug-1994.) |
| ⊢ (𝐴 = 𝐵 → dom 𝐴 = dom 𝐵) | ||
| Theorem | dmeqi 5893 | Equality inference for domain. (Contributed by NM, 4-Mar-2004.) |
| ⊢ 𝐴 = 𝐵 ⇒ ⊢ dom 𝐴 = dom 𝐵 | ||
| Theorem | dmeqd 5894 | Equality deduction for domain. (Contributed by NM, 4-Mar-2004.) |
| ⊢ (𝜑 → 𝐴 = 𝐵) ⇒ ⊢ (𝜑 → dom 𝐴 = dom 𝐵) | ||
| Theorem | opeldmd 5895 | Membership of first of an ordered pair in a domain. Deduction version of opeldm 5896. (Contributed by AV, 11-Mar-2021.) |
| ⊢ (𝜑 → 𝐴 ∈ 𝑉) & ⊢ (𝜑 → 𝐵 ∈ 𝑊) ⇒ ⊢ (𝜑 → (〈𝐴, 𝐵〉 ∈ 𝐶 → 𝐴 ∈ dom 𝐶)) | ||
| Theorem | opeldm 5896 | Membership of first of an ordered pair in a domain. (Contributed by NM, 30-Jul-1995.) |
| ⊢ 𝐴 ∈ V & ⊢ 𝐵 ∈ V ⇒ ⊢ (〈𝐴, 𝐵〉 ∈ 𝐶 → 𝐴 ∈ dom 𝐶) | ||
| Theorem | breldm 5897 | Membership of first of a binary relation in a domain. (Contributed by NM, 30-Jul-1995.) |
| ⊢ 𝐴 ∈ V & ⊢ 𝐵 ∈ V ⇒ ⊢ (𝐴𝑅𝐵 → 𝐴 ∈ dom 𝑅) | ||
| Theorem | breldmg 5898 | Membership of first of a binary relation in a domain. (Contributed by NM, 21-Mar-2007.) |
| ⊢ ((𝐴 ∈ 𝐶 ∧ 𝐵 ∈ 𝐷 ∧ 𝐴𝑅𝐵) → 𝐴 ∈ dom 𝑅) | ||
| Theorem | dmun 5899 | The domain of a union is the union of domains. Exercise 56(a) of [Enderton] p. 65. (Contributed by NM, 12-Aug-1994.) (Proof shortened by Andrew Salmon, 27-Aug-2011.) |
| ⊢ dom (𝐴 ∪ 𝐵) = (dom 𝐴 ∪ dom 𝐵) | ||
| Theorem | dmin 5900 | The domain of an intersection is included in the intersection of the domains. Theorem 6 of [Suppes] p. 60. (Contributed by NM, 15-Sep-2004.) |
| ⊢ dom (𝐴 ∩ 𝐵) ⊆ (dom 𝐴 ∩ dom 𝐵) | ||
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