Theorem csbcow 3871

Description: Composition law for chained substitutions into a class. Version of csbco 3872 with a disjoint variable condition, which does not require ax-13 2407. (Contributed by NM, 10-Nov-2005.) Avoid ax-13 2407. (Revised by GG, 10-Jan-2024.)

Assertion

Ref	Expression
csbcow	⊢ ⦋𝐴 / 𝑦⦌⦋𝑦 / 𝑥⦌𝐵 = ⦋𝐴 / 𝑥⦌𝐵

Distinct variable groups:   𝑥,𝑦   𝑦,𝐵

Allowed substitution hints:   𝐴(𝑥, 𝑦)   𝐵(𝑥)

Proof of Theorem csbcow

Dummy variable 𝑧 is distinct from all other variables.

Step	Hyp	Ref	Expression
1		df-csb 3857	. . . . . 6 ⊢ ⦋𝑦 / 𝑥⦌𝐵 = {𝑧 ∣ [𝑦 / 𝑥]𝑧 ∈ 𝐵}
2	1	eqabri 2908	. . . . 5 ⊢ (𝑧 ∈ ⦋𝑦 / 𝑥⦌𝐵 ↔ [𝑦 / 𝑥]𝑧 ∈ 𝐵)
3	2	sbcbii 3803	. . . 4 ⊢ ([𝐴 / 𝑦]𝑧 ∈ ⦋𝑦 / 𝑥⦌𝐵 ↔ [𝐴 / 𝑦][𝑦 / 𝑥]𝑧 ∈ 𝐵)
4		sbccow 3770	. . . 4 ⊢ ([𝐴 / 𝑦][𝑦 / 𝑥]𝑧 ∈ 𝐵 ↔ [𝐴 / 𝑥]𝑧 ∈ 𝐵)
5	3, 4	bitri 278	. . 3 ⊢ ([𝐴 / 𝑦]𝑧 ∈ ⦋𝑦 / 𝑥⦌𝐵 ↔ [𝐴 / 𝑥]𝑧 ∈ 𝐵)
6	5	abbii 2833	. 2 ⊢ {𝑧 ∣ [𝐴 / 𝑦]𝑧 ∈ ⦋𝑦 / 𝑥⦌𝐵} = {𝑧 ∣ [𝐴 / 𝑥]𝑧 ∈ 𝐵}
7		df-csb 3857	. 2 ⊢ ⦋𝐴 / 𝑦⦌⦋𝑦 / 𝑥⦌𝐵 = {𝑧 ∣ [𝐴 / 𝑦]𝑧 ∈ ⦋𝑦 / 𝑥⦌𝐵}
8		df-csb 3857	. 2 ⊢ ⦋𝐴 / 𝑥⦌𝐵 = {𝑧 ∣ [𝐴 / 𝑥]𝑧 ∈ 𝐵}
9	6, 7, 8	3eqtr4i 2799	1 ⊢ ⦋𝐴 / 𝑦⦌⦋𝑦 / 𝑥⦌𝐵 = ⦋𝐴 / 𝑥⦌𝐵

This proof depends on syntax axioms:   = wceq 1570   ∈ wcel 2146  {cab 2744  [wsbc 3747  ⦋csb 3856

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2148  ax-9 2156  ax-12 2216  ax-ext 2738

This proof depends on definitions:  df-bi 210  df-an 402  df-tru 1573  df-ex 1813  df-sb 2100  df-clab 2745  df-cleq 2758  df-clel 2841  df-v 3460  df-sbc 3748  df-csb 3857

This theorem is used by:  csbnest1g  4400  csbvarg  4402  fvmpocurryd  8276  zsum  15795  fsum  15797  fsumsplitf  15819  zprod  16017  fprod  16021  gsumply1eq  22506  f1od2  33101  bj-csbsn  37580  sbccom2  38815  disjinfi  45951  climinf2mpt  46469  climinfmpt  46470  dvmptmulf  46692