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Theorem intexrab 5315
Description: The intersection of a nonempty restricted class abstraction exists. (Contributed by NM, 21-Oct-2003.)
Assertion
Ref Expression
intexrab (∃𝑥 ∈ 𝐴 𝜑 ↔ ∩ {𝑥 ∈ 𝐴 ∣ 𝜑} ∈ V)

Proof of Theorem intexrab
StepHypRef Expression
1 intexab 5314 . 2 (∃𝑥(𝑥 ∈ 𝐴 ∧ 𝜑) ↔ ∩ {𝑥 ∣ (𝑥 ∈ 𝐴 ∧ 𝜑)} ∈ V)
2 df-rex 3091 . 2 (∃𝑥 ∈ 𝐴 𝜑 ↔ ∃𝑥(𝑥 ∈ 𝐴 ∧ 𝜑))
3 df-rab 3417 . . . 4 {𝑥 ∈ 𝐴 ∣ 𝜑} = {𝑥 ∣ (𝑥 ∈ 𝐴 ∧ 𝜑)}
43inteqi 4916 . . 3 ∩ {𝑥 ∈ 𝐴 ∣ 𝜑} = ∩ {𝑥 ∣ (𝑥 ∈ 𝐴 ∧ 𝜑)}
54eleq1i 2855 . 2 (∩ {𝑥 ∈ 𝐴 ∣ 𝜑} ∈ V ↔ ∩ {𝑥 ∣ (𝑥 ∈ 𝐴 ∧ 𝜑)} ∈ V)
61, 2, 53bitr4i 306 1 (∃𝑥 ∈ 𝐴 𝜑 ↔ ∩ {𝑥 ∈ 𝐴 ∣ 𝜑} ∈ V)
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   ↔ wb 209   ∧ wa 401  ∃wex 1812   ∈ wcel 2147  {cab 2741  ∃wrex 3090  {crab 3416  Vcvv 3454  ∩ cint 4912
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1945  ax-6 2002  ax-7 2043  ax-8 2149  ax-9 2157  ax-10 2180  ax-11 2197  ax-12 2216  ax-ext 2735  ax-sep 5255
This proof depends on definitions:  df-bi 210  df-an 402  df-3an 1105  df-tru 1573  df-fal 1583  df-ex 1813  df-nf 1817  df-sb 2102  df-clab 2742  df-cleq 2755  df-clel 2839  df-ne 2960  df-ral 3081  df-rex 3091  df-rab 3417  df-v 3456  df-ss 3901  df-dif 4050  df-in 4094  df-nul 4282  df-int 4913
This theorem is used by:  onintrab2  7845  rankf  9839  rankvalb  9842  cardf2  10061  tskmval  10963  rgspnval  20915  lspval  21301  aspval  22235  clsval  23410  spanval  31992  fldgenval  33978
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