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Theorem rncoeq 5965
Description: Range of a composition. (Contributed by NM, 19-Mar-1998.)
Assertion
Ref Expression
rncoeq (dom 𝐴 = ran 𝐵 → ran (𝐴𝐵) = ran 𝐴)

Proof of Theorem rncoeq
StepHypRef Expression
1 dmcoeq 5964 . 2 (dom 𝐵 = ran 𝐴 → dom (𝐵𝐴) = dom 𝐴)
2 eqcom 2767 . . 3 (dom 𝐴 = ran 𝐵 ↔ ran 𝐵 = dom 𝐴)
3 df-rn 5666 . . . 4 ran 𝐵 = dom 𝐵
4 dfdm4 5879 . . . 4 dom 𝐴 = ran 𝐴
53, 4eqeq12i 2778 . . 3 (ran 𝐵 = dom 𝐴 ↔ dom 𝐵 = ran 𝐴)
62, 5bitri 278 . 2 (dom 𝐴 = ran 𝐵 ↔ dom 𝐵 = ran 𝐴)
7 df-rn 5666 . . . 4 ran (𝐴𝐵) = dom (𝐴𝐵)
8 cnvco 5869 . . . . 5 (𝐴𝐵) = (𝐵𝐴)
98dmeqi 5888 . . . 4 dom (𝐴𝐵) = dom (𝐵𝐴)
107, 9eqtri 2783 . . 3 ran (𝐴𝐵) = dom (𝐵𝐴)
11 df-rn 5666 . . 3 ran 𝐴 = dom 𝐴
1210, 11eqeq12i 2778 . 2 (ran (𝐴𝐵) = ran 𝐴 ↔ dom (𝐵𝐴) = dom 𝐴)
131, 6, 123imtr4i 295 1 (dom 𝐴 = ran 𝐵 → ran (𝐴𝐵) = ran 𝐴)
Colors of variables:    wff setvar class
This proof depends on syntax axioms:  wi 4   = wceq 1570  ccnv 5654  dom cdm 5655  ran crn 5656  ccom 5659
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2147  ax-9 2155  ax-ext 2732  ax-sep 5251  ax-pr 5398
This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3an 1105  df-tru 1573  df-fal 1583  df-ex 1813  df-sb 2100  df-clab 2739  df-cleq 2752  df-clel 2835  df-rab 3413  df-v 3452  df-dif 3902  df-un 3904  df-in 3906  df-ss 3916  df-nul 4280  df-if 4483  df-sn 4585  df-pr 4587  df-op 4591  df-br 5104  df-opab 5168  df-cnv 5663  df-co 5664  df-dm 5665  df-rn 5666
This theorem is used by:  dfdm2  6279  esplysply  34081  algextdeglem4  34230
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