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Theorem rncoeq 5977
Description: Range of a composition. (Contributed by NM, 19-Mar-1998.)
Assertion
Ref Expression
rncoeq (dom 𝐴 = ran 𝐵 → ran (𝐴 ∘ 𝐵) = ran 𝐴)

Proof of Theorem rncoeq
StepHypRef Expression
1 dmcoeq 5974 . 2 (dom ◡𝐵 = ran ◡𝐴 → dom (◡𝐵 ∘ ◡𝐴) = dom ◡𝐴)
2 eqcom 2770 . . 3 (dom 𝐴 = ran 𝐵 ↔ ran 𝐵 = dom 𝐴)
3 df-rn 5669 . . . 4 ran 𝐵 = dom ◡𝐵
4 dfdm4 5889 . . . 4 dom 𝐴 = ran ◡𝐴
53, 4eqeq12i 2781 . . 3 (ran 𝐵 = dom 𝐴 ↔ dom ◡𝐵 = ran ◡𝐴)
62, 5bitri 278 . 2 (dom 𝐴 = ran 𝐵 ↔ dom ◡𝐵 = ran ◡𝐴)
7 df-rn 5669 . . . 4 ran (𝐴 ∘ 𝐵) = dom ◡(𝐴 ∘ 𝐵)
8 cnvco 5879 . . . . 5 ◡(𝐴 ∘ 𝐵) = (◡𝐵 ∘ ◡𝐴)
98dmeqi 5898 . . . 4 dom ◡(𝐴 ∘ 𝐵) = dom (◡𝐵 ∘ ◡𝐴)
107, 9eqtri 2786 . . 3 ran (𝐴 ∘ 𝐵) = dom (◡𝐵 ∘ ◡𝐴)
11 df-rn 5669 . . 3 ran 𝐴 = dom ◡𝐴
1210, 11eqeq12i 2781 . 2 (ran (𝐴 ∘ 𝐵) = ran 𝐴 ↔ dom (◡𝐵 ∘ ◡𝐴) = dom ◡𝐴)
131, 6, 123imtr4i 295 1 (dom 𝐴 = ran 𝐵 → ran (𝐴 ∘ 𝐵) = ran 𝐴)
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   → wi 4   = wceq 1570  ◡ccnv 5657  dom cdm 5658  ran crn 5659   ∘ ccom 5662
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1945  ax-6 2002  ax-7 2043  ax-8 2149  ax-9 2157  ax-ext 2735  ax-sep 5255  ax-pr 5398
This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3an 1105  df-tru 1573  df-fal 1583  df-ex 1813  df-sb 2102  df-clab 2742  df-cleq 2755  df-clel 2839  df-rab 3417  df-v 3456  df-ss 3901  df-dif 4050  df-in 4094  df-un 4154  df-nul 4282  df-if 4486  df-sn 4589  df-pr 4591  df-op 4841  df-br 5109  df-opab 5174  df-cnv 5666  df-co 5667  df-dm 5668  df-rn 5669
This theorem is used by:  rncocnv2  5978  rncocnv1  5979  esplysply  34314  algextdeglem4  34463
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