Theorem ss2ab 4085

Description: Class abstractions in a subclass relationship. (Contributed by NM, 3-Jul-1994.)

Assertion

Ref	Expression
ss2ab	⊢ ({𝑥 ∣ 𝜑} ⊆ {𝑥 ∣ 𝜓} ↔ ∀𝑥(𝜑 → 𝜓))

Proof of Theorem ss2ab

Step	Hyp	Ref	Expression
1		nfab1 2910	. . 3 ⊢ Ⅎ𝑥{𝑥 ∣ 𝜑}
2		nfab1 2910	. . 3 ⊢ Ⅎ𝑥{𝑥 ∣ 𝜓}
3	1, 2	dfssf 3999	. 2 ⊢ ({𝑥 ∣ 𝜑} ⊆ {𝑥 ∣ 𝜓} ↔ ∀𝑥(𝑥 ∈ {𝑥 ∣ 𝜑} → 𝑥 ∈ {𝑥 ∣ 𝜓}))
4		abid 2721	. . . 4 ⊢ (𝑥 ∈ {𝑥 ∣ 𝜑} ↔ 𝜑)
5		abid 2721	. . . 4 ⊢ (𝑥 ∈ {𝑥 ∣ 𝜓} ↔ 𝜓)
6	4, 5	imbi12i 350	. . 3 ⊢ ((𝑥 ∈ {𝑥 ∣ 𝜑} → 𝑥 ∈ {𝑥 ∣ 𝜓}) ↔ (𝜑 → 𝜓))
7	6	albii 1817	. 2 ⊢ (∀𝑥(𝑥 ∈ {𝑥 ∣ 𝜑} → 𝑥 ∈ {𝑥 ∣ 𝜓}) ↔ ∀𝑥(𝜑 → 𝜓))
8	3, 7	bitri 275	1 ⊢ ({𝑥 ∣ 𝜑} ⊆ {𝑥 ∣ 𝜓} ↔ ∀𝑥(𝜑 → 𝜓))

Syntax hints:   → wi 4   ↔ wb 206  ∀wal 1535   ∈ wcel 2108  {cab 2717   ⊆ wss 3976

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1793  ax-4 1807  ax-5 1909  ax-6 1967  ax-7 2007  ax-8 2110  ax-10 2141  ax-11 2158  ax-12 2178

This theorem depends on definitions:  df-bi 207  df-an 396  df-or 847  df-ex 1778  df-nf 1782  df-sb 2065  df-clab 2718  df-clel 2819  df-nfc 2895  df-ss 3993

This theorem is referenced by:  abss  4086  ssab  4087  ss2rab  4094  rabss2  4101  rabsssn  4690  rabsspr  32529  rabsstp  32530  bj-gabss  36901  clss2lem  43573  ssabf  45002  abssf  45014  cfsetssfset  46971  sprssspr  47355