Theorem ss2ab 4013

Description: Class abstractions in a subclass relationship. (Contributed by NM, 3-Jul-1994.)

Assertion

Ref	Expression
ss2ab	⊢ ({𝑥 ∣ 𝜑} ⊆ {𝑥 ∣ 𝜓} ↔ ∀𝑥(𝜑 → 𝜓))

Proof of Theorem ss2ab

Step	Hyp	Ref	Expression
1		nfab1 2900	. . 3 ⊢ Ⅎ𝑥{𝑥 ∣ 𝜑}
2		nfab1 2900	. . 3 ⊢ Ⅎ𝑥{𝑥 ∣ 𝜓}
3	1, 2	dfssf 3924	. 2 ⊢ ({𝑥 ∣ 𝜑} ⊆ {𝑥 ∣ 𝜓} ↔ ∀𝑥(𝑥 ∈ {𝑥 ∣ 𝜑} → 𝑥 ∈ {𝑥 ∣ 𝜓}))
4		abid 2718	. . . 4 ⊢ (𝑥 ∈ {𝑥 ∣ 𝜑} ↔ 𝜑)
5		abid 2718	. . . 4 ⊢ (𝑥 ∈ {𝑥 ∣ 𝜓} ↔ 𝜓)
6	4, 5	imbi12i 350	. . 3 ⊢ ((𝑥 ∈ {𝑥 ∣ 𝜑} → 𝑥 ∈ {𝑥 ∣ 𝜓}) ↔ (𝜑 → 𝜓))
7	6	albii 1820	. 2 ⊢ (∀𝑥(𝑥 ∈ {𝑥 ∣ 𝜑} → 𝑥 ∈ {𝑥 ∣ 𝜓}) ↔ ∀𝑥(𝜑 → 𝜓))
8	3, 7	bitri 275	1 ⊢ ({𝑥 ∣ 𝜑} ⊆ {𝑥 ∣ 𝜓} ↔ ∀𝑥(𝜑 → 𝜓))

Syntax hints:   → wi 4   ↔ wb 206  ∀wal 1539   ∈ wcel 2113  {cab 2714   ⊆ wss 3901

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1796  ax-4 1810  ax-5 1911  ax-6 1968  ax-7 2009  ax-8 2115  ax-10 2146  ax-11 2162  ax-12 2184

This theorem depends on definitions:  df-bi 207  df-an 396  df-or 848  df-ex 1781  df-nf 1785  df-sb 2068  df-clab 2715  df-clel 2811  df-nfc 2885  df-ss 3918

This theorem is referenced by:  abss  4014  ssab  4015  ss2rab  4021  rabss2OLD  4030  rabsssn  4625  rabsspr  32576  rabsstp  32577  bj-gabss  37136  clss2lem  43848  ssabf  45340  abssf  45352  cfsetssfset  47298  sprssspr  47723