Theorem uhgr3cyclexlem 30764

Description: Lemma for uhgr3cyclex 30765. (Contributed by AV, 12-Feb-2021.)

Hypotheses

Ref	Expression
uhgr3cyclex.v	⊢ 𝑉 = (Vtx‘𝐺)
uhgr3cyclex.e	⊢ 𝐸 = (Edg‘𝐺)
uhgr3cyclex.i	⊢ 𝐼 = (iEdg‘𝐺)

Assertion

Ref	Expression
uhgr3cyclexlem	⊢ ((((𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑉) ∧ 𝐴 ≠ 𝐵) ∧ ((𝐽 ∈ dom 𝐼 ∧ {𝐵, 𝐶} = (𝐼‘𝐽)) ∧ (𝐾 ∈ dom 𝐼 ∧ {𝐶, 𝐴} = (𝐼‘𝐾)))) → 𝐽 ≠ 𝐾)

Proof of Theorem uhgr3cyclexlem

Step	Hyp	Ref	Expression
1		fveq2 6877	. . . . . . . . 9 ⊢ (𝐽 = 𝐾 → (𝐼‘𝐽) = (𝐼‘𝐾))
2	1	eqeq2d 2772	. . . . . . . 8 ⊢ (𝐽 = 𝐾 → ({𝐵, 𝐶} = (𝐼‘𝐽) ↔ {𝐵, 𝐶} = (𝐼‘𝐾)))
3		eqeq2 2773	. . . . . . . . . . . 12 ⊢ ((𝐼‘𝐾) = {𝐶, 𝐴} → ({𝐵, 𝐶} = (𝐼‘𝐾) ↔ {𝐵, 𝐶} = {𝐶, 𝐴}))
4	3	eqcoms 2769	. . . . . . . . . . 11 ⊢ ({𝐶, 𝐴} = (𝐼‘𝐾) → ({𝐵, 𝐶} = (𝐼‘𝐾) ↔ {𝐵, 𝐶} = {𝐶, 𝐴}))
5		prcom 4693	. . . . . . . . . . . . . 14 ⊢ {𝐶, 𝐴} = {𝐴, 𝐶}
6	5	eqeq1i 2766	. . . . . . . . . . . . 13 ⊢ ({𝐶, 𝐴} = {𝐵, 𝐶} ↔ {𝐴, 𝐶} = {𝐵, 𝐶})
7		simpl 488	. . . . . . . . . . . . . . 15 ⊢ ((𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑉) → 𝐴 ∈ 𝑉)
8		simpr 490	. . . . . . . . . . . . . . 15 ⊢ ((𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑉) → 𝐵 ∈ 𝑉)
9	7, 8	preq1b 4806	. . . . . . . . . . . . . 14 ⊢ ((𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑉) → ({𝐴, 𝐶} = {𝐵, 𝐶} ↔ 𝐴 = 𝐵))
10	9	biimpcd 252	. . . . . . . . . . . . 13 ⊢ ({𝐴, 𝐶} = {𝐵, 𝐶} → ((𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑉) → 𝐴 = 𝐵))
11	6, 10	sylbi 220	. . . . . . . . . . . 12 ⊢ ({𝐶, 𝐴} = {𝐵, 𝐶} → ((𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑉) → 𝐴 = 𝐵))
12	11	eqcoms 2769	. . . . . . . . . . 11 ⊢ ({𝐵, 𝐶} = {𝐶, 𝐴} → ((𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑉) → 𝐴 = 𝐵))
13	4, 12	biimtrdi 256	. . . . . . . . . 10 ⊢ ({𝐶, 𝐴} = (𝐼‘𝐾) → ({𝐵, 𝐶} = (𝐼‘𝐾) → ((𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑉) → 𝐴 = 𝐵)))
14	13	adantl 487	. . . . . . . . 9 ⊢ ((𝐾 ∈ dom 𝐼 ∧ {𝐶, 𝐴} = (𝐼‘𝐾)) → ({𝐵, 𝐶} = (𝐼‘𝐾) → ((𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑉) → 𝐴 = 𝐵)))
15	14	com12 33	. . . . . . . 8 ⊢ ({𝐵, 𝐶} = (𝐼‘𝐾) → ((𝐾 ∈ dom 𝐼 ∧ {𝐶, 𝐴} = (𝐼‘𝐾)) → ((𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑉) → 𝐴 = 𝐵)))
16	2, 15	biimtrdi 256	. . . . . . 7 ⊢ (𝐽 = 𝐾 → ({𝐵, 𝐶} = (𝐼‘𝐽) → ((𝐾 ∈ dom 𝐼 ∧ {𝐶, 𝐴} = (𝐼‘𝐾)) → ((𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑉) → 𝐴 = 𝐵))))
17	16	adantld 496	. . . . . 6 ⊢ (𝐽 = 𝐾 → ((𝐽 ∈ dom 𝐼 ∧ {𝐵, 𝐶} = (𝐼‘𝐽)) → ((𝐾 ∈ dom 𝐼 ∧ {𝐶, 𝐴} = (𝐼‘𝐾)) → ((𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑉) → 𝐴 = 𝐵))))
18	17	com14 97	. . . . 5 ⊢ ((𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑉) → ((𝐽 ∈ dom 𝐼 ∧ {𝐵, 𝐶} = (𝐼‘𝐽)) → ((𝐾 ∈ dom 𝐼 ∧ {𝐶, 𝐴} = (𝐼‘𝐾)) → (𝐽 = 𝐾 → 𝐴 = 𝐵))))
19	18	imp32 424	. . . 4 ⊢ (((𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑉) ∧ ((𝐽 ∈ dom 𝐼 ∧ {𝐵, 𝐶} = (𝐼‘𝐽)) ∧ (𝐾 ∈ dom 𝐼 ∧ {𝐶, 𝐴} = (𝐼‘𝐾)))) → (𝐽 = 𝐾 → 𝐴 = 𝐵))
20	19	necon3d 2977	. . 3 ⊢ (((𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑉) ∧ ((𝐽 ∈ dom 𝐼 ∧ {𝐵, 𝐶} = (𝐼‘𝐽)) ∧ (𝐾 ∈ dom 𝐼 ∧ {𝐶, 𝐴} = (𝐼‘𝐾)))) → (𝐴 ≠ 𝐵 → 𝐽 ≠ 𝐾))
21	20	impancom 457	. 2 ⊢ (((𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑉) ∧ 𝐴 ≠ 𝐵) → (((𝐽 ∈ dom 𝐼 ∧ {𝐵, 𝐶} = (𝐼‘𝐽)) ∧ (𝐾 ∈ dom 𝐼 ∧ {𝐶, 𝐴} = (𝐼‘𝐾))) → 𝐽 ≠ 𝐾))
22	21	imp 412	1 ⊢ ((((𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑉) ∧ 𝐴 ≠ 𝐵) ∧ ((𝐽 ∈ dom 𝐼 ∧ {𝐵, 𝐶} = (𝐼‘𝐽)) ∧ (𝐾 ∈ dom 𝐼 ∧ {𝐶, 𝐴} = (𝐼‘𝐾)))) → 𝐽 ≠ 𝐾)

This proof depends on syntax axioms:   → wi 4   ↔ wb 209   ∧ wa 401   = wceq 1570   ∈ wcel 2145   ≠ wne 2956  {cpr 4586  dom cdm 5651  ‘cfv 6531  Vtxcvtx 29556  iEdgciedg 29557  Edgcedg 29607

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2147  ax-9 2155  ax-ext 2733

This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3an 1105  df-tru 1573  df-fal 1583  df-ex 1813  df-sb 2100  df-clab 2740  df-cleq 2753  df-clel 2836  df-ne 2957  df-rab 3414  df-v 3453  df-dif 3902  df-un 3904  df-ss 3916  df-nul 4280  df-if 4483  df-sn 4585  df-pr 4587  df-op 4591  df-uni 4868  df-br 5104  df-iota 6487  df-fv 6539

This theorem is used by:  uhgr3cyclex  30765