Theorem pm5.21ndd 695

Description: Eliminate an antecedent implied by each side of a biconditional, deduction version. (Contributed by Paul Chapman, 21-Nov-2012.) (Revised by Mario Carneiro, 31-Jan-2015.)

Hypotheses

Ref	Expression
pm5.21ndd.1	|- ( ph -> ( ch -> ps ) )
pm5.21ndd.2	|- ( ph -> ( th -> ps ) )
pm5.21ndd.3	|- ( ph -> ( ps -> ( ch <-> th ) ) )

Assertion

Ref	Expression
pm5.21ndd	|- ( ph -> ( ch <-> th ) )

Proof of Theorem pm5.21ndd

Step	Hyp	Ref	Expression
1		pm5.21ndd.1	. . . 4 |- ( ph -> ( ch -> ps ) )
2		pm5.21ndd.3	. . . 4 |- ( ph -> ( ps -> ( ch <-> th ) ) )
3	1, 2	syld 45	. . 3 |- ( ph -> ( ch -> ( ch <-> th ) ) )
4	3	ibd 177	. 2 |- ( ph -> ( ch -> th ) )
5		pm5.21ndd.2	. . . . 5 |- ( ph -> ( th -> ps ) )
6	5, 2	syld 45	. . . 4 |- ( ph -> ( th -> ( ch <-> th ) ) )
7		bicom1 130	. . . 4 |- ( ( ch <-> th ) -> ( th <-> ch ) )
8	6, 7	syl6 33	. . 3 |- ( ph -> ( th -> ( th <-> ch ) ) )
9	8	ibd 177	. 2 |- ( ph -> ( th -> ch ) )
10	4, 9	impbid 128	1 |- ( ph -> ( ch <-> th ) )

Syntax hints:   -> wi 4   <-> wb 104

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 105  ax-ia2 106  ax-ia3 107

This theorem depends on definitions:  df-bi 116

This theorem is referenced by:  pm5.21nd  902  sbcrext  2990  rmob  3005  epelg  4220  eqbrrdva  4717  relbrcnvg  4926  fmptco  5594  ovelrn  5927  brtpos2  6156  elpmg  6566  brdomg  6650  elfi2  6868  genpelvl  7344  genpelvu  7345  fzoval  9956  clim  11082  cnrest2  12444  cnptoprest2  12448  lmss  12454  reopnap  12746  limcdifap  12839