Theorem pm5.21ndd 700

Description: Eliminate an antecedent implied by each side of a biconditional, deduction version. (Contributed by Paul Chapman, 21-Nov-2012.) (Revised by Mario Carneiro, 31-Jan-2015.)

Hypotheses

Ref	Expression
pm5.21ndd.1	|- ( ph -> ( ch -> ps ) )
pm5.21ndd.2	|- ( ph -> ( th -> ps ) )
pm5.21ndd.3	|- ( ph -> ( ps -> ( ch <-> th ) ) )

Assertion

Ref	Expression
pm5.21ndd	|- ( ph -> ( ch <-> th ) )

Proof of Theorem pm5.21ndd

Step	Hyp	Ref	Expression
1		pm5.21ndd.1	. . . 4 |- ( ph -> ( ch -> ps ) )
2		pm5.21ndd.3	. . . 4 |- ( ph -> ( ps -> ( ch <-> th ) ) )
3	1, 2	syld 45	. . 3 |- ( ph -> ( ch -> ( ch <-> th ) ) )
4	3	ibd 177	. 2 |- ( ph -> ( ch -> th ) )
5		pm5.21ndd.2	. . . . 5 |- ( ph -> ( th -> ps ) )
6	5, 2	syld 45	. . . 4 |- ( ph -> ( th -> ( ch <-> th ) ) )
7		bicom1 130	. . . 4 |- ( ( ch <-> th ) -> ( th <-> ch ) )
8	6, 7	syl6 33	. . 3 |- ( ph -> ( th -> ( th <-> ch ) ) )
9	8	ibd 177	. 2 |- ( ph -> ( th -> ch ) )
10	4, 9	impbid 128	1 |- ( ph -> ( ch <-> th ) )

Syntax hints:   -> wi 4   <-> wb 104

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 105  ax-ia2 106  ax-ia3 107

This theorem depends on definitions:  df-bi 116

This theorem is referenced by:  pm5.21nd  911  sbcrext  3032  rmob  3047  epelg  4273  eqbrrdva  4779  relbrcnvg  4988  fmptco  5660  ovelrn  5999  brtpos2  6228  elpmg  6640  brdomg  6724  elfi2  6947  genpelvl  7467  genpelvu  7468  fzoval  10097  clim  11237  pceu  12242  mndpropd  12669  cnrest2  12995  cnptoprest2  12999  lmss  13005  reopnap  13297  limcdifap  13390