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Mirrors > Home > MPE Home > Th. List > Mathboxes > aiota0def | Structured version Visualization version GIF version |
Description: Example for a defined alternate iota being the empty set, i.e., ∀𝑦𝑥 ⊆ 𝑦 is a wff satisfied by a unique value 𝑥, namely 𝑥 = ∅ (the empty set is the one and only set which is a subset of every set). This corresponds to iota0def 44419. (Contributed by AV, 25-Aug-2022.) |
Ref | Expression |
---|---|
aiota0def | ⊢ (℩'𝑥∀𝑦 𝑥 ⊆ 𝑦) = ∅ |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | 0ex 5226 | . 2 ⊢ ∅ ∈ V | |
2 | al0ssb 5227 | . . 3 ⊢ (∀𝑦 𝑥 ⊆ 𝑦 ↔ 𝑥 = ∅) | |
3 | 2 | ax-gen 1799 | . 2 ⊢ ∀𝑥(∀𝑦 𝑥 ⊆ 𝑦 ↔ 𝑥 = ∅) |
4 | eqeq2 2750 | . . . . . 6 ⊢ (𝑧 = ∅ → (𝑥 = 𝑧 ↔ 𝑥 = ∅)) | |
5 | 4 | bibi2d 342 | . . . . 5 ⊢ (𝑧 = ∅ → ((∀𝑦 𝑥 ⊆ 𝑦 ↔ 𝑥 = 𝑧) ↔ (∀𝑦 𝑥 ⊆ 𝑦 ↔ 𝑥 = ∅))) |
6 | 5 | albidv 1924 | . . . 4 ⊢ (𝑧 = ∅ → (∀𝑥(∀𝑦 𝑥 ⊆ 𝑦 ↔ 𝑥 = 𝑧) ↔ ∀𝑥(∀𝑦 𝑥 ⊆ 𝑦 ↔ 𝑥 = ∅))) |
7 | eqeq2 2750 | . . . 4 ⊢ (𝑧 = ∅ → ((℩'𝑥∀𝑦 𝑥 ⊆ 𝑦) = 𝑧 ↔ (℩'𝑥∀𝑦 𝑥 ⊆ 𝑦) = ∅)) | |
8 | 6, 7 | imbi12d 344 | . . 3 ⊢ (𝑧 = ∅ → ((∀𝑥(∀𝑦 𝑥 ⊆ 𝑦 ↔ 𝑥 = 𝑧) → (℩'𝑥∀𝑦 𝑥 ⊆ 𝑦) = 𝑧) ↔ (∀𝑥(∀𝑦 𝑥 ⊆ 𝑦 ↔ 𝑥 = ∅) → (℩'𝑥∀𝑦 𝑥 ⊆ 𝑦) = ∅))) |
9 | aiotaval 44474 | . . 3 ⊢ (∀𝑥(∀𝑦 𝑥 ⊆ 𝑦 ↔ 𝑥 = 𝑧) → (℩'𝑥∀𝑦 𝑥 ⊆ 𝑦) = 𝑧) | |
10 | 8, 9 | vtoclg 3495 | . 2 ⊢ (∅ ∈ V → (∀𝑥(∀𝑦 𝑥 ⊆ 𝑦 ↔ 𝑥 = ∅) → (℩'𝑥∀𝑦 𝑥 ⊆ 𝑦) = ∅)) |
11 | 1, 3, 10 | mp2 9 | 1 ⊢ (℩'𝑥∀𝑦 𝑥 ⊆ 𝑦) = ∅ |
Colors of variables: wff setvar class |
Syntax hints: → wi 4 ↔ wb 205 ∀wal 1537 = wceq 1539 ∈ wcel 2108 Vcvv 3422 ⊆ wss 3883 ∅c0 4253 ℩'caiota 44462 |
This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1799 ax-4 1813 ax-5 1914 ax-6 1972 ax-7 2012 ax-8 2110 ax-9 2118 ax-10 2139 ax-11 2156 ax-12 2173 ax-ext 2709 ax-nul 5225 |
This theorem depends on definitions: df-bi 206 df-an 396 df-or 844 df-tru 1542 df-fal 1552 df-ex 1784 df-nf 1788 df-sb 2069 df-mo 2540 df-eu 2569 df-clab 2716 df-cleq 2730 df-clel 2817 df-nfc 2888 df-ne 2943 df-ral 3068 df-rex 3069 df-rab 3072 df-v 3424 df-dif 3886 df-un 3888 df-in 3890 df-ss 3900 df-nul 4254 df-sn 4559 df-pr 4561 df-uni 4837 df-int 4877 df-iota 6376 df-aiota 44464 |
This theorem is referenced by: (None) |
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