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| Mirrors > Home > MPE Home > Th. List > Mathboxes > cononrel1 | Structured version Visualization version GIF version | ||
| Description: Composition with the non-relation part of a class is empty. (Contributed by RP, 22-Oct-2020.) |
| Ref | Expression |
|---|---|
| cononrel1 | ⊢ ((𝐴 ∖ ◡◡𝐴) ∘ 𝐵) = ∅ |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | cnvco 5877 | . . . 4 ⊢ ◡((𝐴 ∖ ◡◡𝐴) ∘ 𝐵) = (◡𝐵 ∘ ◡(𝐴 ∖ ◡◡𝐴)) | |
| 2 | cnvnonrel 44347 | . . . . 5 ⊢ ◡(𝐴 ∖ ◡◡𝐴) = ∅ | |
| 3 | 2 | coeq2i 5848 | . . . 4 ⊢ (◡𝐵 ∘ ◡(𝐴 ∖ ◡◡𝐴)) = (◡𝐵 ∘ ∅) |
| 4 | co02 6264 | . . . 4 ⊢ (◡𝐵 ∘ ∅) = ∅ | |
| 5 | 1, 3, 4 | 3eqtri 2792 | . . 3 ⊢ ◡((𝐴 ∖ ◡◡𝐴) ∘ 𝐵) = ∅ |
| 6 | 5 | cnveqi 5862 | . 2 ⊢ ◡◡((𝐴 ∖ ◡◡𝐴) ∘ 𝐵) = ◡∅ |
| 7 | relco 6112 | . . 3 ⊢ Rel ((𝐴 ∖ ◡◡𝐴) ∘ 𝐵) | |
| 8 | dfrel2 6189 | . . 3 ⊢ (Rel ((𝐴 ∖ ◡◡𝐴) ∘ 𝐵) ↔ ◡◡((𝐴 ∖ ◡◡𝐴) ∘ 𝐵) = ((𝐴 ∖ ◡◡𝐴) ∘ 𝐵)) | |
| 9 | 7, 8 | mpbi 233 | . 2 ⊢ ◡◡((𝐴 ∖ ◡◡𝐴) ∘ 𝐵) = ((𝐴 ∖ ◡◡𝐴) ∘ 𝐵) |
| 10 | cnv0 5871 | . 2 ⊢ ◡∅ = ∅ | |
| 11 | 6, 9, 10 | 3eqtr3i 2796 | 1 ⊢ ((𝐴 ∖ ◡◡𝐴) ∘ 𝐵) = ∅ |
| Colors of variables: wff setvar class |
| This proof depends on syntax axioms: = wceq 1570 ∖ cdif 3903 ∅c0 4286 ◡ccnv 5662 ∘ ccom 5667 Rel wrel 5668 |
| This proof depends on axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1828 ax-4 1842 ax-5 1943 ax-6 2000 ax-7 2041 ax-8 2148 ax-9 2156 ax-ext 2737 ax-sep 5259 ax-pr 5406 |
| This proof depends on definitions: df-bi 210 df-an 402 df-or 862 df-3an 1105 df-tru 1573 df-fal 1583 df-ex 1813 df-sb 2100 df-clab 2744 df-cleq 2757 df-clel 2840 df-rab 3419 df-v 3459 df-dif 3909 df-un 3911 df-in 3913 df-ss 3923 df-nul 4287 df-if 4490 df-sn 4592 df-pr 4594 df-op 4598 df-br 5112 df-opab 5176 df-xp 5669 df-rel 5670 df-cnv 5671 df-co 5672 df-res 5675 |
| This theorem is used by: cnvtrcl0 44385 |
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