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| Mirrors > Home > MPE Home > Th. List > Mathboxes > cononrel2 | Structured version Visualization version GIF version | ||
| Description: Composition with the non-relation part of a class is empty. (Contributed by RP, 22-Oct-2020.) |
| Ref | Expression |
|---|---|
| cononrel2 | ⊢ (𝐴 ∘ (𝐵 ∖ ◡◡𝐵)) = ∅ |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | cnvco 5866 | . . . 4 ⊢ ◡(𝐴 ∘ (𝐵 ∖ ◡◡𝐵)) = (◡(𝐵 ∖ ◡◡𝐵) ∘ ◡𝐴) | |
| 2 | cnvnonrel 44681 | . . . . 5 ⊢ ◡(𝐵 ∖ ◡◡𝐵) = ∅ | |
| 3 | 2 | coeq1i 5836 | . . . 4 ⊢ (◡(𝐵 ∖ ◡◡𝐵) ∘ ◡𝐴) = (∅ ∘ ◡𝐴) |
| 4 | co01 6263 | . . . 4 ⊢ (∅ ∘ ◡𝐴) = ∅ | |
| 5 | 1, 3, 4 | 3eqtri 2787 | . . 3 ⊢ ◡(𝐴 ∘ (𝐵 ∖ ◡◡𝐵)) = ∅ |
| 6 | 5 | cnveqi 5851 | . 2 ⊢ ◡◡(𝐴 ∘ (𝐵 ∖ ◡◡𝐵)) = ◡∅ |
| 7 | relco 6103 | . . 3 ⊢ Rel (𝐴 ∘ (𝐵 ∖ ◡◡𝐵)) | |
| 8 | dfrel2 6180 | . . 3 ⊢ (Rel (𝐴 ∘ (𝐵 ∖ ◡◡𝐵)) ↔ ◡◡(𝐴 ∘ (𝐵 ∖ ◡◡𝐵)) = (𝐴 ∘ (𝐵 ∖ ◡◡𝐵))) | |
| 9 | 7, 8 | mpbi 233 | . 2 ⊢ ◡◡(𝐴 ∘ (𝐵 ∖ ◡◡𝐵)) = (𝐴 ∘ (𝐵 ∖ ◡◡𝐵)) |
| 10 | cnv0 5860 | . 2 ⊢ ◡∅ = ∅ | |
| 11 | 6, 9, 10 | 3eqtr3i 2791 | 1 ⊢ (𝐴 ∘ (𝐵 ∖ ◡◡𝐵)) = ∅ |
| Colors of variables: wff setvar class |
| This proof depends on syntax axioms: = wceq 1569 ∖ cdif 4045 ∅c0 4278 ◡ccnv 5649 ∘ ccom 5654 Rel wrel 5655 |
| This proof depends on axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1827 ax-4 1841 ax-5 1942 ax-6 1999 ax-7 2040 ax-8 2146 ax-9 2154 ax-ext 2732 ax-sep 5248 ax-pr 5390 |
| This proof depends on definitions: df-bi 210 df-an 402 df-or 862 df-3an 1105 df-tru 1572 df-fal 1582 df-ex 1812 df-sb 2099 df-clab 2739 df-cleq 2752 df-clel 2835 df-rab 3413 df-v 3452 df-ss 3896 df-dif 4047 df-in 4091 df-un 4151 df-nul 4279 df-if 4482 df-sn 4585 df-pr 4587 df-op 4835 df-br 5103 df-opab 5167 df-xp 5656 df-rel 5657 df-cnv 5658 df-co 5659 df-res 5662 |
| This theorem is used by: cnvtrcl0 44719 |
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