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| Mirrors > Home > MPE Home > Th. List > co01 | Structured version Visualization version GIF version | ||
| Description: Composition with the empty set. (Contributed by NM, 24-Apr-2004.) |
| Ref | Expression |
|---|---|
| co01 | ⊢ (∅ ∘ 𝐴) = ∅ |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | cnv0 5869 | . . . 4 ⊢ ◡∅ = ∅ | |
| 2 | cnvco 5875 | . . . . 5 ⊢ ◡(∅ ∘ 𝐴) = (◡𝐴 ∘ ◡∅) | |
| 3 | 1 | coeq2i 5846 | . . . . 5 ⊢ (◡𝐴 ∘ ◡∅) = (◡𝐴 ∘ ∅) |
| 4 | co02 6262 | . . . . 5 ⊢ (◡𝐴 ∘ ∅) = ∅ | |
| 5 | 2, 3, 4 | 3eqtri 2790 | . . . 4 ⊢ ◡(∅ ∘ 𝐴) = ∅ |
| 6 | 1, 5 | eqtr4i 2789 | . . 3 ⊢ ◡∅ = ◡(∅ ∘ 𝐴) |
| 7 | 6 | cnveqi 5860 | . 2 ⊢ ◡◡∅ = ◡◡(∅ ∘ 𝐴) |
| 8 | rel0 5785 | . . 3 ⊢ Rel ∅ | |
| 9 | dfrel2 6187 | . . 3 ⊢ (Rel ∅ ↔ ◡◡∅ = ∅) | |
| 10 | 8, 9 | mpbi 233 | . 2 ⊢ ◡◡∅ = ∅ |
| 11 | relco 6110 | . . 3 ⊢ Rel (∅ ∘ 𝐴) | |
| 12 | dfrel2 6187 | . . 3 ⊢ (Rel (∅ ∘ 𝐴) ↔ ◡◡(∅ ∘ 𝐴) = (∅ ∘ 𝐴)) | |
| 13 | 11, 12 | mpbi 233 | . 2 ⊢ ◡◡(∅ ∘ 𝐴) = (∅ ∘ 𝐴) |
| 14 | 7, 10, 13 | 3eqtr3ri 2795 | 1 ⊢ (∅ ∘ 𝐴) = ∅ |
| Colors of variables: wff setvar class |
| Syntax hints: = wceq 1570 ∅c0 4286 ◡ccnv 5660 ∘ ccom 5665 Rel wrel 5666 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1825 ax-4 1839 ax-5 1940 ax-6 1997 ax-7 2038 ax-8 2145 ax-9 2153 ax-ext 2735 ax-sep 5257 ax-pr 5404 |
| This theorem depends on definitions: df-bi 210 df-an 401 df-or 861 df-3an 1105 df-tru 1573 df-fal 1583 df-ex 1810 df-sb 2097 df-clab 2742 df-cleq 2755 df-clel 2838 df-rab 3417 df-v 3457 df-dif 3908 df-un 3910 df-in 3912 df-ss 3922 df-nul 4287 df-if 4488 df-sn 4590 df-pr 4592 df-op 4596 df-br 5110 df-opab 5174 df-xp 5667 df-rel 5668 df-cnv 5669 df-co 5670 |
| This theorem is referenced by: xpcoid 6291 0trrel 15014 relexpsucrd 15066 relexpaddd 15087 gsumval3 19972 utop2nei 24407 cononrel2 44321 setc1ocofval 50272 |
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