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Theorem co01 6265
Description: Composition with the empty set. (Contributed by NM, 24-Apr-2004.)
Assertion
Ref Expression
co01 (∅ ∘ 𝐴) = ∅

Proof of Theorem co01
StepHypRef Expression
1 cnv0 5871 . . . 4 ∅ = ∅
2 cnvco 5877 . . . . 5 (∅ ∘ 𝐴) = (𝐴∅)
31coeq2i 5848 . . . . 5 (𝐴∅) = (𝐴 ∘ ∅)
4 co02 6264 . . . . 5 (𝐴 ∘ ∅) = ∅
52, 3, 43eqtri 2792 . . . 4 (∅ ∘ 𝐴) = ∅
61, 5eqtr4i 2791 . . 3 ∅ = (∅ ∘ 𝐴)
76cnveqi 5862 . 2 ∅ = (∅ ∘ 𝐴)
8 rel0 5787 . . 3 Rel ∅
9 dfrel2 6189 . . 3 (Rel ∅ ↔ ∅ = ∅)
108, 9mpbi 233 . 2 ∅ = ∅
11 relco 6112 . . 3 Rel (∅ ∘ 𝐴)
12 dfrel2 6189 . . 3 (Rel (∅ ∘ 𝐴) ↔ (∅ ∘ 𝐴) = (∅ ∘ 𝐴))
1311, 12mpbi 233 . 2 (∅ ∘ 𝐴) = (∅ ∘ 𝐴)
147, 10, 133eqtr3ri 2797 1 (∅ ∘ 𝐴) = ∅
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   = wceq 1570  c0 4286  ccnv 5662  ccom 5667  Rel wrel 5668
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2148  ax-9 2156  ax-ext 2737  ax-sep 5259  ax-pr 5406
This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3an 1105  df-tru 1573  df-fal 1583  df-ex 1813  df-sb 2100  df-clab 2744  df-cleq 2757  df-clel 2840  df-rab 3419  df-v 3459  df-dif 3909  df-un 3911  df-in 3913  df-ss 3923  df-nul 4287  df-if 4490  df-sn 4592  df-pr 4594  df-op 4598  df-br 5112  df-opab 5176  df-xp 5669  df-rel 5670  df-cnv 5671  df-co 5672
This theorem is used by:  xpcoid  6295  0trrel  15042  relexpsucrd  15094  relexpaddd  15115  gsumval3  20021  utop2nei  24458  cononrel2  44379  setc1ocofval  50329
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