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| Mirrors > Home > MPE Home > Th. List > co01 | Structured version Visualization version GIF version | ||
| Description: Composition with the empty set. (Contributed by NM, 24-Apr-2004.) |
| Ref | Expression |
|---|---|
| co01 | ⊢ (∅ ∘ 𝐴) = ∅ |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | cnv0 6090 | . . . 4 ⊢ ◡∅ = ∅ | |
| 2 | cnvco 5827 | . . . . 5 ⊢ ◡(∅ ∘ 𝐴) = (◡𝐴 ∘ ◡∅) | |
| 3 | 1 | coeq2i 5802 | . . . . 5 ⊢ (◡𝐴 ∘ ◡∅) = (◡𝐴 ∘ ∅) |
| 4 | co02 6212 | . . . . 5 ⊢ (◡𝐴 ∘ ∅) = ∅ | |
| 5 | 2, 3, 4 | 3eqtri 2766 | . . . 4 ⊢ ◡(∅ ∘ 𝐴) = ∅ |
| 6 | 1, 5 | eqtr4i 2765 | . . 3 ⊢ ◡∅ = ◡(∅ ∘ 𝐴) |
| 7 | 6 | cnveqi 5816 | . 2 ⊢ ◡◡∅ = ◡◡(∅ ∘ 𝐴) |
| 8 | rel0 5742 | . . 3 ⊢ Rel ∅ | |
| 9 | dfrel2 6140 | . . 3 ⊢ (Rel ∅ ↔ ◡◡∅ = ∅) | |
| 10 | 8, 9 | mpbi 231 | . 2 ⊢ ◡◡∅ = ∅ |
| 11 | relco 6060 | . . 3 ⊢ Rel (∅ ∘ 𝐴) | |
| 12 | dfrel2 6140 | . . 3 ⊢ (Rel (∅ ∘ 𝐴) ↔ ◡◡(∅ ∘ 𝐴) = (∅ ∘ 𝐴)) | |
| 13 | 11, 12 | mpbi 231 | . 2 ⊢ ◡◡(∅ ∘ 𝐴) = (∅ ∘ 𝐴) |
| 14 | 7, 10, 13 | 3eqtr3ri 2771 | 1 ⊢ (∅ ∘ 𝐴) = ∅ |
| Colors of variables: wff setvar class |
| Syntax hints: = wceq 1547 ∅c0 4261 ◡ccnv 5617 ∘ ccom 5622 Rel wrel 5623 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-3 8 ax-gen 1802 ax-4 1816 ax-5 1917 ax-6 1974 ax-7 2015 ax-8 2121 ax-9 2129 ax-ext 2711 ax-sep 5218 ax-pr 5362 |
| This theorem depends on definitions: df-bi 208 df-an 397 df-or 854 df-3an 1094 df-tru 1550 df-fal 1560 df-ex 1787 df-sb 2074 df-clab 2718 df-cleq 2731 df-clel 2814 df-rab 3392 df-v 3433 df-dif 3886 df-un 3888 df-in 3890 df-ss 3900 df-nul 4262 df-if 4455 df-sn 4556 df-pr 4558 df-op 4562 df-br 5073 df-opab 5135 df-xp 5624 df-rel 5625 df-cnv 5626 df-co 5627 |
| This theorem is referenced by: xpcoid 6241 0trrel 14934 relexpsucrd 14986 relexpaddd 15007 gsumval3 19873 utop2nei 24233 cononrel2 44039 setc1ocofval 49984 |
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