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Theorem co01 6258
Description: Composition with the empty set. (Contributed by NM, 24-Apr-2004.)
Assertion
Ref Expression
co01 (∅ ∘ 𝐴) = ∅

Proof of Theorem co01
StepHypRef Expression
1 cnv0 5863 . . . 4 ∅ = ∅
2 cnvco 5869 . . . . 5 (∅ ∘ 𝐴) = (𝐴∅)
31coeq2i 5840 . . . . 5 (𝐴∅) = (𝐴 ∘ ∅)
4 co02 6257 . . . . 5 (𝐴 ∘ ∅) = ∅
52, 3, 43eqtri 2787 . . . 4 (∅ ∘ 𝐴) = ∅
61, 5eqtr4i 2786 . . 3 ∅ = (∅ ∘ 𝐴)
76cnveqi 5854 . 2 ∅ = (∅ ∘ 𝐴)
8 rel0 5779 . . 3 Rel ∅
9 dfrel2 6182 . . 3 (Rel ∅ ↔ ∅ = ∅)
108, 9mpbi 233 . 2 ∅ = ∅
11 relco 6104 . . 3 Rel (∅ ∘ 𝐴)
12 dfrel2 6182 . . 3 (Rel (∅ ∘ 𝐴) ↔ (∅ ∘ 𝐴) = (∅ ∘ 𝐴))
1311, 12mpbi 233 . 2 (∅ ∘ 𝐴) = (∅ ∘ 𝐴)
147, 10, 133eqtr3ri 2792 1 (∅ ∘ 𝐴) = ∅
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   = wceq 1570  c0 4279  ccnv 5654  ccom 5659  Rel wrel 5660
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2147  ax-9 2155  ax-ext 2732  ax-sep 5251  ax-pr 5398
This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3an 1105  df-tru 1573  df-fal 1583  df-ex 1813  df-sb 2100  df-clab 2739  df-cleq 2752  df-clel 2835  df-rab 3413  df-v 3452  df-dif 3902  df-un 3904  df-in 3906  df-ss 3916  df-nul 4280  df-if 4483  df-sn 4585  df-pr 4587  df-op 4591  df-br 5104  df-opab 5168  df-xp 5661  df-rel 5662  df-cnv 5663  df-co 5664
This theorem is used by:  xpcoid  6288  0trrel  15054  relexpsucrd  15106  relexpaddd  15127  gsumval3  20034  utop2nei  24476  cononrel2  44435  setc1ocofval  50420
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