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Theorem efgcpbllema 19825
Description: Lemma for efgrelex 19822. Define an auxiliary equivalence relation 𝐿 such that 𝐴𝐿𝐵 if there are sequences from 𝐴 to 𝐵 passing through the same reduced word. (Contributed by Mario Carneiro, 1-Oct-2015.)
Hypotheses
Ref Expression
efgval.w 𝑊 = ( I ‘Word (𝐼 × 2o))
efgval.r = ( ~FG𝐼)
efgval2.m 𝑀 = (𝑦𝐼, 𝑧 ∈ 2o ↦ ⟨𝑦, (1o𝑧)⟩)
efgval2.t 𝑇 = (𝑣𝑊 ↦ (𝑛 ∈ (0...(♯‘𝑣)), 𝑤 ∈ (𝐼 × 2o) ↦ (𝑣 splice ⟨𝑛, 𝑛, ⟨“𝑤(𝑀𝑤)”⟩⟩)))
efgred.d 𝐷 = (𝑊 𝑥𝑊 ran (𝑇𝑥))
efgred.s 𝑆 = (𝑚 ∈ {𝑡 ∈ (Word 𝑊 ∖ {∅}) ∣ ((𝑡‘0) ∈ 𝐷 ∧ ∀𝑘 ∈ (1..^(♯‘𝑡))(𝑡𝑘) ∈ ran (𝑇‘(𝑡‘(𝑘 − 1))))} ↦ (𝑚‘((♯‘𝑚) − 1)))
efgcpbllem.1 𝐿 = {⟨𝑖, 𝑗⟩ ∣ ({𝑖, 𝑗} ⊆ 𝑊 ∧ ((𝐴 ++ 𝑖) ++ 𝐵) ((𝐴 ++ 𝑗) ++ 𝐵))}
Assertion
Ref Expression
efgcpbllema (𝑋𝐿𝑌 ↔ (𝑋𝑊𝑌𝑊 ∧ ((𝐴 ++ 𝑋) ++ 𝐵) ((𝐴 ++ 𝑌) ++ 𝐵)))
Distinct variable groups:   𝑖,𝑗,𝐴   𝑦,𝑧   𝑡,𝑛,𝑣,𝑤,𝑦,𝑧   𝑖,𝑚,𝑛,𝑡,𝑣,𝑤,𝑥,𝑀,𝑗   𝑖,𝑘,𝑇,𝑗,𝑚,𝑡,𝑥   𝑖,𝑋,𝑗   𝑦,𝑖,𝑧,𝑊,𝑗   𝑘,𝑛,𝑣,𝑤,𝑦,𝑧,𝑊,𝑚,𝑡,𝑥   ,𝑖,𝑗,𝑚,𝑡,𝑥,𝑦,𝑧   𝐵,𝑖,𝑗   𝑆,𝑖,𝑗   𝑖,𝑌,𝑗   𝑖,𝐼,𝑗,𝑚,𝑛,𝑡,𝑣,𝑤,𝑥,𝑦,𝑧   𝐷,𝑖,𝑗,𝑚,𝑡
Allowed substitution hints:   𝐴(𝑥,𝑦,𝑧,𝑤,𝑣,𝑡,𝑘,𝑚,𝑛)   𝐵(𝑥,𝑦,𝑧,𝑤,𝑣,𝑡,𝑘,𝑚,𝑛)   𝐷(𝑥,𝑦,𝑧,𝑤,𝑣,𝑘,𝑛)   (𝑤,𝑣,𝑘,𝑛)   𝑆(𝑥,𝑦,𝑧,𝑤,𝑣,𝑡,𝑘,𝑚,𝑛)   𝑇(𝑦,𝑧,𝑤,𝑣,𝑛)   𝐼(𝑘)   𝐿(𝑥,𝑦,𝑧,𝑤,𝑣,𝑡,𝑖,𝑗,𝑘,𝑚,𝑛)   𝑀(𝑦,𝑧,𝑘)   𝑋(𝑥,𝑦,𝑧,𝑤,𝑣,𝑡,𝑘,𝑚,𝑛)   𝑌(𝑥,𝑦,𝑧,𝑤,𝑣,𝑡,𝑘,𝑚,𝑛)

Proof of Theorem efgcpbllema
StepHypRef Expression
1 oveq2 7420 . . . . 5 (𝑖 = 𝑋 → (𝐴 ++ 𝑖) = (𝐴 ++ 𝑋))
21oveq1d 7427 . . . 4 (𝑖 = 𝑋 → ((𝐴 ++ 𝑖) ++ 𝐵) = ((𝐴 ++ 𝑋) ++ 𝐵))
3 oveq2 7420 . . . . 5 (𝑗 = 𝑌 → (𝐴 ++ 𝑗) = (𝐴 ++ 𝑌))
43oveq1d 7427 . . . 4 (𝑗 = 𝑌 → ((𝐴 ++ 𝑗) ++ 𝐵) = ((𝐴 ++ 𝑌) ++ 𝐵))
52, 4breqan12d 5126 . . 3 ((𝑖 = 𝑋𝑗 = 𝑌) → (((𝐴 ++ 𝑖) ++ 𝐵) ((𝐴 ++ 𝑗) ++ 𝐵) ↔ ((𝐴 ++ 𝑋) ++ 𝐵) ((𝐴 ++ 𝑌) ++ 𝐵)))
6 efgcpbllem.1 . . . 4 𝐿 = {⟨𝑖, 𝑗⟩ ∣ ({𝑖, 𝑗} ⊆ 𝑊 ∧ ((𝐴 ++ 𝑖) ++ 𝐵) ((𝐴 ++ 𝑗) ++ 𝐵))}
7 vex 3459 . . . . . . 7 𝑖 ∈ V
8 vex 3459 . . . . . . 7 𝑗 ∈ V
97, 8prss 4787 . . . . . 6 ((𝑖𝑊𝑗𝑊) ↔ {𝑖, 𝑗} ⊆ 𝑊)
109anbi1i 635 . . . . 5 (((𝑖𝑊𝑗𝑊) ∧ ((𝐴 ++ 𝑖) ++ 𝐵) ((𝐴 ++ 𝑗) ++ 𝐵)) ↔ ({𝑖, 𝑗} ⊆ 𝑊 ∧ ((𝐴 ++ 𝑖) ++ 𝐵) ((𝐴 ++ 𝑗) ++ 𝐵)))
1110opabbii 5179 . . . 4 {⟨𝑖, 𝑗⟩ ∣ ((𝑖𝑊𝑗𝑊) ∧ ((𝐴 ++ 𝑖) ++ 𝐵) ((𝐴 ++ 𝑗) ++ 𝐵))} = {⟨𝑖, 𝑗⟩ ∣ ({𝑖, 𝑗} ⊆ 𝑊 ∧ ((𝐴 ++ 𝑖) ++ 𝐵) ((𝐴 ++ 𝑗) ++ 𝐵))}
126, 11eqtr4i 2789 . . 3 𝐿 = {⟨𝑖, 𝑗⟩ ∣ ((𝑖𝑊𝑗𝑊) ∧ ((𝐴 ++ 𝑖) ++ 𝐵) ((𝐴 ++ 𝑗) ++ 𝐵))}
135, 12brab2a 5756 . 2 (𝑋𝐿𝑌 ↔ ((𝑋𝑊𝑌𝑊) ∧ ((𝐴 ++ 𝑋) ++ 𝐵) ((𝐴 ++ 𝑌) ++ 𝐵)))
14 df-3an 1105 . 2 ((𝑋𝑊𝑌𝑊 ∧ ((𝐴 ++ 𝑋) ++ 𝐵) ((𝐴 ++ 𝑌) ++ 𝐵)) ↔ ((𝑋𝑊𝑌𝑊) ∧ ((𝐴 ++ 𝑋) ++ 𝐵) ((𝐴 ++ 𝑌) ++ 𝐵)))
1513, 14bitr4i 281 1 (𝑋𝐿𝑌 ↔ (𝑋𝑊𝑌𝑊 ∧ ((𝐴 ++ 𝑋) ++ 𝐵) ((𝐴 ++ 𝑌) ++ 𝐵)))
Colors of variables: wff setvar class
Syntax hints:  wb 209  wa 400  w3a 1103   = wceq 1570  wcel 2143  wral 3079  {crab 3416  cdif 3903  wss 3906  c0 4287  {csn 4590  {cpr 4592  cop 4596  cotp 4598   ciun 4957   class class class wbr 5110  {copab 5174  cmpt 5193   I cid 5557   × cxp 5661  ran crn 5664  cfv 6538  (class class class)co 7412  cmpo 7414  1oc1o 8447  2oc2o 8448  0cc0 11101  1c1 11102  cmin 11442  ...cfz 13536  ..^cfzo 13684  chash 14368  Word cword 14552   ++ cconcat 14609   splice csplice 14788  ⟨“cs2 14880   ~FG cefg 19777
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1825  ax-4 1839  ax-5 1940  ax-6 1997  ax-7 2038  ax-8 2145  ax-9 2153  ax-ext 2735  ax-sep 5258  ax-pr 5406
This theorem depends on definitions:  df-bi 210  df-an 401  df-or 861  df-3an 1105  df-tru 1573  df-fal 1583  df-ex 1810  df-sb 2097  df-clab 2742  df-cleq 2755  df-clel 2838  df-ral 3080  df-rex 3090  df-rab 3417  df-v 3457  df-dif 3909  df-un 3911  df-in 3913  df-ss 3923  df-nul 4288  df-if 4489  df-sn 4591  df-pr 4593  df-op 4597  df-uni 4874  df-br 5111  df-opab 5175  df-xp 5669  df-iota 6494  df-fv 6546  df-ov 7415
This theorem is referenced by:  efgcpbllemb  19826  efgcpbl  19827
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