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Theorem efgcpbllema 19812
Description: Lemma for efgrelex 19809. Define an auxiliary equivalence relation 𝐿 such that 𝐴𝐿𝐵 if there are sequences from 𝐴 to 𝐵 passing through the same reduced word. (Contributed by Mario Carneiro, 1-Oct-2015.)
Hypotheses
Ref Expression
efgval.w 𝑊 = ( I ‘Word (𝐼 × 2o))
efgval.r = ( ~FG𝐼)
efgval2.m 𝑀 = (𝑦𝐼, 𝑧 ∈ 2o ↦ ⟨𝑦, (1o𝑧)⟩)
efgval2.t 𝑇 = (𝑣𝑊 ↦ (𝑛 ∈ (0...(♯‘𝑣)), 𝑤 ∈ (𝐼 × 2o) ↦ (𝑣 splice ⟨𝑛, 𝑛, ⟨“𝑤(𝑀𝑤)”⟩⟩)))
efgred.d 𝐷 = (𝑊 𝑥𝑊 ran (𝑇𝑥))
efgred.s 𝑆 = (𝑚 ∈ {𝑡 ∈ (Word 𝑊 ∖ {∅}) ∣ ((𝑡‘0) ∈ 𝐷 ∧ ∀𝑘 ∈ (1..^(♯‘𝑡))(𝑡𝑘) ∈ ran (𝑇‘(𝑡‘(𝑘 − 1))))} ↦ (𝑚‘((♯‘𝑚) − 1)))
efgcpbllem.1 𝐿 = {⟨𝑖, 𝑗⟩ ∣ ({𝑖, 𝑗} ⊆ 𝑊 ∧ ((𝐴 ++ 𝑖) ++ 𝐵) ((𝐴 ++ 𝑗) ++ 𝐵))}
Assertion
Ref Expression
efgcpbllema (𝑋𝐿𝑌 ↔ (𝑋𝑊𝑌𝑊 ∧ ((𝐴 ++ 𝑋) ++ 𝐵) ((𝐴 ++ 𝑌) ++ 𝐵)))
Distinct variable groups:   𝑖,𝑗,𝐴   𝑦,𝑧   𝑡,𝑛,𝑣,𝑤,𝑦,𝑧   𝑖,𝑚,𝑛,𝑡,𝑣,𝑤,𝑥,𝑀,𝑗   𝑖,𝑘,𝑇,𝑗,𝑚,𝑡,𝑥   𝑖,𝑋,𝑗   𝑦,𝑖,𝑧,𝑊,𝑗   𝑘,𝑛,𝑣,𝑤,𝑦,𝑧,𝑊,𝑚,𝑡,𝑥   ,𝑖,𝑗,𝑚,𝑡,𝑥,𝑦,𝑧   𝐵,𝑖,𝑗   𝑆,𝑖,𝑗   𝑖,𝑌,𝑗   𝑖,𝐼,𝑗,𝑚,𝑛,𝑡,𝑣,𝑤,𝑥,𝑦,𝑧   𝐷,𝑖,𝑗,𝑚,𝑡
Allowed substitution hints:   𝐴(𝑥,𝑦,𝑧,𝑤,𝑣,𝑡,𝑘,𝑚,𝑛)   𝐵(𝑥,𝑦,𝑧,𝑤,𝑣,𝑡,𝑘,𝑚,𝑛)   𝐷(𝑥,𝑦,𝑧,𝑤,𝑣,𝑘,𝑛)   (𝑤,𝑣,𝑘,𝑛)   𝑆(𝑥,𝑦,𝑧,𝑤,𝑣,𝑡,𝑘,𝑚,𝑛)   𝑇(𝑦,𝑧,𝑤,𝑣,𝑛)   𝐼(𝑘)   𝐿(𝑥,𝑦,𝑧,𝑤,𝑣,𝑡,𝑖,𝑗,𝑘,𝑚,𝑛)   𝑀(𝑦,𝑧,𝑘)   𝑋(𝑥,𝑦,𝑧,𝑤,𝑣,𝑡,𝑘,𝑚,𝑛)   𝑌(𝑥,𝑦,𝑧,𝑤,𝑣,𝑡,𝑘,𝑚,𝑛)

Proof of Theorem efgcpbllema
StepHypRef Expression
1 oveq2 7408 . . . . 5 (𝑖 = 𝑋 → (𝐴 ++ 𝑖) = (𝐴 ++ 𝑋))
21oveq1d 7415 . . . 4 (𝑖 = 𝑋 → ((𝐴 ++ 𝑖) ++ 𝐵) = ((𝐴 ++ 𝑋) ++ 𝐵))
3 oveq2 7408 . . . . 5 (𝑗 = 𝑌 → (𝐴 ++ 𝑗) = (𝐴 ++ 𝑌))
43oveq1d 7415 . . . 4 (𝑗 = 𝑌 → ((𝐴 ++ 𝑗) ++ 𝐵) = ((𝐴 ++ 𝑌) ++ 𝐵))
52, 4breqan12d 5120 . . 3 ((𝑖 = 𝑋𝑗 = 𝑌) → (((𝐴 ++ 𝑖) ++ 𝐵) ((𝐴 ++ 𝑗) ++ 𝐵) ↔ ((𝐴 ++ 𝑋) ++ 𝐵) ((𝐴 ++ 𝑌) ++ 𝐵)))
6 efgcpbllem.1 . . . 4 𝐿 = {⟨𝑖, 𝑗⟩ ∣ ({𝑖, 𝑗} ⊆ 𝑊 ∧ ((𝐴 ++ 𝑖) ++ 𝐵) ((𝐴 ++ 𝑗) ++ 𝐵))}
7 vex 3461 . . . . . . 7 𝑖 ∈ V
8 vex 3461 . . . . . . 7 𝑗 ∈ V
97, 8prss 4781 . . . . . 6 ((𝑖𝑊𝑗𝑊) ↔ {𝑖, 𝑗} ⊆ 𝑊)
109anbi1i 635 . . . . 5 (((𝑖𝑊𝑗𝑊) ∧ ((𝐴 ++ 𝑖) ++ 𝐵) ((𝐴 ++ 𝑗) ++ 𝐵)) ↔ ({𝑖, 𝑗} ⊆ 𝑊 ∧ ((𝐴 ++ 𝑖) ++ 𝐵) ((𝐴 ++ 𝑗) ++ 𝐵)))
1110opabbii 5171 . . . 4 {⟨𝑖, 𝑗⟩ ∣ ((𝑖𝑊𝑗𝑊) ∧ ((𝐴 ++ 𝑖) ++ 𝐵) ((𝐴 ++ 𝑗) ++ 𝐵))} = {⟨𝑖, 𝑗⟩ ∣ ({𝑖, 𝑗} ⊆ 𝑊 ∧ ((𝐴 ++ 𝑖) ++ 𝐵) ((𝐴 ++ 𝑗) ++ 𝐵))}
126, 11eqtr4i 2791 . . 3 𝐿 = {⟨𝑖, 𝑗⟩ ∣ ((𝑖𝑊𝑗𝑊) ∧ ((𝐴 ++ 𝑖) ++ 𝐵) ((𝐴 ++ 𝑗) ++ 𝐵))}
135, 12brab2a 5744 . 2 (𝑋𝐿𝑌 ↔ ((𝑋𝑊𝑌𝑊) ∧ ((𝐴 ++ 𝑋) ++ 𝐵) ((𝐴 ++ 𝑌) ++ 𝐵)))
14 df-3an 1103 . 2 ((𝑋𝑊𝑌𝑊 ∧ ((𝐴 ++ 𝑋) ++ 𝐵) ((𝐴 ++ 𝑌) ++ 𝐵)) ↔ ((𝑋𝑊𝑌𝑊) ∧ ((𝐴 ++ 𝑋) ++ 𝐵) ((𝐴 ++ 𝑌) ++ 𝐵)))
1513, 14bitr4i 281 1 (𝑋𝐿𝑌 ↔ (𝑋𝑊𝑌𝑊 ∧ ((𝐴 ++ 𝑋) ++ 𝐵) ((𝐴 ++ 𝑌) ++ 𝐵)))
Colors of variables: wff setvar class
Syntax hints:  wb 209  wa 400  w3a 1101   = wceq 1563  wcel 2145  wral 3079  {crab 3417  cdif 3904  wss 3907  c0 4288  {csn 4585  {cpr 4587  cop 4591  cotp 4593   ciun 4951   class class class wbr 5104  {copab 5166  cmpt 5185   I cid 5545   × cxp 5649  ran crn 5652  cfv 6525  (class class class)co 7400  cmpo 7402  1oc1o 8434  2oc2o 8435  0cc0 11088  1c1 11089  cmin 11429  ...cfz 13523  ..^cfzo 13670  chash 14354  Word cword 14538   ++ cconcat 14595   splice csplice 14774  ⟨“cs2 14866   ~FG cefg 19764
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1818  ax-4 1832  ax-5 1933  ax-6 1990  ax-7 2031  ax-8 2147  ax-9 2155  ax-ext 2737  ax-sep 5250  ax-pr 5394
This theorem depends on definitions:  df-bi 210  df-an 401  df-or 861  df-3an 1103  df-tru 1566  df-fal 1576  df-ex 1803  df-sb 2094  df-clab 2744  df-cleq 2757  df-clel 2840  df-ral 3080  df-rex 3090  df-rab 3418  df-v 3459  df-dif 3910  df-un 3912  df-in 3914  df-ss 3924  df-nul 4289  df-if 4484  df-sn 4586  df-pr 4588  df-op 4592  df-uni 4868  df-br 5105  df-opab 5167  df-xp 5657  df-iota 6481  df-fv 6533  df-ov 7403
This theorem is referenced by:  efgcpbllemb  19813  efgcpbl  19814
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