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Theorem idfudiag1lem 49181
Description: Lemma for idfudiag1bas 49182 and idfudiag1 49183. (Contributed by Zhi Wang, 19-Oct-2025.)
Hypotheses
Ref Expression
idfudiag1lem.1 (𝜑 → ( I ↾ 𝐴) = (𝐴 × {𝐵}))
idfudiag1lem.2 (𝜑𝐴 ≠ ∅)
Assertion
Ref Expression
idfudiag1lem (𝜑𝐴 = {𝐵})

Proof of Theorem idfudiag1lem
StepHypRef Expression
1 rnresi 6092 . . 3 ran ( I ↾ 𝐴) = 𝐴
2 idfudiag1lem.1 . . . 4 (𝜑 → ( I ↾ 𝐴) = (𝐴 × {𝐵}))
32rneqd 5948 . . 3 (𝜑 → ran ( I ↾ 𝐴) = ran (𝐴 × {𝐵}))
41, 3eqtr3id 2790 . 2 (𝜑𝐴 = ran (𝐴 × {𝐵}))
5 idfudiag1lem.2 . . 3 (𝜑𝐴 ≠ ∅)
6 rnxp 6189 . . 3 (𝐴 ≠ ∅ → ran (𝐴 × {𝐵}) = {𝐵})
75, 6syl 17 . 2 (𝜑 → ran (𝐴 × {𝐵}) = {𝐵})
84, 7eqtrd 2776 1 (𝜑𝐴 = {𝐵})
Colors of variables: wff setvar class
Syntax hints:  wi 4   = wceq 1539  wne 2939  c0 4332  {csn 4625   I cid 5576   × cxp 5682  ran crn 5685  cres 5686
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1794  ax-4 1808  ax-5 1909  ax-6 1966  ax-7 2006  ax-8 2109  ax-9 2117  ax-11 2156  ax-ext 2707  ax-sep 5295  ax-nul 5305  ax-pr 5431
This theorem depends on definitions:  df-bi 207  df-an 396  df-or 848  df-3an 1088  df-tru 1542  df-fal 1552  df-ex 1779  df-sb 2064  df-clab 2714  df-cleq 2728  df-clel 2815  df-ne 2940  df-ral 3061  df-rex 3070  df-rab 3436  df-v 3481  df-dif 3953  df-un 3955  df-in 3957  df-ss 3967  df-nul 4333  df-if 4525  df-sn 4626  df-pr 4628  df-op 4632  df-br 5143  df-opab 5205  df-id 5577  df-xp 5690  df-rel 5691  df-cnv 5692  df-dm 5694  df-rn 5695  df-res 5696  df-ima 5697
This theorem is referenced by:  idfudiag1bas  49182  idfudiag1  49183
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