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Theorem istrkgc 28943
Description: Property of being a Tarski geometry - congruence part. (Contributed by Thierry Arnoux, 14-Mar-2019.)
Hypotheses
Ref Expression
istrkg.p 𝑃 = (Base‘𝐺)
istrkg.d − = (dist‘𝐺)
istrkg.i 𝐼 = (Itv‘𝐺)
Assertion
Ref Expression
istrkgc (𝐺 ∈ TarskiGC ↔ (𝐺 ∈ V ∧ (∀𝑥 ∈ 𝑃 ∀𝑦 ∈ 𝑃 (𝑥 − 𝑦) = (𝑦 − 𝑥) ∧ ∀𝑥 ∈ 𝑃 ∀𝑦 ∈ 𝑃 ∀𝑧 ∈ 𝑃 ((𝑥 − 𝑦) = (𝑧 − 𝑧) → 𝑥 = 𝑦))))
Distinct variable groups:   𝑥,𝑦,𝑧,𝐼   𝑥,𝑃,𝑦,𝑧   𝑥, − ,𝑦,𝑧
Allowed substitution hints:   𝐺(𝑥, 𝑦, 𝑧)

Proof of Theorem istrkgc
Dummy variables 𝑓 𝑑 𝑝 are mutually distinct and distinct from all other variables.
StepHypRef Expression
1 istrkg.p . . 3 𝑃 = (Base‘𝐺)
2 istrkg.d . . 3 − = (dist‘𝐺)
3 simpl 488 . . . . 5 ((𝑝 = 𝑃 ∧ 𝑑 = − ) → 𝑝 = 𝑃)
4 simpr 490 . . . . . . . 8 ((𝑝 = 𝑃 ∧ 𝑑 = − ) → 𝑑 = − )
54oveqd 7457 . . . . . . 7 ((𝑝 = 𝑃 ∧ 𝑑 = − ) → (𝑥𝑑𝑦) = (𝑥 − 𝑦))
64oveqd 7457 . . . . . . 7 ((𝑝 = 𝑃 ∧ 𝑑 = − ) → (𝑦𝑑𝑥) = (𝑦 − 𝑥))
75, 6eqeq12d 2779 . . . . . 6 ((𝑝 = 𝑃 ∧ 𝑑 = − ) → ((𝑥𝑑𝑦) = (𝑦𝑑𝑥) ↔ (𝑥 − 𝑦) = (𝑦 − 𝑥)))
83, 7raleqbidv 3338 . . . . 5 ((𝑝 = 𝑃 ∧ 𝑑 = − ) → (∀𝑦 ∈ 𝑝 (𝑥𝑑𝑦) = (𝑦𝑑𝑥) ↔ ∀𝑦 ∈ 𝑃 (𝑥 − 𝑦) = (𝑦 − 𝑥)))
93, 8raleqbidv 3338 . . . 4 ((𝑝 = 𝑃 ∧ 𝑑 = − ) → (∀𝑥 ∈ 𝑝 ∀𝑦 ∈ 𝑝 (𝑥𝑑𝑦) = (𝑦𝑑𝑥) ↔ ∀𝑥 ∈ 𝑃 ∀𝑦 ∈ 𝑃 (𝑥 − 𝑦) = (𝑦 − 𝑥)))
104oveqd 7457 . . . . . . . . 9 ((𝑝 = 𝑃 ∧ 𝑑 = − ) → (𝑧𝑑𝑧) = (𝑧 − 𝑧))
115, 10eqeq12d 2779 . . . . . . . 8 ((𝑝 = 𝑃 ∧ 𝑑 = − ) → ((𝑥𝑑𝑦) = (𝑧𝑑𝑧) ↔ (𝑥 − 𝑦) = (𝑧 − 𝑧)))
1211imbi1d 344 . . . . . . 7 ((𝑝 = 𝑃 ∧ 𝑑 = − ) → (((𝑥𝑑𝑦) = (𝑧𝑑𝑧) → 𝑥 = 𝑦) ↔ ((𝑥 − 𝑦) = (𝑧 − 𝑧) → 𝑥 = 𝑦)))
133, 12raleqbidv 3338 . . . . . 6 ((𝑝 = 𝑃 ∧ 𝑑 = − ) → (∀𝑧 ∈ 𝑝 ((𝑥𝑑𝑦) = (𝑧𝑑𝑧) → 𝑥 = 𝑦) ↔ ∀𝑧 ∈ 𝑃 ((𝑥 − 𝑦) = (𝑧 − 𝑧) → 𝑥 = 𝑦)))
143, 13raleqbidv 3338 . . . . 5 ((𝑝 = 𝑃 ∧ 𝑑 = − ) → (∀𝑦 ∈ 𝑝 ∀𝑧 ∈ 𝑝 ((𝑥𝑑𝑦) = (𝑧𝑑𝑧) → 𝑥 = 𝑦) ↔ ∀𝑦 ∈ 𝑃 ∀𝑧 ∈ 𝑃 ((𝑥 − 𝑦) = (𝑧 − 𝑧) → 𝑥 = 𝑦)))
153, 14raleqbidv 3338 . . . 4 ((𝑝 = 𝑃 ∧ 𝑑 = − ) → (∀𝑥 ∈ 𝑝 ∀𝑦 ∈ 𝑝 ∀𝑧 ∈ 𝑝 ((𝑥𝑑𝑦) = (𝑧𝑑𝑧) → 𝑥 = 𝑦) ↔ ∀𝑥 ∈ 𝑃 ∀𝑦 ∈ 𝑃 ∀𝑧 ∈ 𝑃 ((𝑥 − 𝑦) = (𝑧 − 𝑧) → 𝑥 = 𝑦)))
169, 15anbi12d 644 . . 3 ((𝑝 = 𝑃 ∧ 𝑑 = − ) → ((∀𝑥 ∈ 𝑝 ∀𝑦 ∈ 𝑝 (𝑥𝑑𝑦) = (𝑦𝑑𝑥) ∧ ∀𝑥 ∈ 𝑝 ∀𝑦 ∈ 𝑝 ∀𝑧 ∈ 𝑝 ((𝑥𝑑𝑦) = (𝑧𝑑𝑧) → 𝑥 = 𝑦)) ↔ (∀𝑥 ∈ 𝑃 ∀𝑦 ∈ 𝑃 (𝑥 − 𝑦) = (𝑦 − 𝑥) ∧ ∀𝑥 ∈ 𝑃 ∀𝑦 ∈ 𝑃 ∀𝑧 ∈ 𝑃 ((𝑥 − 𝑦) = (𝑧 − 𝑧) → 𝑥 = 𝑦))))
171, 2, 16sbcie2s 17365 . 2 (𝑓 = 𝐺 → ([(Base‘𝑓) / 𝑝][(dist‘𝑓) / 𝑑](∀𝑥 ∈ 𝑝 ∀𝑦 ∈ 𝑝 (𝑥𝑑𝑦) = (𝑦𝑑𝑥) ∧ ∀𝑥 ∈ 𝑝 ∀𝑦 ∈ 𝑝 ∀𝑧 ∈ 𝑝 ((𝑥𝑑𝑦) = (𝑧𝑑𝑧) → 𝑥 = 𝑦)) ↔ (∀𝑥 ∈ 𝑃 ∀𝑦 ∈ 𝑃 (𝑥 − 𝑦) = (𝑦 − 𝑥) ∧ ∀𝑥 ∈ 𝑃 ∀𝑦 ∈ 𝑃 ∀𝑧 ∈ 𝑃 ((𝑥 − 𝑦) = (𝑧 − 𝑧) → 𝑥 = 𝑦))))
18 df-trkgc 28937 . 2 TarskiGC = {𝑓 ∣ [(Base‘𝑓) / 𝑝][(dist‘𝑓) / 𝑑](∀𝑥 ∈ 𝑝 ∀𝑦 ∈ 𝑝 (𝑥𝑑𝑦) = (𝑦𝑑𝑥) ∧ ∀𝑥 ∈ 𝑝 ∀𝑦 ∈ 𝑝 ∀𝑧 ∈ 𝑝 ((𝑥𝑑𝑦) = (𝑧𝑑𝑧) → 𝑥 = 𝑦))}
1917, 18elab4g 3640 1 (𝐺 ∈ TarskiGC ↔ (𝐺 ∈ V ∧ (∀𝑥 ∈ 𝑃 ∀𝑦 ∈ 𝑃 (𝑥 − 𝑦) = (𝑦 − 𝑥) ∧ ∀𝑥 ∈ 𝑃 ∀𝑦 ∈ 𝑃 ∀𝑧 ∈ 𝑃 ((𝑥 − 𝑦) = (𝑧 − 𝑧) → 𝑥 = 𝑦))))
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   → wi 4   ↔ wb 209   ∧ wa 401   = wceq 1570   ∈ wcel 2147  ∀wral 3080  Vcvv 3454  [wsbc 3742  ‘cfv 6555  (class class class)co 7440  Basecbs 17413  distcds 17463  TarskiGCcstrkgc 28917  Itvcitv 28922
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1945  ax-6 2002  ax-7 2043  ax-8 2149  ax-9 2157  ax-ext 2735  ax-nul 5263
This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3an 1105  df-tru 1573  df-fal 1583  df-ex 1813  df-sb 2102  df-clab 2742  df-cleq 2755  df-clel 2839  df-ne 2960  df-ral 3081  df-rab 3417  df-v 3456  df-sbc 3743  df-ss 3901  df-dif 4050  df-un 4154  df-nul 4282  df-if 4486  df-sn 4589  df-pr 4591  df-op 4839  df-uni 4871  df-br 5107  df-iota 6509  df-fv 6563  df-ov 7443  df-trkgc 28937
This theorem is used by:  axtgcgrrflx  28951  axtgcgrid  28952  f1otrg  29475  xmstrkgc  29490  eengtrkg  29591
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