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Theorem istrkgc 28916
Description: Property of being a Tarski geometry - congruence part. (Contributed by Thierry Arnoux, 14-Mar-2019.)
Hypotheses
Ref Expression
istrkg.p 𝑃 = (Base‘𝐺)
istrkg.d − = (dist‘𝐺)
istrkg.i 𝐼 = (Itv‘𝐺)
Assertion
Ref Expression
istrkgc (𝐺 ∈ TarskiGC ↔ (𝐺 ∈ V ∧ (∀𝑥 ∈ 𝑃 ∀𝑦 ∈ 𝑃 (𝑥 − 𝑦) = (𝑦 − 𝑥) ∧ ∀𝑥 ∈ 𝑃 ∀𝑦 ∈ 𝑃 ∀𝑧 ∈ 𝑃 ((𝑥 − 𝑦) = (𝑧 − 𝑧) → 𝑥 = 𝑦))))
Distinct variable groups:   𝑥,𝑦,𝑧,𝐼   𝑥,𝑃,𝑦,𝑧   𝑥, − ,𝑦,𝑧
Allowed substitution hints:   𝐺(𝑥, 𝑦, 𝑧)

Proof of Theorem istrkgc
Dummy variables 𝑓 𝑑 𝑝 are mutually distinct and distinct from all other variables.
StepHypRef Expression
1 istrkg.p . . 3 𝑃 = (Base‘𝐺)
2 istrkg.d . . 3 − = (dist‘𝐺)
3 simpl 488 . . . . 5 ((𝑝 = 𝑃 ∧ 𝑑 = − ) → 𝑝 = 𝑃)
4 simpr 490 . . . . . . . 8 ((𝑝 = 𝑃 ∧ 𝑑 = − ) → 𝑑 = − )
54oveqd 7437 . . . . . . 7 ((𝑝 = 𝑃 ∧ 𝑑 = − ) → (𝑥𝑑𝑦) = (𝑥 − 𝑦))
64oveqd 7437 . . . . . . 7 ((𝑝 = 𝑃 ∧ 𝑑 = − ) → (𝑦𝑑𝑥) = (𝑦 − 𝑥))
75, 6eqeq12d 2776 . . . . . 6 ((𝑝 = 𝑃 ∧ 𝑑 = − ) → ((𝑥𝑑𝑦) = (𝑦𝑑𝑥) ↔ (𝑥 − 𝑦) = (𝑦 − 𝑥)))
83, 7raleqbidv 3334 . . . . 5 ((𝑝 = 𝑃 ∧ 𝑑 = − ) → (∀𝑦 ∈ 𝑝 (𝑥𝑑𝑦) = (𝑦𝑑𝑥) ↔ ∀𝑦 ∈ 𝑃 (𝑥 − 𝑦) = (𝑦 − 𝑥)))
93, 8raleqbidv 3334 . . . 4 ((𝑝 = 𝑃 ∧ 𝑑 = − ) → (∀𝑥 ∈ 𝑝 ∀𝑦 ∈ 𝑝 (𝑥𝑑𝑦) = (𝑦𝑑𝑥) ↔ ∀𝑥 ∈ 𝑃 ∀𝑦 ∈ 𝑃 (𝑥 − 𝑦) = (𝑦 − 𝑥)))
104oveqd 7437 . . . . . . . . 9 ((𝑝 = 𝑃 ∧ 𝑑 = − ) → (𝑧𝑑𝑧) = (𝑧 − 𝑧))
115, 10eqeq12d 2776 . . . . . . . 8 ((𝑝 = 𝑃 ∧ 𝑑 = − ) → ((𝑥𝑑𝑦) = (𝑧𝑑𝑧) ↔ (𝑥 − 𝑦) = (𝑧 − 𝑧)))
1211imbi1d 344 . . . . . . 7 ((𝑝 = 𝑃 ∧ 𝑑 = − ) → (((𝑥𝑑𝑦) = (𝑧𝑑𝑧) → 𝑥 = 𝑦) ↔ ((𝑥 − 𝑦) = (𝑧 − 𝑧) → 𝑥 = 𝑦)))
133, 12raleqbidv 3334 . . . . . 6 ((𝑝 = 𝑃 ∧ 𝑑 = − ) → (∀𝑧 ∈ 𝑝 ((𝑥𝑑𝑦) = (𝑧𝑑𝑧) → 𝑥 = 𝑦) ↔ ∀𝑧 ∈ 𝑃 ((𝑥 − 𝑦) = (𝑧 − 𝑧) → 𝑥 = 𝑦)))
143, 13raleqbidv 3334 . . . . 5 ((𝑝 = 𝑃 ∧ 𝑑 = − ) → (∀𝑦 ∈ 𝑝 ∀𝑧 ∈ 𝑝 ((𝑥𝑑𝑦) = (𝑧𝑑𝑧) → 𝑥 = 𝑦) ↔ ∀𝑦 ∈ 𝑃 ∀𝑧 ∈ 𝑃 ((𝑥 − 𝑦) = (𝑧 − 𝑧) → 𝑥 = 𝑦)))
153, 14raleqbidv 3334 . . . 4 ((𝑝 = 𝑃 ∧ 𝑑 = − ) → (∀𝑥 ∈ 𝑝 ∀𝑦 ∈ 𝑝 ∀𝑧 ∈ 𝑝 ((𝑥𝑑𝑦) = (𝑧𝑑𝑧) → 𝑥 = 𝑦) ↔ ∀𝑥 ∈ 𝑃 ∀𝑦 ∈ 𝑃 ∀𝑧 ∈ 𝑃 ((𝑥 − 𝑦) = (𝑧 − 𝑧) → 𝑥 = 𝑦)))
169, 15anbi12d 644 . . 3 ((𝑝 = 𝑃 ∧ 𝑑 = − ) → ((∀𝑥 ∈ 𝑝 ∀𝑦 ∈ 𝑝 (𝑥𝑑𝑦) = (𝑦𝑑𝑥) ∧ ∀𝑥 ∈ 𝑝 ∀𝑦 ∈ 𝑝 ∀𝑧 ∈ 𝑝 ((𝑥𝑑𝑦) = (𝑧𝑑𝑧) → 𝑥 = 𝑦)) ↔ (∀𝑥 ∈ 𝑃 ∀𝑦 ∈ 𝑃 (𝑥 − 𝑦) = (𝑦 − 𝑥) ∧ ∀𝑥 ∈ 𝑃 ∀𝑦 ∈ 𝑃 ∀𝑧 ∈ 𝑃 ((𝑥 − 𝑦) = (𝑧 − 𝑧) → 𝑥 = 𝑦))))
171, 2, 16sbcie2s 17339 . 2 (𝑓 = 𝐺 → ([(Base‘𝑓) / 𝑝][(dist‘𝑓) / 𝑑](∀𝑥 ∈ 𝑝 ∀𝑦 ∈ 𝑝 (𝑥𝑑𝑦) = (𝑦𝑑𝑥) ∧ ∀𝑥 ∈ 𝑝 ∀𝑦 ∈ 𝑝 ∀𝑧 ∈ 𝑝 ((𝑥𝑑𝑦) = (𝑧𝑑𝑧) → 𝑥 = 𝑦)) ↔ (∀𝑥 ∈ 𝑃 ∀𝑦 ∈ 𝑃 (𝑥 − 𝑦) = (𝑦 − 𝑥) ∧ ∀𝑥 ∈ 𝑃 ∀𝑦 ∈ 𝑃 ∀𝑧 ∈ 𝑃 ((𝑥 − 𝑦) = (𝑧 − 𝑧) → 𝑥 = 𝑦))))
18 df-trkgc 28910 . 2 TarskiGC = {𝑓 ∣ [(Base‘𝑓) / 𝑝][(dist‘𝑓) / 𝑑](∀𝑥 ∈ 𝑝 ∀𝑦 ∈ 𝑝 (𝑥𝑑𝑦) = (𝑦𝑑𝑥) ∧ ∀𝑥 ∈ 𝑝 ∀𝑦 ∈ 𝑝 ∀𝑧 ∈ 𝑝 ((𝑥𝑑𝑦) = (𝑧𝑑𝑧) → 𝑥 = 𝑦))}
1917, 18elab4g 3636 1 (𝐺 ∈ TarskiGC ↔ (𝐺 ∈ V ∧ (∀𝑥 ∈ 𝑃 ∀𝑦 ∈ 𝑃 (𝑥 − 𝑦) = (𝑦 − 𝑥) ∧ ∀𝑥 ∈ 𝑃 ∀𝑦 ∈ 𝑃 ∀𝑧 ∈ 𝑃 ((𝑥 − 𝑦) = (𝑧 − 𝑧) → 𝑥 = 𝑦))))
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   → wi 4   ↔ wb 209   ∧ wa 401   = wceq 1569   ∈ wcel 2144  ∀wral 3076  Vcvv 3450  [wsbc 3738  ‘cfv 6538  (class class class)co 7420  Basecbs 17387  distcds 17437  TarskiGCcstrkgc 28890  Itvcitv 28895
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1827  ax-4 1841  ax-5 1942  ax-6 1999  ax-7 2040  ax-8 2146  ax-9 2154  ax-ext 2732  ax-nul 5259
This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3an 1105  df-tru 1572  df-fal 1582  df-ex 1812  df-sb 2099  df-clab 2739  df-cleq 2752  df-clel 2835  df-ne 2956  df-ral 3077  df-rab 3413  df-v 3452  df-sbc 3739  df-ss 3896  df-dif 4047  df-un 4151  df-nul 4279  df-if 4482  df-sn 4584  df-pr 4586  df-op 4590  df-uni 4867  df-br 5103  df-iota 6494  df-fv 6546  df-ov 7423  df-trkgc 28910
This theorem is used by:  axtgcgrrflx  28924  axtgcgrid  28925  f1otrg  29448  xmstrkgc  29463  eengtrkg  29564
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