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Theorem xpidtr 6068
Description: A Cartesian square is a transitive relation. (Contributed by FL, 31-Jul-2009.)
Assertion
Ref Expression
xpidtr ((𝐴 × 𝐴) ∘ (𝐴 × 𝐴)) ⊆ (𝐴 × 𝐴)

Proof of Theorem xpidtr
Dummy variables 𝑥 𝑦 𝑧 are mutually distinct and distinct from all other variables.
StepHypRef Expression
1 brxp 5663 . . . . . 6 (𝑥(𝐴 × 𝐴)𝑦 ↔ (𝑥𝐴𝑦𝐴))
2 brxp 5663 . . . . . . . . 9 (𝑦(𝐴 × 𝐴)𝑧 ↔ (𝑦𝐴𝑧𝐴))
3 brxp 5663 . . . . . . . . . 10 (𝑥(𝐴 × 𝐴)𝑧 ↔ (𝑥𝐴𝑧𝐴))
43simplbi2com 502 . . . . . . . . 9 (𝑧𝐴 → (𝑥𝐴𝑥(𝐴 × 𝐴)𝑧))
52, 4simplbiim 504 . . . . . . . 8 (𝑦(𝐴 × 𝐴)𝑧 → (𝑥𝐴𝑥(𝐴 × 𝐴)𝑧))
65com12 32 . . . . . . 7 (𝑥𝐴 → (𝑦(𝐴 × 𝐴)𝑧𝑥(𝐴 × 𝐴)𝑧))
76adantr 480 . . . . . 6 ((𝑥𝐴𝑦𝐴) → (𝑦(𝐴 × 𝐴)𝑧𝑥(𝐴 × 𝐴)𝑧))
81, 7sylbi 217 . . . . 5 (𝑥(𝐴 × 𝐴)𝑦 → (𝑦(𝐴 × 𝐴)𝑧𝑥(𝐴 × 𝐴)𝑧))
98imp 406 . . . 4 ((𝑥(𝐴 × 𝐴)𝑦𝑦(𝐴 × 𝐴)𝑧) → 𝑥(𝐴 × 𝐴)𝑧)
109ax-gen 1796 . . 3 𝑧((𝑥(𝐴 × 𝐴)𝑦𝑦(𝐴 × 𝐴)𝑧) → 𝑥(𝐴 × 𝐴)𝑧)
1110gen2 1797 . 2 𝑥𝑦𝑧((𝑥(𝐴 × 𝐴)𝑦𝑦(𝐴 × 𝐴)𝑧) → 𝑥(𝐴 × 𝐴)𝑧)
12 cotr 6058 . 2 (((𝐴 × 𝐴) ∘ (𝐴 × 𝐴)) ⊆ (𝐴 × 𝐴) ↔ ∀𝑥𝑦𝑧((𝑥(𝐴 × 𝐴)𝑦𝑦(𝐴 × 𝐴)𝑧) → 𝑥(𝐴 × 𝐴)𝑧))
1311, 12mpbir 231 1 ((𝐴 × 𝐴) ∘ (𝐴 × 𝐴)) ⊆ (𝐴 × 𝐴)
Colors of variables: wff setvar class
Syntax hints:  wi 4  wa 395  wal 1539  wcel 2111  wss 3897   class class class wbr 5089   × cxp 5612  ccom 5618
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1796  ax-4 1810  ax-5 1911  ax-6 1968  ax-7 2009  ax-8 2113  ax-9 2121  ax-ext 2703  ax-sep 5232  ax-nul 5242  ax-pr 5368
This theorem depends on definitions:  df-bi 207  df-an 396  df-or 848  df-3an 1088  df-tru 1544  df-fal 1554  df-ex 1781  df-sb 2068  df-clab 2710  df-cleq 2723  df-clel 2806  df-ral 3048  df-rex 3057  df-rab 3396  df-v 3438  df-dif 3900  df-un 3902  df-ss 3914  df-nul 4281  df-if 4473  df-sn 4574  df-pr 4576  df-op 4580  df-br 5090  df-opab 5152  df-xp 5620  df-rel 5621  df-co 5623
This theorem is referenced by:  trinxp  6071  xpider  8712  trust  24144  rtrclex  43720  rtrclexi  43724
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