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| Type | Label | Description |
|---|---|---|
| Statement | ||
| Theorem | rnin 6101 | The range of an intersection belongs the intersection of ranges. Theorem 9 of [Suppes] p. 60. (Contributed by NM, 15-Sep-2004.) |
| ⊢ ran (𝐴 ∩ 𝐵) ⊆ (ran 𝐴 ∩ ran 𝐵) | ||
| Theorem | rniun 6102 | The range of an indexed union. (Contributed by Mario Carneiro, 29-May-2015.) |
| ⊢ ran ∪ 𝑥 ∈ 𝐴 𝐵 = ∪ 𝑥 ∈ 𝐴 ran 𝐵 | ||
| Theorem | rnuni 6103* | The range of a union. Part of Exercise 8 of [Enderton] p. 41. (Contributed by NM, 17-Mar-2004.) (Revised by Mario Carneiro, 29-May-2015.) |
| ⊢ ran ∪ 𝐴 = ∪ 𝑥 ∈ 𝐴 ran 𝑥 | ||
| Theorem | imaundi 6104 | Distributive law for image over union. Theorem 35 of [Suppes] p. 65. (Contributed by NM, 30-Sep-2002.) |
| ⊢ (𝐴 “ (𝐵 ∪ 𝐶)) = ((𝐴 “ 𝐵) ∪ (𝐴 “ 𝐶)) | ||
| Theorem | imaundir 6105 | The image of a union. (Contributed by Jeff Hoffman, 17-Feb-2008.) |
| ⊢ ((𝐴 ∪ 𝐵) “ 𝐶) = ((𝐴 “ 𝐶) ∪ (𝐵 “ 𝐶)) | ||
| Theorem | imadifssran 6106 | Condition for the range of a relation to be the range of one its restrictions. (Contributed by AV, 4-Oct-2025.) |
| ⊢ ((Rel 𝐹 ∧ 𝐴 ⊆ dom 𝐹) → ((𝐹 “ (dom 𝐹 ∖ 𝐴)) ⊆ ran (𝐹 ↾ 𝐴) → ran 𝐹 = ran (𝐹 ↾ 𝐴))) | ||
| Theorem | cnvimassrndm 6107 | The preimage of a superset of the range of a class is the domain of the class. Generalization of cnvimarndm 6039 for subsets. (Contributed by AV, 18-Sep-2024.) |
| ⊢ (ran 𝐹 ⊆ 𝐴 → (◡𝐹 “ 𝐴) = dom 𝐹) | ||
| Theorem | dminss 6108 | An upper bound for intersection with a domain. Theorem 40 of [Suppes] p. 66, who calls it "somewhat surprising". (Contributed by NM, 11-Aug-2004.) |
| ⊢ (dom 𝑅 ∩ 𝐴) ⊆ (◡𝑅 “ (𝑅 “ 𝐴)) | ||
| Theorem | imainss 6109 | An upper bound for intersection with an image. Theorem 41 of [Suppes] p. 66. (Contributed by NM, 11-Aug-2004.) |
| ⊢ ((𝑅 “ 𝐴) ∩ 𝐵) ⊆ (𝑅 “ (𝐴 ∩ (◡𝑅 “ 𝐵))) | ||
| Theorem | inimass 6110 | The image of an intersection. (Contributed by Thierry Arnoux, 16-Dec-2017.) |
| ⊢ ((𝐴 ∩ 𝐵) “ 𝐶) ⊆ ((𝐴 “ 𝐶) ∩ (𝐵 “ 𝐶)) | ||
| Theorem | inimasn 6111 | The intersection of the image of singleton. (Contributed by Thierry Arnoux, 16-Dec-2017.) |
| ⊢ (𝐶 ∈ 𝑉 → ((𝐴 ∩ 𝐵) “ {𝐶}) = ((𝐴 “ {𝐶}) ∩ (𝐵 “ {𝐶}))) | ||
| Theorem | cnvxp 6112 | The converse of a Cartesian product. Exercise 11 of [Suppes] p. 67. (Contributed by NM, 14-Aug-1999.) (Proof shortened by Andrew Salmon, 27-Aug-2011.) |
| ⊢ ◡(𝐴 × 𝐵) = (𝐵 × 𝐴) | ||
| Theorem | xp0OLD 6113 | Obsolete version of xp0 5721 as of 1-Feb-2026. (Contributed by NM, 12-Apr-2004.) (Proof modification is discouraged.) (New usage is discouraged.) |
| ⊢ (𝐴 × ∅) = ∅ | ||
| Theorem | xpnz 6114 | The Cartesian product of nonempty classes is nonempty. (Variation of a theorem contributed by Raph Levien, 30-Jun-2006.) (Contributed by NM, 30-Jun-2006.) |
| ⊢ ((𝐴 ≠ ∅ ∧ 𝐵 ≠ ∅) ↔ (𝐴 × 𝐵) ≠ ∅) | ||
| Theorem | xpeq0 6115 | At least one member of an empty Cartesian product is empty. (Contributed by NM, 27-Aug-2006.) |
| ⊢ ((𝐴 × 𝐵) = ∅ ↔ (𝐴 = ∅ ∨ 𝐵 = ∅)) | ||
| Theorem | xpdisj1 6116 | Cartesian products with disjoint sets are disjoint. (Contributed by NM, 13-Sep-2004.) |
| ⊢ ((𝐴 ∩ 𝐵) = ∅ → ((𝐴 × 𝐶) ∩ (𝐵 × 𝐷)) = ∅) | ||
| Theorem | xpdisj2 6117 | Cartesian products with disjoint sets are disjoint. (Contributed by NM, 13-Sep-2004.) |
| ⊢ ((𝐴 ∩ 𝐵) = ∅ → ((𝐶 × 𝐴) ∩ (𝐷 × 𝐵)) = ∅) | ||
| Theorem | xpsndisj 6118 | Cartesian products with two different singletons are disjoint. (Contributed by NM, 28-Jul-2004.) |
| ⊢ (𝐵 ≠ 𝐷 → ((𝐴 × {𝐵}) ∩ (𝐶 × {𝐷})) = ∅) | ||
| Theorem | difxp 6119 | Difference of Cartesian products, expressed in terms of a union of Cartesian products of differences. (Contributed by Jeff Madsen, 2-Sep-2009.) (Revised by Mario Carneiro, 26-Jun-2014.) (Proof shortened by Wolf Lammen, 16-May-2025.) |
| ⊢ ((𝐶 × 𝐷) ∖ (𝐴 × 𝐵)) = (((𝐶 ∖ 𝐴) × 𝐷) ∪ (𝐶 × (𝐷 ∖ 𝐵))) | ||
| Theorem | difxp1 6120 | Difference law for Cartesian product. (Contributed by Scott Fenton, 18-Feb-2013.) (Revised by Mario Carneiro, 26-Jun-2014.) |
| ⊢ ((𝐴 ∖ 𝐵) × 𝐶) = ((𝐴 × 𝐶) ∖ (𝐵 × 𝐶)) | ||
| Theorem | difxp2 6121 | Difference law for Cartesian product. (Contributed by Scott Fenton, 18-Feb-2013.) (Revised by Mario Carneiro, 26-Jun-2014.) |
| ⊢ (𝐴 × (𝐵 ∖ 𝐶)) = ((𝐴 × 𝐵) ∖ (𝐴 × 𝐶)) | ||
| Theorem | djudisj 6122* | Disjoint unions with disjoint index sets are disjoint. (Contributed by Stefan O'Rear, 21-Nov-2014.) |
| ⊢ ((𝐴 ∩ 𝐵) = ∅ → (∪ 𝑥 ∈ 𝐴 ({𝑥} × 𝐶) ∩ ∪ 𝑦 ∈ 𝐵 ({𝑦} × 𝐷)) = ∅) | ||
| Theorem | xpdifid 6123* | The set of distinct couples in a Cartesian product. (Contributed by Thierry Arnoux, 25-May-2019.) |
| ⊢ ∪ 𝑥 ∈ 𝐴 ({𝑥} × (𝐵 ∖ {𝑥})) = ((𝐴 × 𝐵) ∖ I ) | ||
| Theorem | resdisj 6124 | A double restriction to disjoint classes is the empty set. (Contributed by NM, 7-Oct-2004.) (Proof shortened by Andrew Salmon, 27-Aug-2011.) |
| ⊢ ((𝐴 ∩ 𝐵) = ∅ → ((𝐶 ↾ 𝐴) ↾ 𝐵) = ∅) | ||
| Theorem | rnxp 6125 | The range of a Cartesian product. Part of Theorem 3.13(x) of [Monk1] p. 37. (Contributed by NM, 12-Apr-2004.) |
| ⊢ (𝐴 ≠ ∅ → ran (𝐴 × 𝐵) = 𝐵) | ||
| Theorem | dmxpss 6126 | The domain of a Cartesian product is included in its first factor. (Contributed by NM, 19-Mar-2007.) |
| ⊢ dom (𝐴 × 𝐵) ⊆ 𝐴 | ||
| Theorem | rnxpss 6127 | The range of a Cartesian product is included in its second factor. (Contributed by NM, 16-Jan-2006.) (Proof shortened by Andrew Salmon, 27-Aug-2011.) |
| ⊢ ran (𝐴 × 𝐵) ⊆ 𝐵 | ||
| Theorem | rnxpid 6128 | The range of a Cartesian square. (Contributed by FL, 17-May-2010.) |
| ⊢ ran (𝐴 × 𝐴) = 𝐴 | ||
| Theorem | ssxpb 6129 | A Cartesian product subclass relationship is equivalent to the conjunction of the analogous relationships for the factors. (Contributed by NM, 17-Dec-2008.) |
| ⊢ ((𝐴 × 𝐵) ≠ ∅ → ((𝐴 × 𝐵) ⊆ (𝐶 × 𝐷) ↔ (𝐴 ⊆ 𝐶 ∧ 𝐵 ⊆ 𝐷))) | ||
| Theorem | xp11 6130 | The Cartesian product of nonempty classes is a one-to-one "function" of its two "arguments". In other words, two Cartesian products, at least one with nonempty factors, are equal if and only if their respective factors are equal. (Contributed by NM, 31-May-2008.) |
| ⊢ ((𝐴 ≠ ∅ ∧ 𝐵 ≠ ∅) → ((𝐴 × 𝐵) = (𝐶 × 𝐷) ↔ (𝐴 = 𝐶 ∧ 𝐵 = 𝐷))) | ||
| Theorem | xpcan 6131 | Cancellation law for Cartesian product. (Contributed by NM, 30-Aug-2011.) |
| ⊢ (𝐶 ≠ ∅ → ((𝐶 × 𝐴) = (𝐶 × 𝐵) ↔ 𝐴 = 𝐵)) | ||
| Theorem | xpcan2 6132 | Cancellation law for Cartesian product. (Contributed by NM, 30-Aug-2011.) |
| ⊢ (𝐶 ≠ ∅ → ((𝐴 × 𝐶) = (𝐵 × 𝐶) ↔ 𝐴 = 𝐵)) | ||
| Theorem | ssrnres 6133 | Two ways to express surjectivity of a restricted and corestricted binary relation (intersection of a binary relation with a Cartesian product): the LHS expresses inclusion in the range of the restricted relation, while the RHS expresses equality with the range of the restricted and corestricted relation. (Contributed by NM, 16-Jan-2006.) (Proof shortened by Peter Mazsa, 2-Oct-2022.) |
| ⊢ (𝐵 ⊆ ran (𝐶 ↾ 𝐴) ↔ ran (𝐶 ∩ (𝐴 × 𝐵)) = 𝐵) | ||
| Theorem | rninxp 6134* | Two ways to express surjectivity of a restricted and corestricted binary relation (intersection of a binary relation with a Cartesian product). (Contributed by NM, 17-Jan-2006.) (Proof shortened by Andrew Salmon, 27-Aug-2011.) |
| ⊢ (ran (𝐶 ∩ (𝐴 × 𝐵)) = 𝐵 ↔ ∀𝑦 ∈ 𝐵 ∃𝑥 ∈ 𝐴 𝑥𝐶𝑦) | ||
| Theorem | dminxp 6135* | Two ways to express totality of a restricted and corestricted binary relation (intersection of a binary relation with a Cartesian product). (Contributed by NM, 17-Jan-2006.) |
| ⊢ (dom (𝐶 ∩ (𝐴 × 𝐵)) = 𝐴 ↔ ∀𝑥 ∈ 𝐴 ∃𝑦 ∈ 𝐵 𝑥𝐶𝑦) | ||
| Theorem | imainrect 6136 | Image by a restricted and corestricted binary relation (intersection of a binary relation with a Cartesian product). (Contributed by Stefan O'Rear, 19-Feb-2015.) |
| ⊢ ((𝐺 ∩ (𝐴 × 𝐵)) “ 𝑌) = ((𝐺 “ (𝑌 ∩ 𝐴)) ∩ 𝐵) | ||
| Theorem | xpima 6137 | Direct image by a Cartesian product. (Contributed by Thierry Arnoux, 4-Feb-2017.) |
| ⊢ ((𝐴 × 𝐵) “ 𝐶) = if((𝐴 ∩ 𝐶) = ∅, ∅, 𝐵) | ||
| Theorem | xpima1 6138 | Direct image by a Cartesian product (case of empty intersection with the domain). (Contributed by Thierry Arnoux, 16-Dec-2017.) |
| ⊢ ((𝐴 ∩ 𝐶) = ∅ → ((𝐴 × 𝐵) “ 𝐶) = ∅) | ||
| Theorem | xpima2 6139 | Direct image by a Cartesian product (case of nonempty intersection with the domain). (Contributed by Thierry Arnoux, 16-Dec-2017.) |
| ⊢ ((𝐴 ∩ 𝐶) ≠ ∅ → ((𝐴 × 𝐵) “ 𝐶) = 𝐵) | ||
| Theorem | xpimasn 6140 | Direct image of a singleton by a Cartesian product. (Contributed by Thierry Arnoux, 14-Jan-2018.) (Proof shortened by BJ, 6-Apr-2019.) |
| ⊢ (𝑋 ∈ 𝐴 → ((𝐴 × 𝐵) “ {𝑋}) = 𝐵) | ||
| Theorem | sossfld 6141 | The base set of a strict order is contained in the field of the relation, except possibly for one element (note that ∅ Or {𝐵}). (Contributed by Mario Carneiro, 27-Apr-2015.) |
| ⊢ ((𝑅 Or 𝐴 ∧ 𝐵 ∈ 𝐴) → (𝐴 ∖ {𝐵}) ⊆ (dom 𝑅 ∪ ran 𝑅)) | ||
| Theorem | sofld 6142 | The base set of a nonempty strict order is the same as the field of the relation. (Contributed by Mario Carneiro, 15-May-2015.) |
| ⊢ ((𝑅 Or 𝐴 ∧ 𝑅 ⊆ (𝐴 × 𝐴) ∧ 𝑅 ≠ ∅) → 𝐴 = (dom 𝑅 ∪ ran 𝑅)) | ||
| Theorem | cnvcnv3 6143* | The set of all ordered pairs in a class is the same as the double converse. (Contributed by Mario Carneiro, 16-Aug-2015.) |
| ⊢ ◡◡𝑅 = {〈𝑥, 𝑦〉 ∣ 𝑥𝑅𝑦} | ||
| Theorem | dfrel2 6144 | Alternate definition of relation. Exercise 2 of [TakeutiZaring] p. 25. (Contributed by NM, 29-Dec-1996.) |
| ⊢ (Rel 𝑅 ↔ ◡◡𝑅 = 𝑅) | ||
| Theorem | dfrel4v 6145* | A relation can be expressed as the set of ordered pairs in it. An analogue of dffn5 6889 for relations. (Contributed by Mario Carneiro, 16-Aug-2015.) |
| ⊢ (Rel 𝑅 ↔ 𝑅 = {〈𝑥, 𝑦〉 ∣ 𝑥𝑅𝑦}) | ||
| Theorem | dfrel4 6146* | A relation can be expressed as the set of ordered pairs in it. An analogue of dffn5 6889 for relations. (Contributed by Mario Carneiro, 16-Aug-2015.) (Revised by Thierry Arnoux, 11-May-2017.) |
| ⊢ Ⅎ𝑥𝑅 & ⊢ Ⅎ𝑦𝑅 ⇒ ⊢ (Rel 𝑅 ↔ 𝑅 = {〈𝑥, 𝑦〉 ∣ 𝑥𝑅𝑦}) | ||
| Theorem | cnvcnv 6147 | The double converse of a class strips out all elements that are not ordered pairs. (Contributed by NM, 8-Dec-2003.) (Proof shortened by BJ, 26-Nov-2021.) |
| ⊢ ◡◡𝐴 = (𝐴 ∩ (V × V)) | ||
| Theorem | cnvcnv2 6148 | The double converse of a class equals its restriction to the universe. (Contributed by NM, 8-Oct-2007.) |
| ⊢ ◡◡𝐴 = (𝐴 ↾ V) | ||
| Theorem | cnvcnvss 6149 | The double converse of a class is a subclass. Exercise 2 of [TakeutiZaring] p. 25. (Contributed by NM, 23-Jul-2004.) |
| ⊢ ◡◡𝐴 ⊆ 𝐴 | ||
| Theorem | cnvrescnv 6150 | Two ways to express the corestriction of a class. (Contributed by BJ, 28-Dec-2023.) |
| ⊢ ◡(◡𝑅 ↾ 𝐵) = (𝑅 ∩ (V × 𝐵)) | ||
| Theorem | cnveqb 6151 | Equality theorem for converse. (Contributed by FL, 19-Sep-2011.) |
| ⊢ ((Rel 𝐴 ∧ Rel 𝐵) → (𝐴 = 𝐵 ↔ ◡𝐴 = ◡𝐵)) | ||
| Theorem | cnveq0 6152 | A relation empty iff its converse is empty. (Contributed by FL, 19-Sep-2011.) |
| ⊢ (Rel 𝐴 → (𝐴 = ∅ ↔ ◡𝐴 = ∅)) | ||
| Theorem | dfrel3 6153 | Alternate definition of relation. (Contributed by NM, 14-May-2008.) |
| ⊢ (Rel 𝑅 ↔ (𝑅 ↾ V) = 𝑅) | ||
| Theorem | elid 6154* | Characterization of the elements of the identity relation. TODO: reorder theorems to move this theorem and dfrel3 6153 after elrid 6002. (Contributed by BJ, 28-Aug-2022.) |
| ⊢ (𝐴 ∈ I ↔ ∃𝑥 𝐴 = 〈𝑥, 𝑥〉) | ||
| Theorem | dmresv 6155 | The domain of a universal restriction. (Contributed by NM, 14-May-2008.) |
| ⊢ dom (𝐴 ↾ V) = dom 𝐴 | ||
| Theorem | rnresv 6156 | The range of a universal restriction. (Contributed by NM, 14-May-2008.) |
| ⊢ ran (𝐴 ↾ V) = ran 𝐴 | ||
| Theorem | dfrn4 6157 | Range defined in terms of image. (Contributed by NM, 14-May-2008.) |
| ⊢ ran 𝐴 = (𝐴 “ V) | ||
| Theorem | csbrn 6158 | Distribute proper substitution through the range of a class. (Contributed by Alan Sare, 10-Nov-2012.) |
| ⊢ ⦋𝐴 / 𝑥⦌ran 𝐵 = ran ⦋𝐴 / 𝑥⦌𝐵 | ||
| Theorem | rescnvcnv 6159 | The restriction of the double converse of a class. (Contributed by NM, 8-Apr-2007.) (Proof shortened by Andrew Salmon, 27-Aug-2011.) |
| ⊢ (◡◡𝐴 ↾ 𝐵) = (𝐴 ↾ 𝐵) | ||
| Theorem | cnvcnvres 6160 | The double converse of the restriction of a class. (Contributed by NM, 3-Jun-2007.) |
| ⊢ ◡◡(𝐴 ↾ 𝐵) = (◡◡𝐴 ↾ 𝐵) | ||
| Theorem | imacnvcnv 6161 | The image of the double converse of a class. (Contributed by NM, 8-Apr-2007.) |
| ⊢ (◡◡𝐴 “ 𝐵) = (𝐴 “ 𝐵) | ||
| Theorem | dmsnn0 6162 | The domain of a singleton is nonzero iff the singleton argument is an ordered pair. (Contributed by NM, 14-Dec-2008.) (Proof shortened by Andrew Salmon, 27-Aug-2011.) |
| ⊢ (𝐴 ∈ (V × V) ↔ dom {𝐴} ≠ ∅) | ||
| Theorem | rnsnn0 6163 | The range of a singleton is nonzero iff the singleton argument is an ordered pair. (Contributed by NM, 14-Dec-2008.) |
| ⊢ (𝐴 ∈ (V × V) ↔ ran {𝐴} ≠ ∅) | ||
| Theorem | dmsn0 6164 | The domain of the singleton of the empty set is empty. (Contributed by NM, 30-Jan-2004.) |
| ⊢ dom {∅} = ∅ | ||
| Theorem | cnvsn0 6165 | The converse of the singleton of the empty set is empty. (Contributed by Mario Carneiro, 30-Aug-2015.) |
| ⊢ ◡{∅} = ∅ | ||
| Theorem | dmsn0el 6166 | The domain of a singleton is empty if the singleton's argument contains the empty set. (Contributed by NM, 15-Dec-2008.) |
| ⊢ (∅ ∈ 𝐴 → dom {𝐴} = ∅) | ||
| Theorem | relsn2 6167 | A singleton is a relation iff it has a nonempty domain. (Contributed by NM, 25-Sep-2013.) Make hypothesis an antecedent. (Revised by BJ, 12-Feb-2022.) |
| ⊢ (𝐴 ∈ 𝑉 → (Rel {𝐴} ↔ dom {𝐴} ≠ ∅)) | ||
| Theorem | dmsnopg 6168 | The domain of a singleton of an ordered pair is the singleton of the first member. (Contributed by Mario Carneiro, 26-Apr-2015.) |
| ⊢ (𝐵 ∈ 𝑉 → dom {〈𝐴, 𝐵〉} = {𝐴}) | ||
| Theorem | dmsnopss 6169 | The domain of a singleton of an ordered pair is a subset of the singleton of the first member (with no sethood assumptions on 𝐵). (Contributed by Mario Carneiro, 30-Apr-2015.) |
| ⊢ dom {〈𝐴, 𝐵〉} ⊆ {𝐴} | ||
| Theorem | dmpropg 6170 | The domain of an unordered pair of ordered pairs. (Contributed by Mario Carneiro, 26-Apr-2015.) |
| ⊢ ((𝐵 ∈ 𝑉 ∧ 𝐷 ∈ 𝑊) → dom {〈𝐴, 𝐵〉, 〈𝐶, 𝐷〉} = {𝐴, 𝐶}) | ||
| Theorem | dmsnop 6171 | The domain of a singleton of an ordered pair is the singleton of the first member. (Contributed by NM, 30-Jan-2004.) (Proof shortened by Andrew Salmon, 27-Aug-2011.) (Revised by Mario Carneiro, 26-Apr-2015.) |
| ⊢ 𝐵 ∈ V ⇒ ⊢ dom {〈𝐴, 𝐵〉} = {𝐴} | ||
| Theorem | dmprop 6172 | The domain of an unordered pair of ordered pairs. (Contributed by NM, 13-Sep-2011.) |
| ⊢ 𝐵 ∈ V & ⊢ 𝐷 ∈ V ⇒ ⊢ dom {〈𝐴, 𝐵〉, 〈𝐶, 𝐷〉} = {𝐴, 𝐶} | ||
| Theorem | dmtpop 6173 | The domain of an unordered triple of ordered pairs. (Contributed by NM, 14-Sep-2011.) |
| ⊢ 𝐵 ∈ V & ⊢ 𝐷 ∈ V & ⊢ 𝐹 ∈ V ⇒ ⊢ dom {〈𝐴, 𝐵〉, 〈𝐶, 𝐷〉, 〈𝐸, 𝐹〉} = {𝐴, 𝐶, 𝐸} | ||
| Theorem | cnvcnvsn 6174 | Double converse of a singleton of an ordered pair. (Unlike cnvsn 6181, this does not need any sethood assumptions on 𝐴 and 𝐵.) (Contributed by Mario Carneiro, 26-Apr-2015.) |
| ⊢ ◡◡{〈𝐴, 𝐵〉} = ◡{〈𝐵, 𝐴〉} | ||
| Theorem | dmsnsnsn 6175 | The domain of the singleton of the singleton of a singleton. (Contributed by NM, 15-Sep-2004.) (Revised by Mario Carneiro, 26-Apr-2015.) |
| ⊢ dom {{{𝐴}}} = {𝐴} | ||
| Theorem | rnsnopg 6176 | The range of a singleton of an ordered pair is the singleton of the second member. (Contributed by NM, 24-Jul-2004.) (Revised by Mario Carneiro, 30-Apr-2015.) |
| ⊢ (𝐴 ∈ 𝑉 → ran {〈𝐴, 𝐵〉} = {𝐵}) | ||
| Theorem | rnpropg 6177 | The range of a pair of ordered pairs is the pair of second members. (Contributed by Thierry Arnoux, 3-Jan-2017.) |
| ⊢ ((𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊) → ran {〈𝐴, 𝐶〉, 〈𝐵, 𝐷〉} = {𝐶, 𝐷}) | ||
| Theorem | cnvsng 6178 | Converse of a singleton of an ordered pair. (Contributed by NM, 23-Jan-2015.) (Proof shortened by BJ, 12-Feb-2022.) |
| ⊢ ((𝐴 ∈ 𝑉 ∧ 𝐵 ∈ 𝑊) → ◡{〈𝐴, 𝐵〉} = {〈𝐵, 𝐴〉}) | ||
| Theorem | rnsnop 6179 | The range of a singleton of an ordered pair is the singleton of the second member. (Contributed by NM, 24-Jul-2004.) (Revised by Mario Carneiro, 26-Apr-2015.) |
| ⊢ 𝐴 ∈ V ⇒ ⊢ ran {〈𝐴, 𝐵〉} = {𝐵} | ||
| Theorem | op1sta 6180 | Extract the first member of an ordered pair. (See op2nda 6183 to extract the second member, op1stb 5416 for an alternate version, and op1st 7938 for the preferred version.) (Contributed by Raph Levien, 4-Dec-2003.) |
| ⊢ 𝐴 ∈ V & ⊢ 𝐵 ∈ V ⇒ ⊢ ∪ dom {〈𝐴, 𝐵〉} = 𝐴 | ||
| Theorem | cnvsn 6181 | Converse of a singleton of an ordered pair. (Contributed by NM, 11-May-1998.) (Revised by Mario Carneiro, 26-Apr-2015.) (Proof shortened by BJ, 12-Feb-2022.) |
| ⊢ 𝐴 ∈ V & ⊢ 𝐵 ∈ V ⇒ ⊢ ◡{〈𝐴, 𝐵〉} = {〈𝐵, 𝐴〉} | ||
| Theorem | op2ndb 6182 | Extract the second member of an ordered pair. Theorem 5.12(ii) of [Monk1] p. 52. (See op1stb 5416 to extract the first member, op2nda 6183 for an alternate version, and op2nd 7939 for the preferred version.) (Contributed by NM, 25-Nov-2003.) |
| ⊢ 𝐴 ∈ V & ⊢ 𝐵 ∈ V ⇒ ⊢ ∩ ∩ ∩ ◡{〈𝐴, 𝐵〉} = 𝐵 | ||
| Theorem | op2nda 6183 | Extract the second member of an ordered pair. (See op1sta 6180 to extract the first member, op2ndb 6182 for an alternate version, and op2nd 7939 for the preferred version.) (Contributed by NM, 17-Feb-2004.) (Proof shortened by Andrew Salmon, 27-Aug-2011.) |
| ⊢ 𝐴 ∈ V & ⊢ 𝐵 ∈ V ⇒ ⊢ ∪ ran {〈𝐴, 𝐵〉} = 𝐵 | ||
| Theorem | opswap 6184 | Swap the members of an ordered pair. (Contributed by NM, 14-Dec-2008.) (Revised by Mario Carneiro, 30-Aug-2015.) |
| ⊢ ∪ ◡{〈𝐴, 𝐵〉} = 〈𝐵, 𝐴〉 | ||
| Theorem | cnvresima 6185 | An image under the converse of a restriction. (Contributed by Jeff Hankins, 12-Jul-2009.) |
| ⊢ (◡(𝐹 ↾ 𝐴) “ 𝐵) = ((◡𝐹 “ 𝐵) ∩ 𝐴) | ||
| Theorem | resdm2 6186 | A class restricted to its domain equals its double converse. (Contributed by NM, 8-Apr-2007.) |
| ⊢ (𝐴 ↾ dom 𝐴) = ◡◡𝐴 | ||
| Theorem | resdmres 6187 | Restriction to the domain of a restriction. (Contributed by NM, 8-Apr-2007.) |
| ⊢ (𝐴 ↾ dom (𝐴 ↾ 𝐵)) = (𝐴 ↾ 𝐵) | ||
| Theorem | resresdm 6188 | A restriction by an arbitrary set is a restriction by its domain. (Contributed by AV, 16-Nov-2020.) |
| ⊢ (𝐹 = (𝐸 ↾ 𝐴) → 𝐹 = (𝐸 ↾ dom 𝐹)) | ||
| Theorem | imadmres 6189 | The image of the domain of a restriction. (Contributed by NM, 8-Apr-2007.) |
| ⊢ (𝐴 “ dom (𝐴 ↾ 𝐵)) = (𝐴 “ 𝐵) | ||
| Theorem | resdmss 6190 | Subset relationship for the domain of a restriction. (Contributed by Scott Fenton, 9-Aug-2024.) |
| ⊢ dom (𝐴 ↾ 𝐵) ⊆ 𝐵 | ||
| Theorem | resdifdi 6191 | Distributive law for restriction over difference. (Contributed by BTernaryTau, 15-Aug-2024.) |
| ⊢ (𝐴 ↾ (𝐵 ∖ 𝐶)) = ((𝐴 ↾ 𝐵) ∖ (𝐴 ↾ 𝐶)) | ||
| Theorem | resdifdir 6192 | Distributive law for restriction over difference. (Contributed by BTernaryTau, 15-Aug-2024.) |
| ⊢ ((𝐴 ∖ 𝐵) ↾ 𝐶) = ((𝐴 ↾ 𝐶) ∖ (𝐵 ↾ 𝐶)) | ||
| Theorem | mptpreima 6193* | The preimage of a function in maps-to notation. (Contributed by Stefan O'Rear, 25-Jan-2015.) |
| ⊢ 𝐹 = (𝑥 ∈ 𝐴 ↦ 𝐵) ⇒ ⊢ (◡𝐹 “ 𝐶) = {𝑥 ∈ 𝐴 ∣ 𝐵 ∈ 𝐶} | ||
| Theorem | mptiniseg 6194* | Converse singleton image of a function defined by maps-to. (Contributed by Stefan O'Rear, 25-Jan-2015.) |
| ⊢ 𝐹 = (𝑥 ∈ 𝐴 ↦ 𝐵) ⇒ ⊢ (𝐶 ∈ 𝑉 → (◡𝐹 “ {𝐶}) = {𝑥 ∈ 𝐴 ∣ 𝐵 = 𝐶}) | ||
| Theorem | dmmpt 6195 | The domain of the mapping operation in general. (Contributed by NM, 16-May-1995.) (Revised by Mario Carneiro, 22-Mar-2015.) |
| ⊢ 𝐹 = (𝑥 ∈ 𝐴 ↦ 𝐵) ⇒ ⊢ dom 𝐹 = {𝑥 ∈ 𝐴 ∣ 𝐵 ∈ V} | ||
| Theorem | dmmptss 6196* | The domain of a mapping is a subset of its base class. (Contributed by Scott Fenton, 17-Jun-2013.) |
| ⊢ 𝐹 = (𝑥 ∈ 𝐴 ↦ 𝐵) ⇒ ⊢ dom 𝐹 ⊆ 𝐴 | ||
| Theorem | dmmptg 6197* | The domain of the mapping operation is the stated domain, if the function value is always a set. (Contributed by Mario Carneiro, 9-Feb-2013.) (Revised by Mario Carneiro, 14-Sep-2013.) |
| ⊢ (∀𝑥 ∈ 𝐴 𝐵 ∈ 𝑉 → dom (𝑥 ∈ 𝐴 ↦ 𝐵) = 𝐴) | ||
| Theorem | rnmpt0f 6198* | The range of a function in maps-to notation is empty if and only if its domain is empty. (Contributed by Glauco Siliprandi, 8-Apr-2021.) |
| ⊢ Ⅎ𝑥𝜑 & ⊢ ((𝜑 ∧ 𝑥 ∈ 𝐴) → 𝐵 ∈ 𝑉) & ⊢ 𝐹 = (𝑥 ∈ 𝐴 ↦ 𝐵) ⇒ ⊢ (𝜑 → (ran 𝐹 = ∅ ↔ 𝐴 = ∅)) | ||
| Theorem | rnmptn0 6199* | The range of a function in maps-to notation is nonempty if the domain is nonempty. (Contributed by Glauco Siliprandi, 8-Apr-2021.) |
| ⊢ Ⅎ𝑥𝜑 & ⊢ ((𝜑 ∧ 𝑥 ∈ 𝐴) → 𝐵 ∈ 𝑉) & ⊢ 𝐹 = (𝑥 ∈ 𝐴 ↦ 𝐵) & ⊢ (𝜑 → 𝐴 ≠ ∅) ⇒ ⊢ (𝜑 → ran 𝐹 ≠ ∅) | ||
| Theorem | dfco2 6200* | Alternate definition of a class composition, using only one bound variable. (Contributed by NM, 19-Dec-2008.) |
| ⊢ (𝐴 ∘ 𝐵) = ∪ 𝑥 ∈ V ((◡𝐵 “ {𝑥}) × (𝐴 “ {𝑥})) | ||
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