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Theorem nfsbxy 2002
Description: Similar to hbsb 2009 but with an extra distinct variable constraint, on 𝑥 and 𝑦. (Contributed by Jim Kingdon, 19-Mar-2018.)
Hypothesis
Ref Expression
nfsbxy.1 Ⅎ𝑧𝜑
Assertion
Ref Expression
nfsbxy Ⅎ𝑧[𝑦 / 𝑥]𝜑
Distinct variable groups:   𝑥,𝑦   𝑦,𝑧
Allowed substitution hints:   𝜑(𝑥, 𝑦, 𝑧)

Proof of Theorem nfsbxy
StepHypRef Expression
1 ax-bndl 1562 . 2 (∀𝑧 𝑧 = 𝑥 ∨ (∀𝑧 𝑧 = 𝑦 ∨ ∀𝑥∀𝑧(𝑥 = 𝑦 → ∀𝑧 𝑥 = 𝑦)))
2 nfs1v 1999 . . . 4 Ⅎ𝑧[𝑦 / 𝑧]𝜑
3 drsb1 1852 . . . . 5 (∀𝑧 𝑧 = 𝑥 → ([𝑦 / 𝑧]𝜑 ↔ [𝑦 / 𝑥]𝜑))
43drnf2 1787 . . . 4 (∀𝑧 𝑧 = 𝑥 → (Ⅎ𝑧[𝑦 / 𝑧]𝜑 ↔ Ⅎ𝑧[𝑦 / 𝑥]𝜑))
52, 4mpbii 148 . . 3 (∀𝑧 𝑧 = 𝑥 → Ⅎ𝑧[𝑦 / 𝑥]𝜑)
6 a16nf 1919 . . . 4 (∀𝑧 𝑧 = 𝑦 → Ⅎ𝑧[𝑦 / 𝑥]𝜑)
7 df-nf 1514 . . . . . 6 (Ⅎ𝑧 𝑥 = 𝑦 ↔ ∀𝑧(𝑥 = 𝑦 → ∀𝑧 𝑥 = 𝑦))
87albii 1523 . . . . 5 (∀𝑥Ⅎ𝑧 𝑥 = 𝑦 ↔ ∀𝑥∀𝑧(𝑥 = 𝑦 → ∀𝑧 𝑥 = 𝑦))
9 sb5 1942 . . . . . 6 ([𝑦 / 𝑥]𝜑 ↔ ∃𝑥(𝑥 = 𝑦 ∧ 𝜑))
10 nfa1 1594 . . . . . . 7 Ⅎ𝑥∀𝑥Ⅎ𝑧 𝑥 = 𝑦
11 sp 1564 . . . . . . . 8 (∀𝑥Ⅎ𝑧 𝑥 = 𝑦 → Ⅎ𝑧 𝑥 = 𝑦)
12 nfsbxy.1 . . . . . . . . 9 Ⅎ𝑧𝜑
1312a1i 9 . . . . . . . 8 (∀𝑥Ⅎ𝑧 𝑥 = 𝑦 → Ⅎ𝑧𝜑)
1411, 13nfand 1621 . . . . . . 7 (∀𝑥Ⅎ𝑧 𝑥 = 𝑦 → Ⅎ𝑧(𝑥 = 𝑦 ∧ 𝜑))
1510, 14nfexd 1814 . . . . . 6 (∀𝑥Ⅎ𝑧 𝑥 = 𝑦 → Ⅎ𝑧∃𝑥(𝑥 = 𝑦 ∧ 𝜑))
169, 15nfxfrd 1528 . . . . 5 (∀𝑥Ⅎ𝑧 𝑥 = 𝑦 → Ⅎ𝑧[𝑦 / 𝑥]𝜑)
178, 16sylbir 135 . . . 4 (∀𝑥∀𝑧(𝑥 = 𝑦 → ∀𝑧 𝑥 = 𝑦) → Ⅎ𝑧[𝑦 / 𝑥]𝜑)
186, 17jaoi 728 . . 3 ((∀𝑧 𝑧 = 𝑦 ∨ ∀𝑥∀𝑧(𝑥 = 𝑦 → ∀𝑧 𝑥 = 𝑦)) → Ⅎ𝑧[𝑦 / 𝑥]𝜑)
195, 18jaoi 728 . 2 ((∀𝑧 𝑧 = 𝑥 ∨ (∀𝑧 𝑧 = 𝑦 ∨ ∀𝑥∀𝑧(𝑥 = 𝑦 → ∀𝑧 𝑥 = 𝑦))) → Ⅎ𝑧[𝑦 / 𝑥]𝜑)
201, 19ax-mp 5 1 Ⅎ𝑧[𝑦 / 𝑥]𝜑
Colors of variables:    wff set class
This proof depends on syntax axioms:   → wi 4   ∧ wa 104   ∨ wo 720  ∀wal 1400  Ⅎwnf 1513  ∃wex 1545  [wsb 1815
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-io 721  ax-5 1500  ax-7 1501  ax-gen 1502  ax-ie1 1546  ax-ie2 1547  ax-8 1557  ax-10 1558  ax-11 1559  ax-i12 1560  ax-bndl 1562  ax-4 1563  ax-17 1579  ax-i9 1583  ax-ial 1587
This proof depends on definitions:  df-bi 117  df-nf 1514  df-sb 1816
This theorem is used by:  nfsb  2006  sbalyz  2059  opelopabsb  4402  bezoutlemmain  12794
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