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Theorem reseq1 4903
Description: Equality theorem for restrictions. (Contributed by NM, 7-Aug-1994.)
Assertion
Ref Expression
reseq1 (𝐴 = 𝐵 → (𝐴𝐶) = (𝐵𝐶))

Proof of Theorem reseq1
StepHypRef Expression
1 ineq1 3331 . 2 (𝐴 = 𝐵 → (𝐴 ∩ (𝐶 × V)) = (𝐵 ∩ (𝐶 × V)))
2 df-res 4640 . 2 (𝐴𝐶) = (𝐴 ∩ (𝐶 × V))
3 df-res 4640 . 2 (𝐵𝐶) = (𝐵 ∩ (𝐶 × V))
41, 2, 33eqtr4g 2235 1 (𝐴 = 𝐵 → (𝐴𝐶) = (𝐵𝐶))
Colors of variables: wff set class
Syntax hints:  wi 4   = wceq 1353  Vcvv 2739  cin 3130   × cxp 4626  cres 4630
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-io 709  ax-5 1447  ax-7 1448  ax-gen 1449  ax-ie1 1493  ax-ie2 1494  ax-8 1504  ax-10 1505  ax-11 1506  ax-i12 1507  ax-bndl 1509  ax-4 1510  ax-17 1526  ax-i9 1530  ax-ial 1534  ax-i5r 1535  ax-ext 2159
This theorem depends on definitions:  df-bi 117  df-tru 1356  df-nf 1461  df-sb 1763  df-clab 2164  df-cleq 2170  df-clel 2173  df-nfc 2308  df-v 2741  df-in 3137  df-res 4640
This theorem is referenced by:  reseq1i  4905  reseq1d  4908  imaeq1  4967  relcoi1  5162  tfr0dm  6325  tfrlemiex  6334  tfr1onlemex  6350  tfr1onlemaccex  6351  tfrcllemsucaccv  6357  tfrcllembxssdm  6359  tfrcllemex  6363  tfrcllemaccex  6364  tfrcllemres  6365  pmresg  6678  lmbr  13798
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