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Theorem reseq1 4878
Description: Equality theorem for restrictions. (Contributed by NM, 7-Aug-1994.)
Assertion
Ref Expression
reseq1 (𝐴 = 𝐵 → (𝐴𝐶) = (𝐵𝐶))

Proof of Theorem reseq1
StepHypRef Expression
1 ineq1 3316 . 2 (𝐴 = 𝐵 → (𝐴 ∩ (𝐶 × V)) = (𝐵 ∩ (𝐶 × V)))
2 df-res 4616 . 2 (𝐴𝐶) = (𝐴 ∩ (𝐶 × V))
3 df-res 4616 . 2 (𝐵𝐶) = (𝐵 ∩ (𝐶 × V))
41, 2, 33eqtr4g 2224 1 (𝐴 = 𝐵 → (𝐴𝐶) = (𝐵𝐶))
Colors of variables: wff set class
Syntax hints:  wi 4   = wceq 1343  Vcvv 2726  cin 3115   × cxp 4602  cres 4606
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-io 699  ax-5 1435  ax-7 1436  ax-gen 1437  ax-ie1 1481  ax-ie2 1482  ax-8 1492  ax-10 1493  ax-11 1494  ax-i12 1495  ax-bndl 1497  ax-4 1498  ax-17 1514  ax-i9 1518  ax-ial 1522  ax-i5r 1523  ax-ext 2147
This theorem depends on definitions:  df-bi 116  df-tru 1346  df-nf 1449  df-sb 1751  df-clab 2152  df-cleq 2158  df-clel 2161  df-nfc 2297  df-v 2728  df-in 3122  df-res 4616
This theorem is referenced by:  reseq1i  4880  reseq1d  4883  imaeq1  4941  relcoi1  5135  tfr0dm  6290  tfrlemiex  6299  tfr1onlemex  6315  tfr1onlemaccex  6316  tfrcllemsucaccv  6322  tfrcllembxssdm  6324  tfrcllemex  6328  tfrcllemaccex  6329  tfrcllemres  6330  pmresg  6642  lmbr  12853
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