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Theorem reseq1 5005
Description: Equality theorem for restrictions. (Contributed by NM, 7-Aug-1994.)
Assertion
Ref Expression
reseq1 (𝐴 = 𝐵 → (𝐴𝐶) = (𝐵𝐶))

Proof of Theorem reseq1
StepHypRef Expression
1 ineq1 3399 . 2 (𝐴 = 𝐵 → (𝐴 ∩ (𝐶 × V)) = (𝐵 ∩ (𝐶 × V)))
2 df-res 4735 . 2 (𝐴𝐶) = (𝐴 ∩ (𝐶 × V))
3 df-res 4735 . 2 (𝐵𝐶) = (𝐵 ∩ (𝐶 × V))
41, 2, 33eqtr4g 2287 1 (𝐴 = 𝐵 → (𝐴𝐶) = (𝐵𝐶))
Colors of variables: wff set class
Syntax hints:  wi 4   = wceq 1395  Vcvv 2800  cin 3197   × cxp 4721  cres 4725
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-io 714  ax-5 1493  ax-7 1494  ax-gen 1495  ax-ie1 1539  ax-ie2 1540  ax-8 1550  ax-10 1551  ax-11 1552  ax-i12 1553  ax-bndl 1555  ax-4 1556  ax-17 1572  ax-i9 1576  ax-ial 1580  ax-i5r 1581  ax-ext 2211
This theorem depends on definitions:  df-bi 117  df-tru 1398  df-nf 1507  df-sb 1809  df-clab 2216  df-cleq 2222  df-clel 2225  df-nfc 2361  df-v 2802  df-in 3204  df-res 4735
This theorem is referenced by:  reseq1i  5007  reseq1d  5010  imaeq1  5069  relcoi1  5266  tfr0dm  6483  tfrlemiex  6492  tfr1onlemex  6508  tfr1onlemaccex  6509  tfrcllemsucaccv  6515  tfrcllembxssdm  6517  tfrcllemex  6521  tfrcllemaccex  6522  tfrcllemres  6523  pmresg  6840  lmbr  14927
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