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Theorem reseq1 5013
Description: Equality theorem for restrictions. (Contributed by NM, 7-Aug-1994.)
Assertion
Ref Expression
reseq1 (𝐴 = 𝐵 → (𝐴𝐶) = (𝐵𝐶))

Proof of Theorem reseq1
StepHypRef Expression
1 ineq1 3403 . 2 (𝐴 = 𝐵 → (𝐴 ∩ (𝐶 × V)) = (𝐵 ∩ (𝐶 × V)))
2 df-res 4743 . 2 (𝐴𝐶) = (𝐴 ∩ (𝐶 × V))
3 df-res 4743 . 2 (𝐵𝐶) = (𝐵 ∩ (𝐶 × V))
41, 2, 33eqtr4g 2289 1 (𝐴 = 𝐵 → (𝐴𝐶) = (𝐵𝐶))
Colors of variables: wff set class
Syntax hints:  wi 4   = wceq 1398  Vcvv 2803  cin 3200   × cxp 4729  cres 4733
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-io 717  ax-5 1496  ax-7 1497  ax-gen 1498  ax-ie1 1542  ax-ie2 1543  ax-8 1553  ax-10 1554  ax-11 1555  ax-i12 1556  ax-bndl 1558  ax-4 1559  ax-17 1575  ax-i9 1579  ax-ial 1583  ax-i5r 1584  ax-ext 2213
This theorem depends on definitions:  df-bi 117  df-tru 1401  df-nf 1510  df-sb 1811  df-clab 2218  df-cleq 2224  df-clel 2227  df-nfc 2364  df-v 2805  df-in 3207  df-res 4743
This theorem is referenced by:  reseq1i  5015  reseq1d  5018  imaeq1  5077  relcoi1  5275  tfr0dm  6531  tfrlemiex  6540  tfr1onlemex  6556  tfr1onlemaccex  6557  tfrcllemsucaccv  6563  tfrcllembxssdm  6565  tfrcllemex  6569  tfrcllemaccex  6570  tfrcllemres  6571  pmresg  6888  lmbr  15007
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