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Theorem reseq1 4936
Description: Equality theorem for restrictions. (Contributed by NM, 7-Aug-1994.)
Assertion
Ref Expression
reseq1 (𝐴 = 𝐵 → (𝐴𝐶) = (𝐵𝐶))

Proof of Theorem reseq1
StepHypRef Expression
1 ineq1 3353 . 2 (𝐴 = 𝐵 → (𝐴 ∩ (𝐶 × V)) = (𝐵 ∩ (𝐶 × V)))
2 df-res 4671 . 2 (𝐴𝐶) = (𝐴 ∩ (𝐶 × V))
3 df-res 4671 . 2 (𝐵𝐶) = (𝐵 ∩ (𝐶 × V))
41, 2, 33eqtr4g 2251 1 (𝐴 = 𝐵 → (𝐴𝐶) = (𝐵𝐶))
Colors of variables: wff set class
Syntax hints:  wi 4   = wceq 1364  Vcvv 2760  cin 3152   × cxp 4657  cres 4661
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-io 710  ax-5 1458  ax-7 1459  ax-gen 1460  ax-ie1 1504  ax-ie2 1505  ax-8 1515  ax-10 1516  ax-11 1517  ax-i12 1518  ax-bndl 1520  ax-4 1521  ax-17 1537  ax-i9 1541  ax-ial 1545  ax-i5r 1546  ax-ext 2175
This theorem depends on definitions:  df-bi 117  df-tru 1367  df-nf 1472  df-sb 1774  df-clab 2180  df-cleq 2186  df-clel 2189  df-nfc 2325  df-v 2762  df-in 3159  df-res 4671
This theorem is referenced by:  reseq1i  4938  reseq1d  4941  imaeq1  5000  relcoi1  5197  tfr0dm  6375  tfrlemiex  6384  tfr1onlemex  6400  tfr1onlemaccex  6401  tfrcllemsucaccv  6407  tfrcllembxssdm  6409  tfrcllemex  6413  tfrcllemaccex  6414  tfrcllemres  6415  pmresg  6730  lmbr  14381
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