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Theorem reseq1 4998
Description: Equality theorem for restrictions. (Contributed by NM, 7-Aug-1994.)
Assertion
Ref Expression
reseq1 (𝐴 = 𝐵 → (𝐴𝐶) = (𝐵𝐶))

Proof of Theorem reseq1
StepHypRef Expression
1 ineq1 3398 . 2 (𝐴 = 𝐵 → (𝐴 ∩ (𝐶 × V)) = (𝐵 ∩ (𝐶 × V)))
2 df-res 4730 . 2 (𝐴𝐶) = (𝐴 ∩ (𝐶 × V))
3 df-res 4730 . 2 (𝐵𝐶) = (𝐵 ∩ (𝐶 × V))
41, 2, 33eqtr4g 2287 1 (𝐴 = 𝐵 → (𝐴𝐶) = (𝐵𝐶))
Colors of variables: wff set class
Syntax hints:  wi 4   = wceq 1395  Vcvv 2799  cin 3196   × cxp 4716  cres 4720
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-io 714  ax-5 1493  ax-7 1494  ax-gen 1495  ax-ie1 1539  ax-ie2 1540  ax-8 1550  ax-10 1551  ax-11 1552  ax-i12 1553  ax-bndl 1555  ax-4 1556  ax-17 1572  ax-i9 1576  ax-ial 1580  ax-i5r 1581  ax-ext 2211
This theorem depends on definitions:  df-bi 117  df-tru 1398  df-nf 1507  df-sb 1809  df-clab 2216  df-cleq 2222  df-clel 2225  df-nfc 2361  df-v 2801  df-in 3203  df-res 4730
This theorem is referenced by:  reseq1i  5000  reseq1d  5003  imaeq1  5062  relcoi1  5259  tfr0dm  6466  tfrlemiex  6475  tfr1onlemex  6491  tfr1onlemaccex  6492  tfrcllemsucaccv  6498  tfrcllembxssdm  6500  tfrcllemex  6504  tfrcllemaccex  6505  tfrcllemres  6506  pmresg  6821  lmbr  14881
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