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Theorem reseq1 5032
Description: Equality theorem for restrictions. (Contributed by NM, 7-Aug-1994.)
Assertion
Ref Expression
reseq1 (𝐴 = 𝐵 → (𝐴𝐶) = (𝐵𝐶))

Proof of Theorem reseq1
StepHypRef Expression
1 ineq1 3415 . 2 (𝐴 = 𝐵 → (𝐴 ∩ (𝐶 × V)) = (𝐵 ∩ (𝐶 × V)))
2 df-res 4761 . 2 (𝐴𝐶) = (𝐴 ∩ (𝐶 × V))
3 df-res 4761 . 2 (𝐵𝐶) = (𝐵 ∩ (𝐶 × V))
41, 2, 33eqtr4g 2290 1 (𝐴 = 𝐵 → (𝐴𝐶) = (𝐵𝐶))
Colors of variables: wff set class
Syntax hints:  wi 4   = wceq 1398  Vcvv 2813  cin 3210   × cxp 4747  cres 4751
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-io 717  ax-5 1496  ax-7 1497  ax-gen 1498  ax-ie1 1542  ax-ie2 1543  ax-8 1553  ax-10 1554  ax-11 1555  ax-i12 1556  ax-bndl 1558  ax-4 1559  ax-17 1575  ax-i9 1579  ax-ial 1583  ax-i5r 1584  ax-ext 2214
This theorem depends on definitions:  df-bi 117  df-tru 1401  df-nf 1510  df-sb 1812  df-clab 2219  df-cleq 2225  df-clel 2228  df-nfc 2373  df-v 2815  df-in 3217  df-res 4761
This theorem is referenced by:  reseq1i  5034  reseq1d  5037  imaeq1  5096  relcoi1  5294  tfr0dm  6553  tfrlemiex  6562  tfr1onlemex  6578  tfr1onlemaccex  6579  tfrcllemsucaccv  6585  tfrcllembxssdm  6587  tfrcllemex  6591  tfrcllemaccex  6592  tfrcllemres  6593  pmresg  6910  mapunen  7104  lmbr  15078
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