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Theorem reseq1 5052
Description: Equality theorem for restrictions. (Contributed by NM, 7-Aug-1994.)
Assertion
Ref Expression
reseq1 (𝐴 = 𝐵 → (𝐴𝐶) = (𝐵𝐶))

Proof of Theorem reseq1
StepHypRef Expression
1 ineq1 3425 . 2 (𝐴 = 𝐵 → (𝐴 ∩ (𝐶 × V)) = (𝐵 ∩ (𝐶 × V)))
2 df-res 4781 . 2 (𝐴𝐶) = (𝐴 ∩ (𝐶 × V))
3 df-res 4781 . 2 (𝐵𝐶) = (𝐵 ∩ (𝐶 × V))
41, 2, 33eqtr4g 2296 1 (𝐴 = 𝐵 → (𝐴𝐶) = (𝐵𝐶))
Colors of variables: wff set class
Syntax hints:  wi 4   = wceq 1402  Vcvv 2821  cin 3219   × cxp 4767  cres 4771
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-io 721  ax-5 1500  ax-7 1501  ax-gen 1502  ax-ie1 1546  ax-ie2 1547  ax-8 1557  ax-10 1558  ax-11 1559  ax-i12 1560  ax-bndl 1562  ax-4 1563  ax-17 1579  ax-i9 1583  ax-ial 1587  ax-i5r 1588  ax-ext 2220
This theorem depends on definitions:  df-bi 117  df-tru 1405  df-nf 1514  df-sb 1816  df-clab 2225  df-cleq 2231  df-clel 2234  df-nfc 2381  df-v 2823  df-in 3226  df-res 4781
This theorem is referenced by:  reseq1i  5054  reseq1d  5057  imaeq1  5116  relcoi1  5314  tfr0dm  6583  tfrlemiex  6592  tfr1onlemex  6608  tfr1onlemaccex  6609  tfrcllemsucaccv  6615  tfrcllembxssdm  6617  tfrcllemex  6621  tfrcllemaccex  6622  tfrcllemres  6623  pmresg  6947  mapunen  7141  hashf1lem1  11263  lmbr  15237
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