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Theorem reseq1 4962
Description: Equality theorem for restrictions. (Contributed by NM, 7-Aug-1994.)
Assertion
Ref Expression
reseq1 (𝐴 = 𝐵 → (𝐴𝐶) = (𝐵𝐶))

Proof of Theorem reseq1
StepHypRef Expression
1 ineq1 3371 . 2 (𝐴 = 𝐵 → (𝐴 ∩ (𝐶 × V)) = (𝐵 ∩ (𝐶 × V)))
2 df-res 4695 . 2 (𝐴𝐶) = (𝐴 ∩ (𝐶 × V))
3 df-res 4695 . 2 (𝐵𝐶) = (𝐵 ∩ (𝐶 × V))
41, 2, 33eqtr4g 2264 1 (𝐴 = 𝐵 → (𝐴𝐶) = (𝐵𝐶))
Colors of variables: wff set class
Syntax hints:  wi 4   = wceq 1373  Vcvv 2773  cin 3169   × cxp 4681  cres 4685
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-io 711  ax-5 1471  ax-7 1472  ax-gen 1473  ax-ie1 1517  ax-ie2 1518  ax-8 1528  ax-10 1529  ax-11 1530  ax-i12 1531  ax-bndl 1533  ax-4 1534  ax-17 1550  ax-i9 1554  ax-ial 1558  ax-i5r 1559  ax-ext 2188
This theorem depends on definitions:  df-bi 117  df-tru 1376  df-nf 1485  df-sb 1787  df-clab 2193  df-cleq 2199  df-clel 2202  df-nfc 2338  df-v 2775  df-in 3176  df-res 4695
This theorem is referenced by:  reseq1i  4964  reseq1d  4967  imaeq1  5026  relcoi1  5223  tfr0dm  6421  tfrlemiex  6430  tfr1onlemex  6446  tfr1onlemaccex  6447  tfrcllemsucaccv  6453  tfrcllembxssdm  6455  tfrcllemex  6459  tfrcllemaccex  6460  tfrcllemres  6461  pmresg  6776  lmbr  14760
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