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Theorem reseq1 5007
Description: Equality theorem for restrictions. (Contributed by NM, 7-Aug-1994.)
Assertion
Ref Expression
reseq1 (𝐴 = 𝐵 → (𝐴𝐶) = (𝐵𝐶))

Proof of Theorem reseq1
StepHypRef Expression
1 ineq1 3401 . 2 (𝐴 = 𝐵 → (𝐴 ∩ (𝐶 × V)) = (𝐵 ∩ (𝐶 × V)))
2 df-res 4737 . 2 (𝐴𝐶) = (𝐴 ∩ (𝐶 × V))
3 df-res 4737 . 2 (𝐵𝐶) = (𝐵 ∩ (𝐶 × V))
41, 2, 33eqtr4g 2289 1 (𝐴 = 𝐵 → (𝐴𝐶) = (𝐵𝐶))
Colors of variables: wff set class
Syntax hints:  wi 4   = wceq 1397  Vcvv 2802  cin 3199   × cxp 4723  cres 4727
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-io 716  ax-5 1495  ax-7 1496  ax-gen 1497  ax-ie1 1541  ax-ie2 1542  ax-8 1552  ax-10 1553  ax-11 1554  ax-i12 1555  ax-bndl 1557  ax-4 1558  ax-17 1574  ax-i9 1578  ax-ial 1582  ax-i5r 1583  ax-ext 2213
This theorem depends on definitions:  df-bi 117  df-tru 1400  df-nf 1509  df-sb 1811  df-clab 2218  df-cleq 2224  df-clel 2227  df-nfc 2363  df-v 2804  df-in 3206  df-res 4737
This theorem is referenced by:  reseq1i  5009  reseq1d  5012  imaeq1  5071  relcoi1  5268  tfr0dm  6487  tfrlemiex  6496  tfr1onlemex  6512  tfr1onlemaccex  6513  tfrcllemsucaccv  6519  tfrcllembxssdm  6521  tfrcllemex  6525  tfrcllemaccex  6526  tfrcllemres  6527  pmresg  6844  lmbr  14936
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