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Theorem tfr1onlemex 6618
Description: Lemma for tfr1on 6621. (Contributed by Jim Kingdon, 16-Mar-2022.)
Hypotheses
Ref Expression
tfr1on.f 𝐹 = recs(𝐺)
tfr1on.g (𝜑 → Fun 𝐺)
tfr1on.x (𝜑 → Ord 𝑋)
tfr1on.ex ((𝜑𝑥𝑋𝑓 Fn 𝑥) → (𝐺𝑓) ∈ V)
tfr1onlemsucfn.1 𝐴 = {𝑓 ∣ ∃𝑥𝑋 (𝑓 Fn 𝑥 ∧ ∀𝑦𝑥 (𝑓𝑦) = (𝐺‘(𝑓𝑦)))}
tfr1onlembacc.3 𝐵 = { ∣ ∃𝑧𝐷𝑔(𝑔 Fn 𝑧𝑔𝐴 = (𝑔 ∪ {⟨𝑧, (𝐺𝑔)⟩}))}
tfr1onlembacc.u ((𝜑𝑥 𝑋) → suc 𝑥𝑋)
tfr1onlembacc.4 (𝜑𝐷𝑋)
tfr1onlembacc.5 (𝜑 → ∀𝑧𝐷𝑔(𝑔 Fn 𝑧 ∧ ∀𝑤𝑧 (𝑔𝑤) = (𝐺‘(𝑔𝑤))))
Assertion
Ref Expression
tfr1onlemex (𝜑 → ∃𝑓(𝑓 Fn 𝐷 ∧ ∀𝑢𝐷 (𝑓𝑢) = (𝐺‘(𝑓𝑢))))
Distinct variable groups:   𝐴,𝑓,𝑔,,𝑥,𝑧   𝐷,𝑓,𝑔,𝑥   𝑓,𝐺,𝑥,𝑦   𝑓,𝑋,𝑥   𝜑,𝑓,𝑔,,𝑥,𝑧   𝑦,𝑔,𝑧   𝐵,𝑓,𝑔,,𝑤,𝑧   𝑢,𝐵,𝑓,𝑤   𝐷,,𝑤,𝑧,𝑥   𝑢,𝐷   ,𝐺,𝑧,𝑦   𝑢,𝐺,𝑤   𝑔,𝑋,𝑧   𝜑,𝑤   𝑦,𝑤
Allowed substitution hints:   𝜑(𝑦, 𝑢)   𝐴(𝑦, 𝑤, 𝑢)   𝐵(𝑥, 𝑦)   𝐷(𝑦)   𝐹(𝑥, 𝑦, 𝑧, 𝑤, 𝑢, 𝑓, 𝑔, )   𝐺(𝑔)   𝑋(𝑦, 𝑤, 𝑢, )

Proof of Theorem tfr1onlemex
StepHypRef Expression
1 tfr1on.f . . . 4 𝐹 = recs(𝐺)
2 tfr1on.g . . . 4 (𝜑 → Fun 𝐺)
3 tfr1on.x . . . 4 (𝜑 → Ord 𝑋)
4 tfr1on.ex . . . 4 ((𝜑𝑥𝑋𝑓 Fn 𝑥) → (𝐺𝑓) ∈ V)
5 tfr1onlemsucfn.1 . . . 4 𝐴 = {𝑓 ∣ ∃𝑥𝑋 (𝑓 Fn 𝑥 ∧ ∀𝑦𝑥 (𝑓𝑦) = (𝐺‘(𝑓𝑦)))}
6 tfr1onlembacc.3 . . . 4 𝐵 = { ∣ ∃𝑧𝐷𝑔(𝑔 Fn 𝑧𝑔𝐴 = (𝑔 ∪ {⟨𝑧, (𝐺𝑔)⟩}))}
7 tfr1onlembacc.u . . . 4 ((𝜑𝑥 𝑋) → suc 𝑥𝑋)
8 tfr1onlembacc.4 . . . 4 (𝜑𝐷𝑋)
9 tfr1onlembacc.5 . . . 4 (𝜑 → ∀𝑧𝐷𝑔(𝑔 Fn 𝑧 ∧ ∀𝑤𝑧 (𝑔𝑤) = (𝐺‘(𝑔𝑤))))
101, 2, 3, 4, 5, 6, 7, 8, 9tfr1onlembex 6616 . . 3 (𝜑𝐵 ∈ V)
11 uniexg 4585 . . 3 (𝐵 ∈ V → 𝐵 ∈ V)
1210, 11syl 14 . 2 (𝜑 𝐵 ∈ V)
131, 2, 3, 4, 5, 6, 7, 8, 9tfr1onlembfn 6615 . . 3 (𝜑 𝐵 Fn 𝐷)
141, 2, 3, 4, 5, 6, 7, 8, 9tfr1onlemubacc 6617 . . 3 (𝜑 → ∀𝑢𝐷 ( 𝐵𝑢) = (𝐺‘( 𝐵𝑢)))
1513, 14jca 306 . 2 (𝜑 → ( 𝐵 Fn 𝐷 ∧ ∀𝑢𝐷 ( 𝐵𝑢) = (𝐺‘( 𝐵𝑢))))
16 fneq1 5469 . . . 4 (𝑓 = 𝐵 → (𝑓 Fn 𝐷 𝐵 Fn 𝐷))
17 fveq1 5694 . . . . . 6 (𝑓 = 𝐵 → (𝑓𝑢) = ( 𝐵𝑢))
18 reseq1 5057 . . . . . . 7 (𝑓 = 𝐵 → (𝑓𝑢) = ( 𝐵𝑢))
1918fveq2d 5699 . . . . . 6 (𝑓 = 𝐵 → (𝐺‘(𝑓𝑢)) = (𝐺‘( 𝐵𝑢)))
2017, 19eqeq12d 2253 . . . . 5 (𝑓 = 𝐵 → ((𝑓𝑢) = (𝐺‘(𝑓𝑢)) ↔ ( 𝐵𝑢) = (𝐺‘( 𝐵𝑢))))
2120ralbidv 2550 . . . 4 (𝑓 = 𝐵 → (∀𝑢𝐷 (𝑓𝑢) = (𝐺‘(𝑓𝑢)) ↔ ∀𝑢𝐷 ( 𝐵𝑢) = (𝐺‘( 𝐵𝑢))))
2216, 21anbi12d 477 . . 3 (𝑓 = 𝐵 → ((𝑓 Fn 𝐷 ∧ ∀𝑢𝐷 (𝑓𝑢) = (𝐺‘(𝑓𝑢))) ↔ ( 𝐵 Fn 𝐷 ∧ ∀𝑢𝐷 ( 𝐵𝑢) = (𝐺‘( 𝐵𝑢)))))
2322spcegv 2913 . 2 ( 𝐵 ∈ V → (( 𝐵 Fn 𝐷 ∧ ∀𝑢𝐷 ( 𝐵𝑢) = (𝐺‘( 𝐵𝑢))) → ∃𝑓(𝑓 Fn 𝐷 ∧ ∀𝑢𝐷 (𝑓𝑢) = (𝐺‘(𝑓𝑢)))))
2412, 15, 23sylc 62 1 (𝜑 → ∃𝑓(𝑓 Fn 𝐷 ∧ ∀𝑢𝐷 (𝑓𝑢) = (𝐺‘(𝑓𝑢))))
Colors of variables:    wff set class
This proof depends on syntax axioms:  wi 4  wa 104  w3a 1009   = wceq 1402  wex 1545  wcel 2209  {cab 2224  wral 2528  wrex 2529  Vcvv 2821  cun 3218  {csn 3709  cop 3712   cuni 3935  Ord word 4507  suc csuc 4510  cres 4776  Fun wfun 5371   Fn wfn 5372  cfv 5377  recscrecs 6575
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-in1 623  ax-in2 624  ax-io 721  ax-5 1500  ax-7 1501  ax-gen 1502  ax-ie1 1546  ax-ie2 1547  ax-8 1557  ax-10 1558  ax-11 1559  ax-i12 1560  ax-bndl 1562  ax-4 1563  ax-17 1579  ax-i9 1583  ax-ial 1587  ax-i5r 1588  ax-14 2212  ax-ext 2220  ax-coll 4246  ax-sep 4249  ax-pow 4311  ax-pr 4346  ax-un 4578  ax-setind 4684
This proof depends on definitions:  df-bi 117  df-3an 1011  df-tru 1405  df-fal 1408  df-nf 1514  df-sb 1816  df-eu 2089  df-mo 2090  df-clab 2225  df-cleq 2231  df-clel 2234  df-nfc 2381  df-ne 2421  df-ral 2533  df-rex 2534  df-reu 2535  df-rab 2537  df-v 2823  df-sbc 3052  df-csb 3148  df-dif 3222  df-un 3224  df-in 3226  df-ss 3233  df-nul 3521  df-pw 3690  df-sn 3715  df-pr 3716  df-op 3718  df-uni 3936  df-iun 4014  df-br 4131  df-opab 4193  df-mpt 4194  df-tr 4230  df-id 4438  df-iord 4511  df-on 4513  df-suc 4516  df-xp 4780  df-rel 4781  df-cnv 4782  df-co 4783  df-dm 4784  df-rn 4785  df-res 4786  df-ima 4787  df-iota 5337  df-fun 5379  df-fn 5380  df-f 5381  df-f1 5382  df-fo 5383  df-f1o 5384  df-fv 5385  df-recs 6576
This theorem is used by:  tfr1onlemaccex  6619
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