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Theorem tfr1onlemex 6405
Description: Lemma for tfr1on 6408. (Contributed by Jim Kingdon, 16-Mar-2022.)
Hypotheses
Ref Expression
tfr1on.f 𝐹 = recs(𝐺)
tfr1on.g (𝜑 → Fun 𝐺)
tfr1on.x (𝜑 → Ord 𝑋)
tfr1on.ex ((𝜑𝑥𝑋𝑓 Fn 𝑥) → (𝐺𝑓) ∈ V)
tfr1onlemsucfn.1 𝐴 = {𝑓 ∣ ∃𝑥𝑋 (𝑓 Fn 𝑥 ∧ ∀𝑦𝑥 (𝑓𝑦) = (𝐺‘(𝑓𝑦)))}
tfr1onlembacc.3 𝐵 = { ∣ ∃𝑧𝐷𝑔(𝑔 Fn 𝑧𝑔𝐴 = (𝑔 ∪ {⟨𝑧, (𝐺𝑔)⟩}))}
tfr1onlembacc.u ((𝜑𝑥 𝑋) → suc 𝑥𝑋)
tfr1onlembacc.4 (𝜑𝐷𝑋)
tfr1onlembacc.5 (𝜑 → ∀𝑧𝐷𝑔(𝑔 Fn 𝑧 ∧ ∀𝑤𝑧 (𝑔𝑤) = (𝐺‘(𝑔𝑤))))
Assertion
Ref Expression
tfr1onlemex (𝜑 → ∃𝑓(𝑓 Fn 𝐷 ∧ ∀𝑢𝐷 (𝑓𝑢) = (𝐺‘(𝑓𝑢))))
Distinct variable groups:   𝐴,𝑓,𝑔,,𝑥,𝑧   𝐷,𝑓,𝑔,𝑥   𝑓,𝐺,𝑥,𝑦   𝑓,𝑋,𝑥   𝜑,𝑓,𝑔,,𝑥,𝑧   𝑦,𝑔,𝑧   𝐵,𝑓,𝑔,,𝑤,𝑧   𝑢,𝐵,𝑓,𝑤   𝐷,,𝑤,𝑧,𝑥   𝑢,𝐷   ,𝐺,𝑧,𝑦   𝑢,𝐺,𝑤   𝑔,𝑋,𝑧   𝜑,𝑤   𝑦,𝑤
Allowed substitution hints:   𝜑(𝑦,𝑢)   𝐴(𝑦,𝑤,𝑢)   𝐵(𝑥,𝑦)   𝐷(𝑦)   𝐹(𝑥,𝑦,𝑧,𝑤,𝑢,𝑓,𝑔,)   𝐺(𝑔)   𝑋(𝑦,𝑤,𝑢,)

Proof of Theorem tfr1onlemex
StepHypRef Expression
1 tfr1on.f . . . 4 𝐹 = recs(𝐺)
2 tfr1on.g . . . 4 (𝜑 → Fun 𝐺)
3 tfr1on.x . . . 4 (𝜑 → Ord 𝑋)
4 tfr1on.ex . . . 4 ((𝜑𝑥𝑋𝑓 Fn 𝑥) → (𝐺𝑓) ∈ V)
5 tfr1onlemsucfn.1 . . . 4 𝐴 = {𝑓 ∣ ∃𝑥𝑋 (𝑓 Fn 𝑥 ∧ ∀𝑦𝑥 (𝑓𝑦) = (𝐺‘(𝑓𝑦)))}
6 tfr1onlembacc.3 . . . 4 𝐵 = { ∣ ∃𝑧𝐷𝑔(𝑔 Fn 𝑧𝑔𝐴 = (𝑔 ∪ {⟨𝑧, (𝐺𝑔)⟩}))}
7 tfr1onlembacc.u . . . 4 ((𝜑𝑥 𝑋) → suc 𝑥𝑋)
8 tfr1onlembacc.4 . . . 4 (𝜑𝐷𝑋)
9 tfr1onlembacc.5 . . . 4 (𝜑 → ∀𝑧𝐷𝑔(𝑔 Fn 𝑧 ∧ ∀𝑤𝑧 (𝑔𝑤) = (𝐺‘(𝑔𝑤))))
101, 2, 3, 4, 5, 6, 7, 8, 9tfr1onlembex 6403 . . 3 (𝜑𝐵 ∈ V)
11 uniexg 4474 . . 3 (𝐵 ∈ V → 𝐵 ∈ V)
1210, 11syl 14 . 2 (𝜑 𝐵 ∈ V)
131, 2, 3, 4, 5, 6, 7, 8, 9tfr1onlembfn 6402 . . 3 (𝜑 𝐵 Fn 𝐷)
141, 2, 3, 4, 5, 6, 7, 8, 9tfr1onlemubacc 6404 . . 3 (𝜑 → ∀𝑢𝐷 ( 𝐵𝑢) = (𝐺‘( 𝐵𝑢)))
1513, 14jca 306 . 2 (𝜑 → ( 𝐵 Fn 𝐷 ∧ ∀𝑢𝐷 ( 𝐵𝑢) = (𝐺‘( 𝐵𝑢))))
16 fneq1 5346 . . . 4 (𝑓 = 𝐵 → (𝑓 Fn 𝐷 𝐵 Fn 𝐷))
17 fveq1 5557 . . . . . 6 (𝑓 = 𝐵 → (𝑓𝑢) = ( 𝐵𝑢))
18 reseq1 4940 . . . . . . 7 (𝑓 = 𝐵 → (𝑓𝑢) = ( 𝐵𝑢))
1918fveq2d 5562 . . . . . 6 (𝑓 = 𝐵 → (𝐺‘(𝑓𝑢)) = (𝐺‘( 𝐵𝑢)))
2017, 19eqeq12d 2211 . . . . 5 (𝑓 = 𝐵 → ((𝑓𝑢) = (𝐺‘(𝑓𝑢)) ↔ ( 𝐵𝑢) = (𝐺‘( 𝐵𝑢))))
2120ralbidv 2497 . . . 4 (𝑓 = 𝐵 → (∀𝑢𝐷 (𝑓𝑢) = (𝐺‘(𝑓𝑢)) ↔ ∀𝑢𝐷 ( 𝐵𝑢) = (𝐺‘( 𝐵𝑢))))
2216, 21anbi12d 473 . . 3 (𝑓 = 𝐵 → ((𝑓 Fn 𝐷 ∧ ∀𝑢𝐷 (𝑓𝑢) = (𝐺‘(𝑓𝑢))) ↔ ( 𝐵 Fn 𝐷 ∧ ∀𝑢𝐷 ( 𝐵𝑢) = (𝐺‘( 𝐵𝑢)))))
2322spcegv 2852 . 2 ( 𝐵 ∈ V → (( 𝐵 Fn 𝐷 ∧ ∀𝑢𝐷 ( 𝐵𝑢) = (𝐺‘( 𝐵𝑢))) → ∃𝑓(𝑓 Fn 𝐷 ∧ ∀𝑢𝐷 (𝑓𝑢) = (𝐺‘(𝑓𝑢)))))
2412, 15, 23sylc 62 1 (𝜑 → ∃𝑓(𝑓 Fn 𝐷 ∧ ∀𝑢𝐷 (𝑓𝑢) = (𝐺‘(𝑓𝑢))))
Colors of variables: wff set class
Syntax hints:  wi 4  wa 104  w3a 980   = wceq 1364  wex 1506  wcel 2167  {cab 2182  wral 2475  wrex 2476  Vcvv 2763  cun 3155  {csn 3622  cop 3625   cuni 3839  Ord word 4397  suc csuc 4400  cres 4665  Fun wfun 5252   Fn wfn 5253  cfv 5258  recscrecs 6362
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-in1 615  ax-in2 616  ax-io 710  ax-5 1461  ax-7 1462  ax-gen 1463  ax-ie1 1507  ax-ie2 1508  ax-8 1518  ax-10 1519  ax-11 1520  ax-i12 1521  ax-bndl 1523  ax-4 1524  ax-17 1540  ax-i9 1544  ax-ial 1548  ax-i5r 1549  ax-13 2169  ax-14 2170  ax-ext 2178  ax-coll 4148  ax-sep 4151  ax-pow 4207  ax-pr 4242  ax-un 4468  ax-setind 4573
This theorem depends on definitions:  df-bi 117  df-3an 982  df-tru 1367  df-fal 1370  df-nf 1475  df-sb 1777  df-eu 2048  df-mo 2049  df-clab 2183  df-cleq 2189  df-clel 2192  df-nfc 2328  df-ne 2368  df-ral 2480  df-rex 2481  df-reu 2482  df-rab 2484  df-v 2765  df-sbc 2990  df-csb 3085  df-dif 3159  df-un 3161  df-in 3163  df-ss 3170  df-nul 3451  df-pw 3607  df-sn 3628  df-pr 3629  df-op 3631  df-uni 3840  df-iun 3918  df-br 4034  df-opab 4095  df-mpt 4096  df-tr 4132  df-id 4328  df-iord 4401  df-on 4403  df-suc 4406  df-xp 4669  df-rel 4670  df-cnv 4671  df-co 4672  df-dm 4673  df-rn 4674  df-res 4675  df-ima 4676  df-iota 5219  df-fun 5260  df-fn 5261  df-f 5262  df-f1 5263  df-fo 5264  df-f1o 5265  df-fv 5266  df-recs 6363
This theorem is referenced by:  tfr1onlemaccex  6406
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