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Theorem reseq2i 5010
Description: Equality inference for restrictions. (Contributed by Paul Chapman, 22-Jun-2011.)
Hypothesis
Ref Expression
reseqi.1 𝐴 = 𝐵
Assertion
Ref Expression
reseq2i (𝐶𝐴) = (𝐶𝐵)

Proof of Theorem reseq2i
StepHypRef Expression
1 reseqi.1 . 2 𝐴 = 𝐵
2 reseq2 5008 . 2 (𝐴 = 𝐵 → (𝐶𝐴) = (𝐶𝐵))
31, 2ax-mp 5 1 (𝐶𝐴) = (𝐶𝐵)
Colors of variables: wff set class
Syntax hints:   = wceq 1397  cres 4727
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-io 716  ax-5 1495  ax-7 1496  ax-gen 1497  ax-ie1 1541  ax-ie2 1542  ax-8 1552  ax-10 1553  ax-11 1554  ax-i12 1555  ax-bndl 1557  ax-4 1558  ax-17 1574  ax-i9 1578  ax-ial 1582  ax-i5r 1583  ax-ext 2213
This theorem depends on definitions:  df-bi 117  df-tru 1400  df-nf 1509  df-sb 1811  df-clab 2218  df-cleq 2224  df-clel 2227  df-nfc 2363  df-v 2804  df-in 3206  df-opab 4151  df-xp 4731  df-res 4737
This theorem is referenced by:  reseq12i  5011  rescom  5038  resdmdfsn  5056  rescnvcnv  5199  resdm2  5227  funcnvres  5403  funimaexg  5414  resdif  5605  frecfnom  6566  facnn  10988  fac0  10989  expcnv  12064  setsslid  13132  uptx  14997  txcn  14998  0grsubgr  16114
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