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Theorem bnj1400 35465
Description: First-order logic and set theory. (Contributed by Jonathan Ben-Naim, 3-Jun-2011.) (New usage is discouraged.)
Hypothesis
Ref Expression
bnj1400.1 (𝑦 ∈ 𝐴 → ∀𝑥 𝑦 ∈ 𝐴)
Assertion
Ref Expression
bnj1400 dom ∪ 𝐴 = ∪ 𝑥 ∈ 𝐴 dom 𝑥
Distinct variable groups:   𝑦,𝐴   𝑥,𝑦
Allowed substitution hint:   𝐴(𝑥)

Proof of Theorem bnj1400
Dummy variable 𝑧 is distinct from all other variables.
StepHypRef Expression
1 dmuni 5895 . 2 dom ∪ 𝐴 = ∪ 𝑧 ∈ 𝐴 dom 𝑧
2 df-iun 4952 . . 3 ∪ 𝑥 ∈ 𝐴 dom 𝑥 = {𝑦 ∣ ∃𝑥 ∈ 𝐴 𝑦 ∈ dom 𝑥}
3 df-iun 4952 . . . 4 ∪ 𝑧 ∈ 𝐴 dom 𝑧 = {𝑦 ∣ ∃𝑧 ∈ 𝐴 𝑦 ∈ dom 𝑧}
4 bnj1400.1 . . . . . . 7 (𝑦 ∈ 𝐴 → ∀𝑥 𝑦 ∈ 𝐴)
54nfcii 2911 . . . . . 6 Ⅎ𝑥𝐴
6 nfcv 2922 . . . . . 6 Ⅎ𝑧𝐴
7 nfv 1946 . . . . . 6 Ⅎ𝑧 𝑦 ∈ dom 𝑥
8 nfv 1946 . . . . . 6 Ⅎ𝑥 𝑦 ∈ dom 𝑧
9 dmeq 5884 . . . . . . 7 (𝑥 = 𝑧 → dom 𝑥 = dom 𝑧)
109eleq2d 2846 . . . . . 6 (𝑥 = 𝑧 → (𝑦 ∈ dom 𝑥 ↔ 𝑦 ∈ dom 𝑧))
115, 6, 7, 8, 10cbvrexfw 3303 . . . . 5 (∃𝑥 ∈ 𝐴 𝑦 ∈ dom 𝑥 ↔ ∃𝑧 ∈ 𝐴 𝑦 ∈ dom 𝑧)
1211abbii 2827 . . . 4 {𝑦 ∣ ∃𝑥 ∈ 𝐴 𝑦 ∈ dom 𝑥} = {𝑦 ∣ ∃𝑧 ∈ 𝐴 𝑦 ∈ dom 𝑧}
133, 12eqtr4i 2786 . . 3 ∪ 𝑧 ∈ 𝐴 dom 𝑧 = {𝑦 ∣ ∃𝑥 ∈ 𝐴 𝑦 ∈ dom 𝑥}
142, 13eqtr4i 2786 . 2 ∪ 𝑥 ∈ 𝐴 dom 𝑥 = ∪ 𝑧 ∈ 𝐴 dom 𝑧
151, 14eqtr4i 2786 1 dom ∪ 𝐴 = ∪ 𝑥 ∈ 𝐴 dom 𝑥
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   → wi 4  ∀wal 1567   = wceq 1569   ∈ wcel 2144  {cab 2738  ∃wrex 3086  ∪ cuni 4866  ∪ ciun 4950  dom cdm 5650
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1827  ax-4 1841  ax-5 1942  ax-6 1999  ax-7 2040  ax-8 2146  ax-9 2154  ax-10 2177  ax-11 2193  ax-12 2212  ax-ext 2732
This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3an 1105  df-tru 1572  df-fal 1582  df-ex 1812  df-nf 1816  df-sb 2099  df-clab 2739  df-cleq 2752  df-clel 2835  df-nfc 2909  df-ral 3077  df-rex 3087  df-rab 3413  df-v 3452  df-ss 3896  df-dif 4047  df-un 4151  df-nul 4279  df-if 4482  df-sn 4584  df-pr 4586  df-op 4590  df-uni 4867  df-iun 4952  df-br 5103  df-dm 5660
This theorem is used by:  bnj1398  35664  bnj1450  35680  bnj1498  35691  bnj1501  35697
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