P. 342 of Theorem List - Metamath Proof Explorer

Theorem List for Metamath Proof Explorer - 34101-34200   *Has distinct variable group(s)

Type	Label	Description
Statement
Theorem	sraidom 34101	Condition for a subring algebra to be an integral domain. (Contributed by Thierry Arnoux, 13-Oct-2025.)
⊢ 𝐴 = ((subringAlg ‘𝑅)‘𝑉)    &   ⊢ 𝐵 = (Base‘𝑅)    &   ⊢ (𝜑 → 𝑅 ∈ IDomn)    &   ⊢ (𝜑 → 𝑉 ⊆ 𝐵)    ⇒   ⊢ (𝜑 → 𝐴 ∈ IDomn)
Theorem	srasubrg 34102	A subring of the original structure is also a subring of the constructed subring algebra. (Contributed by Thierry Arnoux, 24-Jul-2023.)
⊢ (𝜑 → 𝐴 = ((subringAlg ‘𝑊)‘𝑆))    &   ⊢ (𝜑 → 𝑈 ∈ (SubRing‘𝑊))    &   ⊢ (𝜑 → 𝑆 ⊆ (Base‘𝑊))    ⇒   ⊢ (𝜑 → 𝑈 ∈ (SubRing‘𝐴))
Theorem	sralvec 34103	Given a sub division ring 𝐹 of a division ring 𝐸, 𝐸 may be considered as a vector space over 𝐹, which becomes the field of scalars. (Contributed by Thierry Arnoux, 24-May-2023.)
⊢ 𝐴 = ((subringAlg ‘𝐸)‘𝑈)    &   ⊢ 𝐹 = (𝐸 ↾s 𝑈)    ⇒   ⊢ ((𝐸 ∈ DivRing ∧ 𝐹 ∈ DivRing ∧ 𝑈 ∈ (SubRing‘𝐸)) → 𝐴 ∈ LVec)
Theorem	srafldlvec 34104	Given a subfield 𝐹 of a field 𝐸, 𝐸 may be considered as a vector space over 𝐹, which becomes the field of scalars. (Contributed by Thierry Arnoux, 24-May-2023.)
⊢ 𝐴 = ((subringAlg ‘𝐸)‘𝑈)    &   ⊢ 𝐹 = (𝐸 ↾s 𝑈)    ⇒   ⊢ ((𝐸 ∈ Field ∧ 𝐹 ∈ Field ∧ 𝑈 ∈ (SubRing‘𝐸)) → 𝐴 ∈ LVec)
Theorem	resssra 34105	The subring algebra of a restricted structure is the restriction of the subring algebra. (Contributed by Thierry Arnoux, 2-Apr-2025.)
⊢ 𝐴 = (Base‘𝑅)    &   ⊢ 𝑆 = (𝑅 ↾s 𝐵)    &   ⊢ (𝜑 → 𝐵 ⊆ 𝐴)    &   ⊢ (𝜑 → 𝐶 ⊆ 𝐵)    &   ⊢ (𝜑 → 𝑅 ∈ 𝑉)    ⇒   ⊢ (𝜑 → ((subringAlg ‘𝑆)‘𝐶) = (((subringAlg ‘𝑅)‘𝐶) ↾s 𝐵))
Theorem	lsssra 34106	A subring is a subspace of the subring algebra. (Contributed by Thierry Arnoux, 2-Apr-2025.)
⊢ 𝑊 = ((subringAlg ‘𝑅)‘𝐶)    &   ⊢ 𝐴 = (Base‘𝑅)    &   ⊢ 𝑆 = (𝑅 ↾s 𝐵)    &   ⊢ (𝜑 → 𝐵 ∈ (SubRing‘𝑅))    &   ⊢ (𝜑 → 𝐶 ∈ (SubRing‘𝑆))    ⇒   ⊢ (𝜑 → 𝐵 ∈ (LSubSp‘𝑊))
Theorem	srapwov 34107	The "power" operation on a subring algebra. (Contributed by Thierry Arnoux, 10-Jan-2026.)
⊢ 𝐴 = ((subringAlg ‘𝑊)‘𝑆)    &   ⊢ (𝜑 → 𝑊 ∈ Ring)    &   ⊢ (𝜑 → 𝑆 ⊆ (Base‘𝑊))    ⇒   ⊢ (𝜑 → (.g‘(mulGrp‘𝑊)) = (.g‘(mulGrp‘𝐴)))
21.3.10.52  Division Ring Extensions
Theorem	drgext0g 34108	The additive neutral element of a division ring extension. (Contributed by Thierry Arnoux, 17-Jul-2023.)
⊢ 𝐵 = ((subringAlg ‘𝐸)‘𝑈)    &   ⊢ (𝜑 → 𝐸 ∈ DivRing)    &   ⊢ (𝜑 → 𝑈 ∈ (SubRing‘𝐸))    ⇒   ⊢ (𝜑 → (0g‘𝐸) = (0g‘𝐵))
Theorem	drgextvsca 34109	The scalar multiplication operation of a division ring extension. (Contributed by Thierry Arnoux, 17-Jul-2023.)
⊢ 𝐵 = ((subringAlg ‘𝐸)‘𝑈)    &   ⊢ (𝜑 → 𝐸 ∈ DivRing)    &   ⊢ (𝜑 → 𝑈 ∈ (SubRing‘𝐸))    ⇒   ⊢ (𝜑 → (.r‘𝐸) = ( ·𝑠 ‘𝐵))
Theorem	drgext0gsca 34110	The additive neutral element of the scalar field of a division ring extension. (Contributed by Thierry Arnoux, 17-Jul-2023.)
⊢ 𝐵 = ((subringAlg ‘𝐸)‘𝑈)    &   ⊢ (𝜑 → 𝐸 ∈ DivRing)    &   ⊢ (𝜑 → 𝑈 ∈ (SubRing‘𝐸))    ⇒   ⊢ (𝜑 → (0g‘𝐵) = (0g‘(Scalar‘𝐵)))
Theorem	drgextsubrg 34111	The scalar field is a subring of a division ring extension. (Contributed by Thierry Arnoux, 17-Jul-2023.)
⊢ 𝐵 = ((subringAlg ‘𝐸)‘𝑈)    &   ⊢ (𝜑 → 𝐸 ∈ DivRing)    &   ⊢ (𝜑 → 𝑈 ∈ (SubRing‘𝐸))    &   ⊢ 𝐹 = (𝐸 ↾s 𝑈)    &   ⊢ (𝜑 → 𝐹 ∈ DivRing)    ⇒   ⊢ (𝜑 → 𝑈 ∈ (SubRing‘𝐵))
Theorem	drgextlsp 34112	The scalar field is a subspace of a subring algebra. (Contributed by Thierry Arnoux, 17-Jul-2023.)
⊢ 𝐵 = ((subringAlg ‘𝐸)‘𝑈)    &   ⊢ (𝜑 → 𝐸 ∈ DivRing)    &   ⊢ (𝜑 → 𝑈 ∈ (SubRing‘𝐸))    &   ⊢ 𝐹 = (𝐸 ↾s 𝑈)    &   ⊢ (𝜑 → 𝐹 ∈ DivRing)    ⇒   ⊢ (𝜑 → 𝑈 ∈ (LSubSp‘𝐵))
Theorem	drgextgsum 34113*	Group sum in a division ring extension. (Contributed by Thierry Arnoux, 17-Jul-2023.)
⊢ 𝐵 = ((subringAlg ‘𝐸)‘𝑈)    &   ⊢ (𝜑 → 𝐸 ∈ DivRing)    &   ⊢ (𝜑 → 𝑈 ∈ (SubRing‘𝐸))    &   ⊢ 𝐹 = (𝐸 ↾s 𝑈)    &   ⊢ (𝜑 → 𝐹 ∈ DivRing)    &   ⊢ (𝜑 → 𝑋 ∈ 𝑉)    ⇒   ⊢ (𝜑 → (𝐸 Σg (𝑖 ∈ 𝑋 ↦ 𝑌)) = (𝐵 Σg (𝑖 ∈ 𝑋 ↦ 𝑌)))
21.3.10.53  Vector Spaces
Theorem	lvecdimfi 34114	Finite version of lvecdim 21350 which does not require the axiom of choice. The axiom of choice is used in acsmapd 18648, which is required in the infinite case. Suggested by Gérard Lang. (Contributed by Thierry Arnoux, 24-May-2023.)
⊢ 𝐽 = (LBasis‘𝑊)    &   ⊢ (𝜑 → 𝑊 ∈ LVec)    &   ⊢ (𝜑 → 𝑆 ∈ 𝐽)    &   ⊢ (𝜑 → 𝑇 ∈ 𝐽)    &   ⊢ (𝜑 → 𝑆 ∈ Fin)    ⇒   ⊢ (𝜑 → 𝑆 ≈ 𝑇)
Theorem	exsslsb 34115*	Any finite generating set 𝑆 of a vector space 𝑊 contains a basis. (Contributed by Thierry Arnoux, 13-Oct-2025.)
⊢ 𝐵 = (Base‘𝑊)    &   ⊢ 𝐽 = (LBasis‘𝑊)    &   ⊢ 𝐾 = (LSpan‘𝑊)    &   ⊢ (𝜑 → 𝑊 ∈ LVec)    &   ⊢ (𝜑 → 𝑆 ∈ Fin)    &   ⊢ (𝜑 → 𝑆 ⊆ 𝐵)    &   ⊢ (𝜑 → (𝐾‘𝑆) = 𝐵)    ⇒   ⊢ (𝜑 → ∃𝑠 ∈ 𝐽 𝑠 ⊆ 𝑆)
Theorem	lbslelsp 34116	The size of a basis 𝑋 of a vector space 𝑊 is less than the size of a generating set 𝑌. (Contributed by Thierry Arnoux, 13-Oct-2025.)
⊢ 𝐵 = (Base‘𝑊)    &   ⊢ 𝐽 = (LBasis‘𝑊)    &   ⊢ 𝐾 = (LSpan‘𝑊)    &   ⊢ (𝜑 → 𝑊 ∈ LVec)    &   ⊢ (𝜑 → 𝑋 ∈ 𝐽)    &   ⊢ (𝜑 → 𝑌 ⊆ 𝐵)    &   ⊢ (𝜑 → (𝐾‘𝑌) = 𝐵)    ⇒   ⊢ (𝜑 → (♯‘𝑋) ≤ (♯‘𝑌))
21.3.10.54  Vector Space Dimension
Syntax	cldim 34117	Extend class notation with the dimension of a vector space.
class dim
Definition	df-dim 34118	Define the dimension of a vector space as the cardinality of its bases. Note that by lvecdim 21350, all bases are equinumerous. (Contributed by Thierry Arnoux, 6-May-2023.)
⊢ dim = (𝑓 ∈ V ↦ ∪ (♯ “ (LBasis‘𝑓)))
Theorem	dimval 34119	The dimension of a vector space 𝐹 is the cardinality of one of its bases. (Contributed by Thierry Arnoux, 6-May-2023.)
⊢ 𝐽 = (LBasis‘𝐹)    ⇒   ⊢ ((𝐹 ∈ LVec ∧ 𝑆 ∈ 𝐽) → (dim‘𝐹) = (♯‘𝑆))
Theorem	dimvalfi 34120	The dimension of a vector space 𝐹 is the cardinality of one of its bases. This version of dimval 34119 does not depend on the axiom of choice, but it is limited to the case where the base 𝑆 is finite. (Contributed by Thierry Arnoux, 24-May-2023.)
⊢ 𝐽 = (LBasis‘𝐹)    ⇒   ⊢ ((𝐹 ∈ LVec ∧ 𝑆 ∈ 𝐽 ∧ 𝑆 ∈ Fin) → (dim‘𝐹) = (♯‘𝑆))
Theorem	dimcl 34121	Closure of the vector space dimension. (Contributed by Thierry Arnoux, 18-May-2023.)
⊢ (𝑉 ∈ LVec → (dim‘𝑉) ∈ ℕ0*)
Theorem	lmimdim 34122	Module isomorphisms preserve vector space dimensions. (Contributed by Thierry Arnoux, 25-Feb-2025.)
⊢ (𝜑 → 𝐹 ∈ (𝑆 LMIso 𝑇))    &   ⊢ (𝜑 → 𝑆 ∈ LVec)    ⇒   ⊢ (𝜑 → (dim‘𝑆) = (dim‘𝑇))
Theorem	lmicdim 34123	Module isomorphisms preserve vector space dimensions. (Contributed by Thierry Arnoux, 25-Mar-2025.)
⊢ (𝜑 → 𝑆 ≃𝑚 𝑇)    &   ⊢ (𝜑 → 𝑆 ∈ LVec)    ⇒   ⊢ (𝜑 → (dim‘𝑆) = (dim‘𝑇))
Theorem	lvecdim0i 34124	A vector space of dimension zero is reduced to its identity element. (Contributed by Thierry Arnoux, 31-Jul-2023.)
⊢ 0 = (0g‘𝑉)    ⇒   ⊢ ((𝑉 ∈ LVec ∧ (dim‘𝑉) = 0) → (Base‘𝑉) = { 0 })
Theorem	lvecdim0 34125	A vector space of dimension zero is reduced to its identity element, biconditional version. (Contributed by Thierry Arnoux, 31-Jul-2023.)
⊢ 0 = (0g‘𝑉)    ⇒   ⊢ (𝑉 ∈ LVec → ((dim‘𝑉) = 0 ↔ (Base‘𝑉) = { 0 }))
Theorem	lssdimle 34126	The dimension of a linear subspace is less than or equal to the dimension of the parent vector space. This is corollary 5.4 of [Lang] p. 141. (Contributed by Thierry Arnoux, 20-May-2023.)
⊢ 𝑋 = (𝑊 ↾s 𝑈)    ⇒   ⊢ ((𝑊 ∈ LVec ∧ 𝑈 ∈ (LSubSp‘𝑊)) → (dim‘𝑋) ≤ (dim‘𝑊))
Theorem	dimpropd 34127*	If two structures have the same components (properties), they have the same dimension. (Contributed by Thierry Arnoux, 18-May-2023.)
⊢ (𝜑 → 𝐵 = (Base‘𝐾))    &   ⊢ (𝜑 → 𝐵 = (Base‘𝐿))    &   ⊢ (𝜑 → 𝐵 ⊆ 𝑊)    &   ⊢ ((𝜑 ∧ (𝑥 ∈ 𝑊 ∧ 𝑦 ∈ 𝑊)) → (𝑥(+g‘𝐾)𝑦) = (𝑥(+g‘𝐿)𝑦))    &   ⊢ ((𝜑 ∧ (𝑥 ∈ 𝑃 ∧ 𝑦 ∈ 𝐵)) → (𝑥( ·𝑠 ‘𝐾)𝑦) ∈ 𝑊)    &   ⊢ ((𝜑 ∧ (𝑥 ∈ 𝑃 ∧ 𝑦 ∈ 𝐵)) → (𝑥( ·𝑠 ‘𝐾)𝑦) = (𝑥( ·𝑠 ‘𝐿)𝑦))    &   ⊢ 𝐹 = (Scalar‘𝐾)    &   ⊢ 𝐺 = (Scalar‘𝐿)    &   ⊢ (𝜑 → 𝑃 = (Base‘𝐹))    &   ⊢ (𝜑 → 𝑃 = (Base‘𝐺))    &   ⊢ ((𝜑 ∧ (𝑥 ∈ 𝑃 ∧ 𝑦 ∈ 𝑃)) → (𝑥(+g‘𝐹)𝑦) = (𝑥(+g‘𝐺)𝑦))    &   ⊢ (𝜑 → 𝐾 ∈ LVec)    &   ⊢ (𝜑 → 𝐿 ∈ LVec)    ⇒   ⊢ (𝜑 → (dim‘𝐾) = (dim‘𝐿))
Theorem	rlmdim 34128	The left vector space induced by a ring over itself has dimension 1. (Contributed by Thierry Arnoux, 5-Aug-2023.) Generalize to division rings. (Revised by SN, 22-Mar-2025.)
⊢ 𝑉 = (ringLMod‘𝐹)    ⇒   ⊢ (𝐹 ∈ DivRing → (dim‘𝑉) = 1)
Theorem	frlmdim 34129	Dimension of a free left module. (Contributed by Thierry Arnoux, 20-May-2023.)
⊢ 𝐹 = (𝑅 freeLMod 𝐼)    ⇒   ⊢ ((𝑅 ∈ DivRing ∧ 𝐼 ∈ 𝑉) → (dim‘𝐹) = (♯‘𝐼))
Theorem	tnglvec 34130	Augmenting a structure with a norm conserves left vector spaces. (Contributed by Thierry Arnoux, 20-May-2023.)
⊢ 𝑇 = (𝐺 toNrmGrp 𝑁)    ⇒   ⊢ (𝑁 ∈ 𝑉 → (𝐺 ∈ LVec ↔ 𝑇 ∈ LVec))
Theorem	tngdim 34131	Dimension of a left vector space augmented with a norm. (Contributed by Thierry Arnoux, 20-May-2023.)
⊢ 𝑇 = (𝐺 toNrmGrp 𝑁)    ⇒   ⊢ ((𝐺 ∈ LVec ∧ 𝑁 ∈ 𝑉) → (dim‘𝐺) = (dim‘𝑇))
Theorem	rrxdim 34132	Dimension of the generalized Euclidean space. (Contributed by Thierry Arnoux, 20-May-2023.)
⊢ 𝐻 = (ℝ^‘𝐼)    ⇒   ⊢ (𝐼 ∈ 𝑉 → (dim‘𝐻) = (♯‘𝐼))
Theorem	matdim 34133	Dimension of the space of square matrices. (Contributed by Thierry Arnoux, 20-May-2023.)
⊢ 𝐴 = (𝐼 Mat 𝑅)    &   ⊢ 𝑁 = (♯‘𝐼)    ⇒   ⊢ ((𝐼 ∈ Fin ∧ 𝑅 ∈ DivRing) → (dim‘𝐴) = (𝑁 · 𝑁))
Theorem	lbslsat 34134	A nonzero vector 𝑋 is a basis of a line spanned by the singleton 𝑋. Spans of nonzero singletons are sometimes called "atoms", see df-lsatoms 39857 and for example lsatlspsn 39874. (Contributed by Thierry Arnoux, 20-May-2023.)
⊢ 𝑉 = (Base‘𝑊)    &   ⊢ 𝑁 = (LSpan‘𝑊)    &   ⊢ 0 = (0g‘𝑊)    &   ⊢ 𝑌 = (𝑊 ↾s (𝑁‘{𝑋}))    ⇒   ⊢ ((𝑊 ∈ LVec ∧ 𝑋 ∈ 𝑉 ∧ 𝑋 ≠ 0 ) → {𝑋} ∈ (LBasis‘𝑌))
Theorem	lsatdim 34135	A line, spanned by a nonzero singleton, has dimension 1. (Contributed by Thierry Arnoux, 20-May-2023.)
⊢ 𝑉 = (Base‘𝑊)    &   ⊢ 𝑁 = (LSpan‘𝑊)    &   ⊢ 0 = (0g‘𝑊)    &   ⊢ 𝑌 = (𝑊 ↾s (𝑁‘{𝑋}))    ⇒   ⊢ ((𝑊 ∈ LVec ∧ 𝑋 ∈ 𝑉 ∧ 𝑋 ≠ 0 ) → (dim‘𝑌) = 1)
Theorem	drngdimgt0 34136	The dimension of a vector space that is also a division ring is greater than zero. (Contributed by Thierry Arnoux, 29-Jul-2023.)
⊢ ((𝐹 ∈ LVec ∧ 𝐹 ∈ DivRing) → 0 < (dim‘𝐹))
Theorem	lmhmlvec2 34137	A homomorphism of left vector spaces has a left vector space as codomain. (Contributed by Thierry Arnoux, 7-May-2023.)
⊢ ((𝑉 ∈ LVec ∧ 𝐹 ∈ (𝑉 LMHom 𝑈)) → 𝑈 ∈ LVec)
Theorem	kerlmhm 34138	The kernel of a vector space homomorphism is a vector space itself. (Contributed by Thierry Arnoux, 7-May-2023.)
⊢ 0 = (0g‘𝑈)    &   ⊢ 𝐾 = (𝑉 ↾s (◡𝐹 “ { 0 }))    ⇒   ⊢ ((𝑉 ∈ LVec ∧ 𝐹 ∈ (𝑉 LMHom 𝑈)) → 𝐾 ∈ LVec)
Theorem	imlmhm 34139	The image of a vector space homomorphism is a vector space itself. (Contributed by Thierry Arnoux, 7-May-2023.)
⊢ 𝐼 = (𝑈 ↾s ran 𝐹)    ⇒   ⊢ ((𝑉 ∈ LVec ∧ 𝐹 ∈ (𝑉 LMHom 𝑈)) → 𝐼 ∈ LVec)
Theorem	ply1degltdimlem 34140*	Lemma for ply1degltdim 34141. (Contributed by Thierry Arnoux, 20-Feb-2025.)
⊢ 𝑃 = (Poly1‘𝑅)    &   ⊢ 𝐷 = (deg1‘𝑅)    &   ⊢ 𝑆 = (◡𝐷 “ (-∞[,)𝑁))    &   ⊢ (𝜑 → 𝑁 ∈ ℕ0)    &   ⊢ (𝜑 → 𝑅 ∈ DivRing)    &   ⊢ 𝐸 = (𝑃 ↾s 𝑆)    &   ⊢ 𝐹 = (𝑛 ∈ (0..^𝑁) ↦ (𝑛(.g‘(mulGrp‘𝑃))(var1‘𝑅)))    ⇒   ⊢ (𝜑 → ran 𝐹 ∈ (LBasis‘𝐸))
Theorem	ply1degltdim 34141	The space 𝑆 of the univariate polynomials of degree less than 𝑁 has dimension 𝑁. (Contributed by Thierry Arnoux, 20-Feb-2025.)
⊢ 𝑃 = (Poly1‘𝑅)    &   ⊢ 𝐷 = (deg1‘𝑅)    &   ⊢ 𝑆 = (◡𝐷 “ (-∞[,)𝑁))    &   ⊢ (𝜑 → 𝑁 ∈ ℕ0)    &   ⊢ (𝜑 → 𝑅 ∈ DivRing)    &   ⊢ 𝐸 = (𝑃 ↾s 𝑆)    ⇒   ⊢ (𝜑 → (dim‘𝐸) = 𝑁)
Theorem	lindsunlem 34142	Lemma for lindsun 34143. (Contributed by Thierry Arnoux, 9-May-2023.)
⊢ 𝑁 = (LSpan‘𝑊)    &   ⊢ 0 = (0g‘𝑊)    &   ⊢ (𝜑 → 𝑊 ∈ LVec)    &   ⊢ (𝜑 → 𝑈 ∈ (LIndS‘𝑊))    &   ⊢ (𝜑 → 𝑉 ∈ (LIndS‘𝑊))    &   ⊢ (𝜑 → ((𝑁‘𝑈) ∩ (𝑁‘𝑉)) = { 0 })    &   ⊢ 𝑂 = (0g‘(Scalar‘𝑊))    &   ⊢ 𝐹 = (Base‘(Scalar‘𝑊))    &   ⊢ (𝜑 → 𝐶 ∈ 𝑈)    &   ⊢ (𝜑 → 𝐾 ∈ (𝐹 ∖ {𝑂}))    &   ⊢ (𝜑 → (𝐾( ·𝑠 ‘𝑊)𝐶) ∈ (𝑁‘((𝑈 ∪ 𝑉) ∖ {𝐶})))    ⇒   ⊢ (𝜑 → ⊥)
Theorem	lindsun 34143	Condition for the union of two independent sets to be an independent set. (Contributed by Thierry Arnoux, 9-May-2023.)
⊢ 𝑁 = (LSpan‘𝑊)    &   ⊢ 0 = (0g‘𝑊)    &   ⊢ (𝜑 → 𝑊 ∈ LVec)    &   ⊢ (𝜑 → 𝑈 ∈ (LIndS‘𝑊))    &   ⊢ (𝜑 → 𝑉 ∈ (LIndS‘𝑊))    &   ⊢ (𝜑 → ((𝑁‘𝑈) ∩ (𝑁‘𝑉)) = { 0 })    ⇒   ⊢ (𝜑 → (𝑈 ∪ 𝑉) ∈ (LIndS‘𝑊))
Theorem	lbsdiflsp0 34144	The linear spans of two disjunct independent sets only have a trivial intersection. This can be seen as the opposite direction of lindsun 34143. (Contributed by Thierry Arnoux, 17-May-2023.)
⊢ 𝐽 = (LBasis‘𝑊)    &   ⊢ 𝑁 = (LSpan‘𝑊)    &   ⊢ 0 = (0g‘𝑊)    ⇒   ⊢ ((𝑊 ∈ LVec ∧ 𝐵 ∈ 𝐽 ∧ 𝑉 ⊆ 𝐵) → ((𝑁‘(𝐵 ∖ 𝑉)) ∩ (𝑁‘𝑉)) = { 0 })
Theorem	dimkerim 34145	Given a linear map 𝐹 between vector spaces 𝑉 and 𝑈, the dimension of the vector space 𝑉 is the sum of the dimension of 𝐹 's kernel and the dimension of 𝐹's image. Second part of theorem 5.3 in [Lang] p. 141 This can also be described as the Rank-nullity theorem, (dim‘𝐼) being the rank of 𝐹 (the dimension of its image), and (dim‘𝐾) its nullity (the dimension of its kernel). (Contributed by Thierry Arnoux, 17-May-2023.)
⊢ 0 = (0g‘𝑈)    &   ⊢ 𝐾 = (𝑉 ↾s (◡𝐹 “ { 0 }))    &   ⊢ 𝐼 = (𝑈 ↾s ran 𝐹)    ⇒   ⊢ ((𝑉 ∈ LVec ∧ 𝐹 ∈ (𝑉 LMHom 𝑈)) → (dim‘𝑉) = ((dim‘𝐾) +𝑒 (dim‘𝐼)))
Theorem	qusdimsum 34146	Let 𝑊 be a vector space, and let 𝑋 be a subspace. Then the dimension of 𝑊 is the sum of the dimension of 𝑋 and the dimension of the quotient space of 𝑋. First part of theorem 5.3 in [Lang] p. 141. (Contributed by Thierry Arnoux, 20-May-2023.)
⊢ 𝑋 = (𝑊 ↾s 𝑈)    &   ⊢ 𝑌 = (𝑊 /s (𝑊 ~QG 𝑈))    ⇒   ⊢ ((𝑊 ∈ LVec ∧ 𝑈 ∈ (LSubSp‘𝑊)) → (dim‘𝑊) = ((dim‘𝑋) +𝑒 (dim‘𝑌)))
Theorem	fedgmullem1 34147*	Lemma for fedgmul 34149. (Contributed by Thierry Arnoux, 20-Jul-2023.)
⊢ 𝐴 = ((subringAlg ‘𝐸)‘𝑉)    &   ⊢ 𝐵 = ((subringAlg ‘𝐸)‘𝑈)    &   ⊢ 𝐶 = ((subringAlg ‘𝐹)‘𝑉)    &   ⊢ 𝐹 = (𝐸 ↾s 𝑈)    &   ⊢ 𝐾 = (𝐸 ↾s 𝑉)    &   ⊢ (𝜑 → 𝐸 ∈ DivRing)    &   ⊢ (𝜑 → 𝐹 ∈ DivRing)    &   ⊢ (𝜑 → 𝐾 ∈ DivRing)    &   ⊢ (𝜑 → 𝑈 ∈ (SubRing‘𝐸))    &   ⊢ (𝜑 → 𝑉 ∈ (SubRing‘𝐹))    &   ⊢ 𝐷 = (𝑗 ∈ 𝑌, 𝑖 ∈ 𝑋 ↦ (𝑖(.r‘𝐸)𝑗))    &   ⊢ 𝐻 = (𝑗 ∈ 𝑌, 𝑖 ∈ 𝑋 ↦ ((𝐺‘𝑗)‘𝑖))    &   ⊢ (𝜑 → 𝑋 ∈ (LBasis‘𝐶))    &   ⊢ (𝜑 → 𝑌 ∈ (LBasis‘𝐵))    &   ⊢ (𝜑 → 𝑍 ∈ (Base‘𝐴))    &   ⊢ (𝜑 → 𝐿:𝑌⟶(Base‘(Scalar‘𝐵)))    &   ⊢ (𝜑 → 𝐿 finSupp (0g‘(Scalar‘𝐵)))    &   ⊢ (𝜑 → 𝑍 = (𝐵 Σg (𝑗 ∈ 𝑌 ↦ ((𝐿‘𝑗)( ·𝑠 ‘𝐵)𝑗))))    &   ⊢ (𝜑 → 𝐺:𝑌⟶((Base‘(Scalar‘𝐶)) ↑m 𝑋))    &   ⊢ ((𝜑 ∧ 𝑗 ∈ 𝑌) → (𝐺‘𝑗) finSupp (0g‘(Scalar‘𝐶)))    &   ⊢ ((𝜑 ∧ 𝑗 ∈ 𝑌) → (𝐿‘𝑗) = (𝐶 Σg (𝑖 ∈ 𝑋 ↦ (((𝐺‘𝑗)‘𝑖)( ·𝑠 ‘𝐶)𝑖))))    ⇒   ⊢ (𝜑 → (𝐻 finSupp (0g‘(Scalar‘𝐴)) ∧ 𝑍 = (𝐴 Σg (𝐻 ∘f ( ·𝑠 ‘𝐴)𝐷))))
Theorem	fedgmullem2 34148*	Lemma for fedgmul 34149. (Contributed by Thierry Arnoux, 20-Jul-2023.)
⊢ 𝐴 = ((subringAlg ‘𝐸)‘𝑉)    &   ⊢ 𝐵 = ((subringAlg ‘𝐸)‘𝑈)    &   ⊢ 𝐶 = ((subringAlg ‘𝐹)‘𝑉)    &   ⊢ 𝐹 = (𝐸 ↾s 𝑈)    &   ⊢ 𝐾 = (𝐸 ↾s 𝑉)    &   ⊢ (𝜑 → 𝐸 ∈ DivRing)    &   ⊢ (𝜑 → 𝐹 ∈ DivRing)    &   ⊢ (𝜑 → 𝐾 ∈ DivRing)    &   ⊢ (𝜑 → 𝑈 ∈ (SubRing‘𝐸))    &   ⊢ (𝜑 → 𝑉 ∈ (SubRing‘𝐹))    &   ⊢ 𝐷 = (𝑗 ∈ 𝑌, 𝑖 ∈ 𝑋 ↦ (𝑖(.r‘𝐸)𝑗))    &   ⊢ 𝐻 = (𝑗 ∈ 𝑌, 𝑖 ∈ 𝑋 ↦ ((𝐺‘𝑗)‘𝑖))    &   ⊢ (𝜑 → 𝑋 ∈ (LBasis‘𝐶))    &   ⊢ (𝜑 → 𝑌 ∈ (LBasis‘𝐵))    &   ⊢ (𝜑 → 𝑊 ∈ (Base‘((Scalar‘𝐴) freeLMod (𝑌 × 𝑋))))    &   ⊢ (𝜑 → (𝐴 Σg (𝑊 ∘f ( ·𝑠 ‘𝐴)𝐷)) = (0g‘𝐴))    ⇒   ⊢ (𝜑 → 𝑊 = ((𝑌 × 𝑋) × {(0g‘(Scalar‘𝐴))}))
Theorem	fedgmul 34149	The multiplicativity formula for degrees of field extensions. Given 𝐸 a field extension of 𝐹, itself a field extension of 𝐾, we have [𝐸:𝐾] = [𝐸:𝐹][𝐹:𝐾]. Proposition 1.2 of [Lang], p. 224. Here (dim‘𝐴) is the degree of the extension 𝐸 of 𝐾, (dim‘𝐵) is the degree of the extension 𝐸 of 𝐹, and (dim‘𝐶) is the degree of the extension 𝐹 of 𝐾. This proof is valid for infinite dimensions, and is actually valid for division ring extensions, not just field extensions. (Contributed by Thierry Arnoux, 25-Jul-2023.)
⊢ 𝐴 = ((subringAlg ‘𝐸)‘𝑉)    &   ⊢ 𝐵 = ((subringAlg ‘𝐸)‘𝑈)    &   ⊢ 𝐶 = ((subringAlg ‘𝐹)‘𝑉)    &   ⊢ 𝐹 = (𝐸 ↾s 𝑈)    &   ⊢ 𝐾 = (𝐸 ↾s 𝑉)    &   ⊢ (𝜑 → 𝐸 ∈ DivRing)    &   ⊢ (𝜑 → 𝐹 ∈ DivRing)    &   ⊢ (𝜑 → 𝐾 ∈ DivRing)    &   ⊢ (𝜑 → 𝑈 ∈ (SubRing‘𝐸))    &   ⊢ (𝜑 → 𝑉 ∈ (SubRing‘𝐹))    ⇒   ⊢ (𝜑 → (dim‘𝐴) = ((dim‘𝐵) ·e (dim‘𝐶)))
Theorem	dimlssid 34150	If the dimension of a linear subspace 𝐿 is the dimension of the whole vector space 𝐸, then 𝐿 is the whole space. (Contributed by Thierry Arnoux, 3-Aug-2025.)
⊢ 𝐵 = (Base‘𝐸)    &   ⊢ (𝜑 → 𝐸 ∈ LVec)    &   ⊢ (𝜑 → (dim‘𝐸) ∈ ℕ0)    &   ⊢ (𝜑 → 𝐿 ∈ (LSubSp‘𝐸))    &   ⊢ (𝜑 → (dim‘(𝐸 ↾s 𝐿)) = (dim‘𝐸))    ⇒   ⊢ (𝜑 → 𝐿 = 𝐵)
Theorem	lvecendof1f1o 34151	If an endomorphism 𝑈 of a vector space 𝐸 of finite dimension is injective, then it is bijective. Item (b) of Corollary of Proposition 9 in [BourbakiAlg1] p. 298 . (Contributed by Thierry Arnoux, 3-Aug-2025.)
⊢ 𝐵 = (Base‘𝐸)    &   ⊢ (𝜑 → 𝐸 ∈ LVec)    &   ⊢ (𝜑 → (dim‘𝐸) ∈ ℕ0)    &   ⊢ (𝜑 → 𝑈 ∈ (𝐸 LMHom 𝐸))    &   ⊢ (𝜑 → 𝑈:𝐵–1-1→𝐵)    ⇒   ⊢ (𝜑 → 𝑈:𝐵–1-1-onto→𝐵)
Theorem	lactlmhm 34152*	In an associative algebra 𝐴, left-multiplication by a fixed element of the algebra is a module homomorphism, analogous to ringlghm 20460. (Contributed by Thierry Arnoux, 3-Aug-2025.)
⊢ 𝐵 = (Base‘𝐴)    &   ⊢ · = (.r‘𝐴)    &   ⊢ 𝐹 = (𝑥 ∈ 𝐵 ↦ (𝐶 · 𝑥))    &   ⊢ (𝜑 → 𝐴 ∈ AssAlg)    &   ⊢ (𝜑 → 𝐶 ∈ 𝐵)    ⇒   ⊢ (𝜑 → 𝐹 ∈ (𝐴 LMHom 𝐴))
Theorem	assalactf1o 34153*	In an associative algebra 𝐴, left-multiplication by a fixed element of the algebra is bijective. See also lactlmhm 34152. (Contributed by Thierry Arnoux, 3-Aug-2025.)
⊢ 𝐵 = (Base‘𝐴)    &   ⊢ · = (.r‘𝐴)    &   ⊢ 𝐹 = (𝑥 ∈ 𝐵 ↦ (𝐶 · 𝑥))    &   ⊢ (𝜑 → 𝐴 ∈ AssAlg)    &   ⊢ 𝐸 = (RLReg‘𝐴)    &   ⊢ 𝐾 = (Scalar‘𝐴)    &   ⊢ (𝜑 → 𝐾 ∈ DivRing)    &   ⊢ (𝜑 → (dim‘𝐴) ∈ ℕ0)    &   ⊢ (𝜑 → 𝐶 ∈ 𝐸)    ⇒   ⊢ (𝜑 → 𝐹:𝐵–1-1-onto→𝐵)
Theorem	assarrginv 34154	If an element 𝑋 of an associative algebra 𝐴 over a division ring 𝐾 is regular, then it is a unit. Proposition 2. in Chapter 5. of [BourbakiAlg2] p. 113. (Contributed by Thierry Arnoux, 3-Aug-2025.)
⊢ 𝐸 = (RLReg‘𝐴)    &   ⊢ 𝑈 = (Unit‘𝐴)    &   ⊢ 𝐾 = (Scalar‘𝐴)    &   ⊢ (𝜑 → 𝐴 ∈ AssAlg)    &   ⊢ (𝜑 → 𝐾 ∈ DivRing)    &   ⊢ (𝜑 → (dim‘𝐴) ∈ ℕ0)    &   ⊢ (𝜑 → 𝑋 ∈ 𝐸)    ⇒   ⊢ (𝜑 → 𝑋 ∈ 𝑈)
Theorem	assafld 34155	If an algebra 𝐴 of finite degree over a division ring 𝐾 is an integral domain, then it is a field. Corollary of Proposition 2. in Chapter 5. of [BourbakiAlg2] p. 113. (Contributed by Thierry Arnoux, 3-Aug-2025.)
⊢ 𝐾 = (Scalar‘𝐴)    &   ⊢ (𝜑 → 𝐴 ∈ AssAlg)    &   ⊢ (𝜑 → 𝐴 ∈ IDomn)    &   ⊢ (𝜑 → 𝐾 ∈ DivRing)    &   ⊢ (𝜑 → (dim‘𝐴) ∈ ℕ0)    ⇒   ⊢ (𝜑 → 𝐴 ∈ Field)
21.3.11  Field Extensions
Syntax	cfldext 34156	Syntax for the field extension relation.
class /FldExt
Syntax	cfinext 34157	Syntax for the finite field extension relation.
class /FinExt
Syntax	cextdg 34158	Syntax for the field extension degree operation.
class [:]
Definition	df-fldext 34159*	Definition of the field extension relation. (Contributed by Thierry Arnoux, 29-Jul-2023.)
⊢ /FldExt = {⟨𝑒, 𝑓⟩ ∣ ((𝑒 ∈ Field ∧ 𝑓 ∈ Field) ∧ (𝑓 = (𝑒 ↾s (Base‘𝑓)) ∧ (Base‘𝑓) ∈ (SubRing‘𝑒)))}
Definition	df-extdg 34160*	Definition of the field extension degree operation. (Contributed by Thierry Arnoux, 29-Jul-2023.)
⊢ [:] = (𝑒 ∈ V, 𝑓 ∈ (/FldExt “ {𝑒}) ↦ (dim‘((subringAlg ‘𝑒)‘(Base‘𝑓))))
Definition	df-finext 34161*	Definition of the finite field extension relation. (Contributed by Thierry Arnoux, 29-Jul-2023.)
⊢ /FinExt = {⟨𝑒, 𝑓⟩ ∣ (𝑒/FldExt𝑓 ∧ (𝑒[:]𝑓) ∈ ℕ0)}
Theorem	relfldext 34162	The field extension is a relation. (Contributed by Thierry Arnoux, 29-Jul-2023.)
⊢ Rel /FldExt
Theorem	brfldext 34163	The field extension relation explicited. (Contributed by Thierry Arnoux, 29-Jul-2023.)
⊢ ((𝐸 ∈ Field ∧ 𝐹 ∈ Field) → (𝐸/FldExt𝐹 ↔ (𝐹 = (𝐸 ↾s (Base‘𝐹)) ∧ (Base‘𝐹) ∈ (SubRing‘𝐸))))
Theorem	ccfldextrr 34164	The field of the complex numbers is an extension of the field of the real numbers. (Contributed by Thierry Arnoux, 20-Jul-2023.)
⊢ ℂfld/FldExtℝfld
Theorem	fldextfld1 34165	A field extension is only defined if the extension is a field. (Contributed by Thierry Arnoux, 29-Jul-2023.)
⊢ (𝐸/FldExt𝐹 → 𝐸 ∈ Field)
Theorem	fldextfld2 34166	A field extension is only defined if the subfield is a field. (Contributed by Thierry Arnoux, 29-Jul-2023.)
⊢ (𝐸/FldExt𝐹 → 𝐹 ∈ Field)
Theorem	fldextsubrg 34167	Field extension implies a subring relation. (Contributed by Thierry Arnoux, 29-Jul-2023.)
⊢ 𝑈 = (Base‘𝐹)    ⇒   ⊢ (𝐸/FldExt𝐹 → 𝑈 ∈ (SubRing‘𝐸))
Theorem	sdrgfldext 34168	A field 𝐸 and any sub-division-ring 𝐹 of 𝐸 form a field extension. (Contributed by Thierry Arnoux, 26-Oct-2025.)
⊢ 𝐵 = (Base‘𝐸)    &   ⊢ (𝜑 → 𝐸 ∈ Field)    &   ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐸))    ⇒   ⊢ (𝜑 → 𝐸/FldExt(𝐸 ↾s 𝐹))
Theorem	fldextress 34169	Field extension implies a structure restriction relation. (Contributed by Thierry Arnoux, 29-Jul-2023.)
⊢ (𝐸/FldExt𝐹 → 𝐹 = (𝐸 ↾s (Base‘𝐹)))
Theorem	brfinext 34170	The finite field extension relation explicited. (Contributed by Thierry Arnoux, 29-Jul-2023.)
⊢ (𝐸/FldExt𝐹 → (𝐸/FinExt𝐹 ↔ (𝐸[:]𝐹) ∈ ℕ0))
Theorem	extdgval 34171	Value of the field extension degree operation. (Contributed by Thierry Arnoux, 29-Jul-2023.)
⊢ (𝐸/FldExt𝐹 → (𝐸[:]𝐹) = (dim‘((subringAlg ‘𝐸)‘(Base‘𝐹))))
Theorem	fldextsdrg 34172	Deduce sub-division-ring from field extension. (Contributed by Thierry Arnoux, 26-Oct-2025.)
⊢ 𝐵 = (Base‘𝐹)    &   ⊢ (𝜑 → 𝐸/FldExt𝐹)    ⇒   ⊢ (𝜑 → 𝐵 ∈ (SubDRing‘𝐸))
Theorem	fldextsralvec 34173	The subring algebra associated with a field extension is a vector space. (Contributed by Thierry Arnoux, 3-Aug-2023.)
⊢ (𝐸/FldExt𝐹 → ((subringAlg ‘𝐸)‘(Base‘𝐹)) ∈ LVec)
Theorem	extdgcl 34174	Closure of the field extension degree operation. (Contributed by Thierry Arnoux, 29-Jul-2023.)
⊢ (𝐸/FldExt𝐹 → (𝐸[:]𝐹) ∈ ℕ0*)
Theorem	extdggt0 34175	Degrees of field extension are greater than zero. (Contributed by Thierry Arnoux, 30-Jul-2023.)
⊢ (𝐸/FldExt𝐹 → 0 < (𝐸[:]𝐹))
Theorem	fldexttr 34176	Field extension is a transitive relation. (Contributed by Thierry Arnoux, 29-Jul-2023.)
⊢ ((𝐸/FldExt𝐹 ∧ 𝐹/FldExt𝐾) → 𝐸/FldExt𝐾)
Theorem	fldextid 34177	The field extension relation is reflexive. (Contributed by Thierry Arnoux, 30-Jul-2023.)
⊢ (𝐹 ∈ Field → 𝐹/FldExt𝐹)
Theorem	extdgid 34178	A trivial field extension has degree one. (Contributed by Thierry Arnoux, 4-Aug-2023.)
⊢ (𝐸 ∈ Field → (𝐸[:]𝐸) = 1)
Theorem	fldsdrgfldext 34179	A sub-division-ring of a field forms a field extension. (Contributed by Thierry Arnoux, 19-Oct-2025.)
⊢ 𝐺 = (𝐹 ↾s 𝐴)    &   ⊢ (𝜑 → 𝐹 ∈ Field)    &   ⊢ (𝜑 → 𝐴 ∈ (SubDRing‘𝐹))    ⇒   ⊢ (𝜑 → 𝐹/FldExt𝐺)
Theorem	fldsdrgfldext2 34180	A sub-sub-division-ring of a field forms a field extension. (Contributed by Thierry Arnoux, 19-Oct-2025.)
⊢ 𝐺 = (𝐹 ↾s 𝐴)    &   ⊢ (𝜑 → 𝐹 ∈ Field)    &   ⊢ (𝜑 → 𝐴 ∈ (SubDRing‘𝐹))    &   ⊢ (𝜑 → 𝐵 ∈ (SubDRing‘𝐺))    &   ⊢ 𝐻 = (𝐹 ↾s 𝐵)    ⇒   ⊢ (𝜑 → 𝐺/FldExt𝐻)
Theorem	extdgmul 34181	The multiplicativity formula for degrees of field extensions. Given 𝐸 a field extension of 𝐹, itself a field extension of 𝐾, the degree of the extension 𝐸/FldExt𝐾 is the product of the degrees of the extensions 𝐸/FldExt𝐹 and 𝐹/FldExt𝐾. Proposition 1.2 of [Lang], p. 224. (Contributed by Thierry Arnoux, 30-Jul-2023.)
⊢ ((𝐸/FldExt𝐹 ∧ 𝐹/FldExt𝐾) → (𝐸[:]𝐾) = ((𝐸[:]𝐹) ·e (𝐹[:]𝐾)))
Theorem	finextfldext 34182	A finite field extension is a field extension. (Contributed by Thierry Arnoux, 10-Jan-2026.)
⊢ (𝜑 → 𝐸/FinExt𝐹)    ⇒   ⊢ (𝜑 → 𝐸/FldExt𝐹)
Theorem	finexttrb 34183	The extension 𝐸 of 𝐾 is finite if and only if 𝐸 is finite over 𝐹 and 𝐹 is finite over 𝐾. Corollary 1.3 of [Lang] , p. 225. (Contributed by Thierry Arnoux, 30-Jul-2023.)
⊢ ((𝐸/FldExt𝐹 ∧ 𝐹/FldExt𝐾) → (𝐸/FinExt𝐾 ↔ (𝐸/FinExt𝐹 ∧ 𝐹/FinExt𝐾)))
Theorem	extdg1id 34184	If the degree of the extension 𝐸/FldExt𝐹 is 1, then 𝐸 and 𝐹 are identical. (Contributed by Thierry Arnoux, 6-Aug-2023.)
⊢ ((𝐸/FldExt𝐹 ∧ (𝐸[:]𝐹) = 1) → 𝐸 = 𝐹)
Theorem	extdg1b 34185	The degree of the extension 𝐸/FldExt𝐹 is 1 iff 𝐸 and 𝐹 are the same structure. (Contributed by Thierry Arnoux, 6-Aug-2023.)
⊢ (𝐸/FldExt𝐹 → ((𝐸[:]𝐹) = 1 ↔ 𝐸 = 𝐹))
Theorem	fldgenfldext 34186	A subfield 𝐹 extended with a set 𝐴 forms a field extension. (Contributed by Thierry Arnoux, 22-Jun-2025.)
⊢ 𝐵 = (Base‘𝐸)    &   ⊢ 𝐾 = (𝐸 ↾s 𝐹)    &   ⊢ 𝐿 = (𝐸 ↾s (𝐸 fldGen (𝐹 ∪ 𝐴)))    &   ⊢ (𝜑 → 𝐸 ∈ Field)    &   ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐸))    &   ⊢ (𝜑 → 𝐴 ⊆ 𝐵)    ⇒   ⊢ (𝜑 → 𝐿/FldExt𝐾)
Theorem	fldextchr 34187	The characteristic of a subfield is the same as the characteristic of the larger field. (Contributed by Thierry Arnoux, 20-Aug-2023.)
⊢ (𝐸/FldExt𝐹 → (chr‘𝐹) = (chr‘𝐸))
Theorem	evls1fldgencl 34188	Closure of the subring polynomial evaluation in the field extention. (Contributed by Thierry Arnoux, 2-Apr-2025.)
⊢ 𝐵 = (Base‘𝐸)    &   ⊢ 𝑂 = (𝐸 evalSub1 𝐹)    &   ⊢ 𝑃 = (Poly1‘(𝐸 ↾s 𝐹))    &   ⊢ 𝑈 = (Base‘𝑃)    &   ⊢ (𝜑 → 𝐸 ∈ Field)    &   ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐸))    &   ⊢ (𝜑 → 𝐴 ∈ 𝐵)    &   ⊢ (𝜑 → 𝐺 ∈ 𝑈)    ⇒   ⊢ (𝜑 → ((𝑂‘𝐺)‘𝐴) ∈ (𝐸 fldGen (𝐹 ∪ {𝐴})))
Theorem	ccfldsrarelvec 34189	The subring algebra of the complex numbers over the real numbers is a left vector space. (Contributed by Thierry Arnoux, 20-Aug-2023.)
⊢ ((subringAlg ‘ℂfld)‘ℝ) ∈ LVec
Theorem	ccfldextdgrr 34190	The degree of the field extension of the complex numbers over the real numbers is 2. (Suggested by GL, 4-Aug-2023.) (Contributed by Thierry Arnoux, 20-Aug-2023.)
⊢ (ℂfld[:]ℝfld) = 2
Theorem	fldextrspunlsplem 34191*	Lemma for fldextrspunlsp 34192: First direction. Part of the proof of Proposition 5, Chapter 5, of [BourbakiAlg2] p. 116. (Contributed by Thierry Arnoux, 13-Oct-2025.)
⊢ 𝐾 = (𝐿 ↾s 𝐹)    &   ⊢ 𝐼 = (𝐿 ↾s 𝐺)    &   ⊢ 𝐽 = (𝐿 ↾s 𝐻)    &   ⊢ (𝜑 → 𝐿 ∈ Field)    &   ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐼))    &   ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐽))    &   ⊢ (𝜑 → 𝐺 ∈ (SubDRing‘𝐿))    &   ⊢ (𝜑 → 𝐻 ∈ (SubDRing‘𝐿))    &   ⊢ 𝑁 = (RingSpan‘𝐿)    &   ⊢ 𝐶 = (𝑁‘(𝐺 ∪ 𝐻))    &   ⊢ 𝐸 = (𝐿 ↾s 𝐶)    &   ⊢ (𝜑 → 𝐵 ∈ (LBasis‘((subringAlg ‘𝐽)‘𝐹)))    &   ⊢ (𝜑 → 𝐵 ∈ Fin)    &   ⊢ (𝜑 → 𝑃:𝐻⟶𝐺)    &   ⊢ (𝜑 → 𝑃 finSupp (0g‘𝐿))    &   ⊢ (𝜑 → 𝑋 = (𝐿 Σg (𝑓 ∈ 𝐻 ↦ ((𝑃‘𝑓)(.r‘𝐿)𝑓))))    ⇒   ⊢ (𝜑 → ∃𝑎 ∈ (𝐺 ↑m 𝐵)(𝑎 finSupp (0g‘𝐿) ∧ 𝑋 = (𝐿 Σg (𝑏 ∈ 𝐵 ↦ ((𝑎‘𝑏)(.r‘𝐿)𝑏)))))
Theorem	fldextrspunlsp 34192	Lemma for fldextrspunfld 34194. The subring generated by the union of two field extensions 𝐺 and 𝐻 is the vector sub- 𝐺 space generated by a basis 𝐵 of 𝐻. Part of the proof of Proposition 5, Chapter 5, of [BourbakiAlg2] p. 116. (Contributed by Thierry Arnoux, 13-Oct-2025.)
⊢ 𝐾 = (𝐿 ↾s 𝐹)    &   ⊢ 𝐼 = (𝐿 ↾s 𝐺)    &   ⊢ 𝐽 = (𝐿 ↾s 𝐻)    &   ⊢ (𝜑 → 𝐿 ∈ Field)    &   ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐼))    &   ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐽))    &   ⊢ (𝜑 → 𝐺 ∈ (SubDRing‘𝐿))    &   ⊢ (𝜑 → 𝐻 ∈ (SubDRing‘𝐿))    &   ⊢ 𝑁 = (RingSpan‘𝐿)    &   ⊢ 𝐶 = (𝑁‘(𝐺 ∪ 𝐻))    &   ⊢ 𝐸 = (𝐿 ↾s 𝐶)    &   ⊢ (𝜑 → 𝐵 ∈ (LBasis‘((subringAlg ‘𝐽)‘𝐹)))    &   ⊢ (𝜑 → 𝐵 ∈ Fin)    ⇒   ⊢ (𝜑 → 𝐶 = ((LSpan‘((subringAlg ‘𝐿)‘𝐺))‘𝐵))
Theorem	fldextrspunlem1 34193	Lemma for fldextrspunfld 34194. Part of the proof of Proposition 5, Chapter 5, of [BourbakiAlg2] p. 116. (Contributed by Thierry Arnoux, 13-Oct-2025.)
⊢ 𝐾 = (𝐿 ↾s 𝐹)    &   ⊢ 𝐼 = (𝐿 ↾s 𝐺)    &   ⊢ 𝐽 = (𝐿 ↾s 𝐻)    &   ⊢ (𝜑 → 𝐿 ∈ Field)    &   ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐼))    &   ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐽))    &   ⊢ (𝜑 → 𝐺 ∈ (SubDRing‘𝐿))    &   ⊢ (𝜑 → 𝐻 ∈ (SubDRing‘𝐿))    &   ⊢ (𝜑 → (𝐽[:]𝐾) ∈ ℕ0)    &   ⊢ 𝑁 = (RingSpan‘𝐿)    &   ⊢ 𝐶 = (𝑁‘(𝐺 ∪ 𝐻))    &   ⊢ 𝐸 = (𝐿 ↾s 𝐶)    ⇒   ⊢ (𝜑 → (dim‘((subringAlg ‘𝐸)‘𝐺)) ≤ (𝐽[:]𝐾))
Theorem	fldextrspunfld 34194	The ring generated by the union of two field extensions is a field. Part of the proof of Proposition 5, Chapter 5, of [BourbakiAlg2] p. 116. (Contributed by Thierry Arnoux, 13-Oct-2025.)
⊢ 𝐾 = (𝐿 ↾s 𝐹)    &   ⊢ 𝐼 = (𝐿 ↾s 𝐺)    &   ⊢ 𝐽 = (𝐿 ↾s 𝐻)    &   ⊢ (𝜑 → 𝐿 ∈ Field)    &   ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐼))    &   ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐽))    &   ⊢ (𝜑 → 𝐺 ∈ (SubDRing‘𝐿))    &   ⊢ (𝜑 → 𝐻 ∈ (SubDRing‘𝐿))    &   ⊢ (𝜑 → (𝐽[:]𝐾) ∈ ℕ0)    &   ⊢ 𝑁 = (RingSpan‘𝐿)    &   ⊢ 𝐶 = (𝑁‘(𝐺 ∪ 𝐻))    &   ⊢ 𝐸 = (𝐿 ↾s 𝐶)    ⇒   ⊢ (𝜑 → 𝐸 ∈ Field)
Theorem	fldextrspunlem2 34195	Part of the proof of Proposition 5, Chapter 5, of [BourbakiAlg2] p. 116. (Contributed by Thierry Arnoux, 13-Oct-2025.)
⊢ 𝐾 = (𝐿 ↾s 𝐹)    &   ⊢ 𝐼 = (𝐿 ↾s 𝐺)    &   ⊢ 𝐽 = (𝐿 ↾s 𝐻)    &   ⊢ (𝜑 → 𝐿 ∈ Field)    &   ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐼))    &   ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐽))    &   ⊢ (𝜑 → 𝐺 ∈ (SubDRing‘𝐿))    &   ⊢ (𝜑 → 𝐻 ∈ (SubDRing‘𝐿))    &   ⊢ (𝜑 → (𝐽[:]𝐾) ∈ ℕ0)    &   ⊢ 𝑁 = (RingSpan‘𝐿)    &   ⊢ 𝐶 = (𝑁‘(𝐺 ∪ 𝐻))    &   ⊢ 𝐸 = (𝐿 ↾s 𝐶)    ⇒   ⊢ (𝜑 → 𝐶 = (𝐿 fldGen (𝐺 ∪ 𝐻)))
Theorem	fldextrspundgle 34196	Inequality involving the degree of two different field extensions 𝐼 and 𝐽 of a same field 𝐹. Part of the proof of Proposition 5, Chapter 5, of [BourbakiAlg2] p. 116. (Contributed by Thierry Arnoux, 13-Oct-2025.)
⊢ 𝐾 = (𝐿 ↾s 𝐹)    &   ⊢ 𝐼 = (𝐿 ↾s 𝐺)    &   ⊢ 𝐽 = (𝐿 ↾s 𝐻)    &   ⊢ (𝜑 → 𝐿 ∈ Field)    &   ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐼))    &   ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐽))    &   ⊢ (𝜑 → 𝐺 ∈ (SubDRing‘𝐿))    &   ⊢ (𝜑 → 𝐻 ∈ (SubDRing‘𝐿))    &   ⊢ (𝜑 → (𝐽[:]𝐾) ∈ ℕ0)    &   ⊢ 𝐸 = (𝐿 ↾s (𝐿 fldGen (𝐺 ∪ 𝐻)))    ⇒   ⊢ (𝜑 → (𝐸[:]𝐼) ≤ (𝐽[:]𝐾))
Theorem	fldextrspundglemul 34197	Given two field extensions 𝐼 / 𝐾 and 𝐽 / 𝐾 of the same field 𝐾, 𝐽 / 𝐾 being finite, and the composiste field 𝐸 = 𝐼𝐽, the degree of the extension of the composite field 𝐸 / 𝐾 is at most the product of the field extension degrees of 𝐼 / 𝐾 and 𝐽 / 𝐾. (Contributed by Thierry Arnoux, 19-Oct-2025.)
⊢ 𝐾 = (𝐿 ↾s 𝐹)    &   ⊢ 𝐼 = (𝐿 ↾s 𝐺)    &   ⊢ 𝐽 = (𝐿 ↾s 𝐻)    &   ⊢ (𝜑 → 𝐿 ∈ Field)    &   ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐼))    &   ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐽))    &   ⊢ (𝜑 → 𝐺 ∈ (SubDRing‘𝐿))    &   ⊢ (𝜑 → 𝐻 ∈ (SubDRing‘𝐿))    &   ⊢ (𝜑 → (𝐽[:]𝐾) ∈ ℕ0)    &   ⊢ 𝐸 = (𝐿 ↾s (𝐿 fldGen (𝐺 ∪ 𝐻)))    ⇒   ⊢ (𝜑 → (𝐸[:]𝐾) ≤ ((𝐼[:]𝐾) ·e (𝐽[:]𝐾)))
Theorem	fldextrspundgdvdslem 34198	Lemma for fldextrspundgdvds 34199. (Contributed by Thierry Arnoux, 19-Oct-2025.)
⊢ 𝐾 = (𝐿 ↾s 𝐹)    &   ⊢ 𝐼 = (𝐿 ↾s 𝐺)    &   ⊢ 𝐽 = (𝐿 ↾s 𝐻)    &   ⊢ (𝜑 → 𝐿 ∈ Field)    &   ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐼))    &   ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐽))    &   ⊢ (𝜑 → 𝐺 ∈ (SubDRing‘𝐿))    &   ⊢ (𝜑 → 𝐻 ∈ (SubDRing‘𝐿))    &   ⊢ (𝜑 → (𝐽[:]𝐾) ∈ ℕ0)    &   ⊢ 𝐸 = (𝐿 ↾s (𝐿 fldGen (𝐺 ∪ 𝐻)))    &   ⊢ (𝜑 → (𝐼[:]𝐾) ∈ ℕ)    ⇒   ⊢ (𝜑 → (𝐸[:]𝐼) ∈ ℕ0)
Theorem	fldextrspundgdvds 34199	Given two finite extensions 𝐼 / 𝐾 and 𝐽 / 𝐾 of the same field 𝐾, the degree of the extension 𝐼 / 𝐾 divides the degree of the extension 𝐸 / 𝐾, 𝐸 being the composite field 𝐼𝐽. (Contributed by Thierry Arnoux, 19-Oct-2025.)
⊢ 𝐾 = (𝐿 ↾s 𝐹)    &   ⊢ 𝐼 = (𝐿 ↾s 𝐺)    &   ⊢ 𝐽 = (𝐿 ↾s 𝐻)    &   ⊢ (𝜑 → 𝐿 ∈ Field)    &   ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐼))    &   ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐽))    &   ⊢ (𝜑 → 𝐺 ∈ (SubDRing‘𝐿))    &   ⊢ (𝜑 → 𝐻 ∈ (SubDRing‘𝐿))    &   ⊢ (𝜑 → (𝐽[:]𝐾) ∈ ℕ0)    &   ⊢ 𝐸 = (𝐿 ↾s (𝐿 fldGen (𝐺 ∪ 𝐻)))    &   ⊢ (𝜑 → (𝐼[:]𝐾) ∈ ℕ)    ⇒   ⊢ (𝜑 → (𝐼[:]𝐾) ∥ (𝐸[:]𝐾))
Theorem	fldext2rspun 34200*	Given two field extensions 𝐼 / 𝐾 and 𝐽 / 𝐾, 𝐼 / 𝐾 being a quadratic extension, and the degree of 𝐽 / 𝐾 being a power of 2, the degree of the extension 𝐸 / 𝐾 is a power of 2 , 𝐸 being the composite field 𝐼𝐽. (Contributed by Thierry Arnoux, 19-Oct-2025.)
⊢ 𝐾 = (𝐿 ↾s 𝐹)    &   ⊢ 𝐼 = (𝐿 ↾s 𝐺)    &   ⊢ 𝐽 = (𝐿 ↾s 𝐻)    &   ⊢ (𝜑 → 𝐿 ∈ Field)    &   ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐼))    &   ⊢ (𝜑 → 𝐹 ∈ (SubDRing‘𝐽))    &   ⊢ (𝜑 → 𝐺 ∈ (SubDRing‘𝐿))    &   ⊢ (𝜑 → 𝐻 ∈ (SubDRing‘𝐿))    &   ⊢ (𝜑 → 𝑁 ∈ ℕ0)    &   ⊢ (𝜑 → (𝐼[:]𝐾) = 2)    &   ⊢ (𝜑 → (𝐽[:]𝐾) = (2↑𝑁))    &   ⊢ 𝐸 = (𝐿 ↾s (𝐿 fldGen (𝐺 ∪ 𝐻)))    ⇒   ⊢ (𝜑 → ∃𝑛 ∈ ℕ0 (𝐸[:]𝐾) = (2↑𝑛))