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Theorem brun 5155
Description: The union of two binary relations. (Contributed by NM, 21-Dec-2008.)
Assertion
Ref Expression
brun (𝐴(𝑅 ∪ 𝑆)𝐵 ↔ (𝐴𝑅𝐵 ∨ 𝐴𝑆𝐵))

Proof of Theorem brun
StepHypRef Expression
1 elun 4152 . 2 (⟨𝐴, 𝐵⟩ ∈ (𝑅 ∪ 𝑆) ↔ (⟨𝐴, 𝐵⟩ ∈ 𝑅 ∨ ⟨𝐴, 𝐵⟩ ∈ 𝑆))
2 df-br 5103 . 2 (𝐴(𝑅 ∪ 𝑆)𝐵 ↔ ⟨𝐴, 𝐵⟩ ∈ (𝑅 ∪ 𝑆))
3 df-br 5103 . . 3 (𝐴𝑅𝐵 ↔ ⟨𝐴, 𝐵⟩ ∈ 𝑅)
4 df-br 5103 . . 3 (𝐴𝑆𝐵 ↔ ⟨𝐴, 𝐵⟩ ∈ 𝑆)
53, 4orbi12i 928 . 2 ((𝐴𝑅𝐵 ∨ 𝐴𝑆𝐵) ↔ (⟨𝐴, 𝐵⟩ ∈ 𝑅 ∨ ⟨𝐴, 𝐵⟩ ∈ 𝑆))
61, 2, 53bitr4i 306 1 (𝐴(𝑅 ∪ 𝑆)𝐵 ↔ (𝐴𝑅𝐵 ∨ 𝐴𝑆𝐵))
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   ↔ wb 209   ∨ wo 861   ∈ wcel 2144   ∪ cun 4149  ⟨cop 4834   class class class wbr 5102
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1827  ax-4 1841  ax-5 1942  ax-6 1999  ax-7 2040  ax-8 2146  ax-9 2154  ax-ext 2732
This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-tru 1572  df-ex 1812  df-sb 2099  df-clab 2739  df-cleq 2752  df-clel 2835  df-v 3452  df-un 4151  df-br 5103
This theorem is used by:  dmun  5891  qfto  6114  poleloe  6124  cnvun  6132  coundi  6248  coundir  6249  fununmo  6587  eqfunresadj  7370  brdifun  8751  fpwwe2lem12  10730  ltxrlt  11383  ltxr  13247  dfle2  13279  brprop  33337  satfbrsuc  36217  dfso2  36612  dfon3  36746  brcup  36793  dfrdg4  36807  ecun  39418  dfsucmap3  39488  dffrege99  45055
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