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Theorem ecin0 38851
Description: Two ways of saying that the coset of 𝐴 and the coset of 𝐵 have no elements in common. (Contributed by Peter Mazsa, 1-Dec-2018.)
Assertion
Ref Expression
ecin0 ((𝐴𝑉𝐵𝑊) → (([𝐴]𝑅 ∩ [𝐵]𝑅) = ∅ ↔ ∀𝑥(𝐴𝑅𝑥 → ¬ 𝐵𝑅𝑥)))
Distinct variable groups:   𝑥,𝐴   𝑥,𝐵   𝑥,𝑅   𝑥,𝑉   𝑥,𝑊

Proof of Theorem ecin0
StepHypRef Expression
1 disj1 4406 . 2 (([𝐴]𝑅 ∩ [𝐵]𝑅) = ∅ ↔ ∀𝑥(𝑥 ∈ [𝐴]𝑅 → ¬ 𝑥 ∈ [𝐵]𝑅))
2 elecg 8723 . . . . . 6 ((𝑥 ∈ V ∧ 𝐴𝑉) → (𝑥 ∈ [𝐴]𝑅𝐴𝑅𝑥))
32el2v1 38728 . . . . 5 (𝐴𝑉 → (𝑥 ∈ [𝐴]𝑅𝐴𝑅𝑥))
43adantr 484 . . . 4 ((𝐴𝑉𝐵𝑊) → (𝑥 ∈ [𝐴]𝑅𝐴𝑅𝑥))
5 elecALTV 38770 . . . . . . 7 ((𝐵𝑊𝑥 ∈ V) → (𝑥 ∈ [𝐵]𝑅𝐵𝑅𝑥))
65elvd 3460 . . . . . 6 (𝐵𝑊 → (𝑥 ∈ [𝐵]𝑅𝐵𝑅𝑥))
76adantl 485 . . . . 5 ((𝐴𝑉𝐵𝑊) → (𝑥 ∈ [𝐵]𝑅𝐵𝑅𝑥))
87notbid 320 . . . 4 ((𝐴𝑉𝐵𝑊) → (¬ 𝑥 ∈ [𝐵]𝑅 ↔ ¬ 𝐵𝑅𝑥))
94, 8imbi12d 346 . . 3 ((𝐴𝑉𝐵𝑊) → ((𝑥 ∈ [𝐴]𝑅 → ¬ 𝑥 ∈ [𝐵]𝑅) ↔ (𝐴𝑅𝑥 → ¬ 𝐵𝑅𝑥)))
109albidv 1940 . 2 ((𝐴𝑉𝐵𝑊) → (∀𝑥(𝑥 ∈ [𝐴]𝑅 → ¬ 𝑥 ∈ [𝐵]𝑅) ↔ ∀𝑥(𝐴𝑅𝑥 → ¬ 𝐵𝑅𝑥)))
111, 10bitrid 285 1 ((𝐴𝑉𝐵𝑊) → (([𝐴]𝑅 ∩ [𝐵]𝑅) = ∅ ↔ ∀𝑥(𝐴𝑅𝑥 → ¬ 𝐵𝑅𝑥)))
Colors of variables: wff setvar class
Syntax hints:  ¬ wn 3  wi 4  wb 208  wa 399  wal 1558   = wceq 1560  wcel 2142  Vcvv 3454  cin 3903  c0 4285   class class class wbr 5100  [cec 8676
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1815  ax-4 1829  ax-5 1930  ax-6 1987  ax-7 2028  ax-8 2144  ax-9 2152  ax-ext 2734  ax-sep 5246  ax-pr 5390
This theorem depends on definitions:  df-bi 209  df-an 400  df-or 859  df-3an 1100  df-tru 1563  df-fal 1573  df-ex 1800  df-sb 2091  df-clab 2741  df-cleq 2754  df-clel 2837  df-ral 3077  df-rex 3087  df-rab 3415  df-v 3456  df-dif 3907  df-un 3909  df-in 3911  df-ss 3921  df-nul 4286  df-if 4481  df-sn 4583  df-pr 4585  df-op 4589  df-br 5101  df-opab 5163  df-xp 5653  df-cnv 5655  df-dm 5657  df-rn 5658  df-res 5659  df-ima 5660  df-ec 8680
This theorem is referenced by:  ecinn0  38852
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