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Theorem eldisjeqi 39082
Description: Equality theorem for disjoint elementhood, inference version. (Contributed by Peter Mazsa, 23-Sep-2021.)
Hypothesis
Ref Expression
eldisjeqi.1 𝐴 = 𝐵
Assertion
Ref Expression
eldisjeqi ( ElDisj 𝐴 ↔ ElDisj 𝐵)

Proof of Theorem eldisjeqi
StepHypRef Expression
1 eldisjeqi.1 . 2 𝐴 = 𝐵
2 eldisjeq 39081 . 2 (𝐴 = 𝐵 → ( ElDisj 𝐴 ↔ ElDisj 𝐵))
31, 2ax-mp 5 1 ( ElDisj 𝐴 ↔ ElDisj 𝐵)
Colors of variables: wff setvar class
Syntax hints:  wb 206   = wceq 1542   ElDisj weldisj 38461
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1797  ax-4 1811  ax-5 1912  ax-6 1969  ax-7 2010  ax-8 2116  ax-9 2124  ax-11 2163  ax-ext 2709  ax-sep 5243  ax-pr 5379
This theorem depends on definitions:  df-bi 207  df-an 396  df-or 849  df-3an 1089  df-tru 1545  df-fal 1555  df-ex 1782  df-sb 2069  df-clab 2716  df-cleq 2729  df-clel 2812  df-ral 3053  df-rex 3063  df-rab 3402  df-v 3444  df-dif 3906  df-un 3908  df-in 3910  df-ss 3920  df-nul 4288  df-if 4482  df-sn 4583  df-pr 4585  df-op 4589  df-br 5101  df-opab 5163  df-id 5527  df-xp 5638  df-rel 5639  df-cnv 5640  df-co 5641  df-dm 5642  df-rn 5643  df-res 5644  df-coss 38741  df-cnvrefrel 38847  df-funALTV 39007  df-disjALTV 39030  df-eldisj 39032
This theorem is referenced by:  eldisjs7  39181
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